1.

The correct electronic configuration for Ni^(2=) (Z=28) is

Answer»

`[Ar]4S^(2)3d^(6)`
`[Ar]4s^(2) 3d^(8)`
`[Ar]3d^(8)`
`[Ar]4s^(2)3d^(10)`

Solution :Ni`:[Ar]3d^(8)4s^(2),Ni^(2+),[Ar]3d^(8)`


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