Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

Amongst the following, the maximum number of antacids is : valium, meprobamate, ranitidine, phenelzine, cimetidine, omeprazole, penicillin, chloramphenicol, chlorpheniramine.

Answer»


SOLUTION :THREE. RANITIDINE , CIMETIDINE and OMEPRAZOLE
Discussion
2.

Amongst thefollowing the lowest digree of paramagnetism per mole of the compound at 298 K will be shown by :

Answer»

`MnSO_(4) * 4H_(2)O`
`CuSO_(4) &* 5H_(2)O`
`FeSO_(4) * 6H_(2)O`
`NSO_(4) * 6H_(2)O`

Answer :B
Discussion
3.

Amongst the following the lowest degree of paramagnetism per mole of the compound at 298 K will be shown by

Answer»

`MnSO_(4).4H_(2)O`
`CuSO_(4)5H_(2)O`
`FeSO_(4)6H_(2)O`
`NiSO_(4)6H_(2)O`

Answer :B
Discussion
4.

Amongst the following the incorrect order is :-

Answer»

`IE_(1)(Al) lt IE_(1)(Mg)`
`IE_(1)(Na) lt IE_(1) (Mg)`
`IE_(2)(Mg) gt IE_(2)(Na)`
`IE_(3)(Mg) gt IE_(3)(Al)`

SOLUTION :(i) `IE_(1)[UNDERSET(3s^(2))(Mg) gt underset(3s^(2)3p^(1))(Al)]` penetration power
(ii)`IE_(1)[underset(3s^(1))(Na) lt underset(3s^(2))(Mg)] ""Z_("eff")`
(iii) `IE_(2)[underset(3s^(1))(Mg^(+))lt underset("(inert gas configuration)")underset(darr)underset(2p^(6))(Na^(+))]`
(iv) `IE_(3)[ underset(("inert gas CONF"^(r )))underset(darr)underset(+2)(Mg^(2+)) lt underset(3s^(1))(Na^(2+))]`
Discussion
5.

Amongst the following, the correct statement(s) is /are

Answer»

NO has one unpaired electron in the antiboding molecular orbital
`NO^(+)` is more stable than `O_(2)^(+)`
`OF^(+)` is more paramagnetic than `Ne_(2)^(+)`
In a `pi` bond, the electron density is conncentrated along the bond axis.

Solution :`NO(15):KK(SIGMA2S)^(2)(sigma***2s)^(2)(sigma2p_(Z))^(2)(pi2p_(x))^(2)`
`=(pi2p_(y))^(2)(pi***2p_(x))^(1)`
`NO^(+)(14):KK(sigma2s)^(2)(sigma***2s)^(2)(sigma2p_(z))^(2)(pi2p_(x))^(2)=(pi2p_(y))^(2)`
B.O. =3.0
`O_(2)^(+)(15):KK(sigma2s)^(2)(sigma***2s)^(2)(sigma2p_(z))^(2)(pi2p_(x))^(2)=(pi2p_(y))^(2)(pi***2p_(x))^(1)`
B.O. =2.5
`OF^(+)(16):KK(sigma2s)^(2)(sigma***2s)^2)(sigma2p_(z))^(2)(pi2p_(x))^(2)=(pi2p_(y))^(2)(pi***2p_(x))^(1)=(pi***2p_(y))^(1)`
`Ne_(2)^(+)(19):KK(sigma2s)^(2)(sigma***2s)^(2)(sigma2p_(z))^(2)(pi2p_(x))^(2)=(pi2p_(y))^(2)`
`=(pi***2p_(x))^(2)=(pi***2p_(y))^(2)(sigma***2p_(z))^(1)`
In a `pi`- bond, the electron density is concentrated in the region PERPENDICULAR tothe bond axis.
Discussion
6.

Amongstthe following , the compound that can be most readily sulphonated is

Answer»

Benzene
Toluene
NITROBENZENE
CHLOROBENZENE

ANSWER :B
Discussion
7.

Amongst the following the compound that can be most readily sulphonated is

Answer»

BENZENE cannot be iodinated with `l_(2)` directly
nitrobenzene
toluene
chlorobenzene

Answer :C
Discussion
8.

Amongst the following statements, which is incorrect?

