This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
If Ksp of a salt A2B3 is given by 1 x 10^-25. Then find the solubility of the salt?(a) 10^-3(b) 10^-4(c) 10^-5(d) 10^-8I got this question during a job interview.Query is from Solubility Equilibria of Sparingly Soluble Salts topic in portion Equilibrium of Chemistry – Class 11 |
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Answer» Right answer is (c) 10^-5 |
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| 2. |
Both the solubility product and ionic product are applicable to all types of solutions.(a) true(b) falseThis question was addressed to me in an interview for internship.I would like to ask this question from Solubility Equilibria of Sparingly Soluble Salts topic in division Equilibrium of Chemistry – Class 11 |
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Answer» Correct option is (b) false |
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| 3. |
The solubility for the salts of the type AB3 is given by _______________(a) (Ksp 27)^1/4(b) (Ksp/27)^1/5(c) (Ksp/27)^3/4(d) (Ksp/27)^1/4The question was posed to me in an interview for internship.I would like to ask this question from Solubility Equilibria of Sparingly Soluble Salts in chapter Equilibrium of Chemistry – Class 11 |
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Answer» Correct option is (d) (Ksp/27)^1/4 |
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| 4. |
A salt is soluble is the solubility is ______________(a) less than 0.01 M(b) in between 0.01 M and 0.1 M(c) greater than 0.01 M(d) greater than 0.1 MI got this question in a job interview.My question comes from Solubility Equilibria of Sparingly Soluble Salts in portion Equilibrium of Chemistry – Class 11 |
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Answer» CORRECT option is (d) GREATER than 0.1 M Easiest explanation: A salt is soluble if the solubility is greater than 0.1 M. A salt is slightly soluble if the solubility is between 0.01 M and 0.1 M and the salt is SPARINGLY soluble if the solubility is less than 0.01 M. |
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| 5. |
Solubility product can be used in predicting the solubility of a sparingly soluble salt.(a) true(b) falseThis question was posed to me in homework.This is a very interesting question from Solubility Equilibria of Sparingly Soluble Salts topic in division Equilibrium of Chemistry – Class 11 |
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Answer» Correct option is (a) true |
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| 6. |
Precipitate is formed if ionic product is ______________(a) greater than the solubility product(b) less than the solubility product(c) equal to the solubility product(d) independent of the solubility productThe question was asked in an interview for job.I'd like to ask this question from Solubility Equilibria of Sparingly Soluble Salts in portion Equilibrium of Chemistry – Class 11 |
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Answer» Correct OPTION is (a) GREATER than the SOLUBILITY product |
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| 7. |
For the dissociation of an electrolyte AxBy, Ksp is given as [A^y+]^x[B^x+]^y. What is Ksp?(a) solubility product(b) soluble product(c) solution product(d) solvent productI had been asked this question during an online interview.My query is from Solubility Equilibria of Sparingly Soluble Salts topic in portion Equilibrium of Chemistry – Class 11 |
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Answer» CORRECT ANSWER is (a) solubility product For explanation I would SAY: Solubility product Ksp is defined as the product of the concentrations of the ions of the salt in its standard solution at a given temperature RAISED to the power of the ions produced by the DISSOCIATION of 1 mole of the salt. |
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| 8. |
Common Ion effect can be used in which of the following cases?(a) cloth making(b) alcohol purification(c) quantitative analysis(d) qualitative analysisThe question was posed to me in an interview.This is a very interesting question from Solubility Equilibria of Sparingly Soluble Salts in chapter Equilibrium of Chemistry – Class 11 |
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Answer» RIGHT answer is (d) qualitative analysis Easy explanation: Common Ion EFFECT is USED in the purification of common SALT, salting out of soap and qualitative analysis. In qualitative analysis, Ammonium Hydroxide is added in the presence of Ammonium Chloride to avoid the precipitation of V group radicals. |
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| 9. |
