Explore topic-wise InterviewSolutions in Current Affairs.

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1.

Amongst the compounds given, the one that would form a brilliant colored dye on treatment with NaNO_2 in dil. HCI followed by addition to an alkaline solution of beta-naphthol is

Answer»




SOLUTION :Only primary aromatic amines tmdergo DIAZOTISATION followed by coupling.
Discussion
2.

Amongst the compounds given, the one that would form a brilliant colored dye on treatment with NaNO_(2) in dil. HCl followed by addition to an alkaline solution of beta-naphthol is

Answer»




ANSWER :C
Discussion
3.

Amongst T_(2)F_(6)^(2-), CoF_(6)^(2-), Cu_(2)Cl_(2) and NiCl_(4)^(2-) [Atomic number of Ti, Co, Ni and Cu are 22,27,28 and 29 respectively), the colourless species are

Answer»

`CoF_(6)^(2-)` and `NiCl_(4)^(2-)`
`TiF_(6)^(2-)` and `CoF_(6)^(3-)`
`Cu_(2)Cl_(2)`and `NiCl_(4)^(2-)`
`TiF_(6)^(2-)` and `Cu_(2)Cl_(2)`

ANSWER :D
Discussion
4.

Amongst peracids of halogens, the strongest oxidising agent is............ .

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SOLUTION :`HBrO_(4)`
Discussion
5.

Amongst the C-X bond ( where X = Cl, Br, I), the correct bond energy order is

Answer»

`C - CL GT C - BR gt C - I`
`C - I gt C - Cl gt C - Br`
`C - Br gt C - Cl gt C - I`
`C - I gt C - Br gt C - Cl`.

ANSWER :A
Discussion
6.

Amongst sodium halides, NaF has the highest m.p. because it has

Answer»

highest OXIDIZING POWER.... .
 lower polarity
minimum IONIC character
maximum ionic character

Answer :D
Discussion
7.

Amongst NO_(3)^(-), AsO_(3)^(3-), CO_(3)^(2-),ClO_(3)^(-),SO_(3)^(2-) and BO_(3)^(2-), the non-planar species are :

Answer»

`CO_(3)^(2-), SO_(3)^(2-) and BO_(3)^(2-)`
`AsO_(3)^(3-), ClO_(3)^(-) and SO_(3)^(2-)`
`NO_(3)^(-), CO_(3)^(2-) and BO_(3)^(3-)`
`SO_(3)^(2-), NO_(3)^(-) and BO_(3)^(3-)`

Answer :B
Discussion
8.

Amongst NO_3^(-), AsO_3^(3-), CO_3^(2-), ClO_3^(-), SO_3^(2-) and BO_3^(3-) the non-planar species are

Answer»

`CO_3^(2-), SO_3^(2-) and BO_3^(3-)`
`AsO_3^(3-) , CIO_3^(-) and SO_3^(2-)`
`NO_3^(-) , CO_3^(2-) and BO_3^(3-)`
`SO_3^(2-), NO_3^(-) and BO_3^(3-)`

SOLUTION :
Discussion
9.

Amongst Ni(CO)_(4), [Ni(CN)_(4)]^(2-), NiCl_(4)^(2-) :

Answer»

`Ni(CO)_(4)` and `NiCl_(4)^(2-)` are diamagnetic and `[Ni(CN)_(4)]^(2-)` is PARAMAGNETIC.
`NiCl_(4)^(2-)` and `[Ni(CN)_(4)]^(2-)` are diamagnetic and `Ni(CO)_(4)` is paramagnetic.
`Ni(CO)_(4)` and `[Ni(CN)_(4)]^(2-)` are diamagnetic and `NiCl_(4)^(2-)` is paramagnetic.
`Ni(CO)_(4)` is diamagnetic and, `NiCl_(4)^(2-)` and `[Ni(CN)_(4)]^(2-)` are paramagnetic.

Answer :C
Discussion
10.

Amongst Ni(CO)_(4), [Ni(CN)_(4)]^(2-) and [NiCl_(4)]^(2-) :

Answer»

`Ni(CO)_(4) and NiCl_(4)^(2-)` are diamagnetic and `[Ni(CN)_(4)]^(2-)`is PARAMAGNETIC.
`NiCl_(4)^(2-) and [Ni(CN)_(4)]^(2-)` are diamagneticand `Ni(CO)_(4)` is paramagnetic.
`Ni(CO)_(4) and [Ni(CN)_(4)]^(2-)` are diamagnetic and `NiCl_(4)^(2-)` is paramagnetic.
`Ni(CO)_(4)` is diamagnetic and `NiCl_(4)^(2-)` and `[Ni(CN)_(4)]^(2-)` are diamagnetic.

