The solubility for the salts of the type AB3 is given by _______________(a) (Ksp 27)^1/4(b) (Ksp/27)^1/5(c) (Ksp/27)^3/4(d) (Ksp/27)^1/4The question was posed to me in an interview for internship.I would like to ask this question from Solubility Equilibria of Sparingly Soluble Salts in chapter Equilibrium of Chemistry – Class 11

The solubility for the salts of the type AB3 is given by _____________

1.	The solubility for the salts of the type AB3 is given by _______________(a) (Ksp 27)^1/4(b) (Ksp/27)^1/5(c) (Ksp/27)^3/4(d) (Ksp/27)^1/4The question was posed to me in an interview for internship.I would like to ask this question from Solubility Equilibria of Sparingly Soluble Salts in chapter Equilibrium of Chemistry – Class 11
Answer» Correct option is (d) (Ksp/27)^1/4 To elaborate: For the salt AxBy, (AxBy = xA^y+ + yB^x+), the SOLUBILITY of a sparingly SOLUBLE salt is given by x^x.y^y.s^x+y. Ksp = x^x.y^y.s^x+y, where x = 1 and y = 3; Ksp = 27S^4, by rearranging, we get solubility denoted by S as (Ksp/27)^1/4.

Discussion

No Comment Found

Related InterviewSolutions

If Ksp of a salt A2B3 is given by 1 x 10^-25. Then find the solubility of the salt?(a) 10^-3(b) 10^-4(c) 10^-5(d) 10^-8I got this question during a job interview.Query is from Solubility Equilibria of Sparingly Soluble Salts topic in portion Equilibrium of Chemistry – Class 11
Both the solubility product and ionic product are applicable to all types of solutions.(a) true(b) falseThis question was addressed to me in an interview for internship.I would like to ask this question from Solubility Equilibria of Sparingly Soluble Salts topic in division Equilibrium of Chemistry – Class 11
The solubility for the salts of the type AB3 is given by _______________(a) (Ksp 27)^1/4(b) (Ksp/27)^1/5(c) (Ksp/27)^3/4(d) (Ksp/27)^1/4The question was posed to me in an interview for internship.I would like to ask this question from Solubility Equilibria of Sparingly Soluble Salts in chapter Equilibrium of Chemistry – Class 11
A salt is soluble is the solubility is ______________(a) less than 0.01 M(b) in between 0.01 M and 0.1 M(c) greater than 0.01 M(d) greater than 0.1 MI got this question in a job interview.My question comes from Solubility Equilibria of Sparingly Soluble Salts in portion Equilibrium of Chemistry – Class 11
Solubility product can be used in predicting the solubility of a sparingly soluble salt.(a) true(b) falseThis question was posed to me in homework.This is a very interesting question from Solubility Equilibria of Sparingly Soluble Salts topic in division Equilibrium of Chemistry – Class 11
Precipitate is formed if ionic product is ______________(a) greater than the solubility product(b) less than the solubility product(c) equal to the solubility product(d) independent of the solubility productThe question was asked in an interview for job.I'd like to ask this question from Solubility Equilibria of Sparingly Soluble Salts in portion Equilibrium of Chemistry – Class 11
For the dissociation of an electrolyte AxBy, Ksp is given as [A^y+]^x[B^x+]^y. What is Ksp?(a) solubility product(b) soluble product(c) solution product(d) solvent productI had been asked this question during an online interview.My query is from Solubility Equilibria of Sparingly Soluble Salts topic in portion Equilibrium of Chemistry – Class 11
Common Ion effect can be used in which of the following cases?(a) cloth making(b) alcohol purification(c) quantitative analysis(d) qualitative analysisThe question was posed to me in an interview.This is a very interesting question from Solubility Equilibria of Sparingly Soluble Salts in chapter Equilibrium of Chemistry – Class 11
Hydroxide Ion concentration in calcium hydroxide and barium Hydroxide is an example of ______________ solution.(a) isochoric solution(b) isohydric solutions(c) hypo solution(d) hyper solutionThe question was asked in class test.This question is from Solubility Equilibria of Sparingly Soluble Salts topic in division Equilibrium of Chemistry – Class 11
The degree of dissociation of Ammonium hydroxide increases in the presence of Ammonium Chloride because of ______________(a) solubility product(b) common Ion effect(c) hydrolysis of the salt(d) mixed saltsThe question was posed to me by my college professor while I was bunking the class.This intriguing question comes from Solubility Equilibria of Sparingly Soluble Salts in division Equilibrium of Chemistry – Class 11

Discussion

No Comment Found

Related InterviewSolutions

Reply to Comment