Hydroxide Ion concentration in calcium hydroxide and barium Hydroxide is an example of ______________ solution.(a) isochoric solution(b) isohydric solutions(c) hypo solution(d) hyper solutionThe question was asked in class test.This question is from Solubility Equilibria of Sparingly Soluble Salts topic in division Equilibrium of Chemistry – Class 11 |
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Answer» CORRECT choice is (b) isohydric solutions To explain: In the solution of TWO electrolytes, if the common IONS’ concentration (Hydroxide Ion concentration in calcium hydroxide and BARIUM hydroxide solution) is equal, then on MIXING there is zero change in the degree of association in both of the electrolytes, such solutions are called isohydric solutions. |
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| 10. |
The degree of dissociation of Ammonium hydroxide increases in the presence of Ammonium Chloride because of ______________(a) solubility product(b) common Ion effect(c) hydrolysis of the salt(d) mixed saltsThe question was posed to me by my college professor while I was bunking the class.This intriguing question comes from Solubility Equilibria of Sparingly Soluble Salts in division Equilibrium of Chemistry – Class 11 |
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Answer» RIGHT choice is (C) hydrolysis of the salt Explanation: Common ION effect is defined as the separation of the dissociation of a weak electrolyte by the addition of a strong electrolyte having some common ion. Therefore the DEGREE of dissociation of Ammonium hydroxide decreases in the presence of Ammonium Chloride DUE to common Ion effect. |
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| 11. |
Which of the following do you think is a correct statement?(a) Ammonium hydroxide / ammonium chloride is an acidic buffer(b) boric acid / borax is an acidic buffer(c) henderson hasselbalch equation is given by pH = pKb + log[salt]/[acid](d) PH + pOH = 4The question was posed to me in an online quiz.My query is from Equilibrium topic in division Equilibrium of Chemistry – Class 11 |
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Answer» The correct option is (b) boric acid / borax is an acidic buffer |
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| 12. |
Note that the pKa here is given by 4.752, a buffer is made using 0.8 M acetic acid and 1 M Sodium Acetate what do you think its pH is(log10/8 = 0.097)?(a) 4.84(b) 4.85(c) 4.849(d) 4.846I had been asked this question at a job interview.The origin of the question is Equilibrium in division Equilibrium of Chemistry – Class 11 |
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Answer» The correct option is (b) 4.85 |
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| 13. |
If the pH of a substance is given by 3 then what is the pOH of the substance?(a) 3(b) 7(c) 14(d) 11I have been asked this question by my college director while I was bunking the class.This interesting question is from Equilibrium in chapter Equilibrium of Chemistry – Class 11 |
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Answer» Right choice is (d) 11 |
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| 14. |
If 0.20 mol/L CH3COOH and 0.50 mol/L CH3COO^– together make a buffer solution, calculate the pH of the solution if the acid dissociation constant ofCH3COOH is 1.8 × 10^-5.(a) 2.09(b) 5.14(c) 2.65(d) 3.98The question was asked in quiz.My question is based upon Equilibrium in division Equilibrium of Chemistry – Class 11 |
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Answer» The correct answer is (B) 5.14 |
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| 15. |
Buffer capacity of a buffer is given as two units for a change in pH by Unity. Then what is the number of moles of acid or base, added in one litre of the solution?(a) 2(b) 0.5(c) 1(d) 4I had been asked this question in an international level competition.I'm obligated to ask this question of Equilibrium topic in chapter Equilibrium of Chemistry – Class 11 |
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Answer» Right choice is (a) 2 |
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| 16. |
What is the buffer capacity if 3 moles are added in 5 litres of the solution to change the pH by 2 units?(a) 0.2(b) 0.5(c) 0.15(d) 0.3I got this question during an online exam.My question is from Equilibrium in chapter Equilibrium of Chemistry – Class 11 |
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Answer» Correct option is (d) 0.3 |
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| 17. |
Buffer solution is destroyed when _____________(a) addition of weak base(b) addition of strong acid or base(c) addition of weak acid(d) addition of a saltThe question was posed to me in a job interview.My query is from Equilibrium in portion Equilibrium of Chemistry – Class 11 |
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Answer» Correct answer is (a) ADDITION of WEAK base |
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| 18. |
