Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

The correct IUPAC name of (C_2H_5)_4C is :

Answer»

TETRAETHYL methane
2-ethylpentane
3,3-diethylpentane
None of the above

Answer :C
Discussion
2.

The correct IUPAC name of AlCl_3(EtOH)_4 is:

Answer»

ALUMINIUM(II)chloride-4-ethanoI
Aluminium(III)chloride-4-ethanol
Aluminium(IV) chloride-4-hydroxy ethane
Aluminium chloride-4-ethanol

Answer :B
Discussion
3.

The correct IUPAC name of acetonitrile is :

Answer»

ETHANENITRILE
Cyanomethane
Methanenitrile
Cyanoethane.

SOLUTION :`CH_(3)CN:` Ethanenitrile
Discussion
4.

The correct IUPAC name of

Answer»

Tri `-mu-` CARBONYL bis (tricarbonyl) iron (0)
Hexacarbonyl iron (III) `mu-` tricarbonyl FERRATE(0)
Tricarbonyl iron (0) `mu-`tricarbonyltricarbonyl iron (0)
Nonacarbonyl iron
Discussion
5.

The correct IUPAC name for the compound (CH_(3))_(3)COH is :

Answer»

Trimethylmethan-1-ol
1,1,1-Trimethylmethan-1-ol
1-Butanol
2-Methylpropan-2-ol

Answer :D
Discussion
6.

The correct IUPAC name for CH_(3)-CH_(2)-O-overset(CH_(3))overset(|)(CH)-CH_(2)-CH_(2)-CH_(2)Cl is:

Answer»

2-ethoxy-5-chloropentane
1-chloro-4-ethoxy-4-methylbutane
1-chloro-4-ethoxypentane
ethyl-1-chloropenytylether

ANSWER :C
Discussion
7.

The correct IUPAC name for H_(2)C=CH- C-=CH is:

Answer»

but-3-en-1-yne
but-1-en-3-yne
but-1-yn-3-ene
but-3-yn-1-ene

Answer :B
Discussion
8.

The correct IUPAC name for CH_(2)=CHCH_(2)NHCH_(3) is :

Answer»

Allylmethylamine
2 - AMINE -4- pentene
4 - aminopent -1- ENE
N - methylprop -2- ene -1- amine

Solution :`overset(3)CH_(2)=overset(2)CH overset(1)CH_(2)NHCH_(3):N-"Methylprop -2 - en -1- amine"`
Discussion
9.

The correct IUPAC name for CH_2=CHCH_2NHCH_3 is

Answer»

Allylmethylamine
2-amino-4-pentene
4-aminopent-1-ene
N-methylprop-2-en-1-amine

Solution :N-methylprop-2-en-1-amine
Discussion
10.

The correct IUPAC name for CH_2= CHCH_2 NHCH_3is

Answer»

Allylmethylamine
2-amino-4-pentene
4-aminopent-1-ene
N-methylprop-2-en-1-amine

Solution :N-methylprop-2-en-1-amine
Discussion
11.

The correct information about the given reaction is :

Answer»

The compound (I) MAY show racemisation due to ENOLISATION
The compound (I) is enolisable
The asymmetic CARBON atom has not UNDERGONE any inversion during the reaction
Compound (I) has configuration 'R'

Solution :The compound (I) does not racemise during enolisation, because the carbon atom with `alpha-H` is not asysmmetric carbon atom.
Discussion
12.

The correct increasing order of trans-effect of the following species is -

Answer»

`CN^(-) gt BR^(-) gt C_(6)H_(5)^(-) NH_(3)`
`NH_(3) gt CN^(-) gt Br^(-) gt C_(6)H_(5)^(-)`
`CN^(-) gt C_(6)H_(5)^(-) gt Br^(-) gt NH_(3)`
`Br^(-) gt CN^(-) gt NH_(3) gt C_(6)H_(5)^(-)`

ANSWER :C
Discussion
13.

The correct increasing order of the acid strength of acids, butyric acid (I), 2-chlorobutyric acid (II), 3-chlorobutyric acid (III) and 2,2-dichlorobutyric acid (IV) is :

Answer»

`IltIIltIIIltIV `
`IltIII lt II ltIV `
` III lt II lt IV lt I `
`IIIltIltIIltIV`

Answer :B
Discussion
14.

