1.

Cinnamaldehyde on reduction with NaBH_4 gives

Answer»

`C_(6)H_(5)CH_(2)CH_(2)CH_(2)OH`
`C_(6)H_(5)CH=CH-CH_(3)`
`C_(6)H_(5)CH=CH-CHO`
`C_(6)H_(5)CH=CHCH_(2)OH`

Solution :`NaBH_(4)` does not reduce C=C double BOND.


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