Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

Classify the following into artificial sweetners, preservatives , soap , detergent : Sodium palmitate, sucrolose, salt of sorbic acid, cetytrimethylammonium bromide.

Answer»

Solution :Sodium palmitate-soap , Sucrolose - artificial sweetener , Salt of sorbic acid - PRESERVATIVE , Cetyltrimethylammonium BROMIDE - DETERGENT .
Discussion
2.

Classify the following into antihistamine, antacid, tranquilliser, antibiotic drug : penicillin, meprobamate, terfenadine, ranitidine.

Answer»

SOLUTION :Penicillin - ANTIBIOTIC : MEPROBAMATE - tranquilizer : TERFENADINE - antihistamine RANITIDINE - antacid.
Discussion
3.

Classify the following into acid, base and amphiprotic in terms of protonic concept. Н_(2)РО_(2)(ii) H_(2)PO_(3) (iii) H_(2)APO_(4)(iv) HPO_(3) (V) HPO_(4) (vi) NH_(4) (vii) CH_(3)COOH_(2)

Answer»

SOLUTION : ACIDIC (vi). (VII)
Basic) (iv)
Discussion
4.

CoCl_(3).6NH_(3) can form 4 different types of complexes (According to Werner). Which of the following cannot exhibit optical isomerism as well as geometrical isomerism ?

Answer»

`[Co(NH_(3))_(5)Cl]Cl_(2)-" Purple colour "`
`[Co(NH_(3))_(4)Cl_(2)]Cl-" Green colour "`
`[Co(NH_(3))_(4)Cl_(2)]Cl-" VIOLET colour "`
`[Co(NH_(3))_(6)]Cl_(3)-" Yellow colour "`

Answer :A::B::C
Discussion
5.

Classify the following halogen derivatives of alkanes : CHBr_(3), CH_(3)I, CH_(3)-underset(CH_(3))underset(|)overset(Cl)overset(|)C-H, CH_(3)-underset(Br)underset(|)overset(Br)overset(|)C-CH_(3)

Answer»

Solution :MONOHALOGEN derivatives of ALKANES or alkyl HALIDES :<BR>`CH_(3)I,CH_(3)-underset(CH_(3))underset(|)overset(Cl)overset(|)C-H`
(2) DIHALOGEN derivatives of alkanes: `CH_(3)-underset(Br)underset(|)overset(Br)overset(|)C-CH_(3)`
(3) Trihalogen derivatives of alkanes : `CHBr_(3)`
Discussion
6.

Classify the following groups as o-/p-or m-directing group and activating or deactivating group: (i) -NO_2

Answer»

SOLUTION :`-NO_2` (DEACTIVATING and m-directing ),
Discussion
7.

CoCl_(3).5NH_(3).H_(2)Ois a pink solid,the solution of this salt is also pink and forms 3 mol of AgCl with silver nitrate solution. On heatingpink solid, it loses one water molecule and forms purple solid having the same ratio of Co: NH_(3) :Clas that of pink solid. The purple solid when dissolved in water and treated with silver nitrate forms 2 mol of AgCl. Draw the structures and name the pink and purple solids.

Answer»

Solution :(1) Since the COMPLEX of FORMULA `CoCl_(3).5NH_(3).H_(2)O` in the solution FORMS 3 mol AGCL , the complex contains `3Cl^(-)` in the outer ionisation sphere and the formulaof the pink coordination compound should be ,
`[Co(NH_(3))_(5)(H_(2)O)]Cl_(3)`.
`[Co(NH_(3))_(5)H_(2)O]Cl_(3) hArr[Co(NH_(3))_(5)H_(2)O]^(3+) +3Cl^(-)`
`3AgNO_(3) + 3Cl^(-) hArr 3AgCl_((S)) + 3NO_(3)^(-)`
(2) On heating, the pink solid loses one `H_(2)O` molecules and in the aqueous solution gives 2 mol `AgCl`, with same ratio of `Co:NH_(3)`, the purple coordination compound should be, `[Co(NH_(3))_(5)Cl]Cl_(2)` having the same ratio of `Co:NH_(3)(1:5)`
`[Co(NH_(3))_(5)Cl]Cl_(2) hArr [Co(NH_(3))_(5)Cl]^(2+)+2Cl^(-)`
`2AgNO_(3) + 2Cl^(-) hArr 2AgCl_((S)) + 2NO_(3)^(-)`.