Answer»

The ceaseless zig-zag motion of SOL particles is due to the UNBALANCED bombardment of particlesby the molecules of dispersion medium
The intensity of zig-zag motion INCREASES with the increase in the size of the particles.
The zig-zag motion of particles becomes intenseat high temperature.
This motion has a STIRRING effect which does not permit the particles to settle.

Solution : The zig-zag motions are faster with SMALLER size.
Discussion
9.

Amongst the following statements which is/are correct

Answer»

The second ionization potential of boron is GREATER than that of carbon
First ionization potential of boron is greater than that of carbon
The second I.P. of Mg is greater than that of P
First I.P. of Al and GA are almost the same

Solution :REMOVAL of an electron from `B^(+)(1S^(2)2s^(2))`, requires reater energy than from `C^(+)(1s^(2)2s^(2)2p^(1))`
Discussion
10.

Amongst the following solutions, the buffer solution is Or A basic buffer is made by mixing the solution

Answer»

`NH_(4)Cl+NH_(4)OH` SOLUTION
`NH_(4)Cl + NaOH` solution
`NH_(4)OH + HCl` solution
`NaOH + HCl` solution

Solution :`NH_(4)Cl` and `NH_(4)OH` is a buffer solution (weak base and salt of strong ACID).
Discussion
11.

Amongst the following oxoacids of phosphorus, which oxoacids has phosphorus in (+4), (+3) and (+4) oxidation states ?

Answer»

`H_(5)P_(3)O_(10)`
`H_(5)P_(3)O_(8)`
`H_(5)P_(3)O_(9)`
`H_(5)P_(3)O_(7)`

Solution :SUMMATION of oxidation states :`(+4) + (+3) + (+4)` of all three phosphorus atoms `=(+11)`
`3X + 5(+1) + 8(-2)=0`
`therefore 3x = +11`
Discussion
12.

Amongstthefollowing, oxideoresare: calamine, fools's gold,cupritezincite,chalcocite, haematite,bauxine, magnetite,cassiterite

Answer»


SOLUTION : 6(six , CUPRITE, zincite, haematite, bauxite, magnetite, CASSITERITE).
Discussion
13.

Amongst the following, non-narcotic analgesics are: morphine, paracetamol, aspirin, codeine, naproxen, ibuprofen, diclofenac sodium, heroin, luminal.

Answer»


SOLUTION :FIVE. Paracetamol, aspirin, NAPROXEN, ibuprofen , and diclofenac SODIUM
Discussion
14.

Amongst the following, moderately activating group is

Answer»

`-NHR`
`NHCOCH_(3)`
`-NR_(2)`
`-CH_(3)`

Solution :`-NHCOCH_(3)` is more activating than `-CH_(3)` but LESS activating than `-NHR and -NR_(2)` GROUPS.
Discussion
15.

Amongst the following ions which one has the highest paramagnetism ?

Answer»

`[CR(H_(2)O)_(6)]^(3+)`
`[Fe(H_(2)O)_(6)]^(2+)`
`[CU(H_(2)O)_(6)]^(2+)`
`[Zn(H_(2)O)_(6)]^(2+)`

Answer :B
Discussion
16.

Amongst the following ions, which one has the highest magnetic moment value ? (i) [Cr(H_(2)O)_(6)]^(3+) (ii) [Fe(H_(2)O)_(6)]^(2+) (iii) [Zn(H_(2)O)_(6)]^(2+)

Answer»

Solution :The oxidation STATES in the three complex ions are : CR(III), Fe(II) and Zn(II)
Electronic CONFIGURATION of `Cr^(3+) : 3d^(3)`, Number of unpaired electrons = 3 (inner orbital complex) Electronic configuration of `Fe^(2+) : 3d^(6)`, Number of unpaired electrons= 4 (outer orbital/high SPIN complex)
Electronic configuration of `Zn^(2+) : 3d^(10)`, Number of unpaired electrons= 0 (outer orbital complex)
`mu=sqrt(n(n+2))`
Hence, (ii) having greatest value of n has highest magnetic moment.
Discussion
17.