Which of the following is an equation used to calculate the pH of a buffer solution for an acidic buffer?(a) pH = pKa + log[salt]/[acid](b) pOH = pKa + log[salt]/[acid](c) pH = pKb + log[salt]/[acid](d) pH = pKa + log[salt][acid]This question was posed to me by my college professor while I was bunking the class.My doubt stems from Equilibrium topic in division Equilibrium of Chemistry – Class 11 |
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Answer» CORRECT option is (a) PH = PKA + LOG[salt]/[ACID] The best I can explain: Equation that is used to calculate the pH of a buffer solution for an acidic buffer is pH = pKa + log[salt]/[acid]. This equation is known as henderson-hasselbalch equation, it is used for making of buffer solutions. |
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| 19. |
Which of the following is not an acidic buffer?(a) Acetic Acid-Sodium acetate(b) Boric acid-borax(c) Ammonium hydroxide-ammonium chloride(d) All are acidic buffersThe question was posed to me in an online quiz.My doubt is from Equilibrium in division Equilibrium of Chemistry – Class 11 |
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Answer» The correct CHOICE is (C) Ammonium hydroxide-ammonium chloride |
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| 20. |
Carbonic acid and sodium bicarbonate are present in blood as a buffer.(a) true(b) falseI got this question in class test.I need to ask this question from Equilibrium topic in portion Equilibrium of Chemistry – Class 11 |
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Answer» The CORRECT choice is (a) true |
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| 21. |
Acid strength increases in the order of _____________(a) HF ≪ HCl ≪ HBr ≪ HI(b) HF ≪ HBr ≪ HCl ≪ HI(c) HI ≪ HCl ≪ HBr ≪ HF(d) HCl ≪ HF ≪ HBr ≪ HIThis question was posed to me during an interview.I'd like to ask this question from Equilibrium topic in section Equilibrium of Chemistry – Class 11 |
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Answer» Correct answer is (a) HF ≪ HCl ≪ HBr ≪ HI |
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| 22. |
Acetic acid’s pKa is 4.2 and ammonium hydroxide pKb is 3.24. What is the pH of the ammonium acetate solution?(a) 7.12(b) 7(c) 4.2(d) 7.48The question was posed to me in examination.My question is based upon Equilibrium in chapter Equilibrium of Chemistry – Class 11 |
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Answer» RIGHT answer is (d) 7.48 Easiest explanation: We know that the pH of the solution of a weak acid and a weak BASE is given by 1/2pKW + 1/2pKa – 1/2pKb. So pH = 7 + \(\FRAC{1}{2}\)[4.2 – 3.24]; pH = 7 + 0.48 = 7.48, we GET this by SUBSTITUTING acetic acid’s pKa as 4.2 and ammonium hydroxidepKb as 3.24. |
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| 23. |
Formic acid has a concentration of 0.1M and Ka is 1.77 x 10^-4. What is the value of degree of dissociation?(a) 4(b) 4.2(c) 0.42(d) 42I got this question in a national level competition.My question is based upon Equilibrium topic in division Equilibrium of Chemistry – Class 11 |
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Answer» The CORRECT answer is (b) 4.2 |
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| 24. |
What is the pH of the solution of sulphuric acid having a concentration of 0.01M?(a) 1(b) 2(c) 3(d) 4The question was posed to me in final exam.I want to ask this question from Equilibrium topic in portion Equilibrium of Chemistry – Class 11 |
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Answer» The correct OPTION is (B) 2 |
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| 25. |
Why is the aqueous solution of a salt of a weak acid and strong base is alkaline?(a) utilization(b) neutralization(c) cationic hydrolysis(d) anionic hydrolysisI have been asked this question in unit test.Enquiry is from Equilibrium topic in section Equilibrium of Chemistry – Class 11 |
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Answer» The CORRECT answer is (d) anionic hydrolysis |
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| 26. |
What is the hydrolysis constant of a weak acid-weak base?(a) KW/Kb(b) KW/Ka(c) KW/KaKb(d) 1/KaKbThe question was posed to me during a job interview.I would like to ask this question from Equilibrium topic in division Equilibrium of Chemistry – Class 11 |
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Answer» The correct answer is (C) KW/KaKb |
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| 27. |
What is the reverse process of Neutralization?(a) formation(b) hydrolysis(c) reaction(d) splittingThe question was posed to me in unit test.My question is taken from Equilibrium in portion Equilibrium of Chemistry – Class 11 |
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Answer» Right choice is (b) hydrolysis |