Answer :C
Discussion
11.

Amongst Ni(CO)_(4), [Ni(CN)_(4)]^(2-) and [NiCl_(4)]^(2-)

Answer»

`NI(CO)_(4) and [Ni(CN)_(4)]^(2-)` are diamagnetic and `[Ni(CN)_(4)]^(2-)` is PARAMAGNETIC
`[NiCl_(4)]^(2-) and [Ni(CN)_(4)]^(2-)` are diamagnetic and `Ni(CO)_(4)` is paramagnetic
`Ni(CO)_(4) and [Ni(CN)_(4)]^(2-)` are diamagnetic and `[NiCl_(4)]^(2-)` is paramagnetic
`Ni(CO)_(4)` is diamagnetic and `[NiCl_(4)]^(2-)` and `[Ni(CN)_(4)]^(2-)` are paramagnetic

Solution :`[Ni(CO)_(4)]` and `[Ni(CN)_(4)]^(2-)` do not contain any UNPAIRED electron while `[NiCl_(4)]^(2-)` contains TWO unpaired ELECTRONS.
Discussion
12.

Amongst [NiCl_(4)]^(2-), [Ni(H_(2)O)_(6)]^(2+), [Ni("PP"h_(3))_(2)Cl_(2)], [Ni(CO)_(4)] and [Ni(CNO_(4))]^(2-) the paramagnetic species are

Answer»

`[NiCl_(4)]^(2-),[NI(H_(2)O)_(6)]^(2+), [Ni("PP"h_(3))_(2)Cl_(2)]`
`[Ni(CO)_(4)], [Ni("PP"h_(3))_(2)Cl_(2)], [NiCl_(4)]^(2-)`
`[Ni(CN)_(4)]^(2-), [Ni(H_(2)O_(6)]^(2+),[NiCl_(4)]^(2-)`
`[Ni"PP"h_(3))_(2)Cl_(2)], [Ni(CO)_(4)],[Ni(CN)_(4)]^(2-)`

Solution :`Ni^(2+)=3d^(8)4s^(0)`
(i) `[NiCl_(4)]^(2-)toCl^(-)` is weak ligand (spectrochemical sereis), so no pairing POSSIBLE.
CFSE < pariring energy.
(ii) `[Ni(H_(2)O)_(6)]^(2+)toH_(2)O` is weak field ligand. So,no pairing possible.
CFSE < Pairing energy.
(iii) `[Ni("PP"h_(3))_(2)Cl_(2)]to` Although `"PP"h_(3)` had d- acceptance but presence of Cl makes complex tetrahedral.
Discussion
13.

Amongst LiCl, RbCl, BeCl_2 and MgCl_2, the compounds whith the greatrest and the least ionic character respecitely are :

Answer»

`LiCl,MgCl_(2)`
`RBCL,BeCl_(2)`
`RbCl,MgCl_(2)`
`MgCl_(2),BeCl_(2)`

Solution :According to the Fajan's RULE LARGEST CATION and smallest anion.
Discussion
14.

Amongst I=[Co(Ox)_(3)]^(3-),II=[CoF_(6)]^(3-),III=[Co(NH_(3))_(6)]^(+3)

Answer»

I, II are para, and III is dia
I, III are para, and II is dia
I, III are dia, and II in para
II, III are para, and I is dia

Solution :I. `[Co("OX")_(3)]^(3-)` : ox acts as SFL all paired electrons diamagnetic.
II) `[CoF_(7)]^(3-):` F acts as WFC 4, un in paired electron present, paramagnetic.
III. `[Co(NH_(3))_(6)]^(3+):NH_(3)` acts as SFL, all paired electron diamagnetic
Discussion
15.

Amongst LiCl, RbCl, BeCl_(2) and MgCl_(2), the compounds with the greatest and the least ionic character respectively are :

Answer»

`LiCl, RBCL`
RbCl and `BeCl_(2)`
`RbCl, MgCl_(2)`
`MgCl_(2)`and`BeCl_(2)`

ANSWER :B
Discussion
16.

