Note that the pKa here is given by 4.752, a buffer is made using 0.8 M acetic acid and 1 M Sodium Acetate what do you think its pH is(log10/8 = 0.097)?(a) 4.84(b) 4.85(c) 4.849(d) 4.846I had been asked this question at a job interview.The origin of the question is Equilibrium in division Equilibrium of Chemistry – Class 11

Note that the pKa here is given by 4.752, a buffer is made using 0.8 M

1.	Note that the pKa here is given by 4.752, a buffer is made using 0.8 M acetic acid and 1 M Sodium Acetate what do you think its pH is(log10/8 = 0.097)?(a) 4.84(b) 4.85(c) 4.849(d) 4.846I had been asked this question at a job interview.The origin of the question is Equilibrium in division Equilibrium of Chemistry – Class 11
Answer» The correct option is (b) 4.85 The best EXPLANATION: ACCORDING to the Henderson hasselbalch EQUATION pH = pKa + log[salt]/[acid], if we substitute the concentration of salt as 1 M and the concentration of acid as 0.8 M, pH = 4.752 + 0.097 = 4.849 is the REQUIRED answer.

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