The correct increasing order of solubility among the compounds follows as

Answer»

`CaCO_3 LT NaHCO_3 lt KHCO_3`
`KHCO_3lt NaHCO_3 lt CaCO_3 `
`CaCO_3 lt KHCO_3 lt NaHCO_3 `
`NaHCO_3lt CaCO_3 lt KHCO_3 `

ANSWER :A
Discussion
15.

The correct increasing order of reactivity of halides for S_(N)2 reaction is

Answer»

`CH_(3)CH_(2)X LT (CH_(3))_(2)CHX lt CH_(2)=CHCH_(2)X lt PhCH_(2)X`
`(CH_(3))_(2)CHX lt CH_(3)CH_(2)X lt CH_(2)=CHCH_(2)"X lt PhCH_(2)X`
`PhCH_(2)X lt (CH_(3))_(2)CHX lt CH_(3)CH_(2)X lt CH_(2)=CHCH_(2)X`
`CH_(2)=CHCH_(2)X lt PhCH_(2)X lt (CH_(3))_(2) CHX lt CH_(3)CH_(2)X`

Answer :D
Discussion
16.

The correct Increasing order of Reactivity for following molecule towards E.S.R.

Answer»

`3gt4gt2gt1`
`4gt3gt2gt1`
`1gt2gt3gt4`
`1gt3gt2gt4`

ANSWER :B
Discussion
17.

The CORRECT increasing order of power of precipitation among the following is __________.

Answer»

`Cl^(-) LT PO_(4)^(3-) lt SO_(4)^(2-)`
`PO_(4)^(3-) lt Cl^(-) lt SO_(4)^(2-)`
`Cl^(-) lt SO_(4)^(2-) lt PO_(4)^(3-)`
`SO_(4)^(2-) lt PO_(4)^(3-) lt Cl^(-)`

Answer :C
Discussion
18.

The correct increasing order of dipole moments of the following is

Answer»

`H_(2)O LT H_(2)S lt H_(2)SE lt H_(2)TE`
`H_(2)Te lt H_(2)Se lt H_(2)O lt H_(2)S`
`H_(2)Se lt H_(2)Te lt H_(2)O lt H_(2)S`
`H_(2)S lt H_(2)O lt H_(2)Se lt H_(2)Te`

Solution :`H_(2)O` is more polar and `H_(2)Te` is least polar. So DIPOLE MOMENT increases from `H_(2)Te` to `H_(2)O`.
Discussion
19.

The CORRECT increasing order of dipole moments of the following is _________.

Answer»

`H_(2)O LT H_(2)S lt H_(2)Se lt H_(2)TE`
`H_(2)Te lt H_(2)Se lt H_(2)S lt H_(2)O`
`H_(2)Se lt H_(2)Te lt H_(2)O lt H_(2)S`
`H_(2)Se lt H_(2)O lt H_(2)Se lt H_(2)Te`

ANSWER :B
Discussion
20.

The correct increasing order of basicity of C_(6)H_(5)CH_(2)NH_(2)(A),(B) and is

Answer»

A ltBlt C 
CltAltB 
BltAlt C
CltBltA 

ANSWER :B
Discussion
21.

The correct increasing order of basic strength for the following compounds is

Answer»

IgtIIgtIII
IIIgtIgtII
IIgtIgtIII
IIgtIIIgtI

Solution :More the availability of LONE PAIR on N-atom, more will be the basic NATURE of amine
Basic nature :
Discussion
22.

The correct increasing order of basic strength of following amines, C_(2)H_(5)NH_(2), NH_(3),(C_(2)H_(5))_(2)NH,C_(6)H_(5)NH_(2) in gaseous state is :

Answer»

`(C_(2)H_(5))_(2)NHLT C_(2)H_(5)NH_(2)LT NH_(3)lt C_(6)H_(5)NH_(2)`
`C_(6)H_(5)NH_(2) lt (C_(2)H_(5))_(2)NHlt C_(2)H_(5)NH_(2)ltNH_(3)`
`C_(6)H_(5)NH_(2)ltNH_(3)ltC_(2)H_(5)NH_(2)lt(C_(2)H_(5))_(2)NH`
`(C_(2)H_(5))_(2)NHltC_(2)H_(5)NH_(2)ltC_(6)H_(5)NH_(2)ltNH_(3)`.

