Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

Cis-2butene and transjj-2-buteneare:

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GEOMETRICAL ISOMERS
diasteroeomers
enantiomers
position isomers.

Answer :A::C::D
2.

Cis-2-butene and trans-2-butene can be distinguished on the basis of

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their optical properties <BR>their reduction products
the products they give on ozonolysis
the products they give on ADDITION of bromine.

Solution :Options (a), (b) and (c) are wrong since cis-2- butene and trans-2-butene are not OPTICALLY active, give same product on hydrogenation, ie., n-butane and same product on ozonolysis, ie.,` CH_(3) `CHO.
But addition of `Br_(2)` to these two isomers gives DIFFERENT products. Whereas cis-2-butene gives d-mixture of 2,3-dibromobutane, trans-2-butene gives meso-2,3 dibromobutane.
3.

Cis-2-butene and trans-2-butene are:

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configurational ISOMERS
Structural isomers
CONFORMATIONAL isomers.
optical isomers.

ANSWER :A
4.

Cis-1,4-polyisoprene ' is

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Thermoplastic
Thermosetting PLASTIC
Elastic (rubber)
RESIN

Solution :Natural rubber is the only ADDITION polymer of NATURE and is known as Cis-1,4-polyisoprene.
5.

Cis-1,4- polysoprene is called

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Buna-N
NEOPRENE
Buna-S
NATURAL rubber.

Answer :D
6.

Cinnamic acid towards electrophilic aromatic substitution

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metal directing
o-p directing
Ipso substitution TAKES place
Equally give ORTHO, PARA and META SUBSTITUTED product

Answer :B
7.

Cinnamic acid on decarboxylation gives

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Benzaldehyde
Toluene
Styrene
Benzene

Answer :C
8.

Cinnamic acid is formed when C_(6)H_(5)-CHO condenses with (CH_(3)CO)_(2)O is presence of

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Conc. `H_(2)SO_(4)`
Sodium acetate
Sodium metal
Anhydrous `ZnCI_(2)`

Solution :`C_(6)H_(5)CHO+(CH_(3)CO)_(2)O overset(CH_(3)CO_(2)Na)rarr C_(6)H_(5)CH=CHCO_(2)H`
9.

Cinnamic acid is formed when C_6H_5CHO condenses with (CH_3CO_2)_2Oin the presence of .................

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CONC. `H_2SO_4`
`CH_3COONa`
NA metal
Anhydrous `ZnCl_2`

SOLUTION :`CH_3COONa`
10.

Cinnamic acid is ortho-para directing. Explain

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Solution :It is easier to explain this ORIENTATION by CONSIDERATION of the stabilities of the various carbonium ions. For p-attack For m-attack
` (##FIITJEE_CHE_MB_08_C03_SLV_005_S01.png" width="80%">
Only in case of o and p-attack spreading of positive charge to the side chain is possible , thereby STABILIZING these more than m-attack.
11.

Cinnamaldehyde on reduction with NaBH_4 gives

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`C_(6)H_(5)CH_(2)CH_(2)CH_(2)OH`
`C_(6)H_(5)CH=CH-CH_(3)`
`C_(6)H_(5)CH=CH-CHO`
`C_(6)H_(5)CH=CHCH_(2)OH`

Solution :`NaBH_(4)` does not reduce C=C double BOND.
12.

Cinnabar is an ore of :

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LEAD
ZINC
SILVER
MERCURY

ANSWER :D
13.

Cinnabar is :

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`Cu_2S`
`Ag_2S`
`ZNS`
`HGS`

ANSWER :D
14.

Cinnabar (HgS) and galena (PbS) on roasting often give their respective metals but zinc blende (ZnS) does not . Explain .

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Solution :On roasting all these sulphide ores are partly converted into their RESPECTIVE OXIDES . Since the oxides of mercury and lead are unstable while that of zinc is stable , therefore , oxides of mercury and lead bring about the reduction of their respective sulphides to the CORRESPONDING metals but zinc oxide does not reduce ZnS to Zn metal
`HgS + underset("(unstable)")(2 HgO) overset(Delta)(to) 3 HG+ SO_(2) ,`
`PbS + underset("(unstable)")(2PbO) overset(Delta)(to) 3 Pb + SO_(2)`
`ZnS + underset("(stable)") (2ZnO) to 3 Zn + SO_(2)`
15.

CI^(Θ)is condirned by (a) ____.

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ANSWER :a.Chrumyl CHLORIDE TEST
16.

Cimetidine (Tegamet) and Ranitidine (Zantac) drugs are

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Analgesics
Tramquilizers
Antacids
Antidepressants

Answer :C
17.

Cigarette or gas lighter is made up of

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Misch METAL
Alkali metal
Noble metal
None

Solution :Misch metal MAINLY CONTAINS Lanthenoids and IRON.
18.

CIF_3 exists but FCl_3 does not exist. Why?

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Solution :Chlorine can accommodate three small sized F atoms around it but small sized Fatom cannot accommodate three big sized Cl atoms around it. MOREOVER, FLUORINE cannot EXHIBIT valency more than one due to the absence of vacantd-orbitals
19.