IUPAC names of complexes :
Pink complex `[Co(NH_(3))_(5)H_(2)O]Cl_(3)` : Aquapentaamminecobalt (III) Chloride.
Purple complex `[Co(NH_(3))_(5)Cl]Cl_(2)` : Pentaamminechloridocobalt(III) chloride.
Discussion
8.

Classify the following compounds as primary, secondary and tertiary halies.(i) 1-Bromobut-2-ene(ii) 4-Bromopent-2-ene (iii) 2-Bromo-2-methylpropane

Answer»

SOLUTION :(i)`CH_(3)-underset("H")underset("|")("C")=underset("H")underset("|")("C")-OVERSET(1^(@))(C )H_(2)-Br "" 1^(@)` - Halide
(ii)`CH_(3)-underset(" Br")underset("|")(overset(2^(@))(C ))H-CH-CH_(3) ""2^(@)-` Halide
(iii)`CH_(3)-overset(" Br")overset("|")underset(" "CH_(3))underset("|")(overset(""3^(@))("C"))-CH_(3) ""3^(@)-`Halide
Discussion
9.

CoCl_(3).4H_(2)O is an anyhydrous binary solute hence its Werner's representation is :

Answer»




NONE of these

Solution :`[CO(H_(2)O)_(4)Cl_(2)]Cl`
Discussion
10.

Classify the following compounds as primary, secondary and tertiary halides. (i) 1-Bromobut-2-ene (ii) 4-Bromopent-2-ene (iii) 2-Bromo-2-methylpropane.

Answer»

Solution :(i) `UNDERSET("1-Bromobut-2-ene "(1^(@)" Alkyl halide"))(CH_(3)CH=CH-overset(1^(@))(C)H_(2)Br)`
(ii) `underset("4-Bromopent-2-ene "(2^(@)" Alkyl halide"))(CH_(3)-overset(2^(@))(C)HBr-CH=CH-CH_(3))`
(iii) `underset("2-Bromo-2-methylpropane "(3^(@)" Alkyl halide"))(CH_(3)-underset(CH_(3))underset(|)overset(CH_(3))overset(|)(.^(3^(@))C)-Br)`
Discussion
11.

CoCl_3 . xNH_3 exhibits geometrical isomerism. What is the value of x?

Answer»

Solution :The value of x MAY be 3 and 4. `CoCl_3 . 3NH_3` exhibits facial- meridional isomerism . `[CO(NH_3)_4Cl_2]CL` exhibits cis-trans geometrical isomerism.
Discussion
12.

Classify the following compounds as aromatic, anti-aromatic or non-aromatic compounds: (a) Cyclopropenyl cation (b) Naphthalene (c) Furan Pyrrole (e) Pyridine (f) Cycloctatetraene (g) 1,3,5-Cycloheptatriene.

Answer»

Solution :(a)
is aromatic as the rin is planar `4n+2=2pi -" electrons "( n= 0)`
`pi`electrons are delocalized.
(b)
It has planar structure with delocalized ` (4*2+2) or 10pi` electrons obeys Huckel.s rule. It is aromatic.
(c)
The O atom and each of the four C atoms are in `sp^(2)` hybridized STATE forming a flat pentagonal structure. One of two lone PAIRS of electrons of the O atom is in `sp^(2)` orbital which is in the PLANE of ring and does not contribute towards aromatic sextet and the other in p orbital. Four p orbitals of four C atoms each containing `pi` electron and the filled p orbital of O are parallel to each other and perpendicular to the plane of furan.
Therefore, furan has 4p electrons from four C atoms and 2p electrons from the O atom, i.e. it has six delocalized `pi` electrons which isa Huckel number. Hence,it is an aromatic compound. It has also resonance stablilzation as shown below:

(d)
Huckel number of delocalized `pi-` electrons are present in a planar cyclic structure Hence, it is aromatic. Here, lone PAIR of H- atom is contributing to aromatic sextet.
(e)
Since there are 6 delocalized p-electrons in planar hexagonal structure of pyridine, it is aromatic.
(f)
Cyclootatetraene has 8 `pi-` electrons. It has a puckered ring structure and proper overlap of `pi-`electrons are not possible . Hence , it is not an aromatic compound.
(g)
It has `4xx1+2=6 pi-` electrons but they are not delocalized. Hence, it is non-aromatic.
Discussion
13.

[CoCl_(2)(NH_(3))_(4)]^(+)+Cl^(-) to [CoCl_(3)(NH_(3))_(3)]+NH_(3). If in this reaction two isomers of the produt are obtained, which is true for the iniital (reactant) complex:

Answer»

COMPOUND is in CIS-form
compound is in TRANS-form
compound is in both (cis and trans)
can't be predicted

Solution :
Discussion
14.

