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Formic acid has a concentration of 0.1M and Ka is 1.77 x 10^-4. What is the value of degree of dissociation?(a) 4(b) 4.2(c) 0.42(d) 42I got this question in a national level competition.My question is based upon Equilibrium topic in division Equilibrium of Chemistry – Class 11

Answer»

The CORRECT answer is (b) 4.2

Easy EXPLANATION: The dissociation constant K = [H^+][HCOO^–]/[HCOOH] = x^2/0.1 – x = 1.77 x10^-4; x = [H^+] = 0.0042M. The percent of dissociation is x/0.1 = (0.042M)100% = 4.2. THEREFORE the value of DEGREE of dissociation is 4.2



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