Amongst hexahalides of sulphur, SF_6 is exceptionally stable due to

Answer»

SEE- SAW geometry
High POLARIZATION power
Least steric hindrance
DIMERIC in nature

Answer :C
Discussion
17.

Amongst H_(2)OH_(2)S,H_(2) Seand H_(2)Tethe one with thehighest boiling point is

Answer»

`H_(2)O` because of HYDROGEN bonding
`H_(2)Te` becauseof hydrogen bonding
`H_(2)S` becauseof hydrogen bonding
`H_(2)SE` because of lower molecular WEIGHT

SOLUTION :`H_(2)O` has higher bollingpoint because of hydrogen bonding
Discussion
18.

Amongst H_(2)O, H_(2)S, H_(2) Se and H_(2) Te, the one with the highest boiling point is

Answer»

`H_2O` because of HYDROGEN BONDING
`H_2Te` because of HIGHER molecular weight
`H_2S` because of hydrogen bonding
`H_2Se` because of LOWER molecular weight

Answer :A
Discussion
19.

Amongst H_(2)O,H_(2)S, H_(2)Se and H_(2)Te the one with the highest boiling point is

Answer»

`H_(2)O` because of hydrogen BONDING
`H_(2)`Te because of HIGHER MOLECULAR weight
`H_(2)S` because of hydrogen bonding
`H_(2)Se` because of lower moleculer weight

Solution :`H_(2)O` containing hydrogen bond.
Discussion
20.

Amongst H_(2)O, H_(2)Se and H_(2)Te, the one with highest boiling point is

Answer»

`H_(2)O` because of hydrogen BONDING
`H_(2)Te` because of HIGHER MOLECULAR weight
`H_(2)S` because of hydrogen bonding
`H_(2)Se` because of LOWER molecular weight

ANSWER :A
Discussion
21.

Amongst given polymers, how many of them are addition polymer. (i) Melmac (ii) ABS rubber (iii) Plexiglass (iv) Orlon(v) Teflon(vi) Kevlar (vii) Dextron (viii) Polyurethanes

Answer»


SOLUTION :ABS Rubber, PLEXIGLASS, Orlon, Teflon are addition POLYMER.
Discussion
22.

Amongst fluorides of alkali metals, the lowest solubility of LiF in water is dur to

Answer»

IONIC NATURE of LITHIUM fluoride
High lattice enthalpy
High hydration enthalpy for lithium ion
Low ionisation enthalpy of lithium atom

Answer :B
Discussion
23.

Amongst CuF_(2),CuCl_(2) and CuBr_(2)

Answer»

only `CuF_(2)` is IONIC
both `CuCl_(2)` and `CuBr_(2)` are covalent
`CuF_(2)` and `CuCl_(2)` are ionic but `CuBr_(2)` is covalent
`CuF_(2), CuCl_(2)` as WELL as `CuBr_(2)` are ionic

Solution :Only `CuF_(2)` ionic according to Fasan's RULES
Discussion
24.

Amongst CuF_(2), CuCl_(2) and CuBr_(2)

Answer»

only `CuF_(2)` is IONIC
both `CuCl_(2)` and `CuBr_(2)` are covalent
`CuF_(2)` and `CuCl_(2)` are ionic but `CuBr_(2)` is covalent
both (A) and (B)

Solution :N//A
Discussion
25.

Amongst Cd, Hg, Ag, Au The I.P. Vlaue order will be

Answer»

`Ag LT Cd lt AU lt Hg `
`Ag lt Au lt Cd lt Hg `
`Ag lt Hg lt Au lt Cd `
`Ag = CL lt Hg lt Au`

Answer :A
Discussion
26.

Amongst all noble gases only xenon is known to form compounds with oxygen and flruorine. Give reasons.

Answer»

Solution :Amongst all the noble gases (except Rn), Xe has the LARGEST size and lowest ionization ENTHALPY. Further, since `F_(2) and O_(2)` are the most ELECTRONEGATIVE elements known, THEREFORE, amongst all the noble gases only XENON forms compounds with `O_(2) and F_(2)`.
Discussion
27.