Classify the following carbohydrates into Monosaccharides , disaccharide , Oligosaccharide , Polysaccharide : (1) Glucose(2) Starch(3) Sucrose(4) Maltose(5) Galactose(6) Lactose(7) Ribosome .

Answer»

SOLUTION :
Discussion
15.

[CoCl_(2) (NH_(3))_(4)]^(+)Cl^(-)( green)and[CoCl_(2)(NH_(3))_(4)]^(+)Cl^(-)( violet ) have identicalformulaCoCl_(3) .4NH_(3), butdistinctproperties.Suchcompounds are called….A … here,A refers to

Answer»

ISOMERS
coordinationcompounds
Either (a) or (B)
NONE of these

Solution :`[CoCl_(2) (NH_(3))_(4) ]^(+)`( green)and ` [Co Cl_(2) (NH_(3))_(4)]^(+)CL^(-) `
(violet ) haveidenticalformula` CoCl_(3) .4NH_(3) `butdistinctproperties .Suchcompounds are calledisomers .
Discussion
16.

Classify the following as primary, secondary and tertiary alcohols. (i) CH_3-underset(CH_3)underset(|)overset(CH_3)overset(|)C-CH_2OH(ii) H_2C = CH - CH_2OH(iii) CH_3 - CH_2 - CH_2 - OH

Answer»

SOLUTION :PRIMARY alcohols:
(i) `CH_3 - UNDERSET(CH_3) underset(|)overset(CH_3) overset(|)C- CH_2OH`(ii) `H_2C = CH - CH_2OH`(iii) `CH_3 - CH_2 -CH_2 -OH`
SECONDARY alcohols:

Tertiary alcohols:
Discussion
17.

Classify the following as primary, secondary and tertiary alcohols : (i) CH_(3)-overset(CH_(3))overset("|")underset(CH_(3))underset("|")"C "-CH_(2)OH (ii) H_(2)C=CH-CH_(2)OH (iii) CH_(3)-CH_(2)-CH_(2)-OH

Answer»

SOLUTION :PRIMARY alcohols : (i), (ii), (III), Secondary alcohols: (IV)(v), Tertiary alcohols : (VI).
Discussion
18.

[CoCl_(2)(NH_(3))_(4)]^(+) +Cl^(-) to [CoCl_(3)(NH_(3))_(3)] + NH_(3) If in the above reaction only one isomer of the product is obtained, which is true for the initial (reactant) complex :

Answer»

compound is in CIS FORM
compound is in TRANS form
compound is in both (cis and trans) forms
can't be predicted

Solution : to only one possible because all 'B' position are IDENTICAL.
Discussion
19.

Classify the following as primary alcohols, secondary alcohols and tertiary alcohols. (i) CH_(3)-underset(CH_(3))underset(|)overset(CH_(3))overset(|)(C)-CH_(2)OH (ii) H_(2)C=CH-CH_(2)OH (iv) CH_(3)-CH_(2)-CH_(2)-OH

Answer»

SOLUTION :(i) PRIMARY (ii) Primary (III) Secondary (iv) Primary
Discussion
20.

[COCl_(2)(en)_(3)]^(3+) exhibits………..isomerism.

Answer»


ANSWER :OPTICAL ISOMERISM
Discussion
21.

Classify the following as linear, branched or cross linked polymers (a) Bakelite (b) Nylon (c) polythene

Answer»

Solution :(a) Bakelite - cross LINKED polymer (B) Nylon - Linear polymer (C) Polythene - Linear polymer
Discussion
22.

[CoCl_(2)(en)_(2)]Br will show :

Answer»

COORDINATION position isomerism
ionization isomerism
geometrical isomerism
optical isomerism.

Solution :`CIS[CoCl_(2)("en")_(2)]` Br is optically active.
Discussion
23.

Classify the following as linear, branched or cross linked polymers a) Bakelite b) Nylon c) polythene

Answer»

Solution :(a) BAKELITE -crosslinkedpolymer
(B)NYLON - linearpolymer
(c )POLYTHENE -linearpolymer
Discussion
24.

CoCl_(2) + KNO_(2) + CH_(3)COOH to [X] +H_(2)O +KCl + CH_(3)COOK +NO (Unbalenced equation)

Answer»

`X` is a yellow crystalline solid INSOLUBLE in water.
`X` is a green coloured compounds known as kinman's green
`IUPAC` name of `X` is POTASSIUM hexanitrito-`N`-cobaltate (II)
The compound `X` is an inner orbital complex.