Answer :C
Discussion
23.

The correct increasing order of basic strength for the following compound is

Answer»

II LT IIIlt I
III lt Ilt II
III lt IIlt I
II lt I lt III.

Solution :Electron-donating GROUPS (i.e., `CH_3`) increase while electron-withdrawing groups (i.e., `NO_2`) decrease the BASICITY of amines.Thus, option (d) is correct.
Discussion
24.

The correct increasing order acid strength of carboxylic acid is ...........

Answer»

`F - CH_2 - COOH GT I - CH_2 - COOH gt Cl - CH_2 - COOH gt Br - CH_2 -COOH`
`Br - CH_2 - COOH gt F - CH_2COOH gt I - CH_2COOH gt Cl - CH_2 - COOH`
`F - CH_2 - COOH gt Cl- CH_2COOH gt Br - CH_2COOH gt I - CH_2COOH`
`Br - CH_2 - COOH gt Cl - CH_2 -COOH`

SOLUTION :`F - CH_2 - COOH gt Cl- CH_2COOH gt Br - CH_2COOH gt I - CH_2COOH`
Discussion
25.

The correct increasing order of acidic strength is

Answer»

`CH_3 OH gt H_2O gt (CH_3)_2 CHOH`
`H_2O gt CH_3OH gt (CH_3)_2CHOH`
`(CH_3)_2 CH OH gt CH_3OH gt H_2O`
`H_2O gt(CH_3)_2CH OH gt CH_3OH`

Solution :WATER is more ACIDIC than alcohols because of minimum positive inductive effect of hydrogen atom.
`R-O^(+) H_2 overset(Cl^-)to RCl + H_2O `
Discussion
26.

The correct hybridization of transitio metal ion/atom is …...

Answer»

`K_4[NI(CN)_4]rarrsp^(3)`
`[Ni(NH_3)_6]^(2+)rarrd^2sp^(3)`
`[Fe(CO)_5]rarrsp^3d`
`[Fe9CN)_6]^(4-)rarrsp^3d^(2)`

Answer :A
Discussion
27.

The correct graph showing variation of potential energy with internuclear distance when two hydrogen atoms approach each other is

Answer»

ANSWER :B
Discussion
28.

The correct geometry of hybridization for XeF_(4) are

Answer»

Octahedral, `sp^(3)d`
trigonal bipyramidal, `sp^(3)d`
PLANAR TRIANGLE, `sp^(3)d^(3)`
square planar, `sp^(3)d^(2)`

Solution :`XeF_(4)` (XE is `sp^(3)d^(2)`-hybridized) and has square plannar geometry.
Discussion
29.

The correct geometry and hybridisation for XeF_4are

Answer»

OCTAHEDRAL, `sp^3d^2`
TRIGONAL bipyramidal, `sp^3d`
PLANAR triangle, `sp^3d^3`
Square planar, `sp^3d^2`

ANSWER :D
Discussion
30.

The correct formula of Zeise’s salt is:

Answer»

`[PtCI_3C_2H_6]^(-)K^+`
`[PtCI_2(C_2H_2)]_2^(-)K^+`
`K^+[PtCI_3C_2H_4]^-`
`[PtCI_3(C_6H_6)]^(-)K^+`

ANSWER :C
Discussion
31.

The correct formula of salt formed by the neutralization of hypophosphorus acid with NaOH is

Answer»

`Na_(3)PO_(2)`
`Na_(3)PO_(3)`
`NaH_(2)PO_(2)`
`Na_(2)HPO_(2)`

Solution :Hypophosphorus acid `(H_(3)PO_(2))` is a monobasic acid and hence FORMS `NaH_(2)PO_(2)` SALT.
`H_(3)PO_(2) + NaOH rarr NaH_(2)PO_(2) + H_(2)O`
Discussion
32.

The correct formula of salt formed by the neutralization hypophosphorus acid with NaOH is

Answer»

`Na_(3)PO_(2)`
`Na_(3)PO_(3)`
`NaH_(2)PO_(2)`
`Na_(2)HPO_(2)`

Answer :C
Discussion
33.

