1.

Amongst Ni(CO)_(4), [Ni(CN)_(4)]^(2-) and [NiCl_(4)]^(2-)

Answer»

`NI(CO)_(4) and [Ni(CN)_(4)]^(2-)` are diamagnetic and `[Ni(CN)_(4)]^(2-)` is PARAMAGNETIC
`[NiCl_(4)]^(2-) and [Ni(CN)_(4)]^(2-)` are diamagnetic and `Ni(CO)_(4)` is paramagnetic
`Ni(CO)_(4) and [Ni(CN)_(4)]^(2-)` are diamagnetic and `[NiCl_(4)]^(2-)` is paramagnetic
`Ni(CO)_(4)` is diamagnetic and `[NiCl_(4)]^(2-)` and `[Ni(CN)_(4)]^(2-)` are paramagnetic

Solution :`[Ni(CO)_(4)]` and `[Ni(CN)_(4)]^(2-)` do not contain any UNPAIRED electron while `[NiCl_(4)]^(2-)` contains TWO unpaired ELECTRONS.


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