Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

CO_((g))+H_(2(g))overset([X])rarrHCHO_((g)) In above reaction, what is [X] ? (A)

Answer»

`NI//CrO_(3)`
`CU`
`Ni`
`Cu//ZnO`

SOLUTION :`Cu`
2.

Clemmensen reduction of a ketone is carried out in presence of -

Answer»

`H_2` with PD as catalyst
Glycol with KOH
`LiAIH_4` in ether
ZN -Hg with HCl

Answer :B
3.

Cleasing action of cationic detergent is due to

Answer»

HYDROPHOBIC PART of cation
hydrophillic part of cation
hydrophobic part of anion
hydrophilic part of anion

Answer :B
4.

CO(g)+H_(2)(g)overset(Cu)toX CO(g)+H_(2)(g)overset(Cu//ZnO-Cr_(2)O_(3))toY CO(g)+H_(2)(g)overset(Ni)toZ X,Y and Z respectively are

Answer»

`CH_(3) OH, HCHO, CH_(4)`
`HCHO, CH_(3)OH, CH_(4)`
`CH_(4), CH_(3)OH,k CH_(4)`
`CHOH, CH_(4),CH_(3)OH`

Solution :X, Y and Z will be HCHO, `CH_(3)OH and CH_(4)` respectively.
5.

Clay is an example of

Answer»

THREE DIMENSIONAL SILICATES
Chain silicates
Cyclic silicates
Sheet silicates

ANSWER :D
6.

CO_((g))+2H_(2(g))overset(?)rarrCH_(3)OH_((g))

Answer»

`NI`
`CU//ZNO-Cr_(2)O_(3)`
`Cu`
`ZnO`

SOLUTION :`Cu//ZnO-Cr_(2)O_(3)`
7.

Claus obtained ........... by subjecting ............ to high frequency ultrasonic vibrations.

Answer»

SOLUTION :MERCURY SOL , mercury
8.

Claude process is used in the manufacture of:

Answer»

`N_2`
`NH_3`
`N_2O`
`NO_2`

ANSWER :A
9.

[CoF_(6)]^(3-) is

Answer»

paramagnetic and under `SP^(3)d^(2)` hybridisation
diamagnetic and UNDERGOES `d^(2)sp^(3)` hybridisation
paragamagnetic and undergoes `sp^(3)d` hybridisation
diamagnetic and undergoes `sp^(3)` hybridisation.

Solution :`[CoF_(6)]^(3-)` is parasmagnetic
`[CoF_(6)]^(3-):CO^(3+)(3D^(6))`
10.

Classify the following species into Lewis acids and Lewis bases and show how these can act a Lewis acid/ Lewis base? OH^- ions (ii)F^- (iii)H^+ (iv) BCl_3

Answer»

Solution :`OH^-` IONS can DONATE an electron pair and act as Lewis base.
(II) `F^-` ions can donate an electron pair and act as Lewis base.
(iii) `H^+` ions can accept an electron pair and act as Lewis base.
(iv) `BCl_3` can accept in electron pair since Boron atom is electron DEFICIENT. It is a lewis acid.
11.

[CoF_(6)]^(3-) forms outer orbital complexes while (Co(CN)_(6)]^(3-)forms inner orbital complexes. Why

Answer»

Solution :In`[CoF_(6)^(3-)` FIONS provide a weak LIGAND field and therefore unpaired electrons of cobalt do not get PAIRED. As a result, the orbitals of outer shell are used in hybridization `(sp^(3)d^(2)`. On the contrary, in `[CO(CN)_(6)]^(3+)` the strong ligand field of `CN^(-)` forces the PAIRING of electrons, in inner shell VACATING the inner d-orbitals for hybridization `(d^(2)sp^(3))`
12.

Classify the following solids on the basis of bonding considerations : CO_(2), MgO, Al, H_(2), Si, Gd, Pb, AgCl.

Answer»

Solution :The SOLIDS are arranged against the type of bonding as under :
`{:("Molecular solids", - ,CO_(2) H_(2)),("Iconic solids ",- , MgO AgCI),("Covalent solids ",-,Si),("Metalliac solids",- ,"Gd Al Pb."):}`
13.

COF_2gas passed over a catalyst at 1000^@Ccomes to equilibrium:2 COF_2(g)iffCO_2(g) + CF_4(g)Analysis of the equilibrium mixture (after quick cooling to freeze the equilibrium) shows that 500 mL of equilibrium mixture (NTP) contains 300 mL (NTP) of COF_2 and CO_2 . Taking the total pressure to be 10 atm, calculate K_p .