Amongst the following ions, which one has the highest magnetic moment ? (i) [Cr(H_(2)O)_(6)]^(3+) (ii) [Fe(H_(2)O)_(6)]^(2+) (iii) [Zn(H_(2)O)_(6)]^(2+)

Answer»

Solution :The oxidation states are : Cr (III), Fe (II) and Zn (II).
E.C. of `Cr^(3+)=3d^(3)`, unpaired ELECTRONS = 3 (inner ORBITAL complex)
E.C. of `Fe^(2+)=3d^(6)`, unpaired electrons = 4 (outer orbital/high spin complex)
E.C. of `Zn^(2+)=3d^(10)`, unpaired electrons = 0 (outer orbital complex)
`mu=sqrt(n(n+2))`. Hence (ii) has highest magnetic moment.
Discussion
18.

Amongst the following ions, which one has the highest magnetic moment [Cr(H_(2)O)_(6)]^(3+)[Fe(H_(2)O)_(6)]^(2+) (iii) [Zn(H_(2)O)_(6)]^(2+)

Answer»

Solution :The oxidation state are: Cr(lll), Fe (II)and `Zn (II)`
`E.C. of Cr^(3+) = 3d^(3)`, unpaired electrons =3 (inner orbital complex)
`E. C. of Fe^(2+) = 3d^(6)`unpaired electrons = 4 (OUTER orbital:/high SPIN complex)
` E.C. of Zn^(2+) = 3d^(10)`, unpaired electrons = 0 (outer orbital complex)
`MU= sqrt(n(n+2))` Hence (ii) has highest magnetic moment.
Discussion
19.

Amongst the following ions which has the highest paramagnetism?

Answer»

`[Cr(H_(2)O)_(6)]^(3+)`
`[FE(H_(2)O)_(6)]^(+3)`
`[Cu(H_(2)O)_(6)]^(2+)`
`[ZN(H_(2)O)_(6)]^(2+)`

Solution :`[Cr(H_(2)O)_(6)]^(3+)-3` unpaired electrons.
`[Fe(H_(2)O)_(6)]^(2+)-4` unparied electrons.
`[Cu(H_(2)O)_(6)]^(2+)-1` unpaired electron.
`[Zn(H_(2)O)_(4)]^(2+)-` no unpaired electron.
Discussion
20.

Amongst the following identify the species with an atom with +6 oxidation state

Answer»

`MnO_(4)^(-)`
`CR(CN)_(6)^(3-)`
`NiF_(6)^(2-)`
`CrO_(2)Cl_(2)`

SOLUTION :`CrO_(2)Cl_(2) " " x+2(-2)+2(-1)=0`
`thereforex=+6`
Discussion
21.

Amongst the following, identify the species with an atom in (+6) oxidation state

Answer»


Solution :Mn is in +7 OXIDATION state in `MnO_(4)^(-), Cr is in +3` oxidation state in `(Cr(CN)_(6)]^(3-)`Ni is in (+4) oxidation state in `NIF_(6)^(2-)` and Cris in (+6) oxidation state in `CrO_(2)Cl_(2)` HENCE, (D) is the correct answer
Discussion
22.

Amongst the following identify the criterion for process to be at equilibrium

Answer»

`DeltaGlt0`
`DeltaGgt0`
`DeltaS_("TOTAL")=0`
`DeltaSlt0`

SOLUTION :For a process to be EQUILIBRIUM, the total entropy of the system should be ZERO. THEREFORE,
`DeltaS_("total")=0`
Discussion
23.

Amongst the following hydroxides, the one which has the lowest value of K_(sp) at ordinary temperature (about 25^@ C) is

Answer»

`Mg (OH)_2`
`CA(OH)_2`
`BA(OH)_2`
`Be (OH)_7`

SOLUTION :`Be(OH)_2`has lowestsolubilityand hencelowestsolubilityproduct,
Discussion
24.

Amongst the following hydroxides, the one which has the lowedt value of K_(sp) at ordinary temperatue (about 25^(@)C) is

Answer»

`MG(OH)_(2)`
`Ca(OH)_(2)`
`BA(OH)_(2)`
`Be(OH)_(2)`

Solution :`Be(OH)_(2)` has LOWEST solubility and hence lowest SOLUTBILITY product.
Discussion
25.

Amongst the following how many compounds are more acidic than benzoic acid ?

Answer»


SOLUTION :NA
Discussion
26.

