Cobalt (III) chloride forms several octahedral complexes with ammonia. – InterviewSolution

1.	Cobalt (III) chloride forms several octahedral complexes with ammonia. Which of the following will not give test for chloride ions with silver nitrate at 25^(@)C ?
Answer» `CoCl_(3).5 NH_(3)` `CoCl_(3).6 NH_(3)` `CoCl_(3).3 NH_(3)` `CoCl_(3).4 NH_(3)` Solution :As cobalt forms octahedral complexes for which coordination number = 6, the formulae of the given complexes will be `[Co(NH_(3))_(5)Cl]Cl_(2), [Co(NH_(3))_(6)]Cl_(3)`, `[Co(NH_(3))_(3)Cl_(2)]` and `[Co(NH_(3))_(4)Cl_(2)]Cl` THUS, only (c) does not have any ionizable chloride ion.

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