Answer»

SOLUTION :At eqb:`UNDERSET(100ML)(2COF_2) IFF underset(200ML)(CO_2) + underset(200mL)(CF_4)`
4.0
14.

[Co(en)_(3)]^(3+) ion is expected to show :

Answer»

TWO optically ACTIVE isomers : d and l forms
d, l and meso forms
four optically active isomers : CIS, d and l isomers and TRANS d and l isomers
None of these

ANSWER :A
15.

Classify the following solids into different types (a) Ammonium phosphate (b) Brass (c) S_(8) molecule (d) Diamond

Answer»

SOLUTION :
16.

Classify the following solids into isotropic and anisotropic. Polyvinylchloride, Rubber, Glucose, Glass

Answer»

SOLUTION :ANISOTROPIC - GLUCOSE
Istropic-Glass,RUBBER,POLYVINYLCHLORIDE
17.

Classify the following solids in different categories based on the nature of intermolecular forces operating in them : Potassium sulphate, tin, benzene, urea, ammonia, water, zinc sulphide, graphite, rubidium, argon, silicon carbide.

Answer»

SOLUTION : METALLIC solids : TIN, Rubidium
Ionic solids : Potassium sulphate, Zinc sulphide.
Covalent solids : Graphite, Silicon carbide
Molecular solids : BENZENE, Urea, Ammonia, Water, Argon.
18.

[Co(en)_2(NH_3)_2]Cl_3 can exhibit (A) ionisation isomerism (B) geometrical isomerism (C) optical isomerism

Answer»

A,B
B,C
A,C
A,B,C

Answer :B
19.

Classify the following solids in different categories based on the nature of intermolecular forces operating in them : Potassium sulphate, tin, benzene, urea, ammonia, water, zinc sulphide, graphite, rubidium, argon, silicon carbide. Solid Category Potassium sulphate Ionic

Answer»

Solution :`{:("Solid","Category"),("Potassium sulphate","Ionic"),("Tin","Metallic"),("Benzene","MOLECULAR"),("Urea","Molecular"),("Ammonia","Molecular with H-bonds"),("Water","Molecular with H-bonds"):}{:("Solid","Category"),("ZINC sulphide","Ionic"),("Graphite","Covalent"),("Rubidium","Metallic"),("ARGON","Molecular"),("Silicon carbide","Covalent"):}`
20.

[Co(en)_(2)Cl_(2)]Br react with silver nitrate to form.............coloured precipitate.

Answer»


ANSWER :PALE YELLOW
21.

Classify the following solids in different categories based on the nature of intermolecular forces operating in them : Potassium sulphate, tin, benzene, urea, ammonia, water, zinc sulphide, graphite, rubidium, argon, silicon carbide.

Answer»

Solution :`{:("Potassium sulphate","Ionic"),("Tin","Metallic"),("Benzene","Molecular (non polar)"),("Urea","Molecular (polar)"),("Ammonia","Molecular (hydrogen bonded)"),("WATER","Molecular (hydrogen bonded)"),("Zinc sulphide","Ionic"),("Graphite","Covalent or NETWORK"),("RUBIDIUM","Metallic"),("ARGON","Molecular (non polar)"),("SILICON carbide","Covalent or Network"):}`
22.

Coductivity of an electrolytic solution depends on____

Answer»

NATURE of electrolyte
Concentration of electrolyte
Power of AC source
Distance between the electrodes

Answer :A::B
23.

Classify the following solids based on the nature of intermolecular forces operating in them: potassiumsulphate, tin, benzene, urea, ammonia, water, zinc sulphide, graphite, rubidium, argon, silicon carbide.

Answer»

Solution :Molecular SOLIDS: BENZENE, urea, AMMONIA, water, argon
ionic solids : potassium sulphate, zinc suphide
metallic solids : tin, RUBIDIUM
covalent solids : graphite, silicon carbide
24.

Classify the following solids (a) P_(4) (b) Brass (c ) Diamond (d) NaCl (e ) Iodine

Answer»

Solution :(a) `P_(4)` - Molecular solid
(B) Brass - Metallic solid
(C ) Diamond - Covalent solid
(d) NACL - IONIC solid
(e ) Iodine - Molecular solid
25.

[Co(e n)_(3)]^(3+) ion is expected to show :-

Answer»

Two OPTICALLY active isomers
Two optically inactive isomers
four optically active isomers, CIS, d & `L` from and trans d & `l` form
None

Answer :A
26.

Codon is present in

Answer»

t- RNA
m- RNA
r- RNA
All of these

Solution :CODON is PRESENT in m-RNA , which is RESPONSIBLE for TRANSLATION.
27.