The correct formula of Freon-12 is

Answer»

`CF_4`
`CF_3 CL`
`CF_2 Cl_2`
`CFCl_3`

ANSWER :C
Discussion
34.

The correct formula for diamine silver (I) chloride is :

Answer»

`[AG(NH_3)]CI`
`[Ag(NH_3)_2]CI`
`[Ag(NH_2)_2]CI`
`[Ag(NH_4)_2]CI`

ANSWER :B
Discussion
35.

The correct formula for tetraamineaquachloridocobalt (III) chloride is :

Answer»

`[Co(NH_(3))_(4)(H_(2)O)Cl]Cl_(2)`
`[Co(NH_(3))_(4)(H_(2)O)Cl]Cl_(3)`
`[Co(NH_(3))_(4)(H_(2)O)Cl]Cl`
`[COCL(H_(2)O)(NH_(3))_(4)]Cl_(2)`

Solution :N//A
Discussion
36.

The correct features of the enzymes are

Answer»

they are mainly GLOBULAR proteins
they show MAXIMUM activity at `37^(@)C`
each enzyme can CATALYSE a large NUMBER of biological REACTIONS
the enzymes present in yeast are invertase and zymase only.

Solution : Each enzyme catalyses a particular reaction. Yeast also contains other enzymes like maltase.
Discussion
37.

The correct expression in SI system relating the equivalent conductance (wedge_(aq)) , specific conductance (K) and equivalent concentration (C) is (where C is the number of gram equivalents in one litre of the solution).

Answer»

`wedge_(aq)=K/C`
`wedge_(aq)=(Kxx1000)/C`
`wedge_(aq)=(Kxx1000^(-3))/C`
`wedge_(aq)=(Kxx1000^(-6))/C`

Answer :B
Discussion
38.

The correct expression the rate of reaction of elementary reaction, A+B to C is

Answer»

`(d[C])/(dt)= k [A]`
`(d[C])/(dt)= k[B]`
`(-d[A])/(dt)=k[A][B]`
`(-d[A])/(dt)=k[A]`

SOLUTION :For first order reaction `(-d[A])/(dt)=k[A]`
Discussion
39.

The correct expression the rate of reaction of elementary reaction ,A+B---->C is:

Answer»

`d([C])/dt=K[A]`
`(d[C])/dt=K[B]`
`(-d[A])/dt=K[A][B]`
`(-d[A])/dt=K[A]`

ANSWER :C
Discussion
40.

The correct expression in SI system relating the equivalent conductance (lamda_(C)), specific conductance (kappa) and equivalent (C) is:-

Answer»

`lamda_(C)=(KAPPA)/(C)`
`lamda_(C)=kappaxx(1000)/(C)`
`lamda_(C)=(kappaxx10^(-3))/(C)`
`lamda_(C)=(kappaxx10^(-6))/(C)`

Answer :B
Discussion
41.

The correct expression for the the rate constant for reactions of zero order is

Answer»

`K = [A_0]//2t`
`k = 1/t {[A_0]-[A]}`
`k= 1/t { [A] - [A]_0}`
`k = 2.303/t log { [A_0]-[A]}`

SOLUTION :For zero order REACTION , `k = (1)/(t) ([A_(0)]- [A])`
Discussion
42.

The correct expression for the rate constant for reactions of zero order is

Answer»

`K-[A_(o)]//2T`
`k=1/t{[A_(0)]-[A]}`
`k=1/t{[A]-[A_(0)]}`
`k=(2.303)/(t)"log"{[A_(0)]-[A]}`

ANSWER :B
Discussion
43.

The correct equation for the degree of association 'alpha' of an associating solute, 'n' molecules of which undergoes association in solution, is

Answer»

`alpha = (n(i-1))/(1-n)`
`alpha =(i(n-1))/(1 + n)`
`alpha = (i(1+n))/(1-n)`
`alpha = (i(n+1))/(n-1)`

Solution :CONSIDER following association reaction,
`nA HARR (A)_n`
`{:("Initial mole","1 mole","0"),("Associated change",-alpha"mole",+alpha//n"mole"),("Equilibrium mole",(1-alpha)"mole",alpha//n"mole"):}`
Total NUMBER of moles after association of 1 mole of A
`=(1 - alpha) + (alpha //n)`mole
Total no. of moles `=1 - alpha + alpha/n`
van.t Hoff factor (i)
`=("Number of moles after association")/("Normal number of mole taken")`
`=(1-alpha + alpha/n)/1`
Discussion
44.