Amongst the following elements (whose electronic configurations are given below) the one having the highest ionisation energy is:

Answer»

`[Ne]3S^(2)3P^(1)`
`[Ne]3s^(2)3p^(3)`
`[Ne] 3s^(2)3p^(2)`
`[Ar]3d^(10)4S^(2)4p^(3)`

Solution :The configuration is half filled.The choice D also has half filled configuration but 4p orbitals lie FARTHER awayfrom nucleus and can be easily removed.
Discussion
27.

Amongst the following elements, the highest ionization energy is

Answer»

`[NE]3s^(2)3p^(1)`
`[Ne]3s^(2)3p^(3)`
`[Ne]3s^(2)3p^(2)`
`[Ar]3d^(10)4s^(2)4p^(3)`

Answer :B
Discussion
28.

Amongst the following electrodes the one with zero electrode potential is

Answer»

CALOMEL ELECTRODE
STANDARD hydrogen electrode
Glass electrode
Gas electrode

Solution :Standard hydrogen electrode have zero electrode POTENTIAL.
Discussion
29.

Amongst the following compounds which is most acidic?

Answer»

<P>Ethanol
p -NITROPHENOL
Picric acid
PHENOL

SOLUTION :DUE to three `-NO_(2)` (-I) groups .
Discussion
30.

Amongst the following compounds, the one(s) which readily react with ethanolic KCN is

Answer»

ethyl chloride
chlorobenzene
benzaldehyde
salicylic acid.

Solution :`overset(-)CN` is a very good nucleophile. KCN can REACT with `1^(@)` halide i.e. `H_(3)CH_(2)Cl` to give `CH_(3)CH_(2)CN.`

`overset(-)CN` is very good nucleophile and a very good leaving gorup. `overset(+)Koverset(-)CN` react with benzaldehyde to caryy Benzoin condensation to give `pH-overset(OH)overset("|")"CH"-overset(O)overset(||)C-Ph`.

Chlorobenzene is inert to KCN because a PARTIAL double bond character is PRODUCED between chloride and benzene ring due to resonance.
`rarr` Salicylic acid does not react with KCN.
Discussion
31.

Amongst the following compounds the one which would not respond to iodoform test is

Answer»

`CH_(3)CH(OH)CH_(2)CH_(3)`
`ICH_(2)COCH_(2)CH_(3)`
`CH_(3)COOH`
`CH_(3)CHO`

Solution :In ACETIC acid, the most acidic proton is attached to O-atom. So, deprotonation of `alpha`-hydrogen does not occur and hence no HALOFORM REACTION TAKES place.
Discussion
32.

Amongst the following compounds, the one which would not respond to iodoform test is

Answer»

`CH_(3)CH(OH)CH_(2)CH_(3)`
`ICH_(2)COCH_(2)CH_(3)`
`CH_(3)COOH`
`CH_(3)CHO`

Solution :Option (a) is a methylcarbinol and hence gives iodoform test. `CH_(3)CHO` CONTAINS the group `CH_(3)CO` attached to H and hence gives iodoform test. Option (b) is the FIRST iodination product of a methyl ketone and hence gives iodoform test.
`ICH_(2)COCH_(2)CH_(3) overset(I_(2)//NaOH)to I_(3)C-COCH_(2)CH_(3) overset(OH^(-))to CHI_(3)+CH_93)CH_(2)COONaCH`
`CH_(3)COOH` does not contain a `CH_(3)CO-` group attached to H or C and hence does not give iodoform test.
Discussion
33.

Amongst the following compounds, identify which are insoluble, partially soluble and highly soluble in water ?(i) Phenol(ii) Toluene(iii) Formic acid(iv) Ethlene glycol(v) Chloroform(vi) Pentanol.

Answer»

SOLUTION :(i) PHENOL : `(C_(6)H_(5)OH)` has the polar group `""^(-)OH`and non - polar `""^(-)C_(6)H_(5)` group.
THUS, phenol is partially soluble in water.
(II) Toluene : `(C_(6)H_(5)-CH_(3))` has no polar groups.
Thus,toluene is insoluble in water.
(iii)Formic acid : (HCOOH) has the polar group `""^(-)OH` and can form H - bond with water.
Thus, formic acid is highly soluble in water.
(iv) Ethylene glycol :has polar - OHgroup and can form H - bond.
Thus, it is highly soluble in water.
(v) Chloroform :is insoluble in water.
(vi) Pentanol `(C_(5)H_(11)OH)` : has polar - OH group, but it also contains a very bulky non - polar `- C_(5)H_(11)` group.
Thus,pentanol is partially soluble in water.
Discussion
34.