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| 28. |
NaCl is a ________ salt.(a) Normal(b) Acidic(c) Basic(d) DoubleThis question was posed to me by my college professor while I was bunking the class.This intriguing question originated from Equilibrium topic in section Equilibrium of Chemistry – Class 11 |
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Answer» Correct OPTION is (a) Normal |
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| 29. |
A neutralization reaction results in the formation of _______________(a) salts(b) acid(c) base(d) hydrogenI got this question during a job interview.My question is taken from Equilibrium topic in section Equilibrium of Chemistry – Class 11 |
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Answer» Right CHOICE is (a) salts |
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| 30. |
Which of the following has a PH greater than 7?(a) gastric juice(b) vinegar(c) blood plasma(d) lemon juiceI had been asked this question during an interview.Enquiry is from Equilibrium in section Equilibrium of Chemistry – Class 11 |
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Answer» Right choice is (c) blood plasma |
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| 31. |
What is the pKW at 298 k?(a) 14(b) 7(c) 1(d) 0This question was posed to me in unit test.I'd like to ask this question from Equilibrium in section Equilibrium of Chemistry – Class 11 |
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Answer» Correct option is (a) 14 |
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| 32. |
The ionization constant of water increases with increase in temperature.(a) true(b) falseThe question was asked by my college director while I was bunking the class.My doubt is from Equilibrium topic in portion Equilibrium of Chemistry – Class 11 |
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Answer» Correct OPTION is (a) true |
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| 33. |
Write pH in terms of concentration of hydrogen ion?(a) [H^+] = 1^-pH(b) [H^+] = 10^-pH(c) [H^+] = 10^pH(d) [H] = 10^-pHThis question was posed to me in an international level competition.I'm obligated to ask this question of Equilibrium topic in portion Equilibrium of Chemistry – Class 11 |
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Answer» Right answer is (b) [H^+] = 10^-pH |
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| 34. |
What is the value of the ionic product of water at 298k?(a) 7 x 10^-14/mol^2L^2(b) 1 x 10^-10/mol^2L^2(c) 1 x 10^-14/molL^2(d) 1 x 10^-14/mol^2L^2I had been asked this question in an interview for internship.This interesting question is from Equilibrium topic in portion Equilibrium of Chemistry – Class 11 |
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Answer» Right option is (d) 1 x 10^-14/mol^2L^2 |
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| 35. |
Which of the following is not a Lewis acid?(a) aluminium chloride(b) sodium ion(c) sulphur tetrafluoride(d) hydroxide ionThis question was addressed to me in an online quiz.My question is taken from Equilibrium topic in division Equilibrium of Chemistry – Class 11 |
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Answer» Right answer is (d) hydroxide ion |
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| 36. |
Water in case of HCl acts as a/an ___________, in case of ammonia acts as a/an ________(a) base, base(b) base, acid(c) acid, base(d) acid, acidI had been asked this question in an internship interview.I'm obligated to ask this question of Equilibrium in section Equilibrium of Chemistry – Class 11 |
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Answer» Correct OPTION is (b) base, acid |
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| 37. |
Hydroxide ion is a bronsted base.(a) true(b) falseI got this question by my college director while I was bunking the class.I want to ask this question from Equilibrium in section Equilibrium of Chemistry – Class 11 |
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Answer» Right choice is (a) true |
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| 38. |
Which of the following is the strongest hydracid known?(a) HCN(b) HClO4(c) HCl(d) HNO3This question was posed to me by my school principal while I was bunking the class.This key question is from Equilibrium topic in chapter Equilibrium of Chemistry – Class 11 |
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Answer» Correct option is (b) HClO4 |
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| 39. |
Identify a conjugate pair in the equation: NH3 + H2O \(\rightleftharpoons\) NH4^+ + OH^–.(a) ammonia and water(b) water and hydroxide ion(c) ammonium ion and hydroxide ion(d) ammonia and hydroxide ionThe question was posed to me in class test.My question is taken from Equilibrium in section Equilibrium of Chemistry – Class 11 |