Classify the following solids (a) P_(4), (b) Brass (c) Diamond (d) NaCI (e) lodine

Answer»

SOLUTION :`{:("(a) P4 - MOLECULAR SOLID"),("(b) Brass - Metallic solid"),("(C) Diamond - Covalent solid"),("(d) NaCl - Ionic solid"),("(E) Iodine - Molecular solid"):}`
28.

COD stands for

Answer»

ChemicalOxygendemand .
Controlledoxygendemand
cloudscausing ozone depletion
CHLORINATED OXYGEN DEMAND

ANSWER :A
29.

Classify the following reactions as homegeneous and heterogeneous catalysis : (a) Vegetable oil (l)+H_(2)(g)overset (Ni(s))rarrVegetable ghee (s) (b) C_(12)H_(22)O_(11)(aq)+H_(2)O(l) overset (H_(2)SO_(4)(aq))rarr C_(6) H_(12)O_(6)(aq)+C_(6)H_(12)O_(6)(aq)

Answer»

SOLUTION :(a) : HETEROGENEOUS CATALYSIS
(B): HOMOGENEOUS catalysis
30.

Cod liver oil is-

Answer»

FAT DISPERSED in water
Water dispersed in fat
Water dispersed in oil
Fat dispersed in fat

Answer :C
31.

Classify the following reaction in one of the reacation type studied in this unit. (1) CH_(3)CH_(2)Br+HS^(-)rarrCH_(3)CH_(2)SH+Br^(-) (2) (CH_(3))_(2)C=CH_(2)+HCIrarr(CH_(3))_(2)C CI-CH_(3) (3) CH_(3)CH_(2)Br+HO^(-)rarrCH_(2)=CH_(2)+H_(2)O+Br^(-) (4) (CH_(3))_(3)C-CH_(2)OH+HBrrarr(CH_(3))_(2)CBrCH_(2)CH_(2)CH_(3)+H_(2)O

Answer»

Solution :(1) Nucleophilic substitution
(2) ELECTROPHILIC ADDITION
(3) `BETA` - ELIMINATION
(4) Nucleophilic substitution & rearrangement
32.

Classify the following ligand based on the number of donor atoms. (a) NH_(3) (b) en (c )"ox"^(2-) (d) triaminotriethylamine (e) pyridine

Answer»

Solution :`(a) NH_(3)`- Monodentate LIGANDS (`N`-Donor ATOM)
`(B) en`- Bidentate ligand (`2N`-Donor atom)
`(c ) OX^(2-)`- Bidentate ligand (`2O`- Donor atom )
`(d)` triaminotriethylamine- Tridentate ligand (`3N`-Donor atom)
`(e )` pyridine- Monodentate ligand (`N`- Donor atom)
33.

Classify the following ligands into monodentate and polydentate : (a) Ammonia (b ) Carbon monoxide(c ) Ethylene diamine (d ) Ethylene diamine tetra 0 acetate ion

Answer»

Solution :Monodentate LIGANDS are :
AMMONIA
Carbon MONOXIDE
Polydenatate ligands are :
ETHYLENE diamine
Ethylene diamine tetra - acetate ION.
34.

Fats on alkaline hydrolysis, give

Answer»

Glycol
Alcohol
Glycerol
Ethylene oxide

Solution :Coconut OIL + ALKALI `to` Soap `to` + Glycerol
It is a SAPONIFICATION REACTION.
35.

Classifythe following intomonosacharides ,oligosaccharides and polysaccharides . (i)Strach(ii) fructose(iii) surcose (iv) lactose(v) maltose .

Answer»

Solution :(i) Starch -Polysaccharides .
(II) FURCTOSE- Mono saccharides .
(iii) SURCOSE- Oligo saccharides .
(iv)LACTOSE - Oilgosacchardie
(v) MALTOSE - Oligosaccharide .
Surcose , Lactose and Maltoseare typicaldisaccharides .
36.

Coconut charcoal at 93K in used to separate

Answer»

AR and KR
NE and Kr
He and Kr
He and Ne

Answer :D
37.

Coconut charcoal at-180^0C is used to separate a mixture of:

Answer»

AR and Kr
Ne and Ar
He and Kr
He and Ne

Answer :B
38.

Classify the following into monosaccharides and disaccharides. Ribose, 2-deoxyribose, maltose, galactose, fructose and lactose.

Answer»

Solution :MONOSACCHARIDES : Ribose, 2-deoxyribose, galactose and FRUCTOSE.
Disaccharides : MALTOSE and Lactose
39.

Coconut charcoal at -100^@C adsorbs a mixture of

Answer»

He and KR
AR, Kr and Xe
Kr and Xe
He and Ne

Solution :In Deewars method. Coconut charcoal at `- 100^@C` . Ar, Kr, Xe are adsorbed.
40.