The correct equation for the degree of association 'alpha' of an associating solute, 'n' molecules of which undergo association in solution is

Answer»

`alpha=(N(i-1))/(1-n)`
`alpha=(i(n-1))/(1+n)`
`alpha=(i(n+1))/(1-n)`
`alpha=(i(n+1))/(n-1)`

SOLUTION :`underset("1 MOLE")(NA)hArrA_(n)`
`1-alpha""(alpha)/(n),"Total"=1-alpha+(alpha)/(n)`
`therefore i=1-alpha+(alpha)/(n) or 1-i=alpha-(alpha)/(n)=alpha(1-(1)/(n))`
`=alpha((n-1)/(n))`
`or alpha=(n)/((n-1))(i-i)=(n(i-1))/((1-n))`
Discussion
45.

The correct electronic configuration of nitrogen is :

Answer»

`1s^2 2s^2 2p_x^@ 2p_x^@ 2p_x^@`
`1s^2 2s^2 2p_x^1 2p_y^1 2p_z^1`
`1s^2 2s^2 2p_x^2 2p_y^2 2p_z^2`
`1s^2 2s^2 2p_x^@ 2p_y^@ 2p_z^@`

ANSWER :B
Discussion
46.

the correct electronic configuration of Cu^(2+) ion is

Answer»

`[Ar] (3d)^8(4S)^1`
`[Ar] (3d)^7(4s)^2`
`[Ar] (3d)^9(4s)^0`
`[Ar] (3d)^10(4s)^0`

ANSWER :C
Discussion
47.

The correct electronic configuration of Cr is……………

Answer»

`[AR] 3d^(4) 4s^(2)`
`[Ar] 3d^(5)`
`[Ar] 3d^(5) 4s^(1)`
`[Ar] 3d^(6)`

Solution :`[Ar] 3d^(5) 4s^(1)`
Discussion
48.

The correct electronic configuration for Ni^(2=) (Z=28) is

Answer»

`[Ar]4S^(2)3d^(6)`
`[Ar]4s^(2) 3d^(8)`
`[Ar]3d^(8)`
`[Ar]4s^(2)3d^(10)`

Solution :Ni`:[Ar]3d^(8)4s^(2),Ni^(2+),[Ar]3d^(8)`
Discussion
49.

The correct difference between first and second order reactions is that ...........

Answer»

A FIRST order reaction can be cataylsed , a SECOND order reaction cannot b cataysed .
The half life of a first order reaction does not depend on `[A_0]` , the half life of a second order reaction odes depend on `[A_0]`.
The rate of a first order reaction does not depend on reactant concentrations , the rate of a second order reaction does depend on reactant concentrations.
The rate of a first reaction does depend on reactant CONCENTRATION , the rate of a second order reaction does not depend on reactant concentrations.

Solution :For a first order reaction
`t_(1//2)=(0.6932)/k`
For a second order reaction
`t_(1/2)=(2^(n-1)-1)/((n-1)k[A_0]^(n-1))`
n = 2
`t_(1//2)=(2^(2-1)-1)/((2-1)k[A_0]^(2-1))`
`t_(1//2)=1/(k[A_0])`
Discussion
50.

The correct difference between first and second order reactions is that

Answer»

A FIRST order reaction can be catalysed, a second order reaction cannot be catalysed.
The HALF life of a first order reaction does not depend on `[A_(0)]`, the half life of a second order reaction does depend on `[A_(0)]`.
The rate of a first order reaction does not depend on REACTANT CONCENTRATIONS, the rate of a second order reaction does depend on reactant concentrations.
The rate of a first order reaction does depend on reactant concentrations, the rate of a second order reaction does not depend on reactant concentrations.

Solution :For a first order reaction
`t_(1//2)=0.6932/k`
For a second order reaction
`t_(1//2)=(2^(n-1)-1)/((n-1)k[A_(0)]^(n-1)),n=2`
`t_(1//2)=(2^(2-1)-1)/((2-1)k[A_(0)]^(2-1)) RARR t_(1//2)=1/(k[A_(0)])`
Discussion