1.

Amongst I=[Co(Ox)_(3)]^(3-),II=[CoF_(6)]^(3-),III=[Co(NH_(3))_(6)]^(+3)

Answer»

I, II are para, and III is dia
I, III are para, and II is dia
I, III are dia, and II in para
II, III are para, and I is dia

Solution :I. `[Co("OX")_(3)]^(3-)` : ox acts as SFL all paired electrons diamagnetic.
II) `[CoF_(7)]^(3-):` F acts as WFC 4, un in paired electron present, paramagnetic.
III. `[Co(NH_(3))_(6)]^(3+):NH_(3)` acts as SFL, all paired electron diamagnetic


Discussion

No Comment Found

Related InterviewSolutions