CIF_(3) and BrF_(3) are used in the enrichment of _______.

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`""^(237)NP`
`""^(235)U`
`""^(152)Eu`
`""^(210)Po`

Answer :B
20.

Consider the standard potential of the following cells, (i)Mg^(2+) +2e rarr Mg,E^@=-2.37V (ii)Zn^(2+) + 2erarrZn,E^@ =-0.76V (iii)Ni^(2+) +2e rarrNi,E^@=-0.25V(iv)Fe^(3+) + 3e rarrFe, E_0=-0.04 Vfind the strongest reducing agent :

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`MG^(2+)`
Mg
`FE^(3+)`
Fe

Answer :B
21.

Chromyl ion is :

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`CrO_(2)^(+)`
`CrO_(2)^(2+)`
`CRO^(2+)`
`CrO_(2)^(3+)`

ANSWER :B
22.

Chromyl chloride vapours are dissolved in water and acetic acid and lead acetate solution is added, then

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The solution will remain colourless
the solution will become dark GREEN
A yellow solution will be OBTAINED
A yellow ppt. will be obtained

Solution :`CrO_(2)Cl_(2)+2H_(2)O to H_(2)CrO_(4)+2HCl`
`H_(2)CrO_(4)+(CH_(3)CO O)_(2)Pb`
`to underset("Yellow ppt.")(PbCrO_(4) darr) +2CH_(3)CO OH`
23.

Chromyl chloride vapours are dissolved in water and acetic acid and barium acetate solution is added then:

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the solution will remain colourless
the solution will become dark green
a yellow solution will be obtained
a yellow precipitate will be obtained

Solution :`CrO_(2)Cl_(2)+2H_(2)OtoH_(2)CrO_(4)+2HCl`
`H_(2)CrO_(4) +(CH_(3)COO)_(2)BA to BaCrO_(4)DARR ("yellow")+2CH_(3)COOH`
24.

Chromyl chloride testis preformedfor thedetectionof CI^(Theta) A saltsolutioncontaining CI^(Theta) ionis heated with K_(2)Cr_(2)O_(7) and cone H_(2)SO_(4) orange redvapour of Cr_(2)CI_(2)are obatined .Onpassingthese supourthrough a soln of NaOH a yellowppt ,dueto Na_(2)CrO_(2) is obtained if these vapour are dissolve in H_(2)O and acetin acid and leadacetate solutionis added then

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The SOLUTION will remaincolour less
The solution will BECOME dark green
The solution will become BROWN
A yellow PPT will be obtained

Answer :d
25.

Chromyl chloride test is performed for the confirmation of the presence of the following in a mixture

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Sulphate
Chromium
CHLORIDE
Chromium and chloride

Solution :It is a TEST for chloride ION.
26.

Chromyl chloride test is given by -

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`CH_(3)CL`
`AgCl`
`Hg_(2)Cl_(2)`
`NH_(4)Cl`

ANSWER :D
27.

Chromyl chloride test is for

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CHLORIDE salt
nitrate salt
thiosulphate salt
sulphate salt

Answer :A::C::D
28.

Chromyl chloride in CS_(2)(CrO_(2)Cl_(2)//CS_(2)) or chromium trioxide in acetic anhydride [CrO_(3)//(CH_(3)CO)_(2)O] followed by acid hydrolysis.

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SOLUTION :(i) Reactivity increases as the +ve charge on CARBONYL carbon increases. Since alkyl GROUPS have +I-effect, therefore, reactivity increases as the number of alkyl groups on the carbonyl carbon decreases. (ii) Reactivity increases as the number and size of alkyl groups decreases, i.e., STERIC hindrance decreases. due to combined effect of these two factors, the reactivity increases in the order.
`C_(2)H_(5)COCH_(3) lt CH_(3)COCH_(3) lt CH_(3)CHO lt HCHO`.
29.

Chromium trioxide in acidic medium acts as oxidising agent. What is this reagent known as ?

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SOLUTION :JONES REAGENT
30.

Chromosomes are made of ............................

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Only NUCLEIC ACIDS
Only PROTEINS
Proteins and nucleic acid
Proteins and CARBOHYDRATES

SOLUTION :Proteins and nucleic acids
31.

Chromium plating can involve the electrolysis of an electroyte of an acidified mixture of chromic acid and chromium sulphate. If during electrolysis the article being plated increases in mass by 2.6 g and 0.6" dm"^(3) of oxygen are evolved at an inert anode, the oxidation state of chromium ions being discharged must be (assuming Cr = 58 and 1 mole of gas at room temperature and pressure occupies of 24" dm"^(3))

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A) `+2`
B) 0
C) `+1`
D) `-1`

ANSWER :A
32.

Chromium plating can involve the electrolysis of an electrolyte of an acidified mixuture of chromic acid and chromium sulphate . If during electrolysis the article being plated increases in mass by 2.6 g and 0.6 dm3 of oxygen are evolved at an inert anode, the oxidation state of chromium ions being discharged must be:(assuming Cr=52) and I mole of gas at room temperature and pressure occupies a volume of 24 dm^3)

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`-1`
ZERO
`+1`
`+2`

ANSWER :D
33.