Amongst the following compounds, the one that Me_(2)ddotNwill not respond to Cannizzaro reaction upon treatment with alkali is

Answer»

`Cl_(3)C CHO`
`Me_(3)C CHO`
`C_(6)H_(5)CHO`
HCHO

Solution :
That is why `C Cl_(3)CHO` is very much interested to UNDERGO HYDROLYSIS rather than disproportionation.
Discussion
35.

Amongst the following compounds, the one that will not respond to Cannizzaro reaction upon treatment with alkali is

Answer»

`Cl_(3)C CHO`
`Me_(3)C CHO`
`C_(6)H_(5)CHO`
`HCHO`

Solution :Although `Cl_(3)C-CHO` does not contain an ALPHA hydrogen yet it does not undergo cannizzaro REACTION. Instead under basic conditions.

Due to strong -I-effect of the `Cl_(3)C` group, it undergoes nucleophilic attach by `OH^(-)` followed by elimination of `Cl_(3)C^(-)` group. PROTON exchange between `Cl_(3)C^(-)` and HCOOH finally gives `CHCl_(3)`. and `HCOO^(-)`.
Discussion
36.

Amongst the following compounds, identify which are insoluble, partially soluble and highlysoluble in water ?(i) phenol(ii) toluene(iii) formic acid(iv) ethylene glycol(v) chloroform (vi) pentanol.

Answer»

Solution :(i) Partially soluble because phenol has polar – OH group.(ii) INSOLUBLE because toluene is non-polar while water is polar. (iii) Highly soluble because formic acid can form hydrogen bonds with water. (IV) Highly soluble because ethylene GLYCOL can form hydrogen bonds with water. (V) Insoluble because CHLOROFORM is almost non-polar. (vi) Partially soluble because - OH group is polar but the large hydrocarbon part `(C_5H_11)`is nonpolar.
Discussion
37.

Amongst the following compounds, identify which are insoluble, partially soluble and highly soluble in water (iv) pentanol

Answer»

Solution :PARTIALLY soluble because `-OH` group is polar but the LARGE HYDROCARBON PART `(C_(5)H_(11))` is non-polar.
Discussion
38.

Amongst the following compounds, identify which are insoluble, partially soluble and highly soluble in water (v) chloroform

Answer»

SOLUTION :INSOLUBLE because CHLOROFORM is an ORGANIC LIQUID.
Discussion
39.

Amongst the following compounds, identify which are insoluble, partially soluble and highly soluble in water (iii) formic acid

Answer»

Solution :Highly soluble because formic ACID can form HYDROGEN bonds with water.
Discussion
40.

Amongst the following compounds, identify which are insoluble, partially soluble and highly soluble in water (iv) ethylene glycol

Answer»

SOLUTION :Highly soluble because ETHYLENE GLYCOL can form hydrogen bonds with WATER.
Discussion
41.

Amongst the following compounds, identify which are insoluble, partially soluble and highly soluble in water (ii) toluene

Answer»

SOLUTION :INSOLUBLE because TOLUENE is non-POLAR while WATER is polar.
Discussion
42.

Amongst the following compounds, identify which are insoluble, partially soluble and highly soluble in water (i) Phenol

Answer»

Solution :Partially soluble because PHENOL has polar `-OH` group but aromatic phenyl, `C_(6)H_(5)-` group.
Discussion
43.

Amongst the following compound which is/are soluble in aqueous NaOH?

Answer»




ANSWER :A::C::D
Discussion
44.

Amongst the following complexes, (mentioned without any charge) how many of them are expected to have a +vely charged counter ion ? (a) [PtCl_(6)]""(b) [Ni(NH_(3))_(4)] (c ) [Fe(C_(2)O_(4))_(3)]""(d) [Co(en)_(3)] (e ) [Fe(CN)_(6)]""(f) [PtCl_(4)] (g) [Ni(CO)_(4)]""(h) [Co(NH_(3))_(6)] (i) [Cu(CN)_(4)]

Answer»


Solution :`[PtCl_(6)]^(2-),""[Ni(NH_(3))_(4)]^(2+)`,
`[Fe(C_(2)O_(4))]^(3-), "" [Co(en)_(3)]^(3+)`,
`[Fe(CN)_(6)]^(3-) or [Fe(CN)_(6)]^(4-)`,
`[PtCl_(4)]^(2-), "" [Ni(CO)_(4)]`,
`[CU(CN)_(4)]^(3-), "" [Co(NH_(3))_(6)]^(2+)`
Discussion
45.