Amongst CuF_2 ,CuCl_2 and CuBr_2

Answer»

only `CuF_2` is IONIC
Both `CuCl_2` and `CuBr_2` are COVALENT
`CuF_2` and `CuCl_2` areionic but`CuBr_2 ` is covalent
`CuF_2 , CuCl_2` as WELLAS `CuBr_2` are ionic .

ANSWER :A::B
Discussion
28.

Amongs the following identify the criterion for a process to be at equilibrium-

Answer»

`DELTA G lt 0`
`DeltaG gt 0`
`DeltaS_("total")=0`
`DeltaS lt 0`

ANSWER :C
Discussion
29.

Amongest the following , the total number of elastromers is : polythene , polypropylene, natural rubber , vulcanized rubber, nylon 6 , Buna -S, Buna - N , neoprene , polyvinyl chloride , polystyrene.

Answer»


Solution :Five . NATURAL RUBBER, vulcanized rubber , BUNA -N , Buna -S and NEOPRENE are elastomers.
Discussion
30.

Amongest the following . The total number of thermoplastics is : Polyester , bakelite , polythene, PVC , teflon , PAN , PMMA , nylon 6 , melamine formaldehyde.

Answer»


SOLUTION :Seven . Bakelite and melamine - FORMALDEHYDE are not THERMOPLASTICS but the remaining seven are.
Discussion
31.

Amongest the following , total number of essentail amino acids are , : valine , glycine, phenylalanine , lysine , leucine, isoleucine , methionine , alanine , threonine.

Answer»


Solution :EXCEPT GLYCINE and alanine , the remaining 7 are essential amino ACIDS.
Discussion
32.

Amongest the following, the total number of compounds whose aqueous solution turns red litmus paper into blue is- NaCl,Na_(2)SO_(4),CH_(3)COONa,(NH_(4))_(2)C_(2)O_(4),H_(2)SO_(4),Na_(3)PO_(4),K_(2)CO_(3),Zn(NO_(3))_(2)

Answer»

Solution :Aqueous solution which are BASIC in NATURE-
`CH_(3)COOna, Na_(3)PO_(4),NaOH,K_(2)CO_(3)`
Discussion
33.

Amongest the following, the total number of compounds whose aqueous solution turns red litmus paper blue. KCN, K_2 SO_4,(NH_4)_2 C_2 O_4, NaCl Zn(NO_3)_2, FeCl_3, K_2 CO_3, NH_4 NO_3, LiCN.

Answer»
Discussion
34.

Amongest the following the maximum number of alkenes which shows geometrical isomers are 1-pentene, 2-butene, 2-pentene, 1-butene ,propne, 2,3-dimethyl-2-butene, 3-hexene, 1-hexene

Answer»


SOLUTION :2-butene, 2-pentene, 3-hexene.
Discussion
35.

Amongest the following the most basic compounds is-

Answer»

p-nitro aniline
acetanilide
Aniline
Benzylamine

Answer :D
Discussion
36.

Amongest the following ions which one has the highest magnetic value ? [Zn(H_(2)O)_(6)]^(2+),[Fe(H_(2)O)_(6)]^(2+),[Cr(H_(2)O)_(6)]^(3+)

Answer»

Solution :The oxidation states and the number of unpaired electrons in the given octahedral complexes are shown below :
Electronic configuration of `FE^(2+)=3d^(6)`, No. of unpaired electrons = 4 (`H_(2)O` is weak ligand and HENCE OUTER orbital complex is formed, `sp^(3)d^(2)` HYBRIDISATION occurs )
Discussion
37.

Amongest the following, HBr reacts fastest with

Answer»

Propane-1-ol
Propane-2-ol
2-METHYL propane-1-ol
2-methyl propane-2-ol

Solution :TERTIARY ALCOHOLS react fastest with hydrogen halides 2 methyl propan-2-ol is a tertiary alcohol.
Discussion
38.

Among the following hydroxides, one which has the lowest value of K_sp is:

Answer»

`Mg(OH)_2`
`CA(OH)_2`
`Ba(OH)_2`
`Be(OH)_2`

Answer :D
Discussion
39.

Amongest the following compounds, the one which would not form a white precipitate with ammonical silver nitrate solution is

Answer»

`HC -= CH`
`H_(3)C - C -= C - CH_(3)`
`H_(3)C - C = CH`
`CH_(3)CH_(2)CH_(2)C -= CH`

Solution :The STRUCTURE of but-2-yne shows that there is no acidic hydrogen ATTACHED to the sp hybri carbon ATOM. HENCE no REACTION with ammonical `AgNO_(3)` is expected.
Discussion
40.