Classify the following into monosaccharides, , oligosaccharides and polysaccharides i) Starch ii) fructose iii) sucrose iv) lactose v) maltose

Answer»

Solution :(i) Starch -Polysaccharide
(ii) FRUCTOSE - monosaccharide
(iii) SUCROSE- oligosaccharides
(IV) lactose- oligosaccharides
(v) MALTOSE - oligosaccharide
41.

Coconut charcoal at-100^0C absorbs in a mixture of:

Answer»

He and KR
Ar, Kr, and Xe
Kr and Xe
He and Ne

Answer :B
42.

Classify the following into monosaccharides and disaccharides : Ribose, 2-deoxyribose, maltose, galactose, fructose and lactose.

Answer»

Solution :MONOSACCHARIDES : RIBOSE, 2-deoxyribose, galactose and FRUCTOSE.
DISACCHARIDES : Maltose and lactose.
43.

COCO_(3((s))hArrCaO_((s))+SO_(2(g)) with of the following expression is correct or For the equlibrium CaCO_(3(s))hArrCaO_((s))+CO_(2(s)) the equlibrium constant is perpesented by the following from

Answer»

`K_(p)=(P_(CaO+P_(CO_(2)))//P_(CaCo_(3)))`
`K_(p)=P_(CO_(2))`
`K_(p)xx(P_(CaO)xxP_(CO_(2))).P_(CaCO_(3))`
`(K_(p)[CAP][CO_(2)])/([CaCO_(3)])`

Solution :`CaCO_(3(g))hArrCaO_((s))+CO_(2(g))K_(p)=P_(CP_(2))`
Solid molecule does not have PARTIAL pressure so in calculation of `K_(p)` only `P_(CO_(2))` is applicable.
44.

Classify the following into monosaccharides and disaccharides. Ribose, 2-deoxyribose , maltose, galactose, fructose and lactose.

Answer»

SOLUTION :Monosaccharides : RIBOSE , 2-deoxyribose , GALACTOSE and FRUCTOSE.
Disaccharides : Maltose and LACTOSE.
45.

[Co(CN)_(6)]^(3-) and [CoF_(6)]^(3-) both are octahedral complexes. Then what is the difference between the two ?

Answer»

Solution :`[CO(CN)_(6)]^(3-)` is an inner ORBITAL or low spin complex INVOLVING the hybridisation `d^(2)sp^(3)` while `[CoF_(6)]^(3-)` is an outer orbital or high spin complex involving `sp^(3)d^(2)` hybridisation.
46.

Classify the following into homopolymer or copolymer Nylon 6, HDPE

Answer»

Solution :Nylon 6 and HDPE 9 or HDP) are HOMOPOLYMERS
47.

Classify the following into electrophilic and nucleophilic reagents: (a)H^(+)"(b) " Cl^(-)" (d) "NH_(3)"(d)"NO_(2)^(+)"(e)"Cbar(N)"(f)"H_(2)O "(g)"Br^(+)"(h)"ROH"(i)"BF_(3)"(j)"RNH_(2)"(k)"AlCl_(3) "(l)"ROR"(m) Carbocations(n)Carbanions(o) "SO_(3)H "(p)"BeCl_(2)"(q) "I^(-)"(r) "SnCl_(4)"(s)":"CCl"_(2)"(t) ":P(CH_(3))_(3) (u) H_(2)C=CH_(2) (B) Classify the following as Lewis acids and Lewis bases : (a)CH_(3)NH_(2)"(b)"CN^(-)"(c)"AlCl_(3)"(d)"Fe^(3+)"(e) "CO_(2)^(-)

Answer»

<P>

SOLUTION :Electrophilic reagents: (a), (d), (g), (i), (k), (m), (o), (p), (r), (s)
Nucleophilic reagents: (b), (c), (e), (f), (h), (j), (l), (N), (q), (t), (U).
1(B) Lewis ACIDS : (c), (d)
Lewis bases : (a), (b), (c)
48.

[CoCl(NH_(3))_(4)(H_(2)O)]Br_(2) and [Co(NH_(3))_(4)Br_(2)]Cl.H_(2)O are …. Isomers as well as …… .

Answer»

SOLUTION :IONIZATION, HYDRATE
49.

Classify the following into cationic and anionic detergents: Sodium dodecylbenzene sulphonate and Cetyltrimethyammonium bromide.

Answer»

SOLUTION :SODIUM dodecylbenzene sulphonate - Anionic
Cetyltrimethyammonium BROMIDE - Cationic
50.

CO,CN^(-), en and NH_(3) are called..........ligands.

Answer»


ANSWER :STRONG