Amongst the following complexes, find the number of complexes having oxidation number of central atom as +3. Let's say it is equal to x. Similarly find the number of complexes having oxidation number of central atom as +2. Let's say it is equal to y. All other complexes number equal to z : [Co(NH_(3))_94)(H_(2)O)Cl]Cl_(2),""K_(2)[Zn(OH)_(4)], K_(3)[Al(C_(2)O_(4))_(3)]""[CoCl_(2)(en)_(2)]^(+), [Ni(CO)_(4)],""[Pt(NH_(3))_(2)Cl(NO_(2))], K_(3)[Cr(C_(2)O_(4))_(3)],""[CoCl_(2)(en)_(2)]Cl, [Co(NH_(3))_(5)(CO_(3))]Cl,""Hg[Co(SCN)_(4), [Cr(NH_(3))_(3)(H_(2)O)_(3)]Cl_(3), [Co(NH_(2)CH_(2)CH_(2)NH_(2))_(3)]_(2)(SO_(4))_(3), [Ag(NH_(3))_(2)][Ag(CN)_(2)],""K_(3)[Fe(CN)_(6)], K_(2)[PdCl_(4)],""[Pt(NH_(3))_(2)Cl(NH_(2)CH_(3))]Cl, K_(2)[Ni(CN)_(4)],""[Cr(en)_(3)]Cl_(3), Fe_(4)[Fe(CN)_(6)]_(3) Hence, find the value of x-y+z

Answer»


Solution :`+3 "complexes" IMPLIES x=10, +2 "complexes" implies y=7`
`+1 "complexes" implies 1, 0 "complexes" implies 1. "Thus" implies z=2`
Discussion
46.

Amongst the following, artificial sweeteners are : L-glucose, D-glucose, saccharin, cyclamate, D-fructose, alitame, aspartame, sucralose, sucrose.

Answer»

STATEMENT-1 is True, Statement-2 is True , Statement-2 is the correct explanation for statement 1
Statement-1 is True, Statement-2 is True , Statement-2 is not a correct explanation for statement 1
Statement-1 is True, Statement-2 is False
Statement-1 is False, Statement-2 is True.

Solution :Six. L-Glucose , saccharin, cyclamate, ALITAME, ASPARTAME and SUCROLOSE
Discussion
47.

Amongst the following antihistamines, which are antacids ?

Answer»

Ranitidine
Bromopheniramine
Terfenadinne
Cimetidine

Solution :Histamine is a substance that stimulates the secretion of pepsin and hydrochloric acid. There are some antacids like cimetidine were designed to prevent the INTERACTION of histaminewith the RECEPTOR present in the STOMACH wall. As a result less HCl is released and the cause of hyperacidity is conrolled/curved.
Ranitidine is also fall in the category of antihistamine. It is USED to cure hyperacidity.
Brompheniramine is an antihistamine . It is used to TREAT runny nose, sneezing, itching and watery eyes caused by allergy.
Terfenadine, an antihistaine, was used for allergy.
Discussion
48.

Amongst the compounds, Mg_2N_2, NH_3 and N_2O_3 nitrogen shows an oxidation state of +3 in

Answer»

`N_2O_3` only
`NH_(3) only`
`NH_(3) and N_2O_3`
All of the above

Answer :A
Discussion
49.

Amongst the compounds gives, the one that would form a brilliant colored dye on treatment with NaNO_2 in dil. HCl followed by addition to an alkaline solution of beta-naphthol is

Answer»




ANSWER :D
Discussion
50.

Amongst the compounds given, the one that would form a brilliant coloured dye with NaNO_(2) in dil. HCl followed by addition to an alkaline solution of naphthol is

Answer»




Solution :A coloured dye is formed by the reaction of DIAZONIUM salt with `beta`-naphthol. Diazonium COMPOUND is formed by the reaction of an aromatic primary amine with `HNO_(3) (NaNO_(2)+HCL)`.
Discussion