Amongest Be, B, Mg and Al the second ionization potential is maximum for

Answer»

B
Be
Mg
Al

Solution :`B(5) to 1s^(2) 2s^(2) 2p^(1)`
In second ionization POTENTIAL electron has to be REMOVED from 2s. It is quite high ENERGETIC.
Discussion
41.

Amongest the bivalent ions of 3d-elements, Mn(II) shows maximum paramagnetic character, Substantiate.

Answer»


ANSWER :HINT : `mu=5.9BM`
Discussion
42.

Among XeO_(2),XeO_(2)F_(2)" and "XeF_(6), the molecules having same number of lone pairs on Xe are

Answer»

`XeF_(6)" and "XeO_(2)F_(2)`
`XeO_(3)" and "XeO_(2)F_(2)`
`XeO_(3)" and "XeF_(6)`
`XeO_(3), XeO_(2)F_(2)" and "XeF_(6)`

Solution :N//A
Discussion
43.

Among V(Z=23), Cr(Z=24), Mn(Z=25) which will have the highest magnetic moment?

Answer»

V
Cr
Mn
Fe

Answer :B
Discussion
44.

Among Valine, Leucine, Isoleucine, Lysine and phenyl alanine, odd member is

Answer»

LEUCINE since OTHERS are acidic . 
Valine since others are basic 
Isoleucine since others are OPTICALLY ACTIVE 
Lycine since others are neutral

Answer :D
Discussion
45.

Among various alkyl halide which one is the most reaction towards S_(N)1 reaction.

Answer»


SOLUTION :N//A
Discussion
46.

Among TiF_(6)^(2-), CoF_(6)^(3-), Cu_(2)Cl_(2)" and "NiCl_(4)^(2-) the colourless species are :

Answer»

`CoF_(6)^(3-)" and "NiCl_(4)^(2-)`
`TiF_(6)^(2-)" and "CoF_(6)^(3-)`
`NiCl_(4)^(2-)" and "Cu_(2)Cl_(2)`
`TiF_(6)^(2-)" and "Cu_(2)Cl_(2)`

Solution :`OVERSET(+4)TiF_(6)^(2-), d^(0)` CONFIG. , `overset(+1)Cu_(2)Cl_(2),d^(10)` config.
Discussion
47.

Among trihalide of nitrogen,which one is least basic?NF_3,NCl_3,NBr_3,NI_3.

Answer»

`NF_3`
`NCl_3`
`NBr_3`
`NI_3`

ANSWER :A
Discussion
48.

Among TiF_(6)^(2-) , CoF_(6)^(3-), Cu_(2)Cl_(2) and NiCl_(4)^(2-) (At, No Ti=22, Co =27, Cu =29, Ni=28) The colourless species are

Answer»

`CoF_(6)^(3-)` and `NiCl_(4)^(2-)`
`TiF_(6)^(2-)` and `CoF_(6)^(2-)`
`Cu_(2)Cl_(2)` and `NiCl_(4)^(2-)`
`TiF_(6)^(2-)` and `Cu_(2)Cl_(2)`

Solution :Oxidation state of
`"Ti in "TiF_(6)^(2-)=+4" i.e., "Ti^(4+)rarr3d^(0)`
`"Co in "CoF_(6)^(3-)=+3" i.e., "Co^(3+) RARR 3D^(6)`
`"Ni in "NiCl_(4)^(2-)=+2" i.e., "Ni^(2+)rarr3d^(8)`
`"CU in "Cu_(2)Cl_(2)=+1" i.e., "Cu^(+)rarr3d^(10)`
Colour of salts is a property of party filled d - orbitals. Since `TiF_(6)^(2-)` has completely empty d - subshell and `Cu_(2)Cl_(2)` involves completely filled d - subshell, hence these are COLOURLESS salts.
Discussion
49.

Among thr following elements, the most electronegativity is :

Answer»

Oxygen
Chlorine
Nitrogen
Fluorine

Answer :D
Discussion
50.

Among these cations, the correct order of the indicated C-N bond strength is

Answer»

`III GT I gt II`
`II gt III gt I`
`I gt II gt III`
`II gt I gt III`

Solution :EDG `uarr` strength `darr`
Discussion