1.

The correct equation for the degree of association 'alpha' of an associating solute, 'n' molecules of which undergoes association in solution, is

Answer»

`alpha = (n(i-1))/(1-n)`
`alpha =(i(n-1))/(1 + n)`
`alpha = (i(1+n))/(1-n)`
`alpha = (i(n+1))/(n-1)`

Solution :CONSIDER following association reaction,
`nA HARR (A)_n`
`{:("Initial mole","1 mole","0"),("Associated change",-alpha"mole",+alpha//n"mole"),("Equilibrium mole",(1-alpha)"mole",alpha//n"mole"):}`
Total NUMBER of moles after association of 1 mole of A
`=(1 - alpha) + (alpha //n)`mole
Total no. of moles `=1 - alpha + alpha/n`
van.t Hoff factor (i)
`=("Number of moles after association")/("Normal number of mole taken")`
`=(1-alpha + alpha/n)/1`


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