Solution :`Co^(2+)+7NO_(2)^(-)+3K^(+)+2H^(+)toK_(3)[Co(NO_(2))_(6)]DARR("yellow")+NO darr+H_(2)O`
So `[X]` is `K_(3)[Co(NO_(2))]_(6)` It is called Fischer's reagent, `[Co(III)(NO_(2))_(6)]^(3-)` has `d^(2)sp^(3)` HYBRIDISATION and is diamagnetic . It `IUPAC` name is potassium hexanitrito-`N`-cobaltate`(III)`.
Discussion
25.

Classify the following as electrophiles and nucleophiles: (a) CN^(-) (b) H_(2)O (c) Br^(+) (d) NO_(2)^(-) (e) overset(+)NO_(2) (f) CH_(3)OH (g) H_(2)C=CH_(2) (h) RCOCl (i) H_(2)N-OH (j) :(C Cl_(2) (k) H_(3)O^(+) (l) NH_(3) (m) BF_(3) (n) AlCl_(3) (o) OH^(-) (p) R_(3)N

Answer»


ANSWER :A::B::C::D
Discussion
26.

CoCl_(2) is

Answer»

pink
black
green
colourless

Answer :A
Discussion
27.

Classify the following as cationic detergents, anionic detergents or non-ionic detergent CH_3(CH_2)_2CH_2OSO_3^(-)Na^(+)

Answer»

SOLUTION :ANIONIC DETERGENT
Discussion
28.

Classify the following as cationic detergents, anionic detergents or non-ionic detergent

Answer»

SOLUTION :Non-ionic DETERGENT
Discussion
29.

CoCI_(2) givesbluecolourwith NH_(4)SCN duetoformation of

Answer»

`(NH_(4))_(2)[CO(SCN)_(4)]`
`(NH_(4))_(4)[Co(SCN)_(6)]`
`(NH_(4))_(3)[Co(SCN)_(6)]`
`(NH_(4))[Co(SCN)_(4)]`

ANSWER :a
Discussion
30.

Classify the following as cationic detergents, anionic detergents or non-ionic detergent [CH_3-(CH_2)_15N(CH_3)_3]^(+)]Br^(-)

Answer»

SOLUTION :CATIONIC DETERGENT
Discussion
31.

Cocaine is hallucinogen used widely How many chiral carbon does it have.

Answer»


SOLUTION :
Discussion
32.

Classify the following as amorphous or crystalline solids: polyurethane, naphthalene, benzoic, acid, teflon, potassium nitrate, cellophane, polyvinyl chloride, fibre glass, copper.

Answer»

Solution :Amorphous solids: polyurethane, teflon, CELLOPHANE, polyvinyl chloride, fibre glass. Crystalline solids: naphthalene, benzoic ACID, `KNO_3` COPPER.
Discussion
33.

Cocaine is :

Answer»

Vitamin
Poison
Medicine
Antipyretic

Answer :C
Discussion
34.

Classify the following as amorphous or crystalline solids : Polyurethane, naphthalene, benzoic acid, teflon, potassium nitrate, cellophane, polyvinyl chloride, fibre glass, copper.

Answer»

SOLUTION :AMORPHOUS solids: Polyurethane, teflon, cellophane, polyvinyl CHLORIDE, fibre glass. Crystalline solids: BENZOIC acid, naphthalene, potassium nitrate, COPPER.
Discussion
35.

Cobalt (III) chloride forms several octahedral complexes with ammonia. Which of the following will not give test for chloride ions with silver nitrate at 25^@C ?

Answer»

`CoCl_3 . 5NH_3`
`CoCl_3. 6NH_3`
`CoCl_3. 3NH_3`
`CoCl_3. 4NH_3`

ANSWER :C
Discussion
36.

Classify the following as amorphous or crystalline solids : Polyurethane, naphthalene, benzoic acid, teflon, potassium nitrate, cellophane, polyvinyl chloride, fibre glass and copper.

Answer»

Solution :The above MENTIONED SUBSTANCES are classified as under :
Crystalline SOLIDS `""` Amorphous solids
BENZOIC acid`""`Polyurethane
Potassium nitrate`""` Naphthalene
Copper`""` Teflon
Cellophane
Polyvinyl chloride
FIBRE glass
Discussion
37.

Cobalt (III) chloride forms several octahedral complexes with ammonia. Which of the following will not give test for chloride ions with silver nitrate at 25^(@)C ?