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Answer» The correct option is (b) water and HYDROXIDE ion |
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| 40. |
Silver ion is a Lewis acid.(a) True(b) FalseI have been asked this question in quiz.My doubt is from Equilibrium topic in chapter Equilibrium of Chemistry – Class 11 |
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Answer» The CORRECT answer is (a) True |
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| 41. |
Lewis concept does explain the behaviour of __________(a) bases(b) salts(c) protonic acids(d) amphoteric substancesI have been asked this question in an online interview.My query is from Equilibrium in chapter Equilibrium of Chemistry – Class 11 |
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Answer» Correct answer is (c) PROTONIC ACIDS |
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| 42. |
Which of the following is a Lewis base?(a) ammonia(b) magnesium chloride(c) aluminium chloride(d) sodium ionI had been asked this question in an online quiz.My question is taken from Equilibrium in portion Equilibrium of Chemistry – Class 11 |
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Answer» Right choice is (a) ammonia |
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| 43. |
Which of the following substances cannot act as both acid as well as a base?(a) amphoteric substance(b) amphiprotic substance(c) ampholyte(d) protophilicThe question was asked by my college professor while I was bunking the class.Enquiry is from Equilibrium topic in section Equilibrium of Chemistry – Class 11 |
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Answer» Correct CHOICE is (d) protophilic |
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| 44. |
A strong acid has a ______________(a) weak conjugate acid(b) weak conjugate base(c) strong conjugate base(d) strong conjugate acidThe question was asked during an interview.My question is based upon Equilibrium in section Equilibrium of Chemistry – Class 11 |
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Answer» Right answer is (B) weak conjugate base |
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| 45. |
A proton donor is a ____________ substance.(a) protongenic(b) protophilic(c) amphoteric(d) amphiproticI had been asked this question in an international level competition.Asked question is from Equilibrium in division Equilibrium of Chemistry – Class 11 |
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Answer» The correct option is (a) protongenic |
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| 46. |
Arrhenius theory could not explain the acidic and basic behaviour in non-aqueous solutions.(a) true(b) falseThis question was posed to me during an internship interview.This interesting question is from Equilibrium topic in section Equilibrium of Chemistry – Class 11 |
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Answer» Right choice is (a) true |
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| 47. |
Bases turn red litmus blue.(a) True(b) FalseI had been asked this question at a job interview.The doubt is from Equilibrium in division Equilibrium of Chemistry – Class 11 |
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Answer» RIGHT answer is (a) True The EXPLANATION is: Litmus is a mixture of different dyes from LICHENS that is water soluble. Acids change blue litmus red and bases change red litmus blue. The original colour of Litmus is PURPLE. The pH of a BASE is in between 7 and 14. |
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| 48. |
HCl is an Arrhenius ___________(a) acid(b) base(c) salt(d) waterI have been asked this question in an interview for internship.This key question is from Equilibrium in chapter Equilibrium of Chemistry – Class 11 |
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Answer» Right choice is (a) acid |
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| 49. |
Which of the following is not a property of an acid according to Robert Boyle?(a) turns blue Litmus red(b) sour in taste(c) neutralize bases(d) bitter in tasteI had been asked this question during an internship interview.My enquiry is from Equilibrium in division Equilibrium of Chemistry – Class 11 |
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Answer» The correct choice is (d) bitter in taste |
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| 50. |
Can nonelectrolytes conduct electricity?(a) yes(b) no(c) sometimes(d) cannot sayI had been asked this question at a job interview.This question is from Ionic Equilibrium in Solution in division Equilibrium of Chemistry – Class 11 |
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Answer» The correct CHOICE is (b) no |
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