1.

The correct equation for the degree of association 'alpha' of an associating solute, 'n' molecules of which undergo association in solution is

Answer»

`alpha=(N(i-1))/(1-n)`
`alpha=(i(n-1))/(1+n)`
`alpha=(i(n+1))/(1-n)`
`alpha=(i(n+1))/(n-1)`

SOLUTION :`underset("1 MOLE")(NA)hArrA_(n)`
`1-alpha""(alpha)/(n),"Total"=1-alpha+(alpha)/(n)`
`therefore i=1-alpha+(alpha)/(n) or 1-i=alpha-(alpha)/(n)=alpha(1-(1)/(n))`
`=alpha((n-1)/(n))`
`or alpha=(n)/((n-1))(i-i)=(n(i-1))/((1-n))`


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