Answer»

`CoCl_(3).5 NH_(3)`
`CoCl_(3).6 NH_(3)`
`CoCl_(3).3 NH_(3)`
`CoCl_(3).4 NH_(3)`

Solution :As cobalt forms octahedral complexes for which coordination number = 6, the formulae of the given complexes will be
`[Co(NH_(3))_(5)Cl]Cl_(2), [Co(NH_(3))_(6)]Cl_(3)`,
`[Co(NH_(3))_(3)Cl_(2)]` and `[Co(NH_(3))_(4)Cl_(2)]Cl`
THUS, only (c) does not have any ionizable chloride ion.
Discussion
38.

Classify the following as alkyl, allyl and vinyl halides (i) CH_(2)CH=CFCH_(2)CH_(3) (ii). (CH_(3))_(2)C ClCH_(3) (iii). CH_(2)=CHCH_(2)I (iv). .

Answer»

Solution :(i). Vinyl fluride
(II). Alkyl chloride
(III). Allyl iodide
(iv). Vinyl chloride and alkyl BROMIDE.
Discussion
39.

Classify the following as addition and condensation polymers : Terylene, Bakelite, polyvinyle chloride, Polythene.

Answer»

SOLUTION :Addition polymers : POLYTHENE, polyvinyle chloride
CONDENSATION polymers : TERYLENE, Bakelite
Discussion
40.

Cobalamine is :

Answer»

VITAMIN `B_(12)`
Vitamin E
Vitamin `B_(2)`
Vitamin K.

Answer :A
Discussion
41.

Classify the following as addition and condensation polymers : Terylene , Baklite , Polyvinyl chloride , Polythene.

Answer»

Solution :ADDITION Polymers : POLYVINYL CHLORIDE , polythene .
CONDENSATION polymers : Terylene bakelite.
Discussion
42.

Coating of zinc on iron objects is commonly known as:

Answer»

Electroplating
Surface coating
Galvanising
Sheardising

Answer :C
Discussion
43.

Coaltar is a main source of :

Answer»

AROMATIC compounds
Aliphatic compounds
Cycloalkanes
Heterocyclic compounds

Answer :A
Discussion
44.

Classify the following as addition and condensation polymers: Terylene, Bakelite, Polyvinyl chloride, Polythene.

Answer»

Solution :ADDITION POLYMERS: POLYVINYL chloride, POLYTHENE, CONDENSATION polymers : Terylene, bakelite.
Discussion
45.

Coal-tar is main source of

Answer»

AROMATIC compounds
Cycloalkanes
Aliphatic compounds
Heterocyclic compounds

Answer :A
Discussion
46.

Classify the following as addition and condensation polymers : Terylene, Bakelite, Polyvinyl chloride, Polythene

Answer»

SOLUTION :Addition POLYMERS : POLYVINYL CHLORIDE and polythene.
CONDENSATION polymers : Terylene and bakelite.
Discussion
47.

Classify the following as acid (or) base using Arrhenius concept (i) HNO_3 (ii)Ba(OH)_2 (iii) H_3 PO_4 (iv)CH_3 COOH

Answer»

SOLUTION :ACID:
(i) `HNO_3""(iii) H_3PO_4`
`(IV) CH_3COOH`
Base :
`(ii) Ba(OH)_2`
Discussion
48.

Classify the following as 1^@,2^@ and 3^@ alcohols

Answer»

SOLUTION :`1^@` ALCOHOL
Discussion
49.

Coal is a potential source for ammonia. Comment.

Answer»

Solution :Coal on destructive DISTILLATION gives coal tar, which also contains ammonical liquor. When the liquid is TREATED with MILK of lime and steam is blown, ammonia gas is EVOLVED. Concentrated ammonia solution can be prepared by dissolving in steam directly. A fertiliser ammonium sulphate is obtained when ammonia is absorbed in `H_(2)SO_(4)`.
Discussion
50.

Classify the following as acid (or) base using Arrhenius concept HNO_3 (ii) Ba(OH)_2 (iii) H_3PO_4 (iv) CH_3COOH

Answer»

Solution :`HNO_3:` Nitric acid dissociates to give hydrogen IONS in water
`THEREFORE HNO_3` is acid
(ii) `BA(OH)_2`: Barium HYDROXIDE , dissociates to give hydroxyl ions in water
`therefore Ba(OH)_2`is base.
(iii) `H_3PO_4`: Orthophosphoric acid ,dissociates to give hydrogen ions in water.
`therefore H_3PO_4` in acid.
(IV) `CH_3COOH`: Acetic acid, dissociates to give hydrogen ions in water.
`therefore CH_3COOH` is acid.
Discussion