Chromium metal crystallizes with a body-centred cubic lattice. The length of the unit cell edge is found to be 287pm. Calculate the atomic radius. What woulds be the density of chromiumin g cm^(-3)?

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SOLUTION :124.27 PM, `7.32 g//cm^3`
34.

Chromium metal crystallizes with a body-centred cubic lattice. The edge length of the unit cell is found to be 287pm. Calculate the atomic radius. What would be the density of chromium in g cm^(-3) ? (atomic mass of Cr = 52.99)

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SOLUTION :For a body - centred cubic lattic , Z= 2
Edge length , a= 287 pm = `287 xx 10^(-10) cm`
ATOMIC mass of CHROMIUM , M = 52.99 g `"mol"^(-1)`
For bcc lattice , R = `(sqrt3)/(4) xx a`
`=(1.732)/(4) xx a`
`=(1.732)/(4)xx 287 ` pm = 124.27 pm
`d= (Z xx M)/(a^3 xx N_A)`
`=(2xx 52.99 g "mol"^(-1))/((287 xx 10^(-10) cm)^3 xx 6.02 xx 10^(23) "mol"^(-1))`
=7.44 g `"cm"^(-3)`
35.

Chromium metal crystallizes in a body centred cubic lattice. The length of the unit cell edge is found to be 287 pm. Calculate the atomic radius of chromium.

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SOLUTION :a=287 PM
For a body-centred cubic UNIT cell, RADIUS (r) = `(a xx sqrt3)/(4)= (287 xx sqrt3)/(4) =(287 xx 1.73)/(4)` = 124.13 pm
36.

Chromium metal can be plated out from an acidic solution containing CrO_3according to the following equationCrO3_(aq) + 6H^(+)(aq) + 6etoCr(s) + 3H_2OCalculate (i) how many grams of chromium will be plated out by 24000 coulombs, and (ii) how long will it take to plate out 1.5 g of chromium by using 12.5 amp current?

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Solution : Eq. of CR DEPOSITED = FARADAY of ELECTRICITY passed
` = 24000/96500`
and eq. wt. of chromium ` = 52/6`
2.1554g, 1336 g
37.

Chromium is used in making:

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Bronze
Brass
Stainless steel
Electrodes

Answer :C
38.

Chromium is typical hard metal while mercury is a liquid. Explain why ?

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SOLUTION :Cr has five unpaired d-ELECTRONS. Hence METALLIC bonds are STRONG. In Hg, there is absence of unpaired electrons and SIZE is larger.
39.

Chromium is obtained by reducing purified chromite ore with....

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red hot COKE 
carbon MONOXIDE 
AL powder 
`H_(2(g))`

Answer :C
40.

Chromium is a typical hard metal while mercury is a liquid. Explain why ?

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SOLUTION :Cr has five unpaired d electrons in the d-subshell `( 3d^(5) 4S^(1))` . HENCE, metallic BONDS are very strong. In Hg, all the d-orbitals are fully filled `( 3d^(10) 4s^(2))`. Hence, the metallic bonding is very weak.
41.

Chromium has most stable oxidation state of:

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`+5`
`+3`
`+2`
`+4`

ANSWER :B
42.

Chromium dissolves in dil. H_2SO_4 to form Cr(H_2O)_6^(2+). The colour of the ion is:

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Blue
Green
Yellow
Orange

Answer :A
43.

Chromium crystallizes in a body centred cubic lattice, whose density is 7.20 g//cm^3. The length of the edge of unit cell is 288.4 pm. Calculate Avogadro's number. (Atomic mass of chromium=52)

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SOLUTION :d= 7.20 g `cm^(-3)`, a=288.4 PM, Z2 for bcc unit cell, M = 52 g `MOL^(-1)`, d = `(Z XX M)/(N_A xx a^3)` or `N_A=(Z xx M)/(d xx a^3)=(2xx52)/(7.20 xx (288.4)^3 xx 10^(-30)) =6.02 xx 10^(23) mol^(-1)`
44.

Chromium compound used in training of leather is:

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`Cr_2O_3`
`CrO_2Cl_2`
`CrCl_3`
`K_2SO_4cdotCr(SO_4)_3cdot24H_2O`

ANSWER :D
45.

Chromium carbonyl is:

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`Cr(CO)_4`
`Cr(CO)_5`
`Cr(CO)_6`
None

Answer :C
46.

Chromite ore is fused with Na_(2)CO_(3) in free excess of air. The yellow solution obtained is filtered and acidified with H_(2)SO_(4). The colour of the resulting solution is

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COLOURLESS.
pink.
orange.
green.

Answer :C
47.

Chromite ore has the formula "…....................".

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ANSWER :`FEO. Cr_(2)O_(3)`
48.

Chromite is ...........

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SOLUTION :`FeCr_2O_4`
49.

The chemical formula of chromite mineral :

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SOLUTION :`FeCr_3O_4`
50.

Chromite has the formula

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SOLUTION :`FeCr_3O_4`