Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

Arenium ion involved in the bromination of aniline is /are

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SOLUTION :Resomating STRUCTURES
Discussion
2.

Arenium ion involved in the bromination of aniline is____

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<BR>

Solution :Since `NH_(2)` GROUP is o,p-directing, therefore, `Br^(+)` ATTACKS only at o- and p-positions and hence option (a), (B) and (c) are CORRECT.
Discussion
3.

Aqueous solution of nickel sulphate on treating with pyridine and then adding a solution of sodium nitrite gives dark blue crystals of

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` [NI (py)_4]SO_(4)`
`[Ni(py)_(2)(NO_(2))_(2)]`
`[Ni(py)_(4)](NO_(2))_(2)`
`[Ni(py)_(3)(NO_(2))]_(2)SO_(4)`

Answer :C
Discussion
4.

Arenediazonium salts are more stable than alkanediazonium salts due to dispersal fo the positive charge on the benzene ring. Obviously, electron-donating groups favour diazotisation by retarding the decomposition of diazonium salts to phenyl cation. The high reactivity of arenediazonium salts is due to the excellent leaving ability of the diazo group as N_(2) gas. Q. The product formed when bromobenzene reacts with benzenediazonium chloride in presence of NaOH is

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diphenyl
p-bromodiphenyl
p,p'-dibromodiphenyl
p-bromoazobenzene

Answer :B
Discussion
5.

Aqueous solution of nickel sulphate on treating with pyridine and then adding a solution of sodium nitrite gives dark blue crystals of :

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`[Ni(PY)_(4)]SO_(4)`
`[Ni(py)_(2)(NO_(2))_(2)]`
`[Ni(py)_(4)](NO_(2))_(2)`
`[Ni(py)_(3)(NO_(2))]_(2)SO_(4)`

ANSWER :C
Discussion
6.

Aqueous solution of nickel sulphate on treating with pyridine and then adding a solution of sodium nitrite gives dark blue crystals of:

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`[Ni(Py)_4]SO_4`
`[Ni(Py)_2(NO_2)_2]`
`[Ni(Py)_4](NO_2)_2`
`[Ni(Py)_3(NO_2]_2SO_4`

Answer :C
Discussion
7.

Arenes on treatment with chloride in presence of ferric chloride as a catalyst undergo what type of reaction?

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ELECTROPHILIC substitions
NUCLEOPHILIC SUBSTITUTION
Electrophilic ADDITION
Nucleophilic addition

SOLUTION :
Discussion
8.

Aqueous solution of Ni^(2+) contains [Ni(H_(2)O)_(6)]^(2+) and its magnetic moment is 2.83 B.M. When ammonia is added in it, comment on the magnetic moment of solution :

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It will REMAIN same
It increases from 2.83 B.M.
It decreases from 2.83 B.M.
It cannot be predicted theoretically

SOLUTION :`[Ni(NH_(3))_(6)]^(2+) IMPLIES sp^(3)d^(2)`
Discussion
9.

Arenediazonium salts are more stable than alkanediazonium salts due to dispersal fo the positive charge on the benzene ring. Obviously, electron-donating groups favour diazotisation by retarding the decomposition of diazonium salts to phenyl cation. The high reactivity of arenediazonium salts is due to the excellent leaving ability of the diazo group as N_(2) gas. Q. Which of the following diazonium salts when boiled dil. H_(2)SO_(4) gives the corresponding phenol most readily?

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Solution :MeO group at m-position exerts -I-effect which TENDS to WEAKEN the `Ar-N_(2)^(+)` BOD thereby facilitating its DECOMPOSITION.
Discussion
10.

Arenediazonium salts are more stable than alkanediazonium salts due to dispersal fo the positive charge on the benzene ring. Obviously, electron-donating groups favour diazotisation by retarding the decomposition of diazonium salts to phenyl cation. The high reactivity of arenediazonium salts is due to the excellent leaving ability of the diazo group as N_(2) gas. Q. Which of the following arylamines undergoes diazotisation most readily?

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SOLUTION :The diazonium salt formed is STABILIZED by the POWERFUL +R-effet of the `OCH_(3)` group.
Discussion
11.

Aqueoussolutionof NaOH ismarked10%(w//w). Thedensityof thesolutionis 1.070 g cm^(-3). Calculate (i) molarity and (ii)molalityof NaOH.

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Solution :Given :Percentage byweightof NaOH`=10% (w//w)`
Densityof NaOHsolution =D =1.070 G `CM^(-3)`
Molarmass ofNaOH=40 g `mol^(-1)`
(i) Molarity of NaOHsolution = ?
(ii)Molalityof NaOHsolution = ?
(i) Formolarityof solution: Consider 100 gNaOHsolution
`:. ` Weight `H_(2)O+` Weightof NaOH =100 g
`:. ` Weightof `H_(2)O = 100 - 10= 90 g`
Numberof molesof NaOH`= (W_(NaOH))/(M_(NaOH))`
`:. n_(NaOH) = .(10)/(40)`
`=0.25 `mol
Densityof solution `(D) = ("Weight of solution" )/(" volumeof solution " ) = (W)/(V)`
`:.V = (W)/(D)`
`=(100)/(1.070)`
`=93 . 46 cm^(3)`
`=0.09346 dm^(3)`
Molarity`=(n)/(V)= (0.25)/(0.09346) =2.675 "mol"dm^(-3)(or M)`
(ii) For molalityof NaOHsolution :
Molality`=("MOLAR of NaOH ") /("Mass ofsolventin gram ") xx 1000`
`=(0.25)/(90) xx 1000`
`=2.779"mol" kg^(-1)(or m)`
Discussion
12.

Aqueous solution of NaCl containing a small amount of MeOH( methyl orange ) is electrolysed using Pt- electrodes . The color of the solution after some time will .

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REMAINS yellow
change from yellow to colorless
change from yellow to RED
remain red

Solution :Remains yellow since solution is basic after ELECTROLYSIS& MEOH shows red colour in ACIDIC medium .
Discussion
13.

Are the sols of metals hydrophilic or hydrophobic?

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SOLUTION :HYDROPHOBIC
Discussion
14.

Aqueous solution of Na_(2)SO_(4) containing a small amount of HPh is electrolysed using Pt-electrodes. The colour of the solution after some time will:

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REMAINS COLOURLESS
change from PINK to colourless
change from colourless to pink
REMAIN pink

ANSWER :A
Discussion
15.

pH value of aqueous solution of Nacl after electrolysis is ________

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SOLUTION :GREATER than 7
Discussion
16.

Are the rate equations obtained from law of mass action always equal to those obtained experimentally? If not, then for what type of reactions are they equal?

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SOLUTION :No, elementaryreaction
Discussion
17.

Aqueous solution of Na_(2)S_(2)O_(3) on reaction with Cl_(2) gives

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`Na_(2)S_(4)O_(6)`
`NaHSO_(4)`
`NACL`
`NaOH`

Solution :`Na_(2)S_(2)O_(3) + 4 Cl_(2) + 5 H_(2)O rarr 2 NaHSO_(4) + 8 HCl`.
Discussion
18.

Aqueoussolution of Na_(2)S_(2)O_(3) onreactionwith CI_(2) water gives

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`Na_(2)S_(4)O_(4)`
`Na_(2)SO_(4)`
`Na_(2)S_(4)O_(6)`
`NaOH`

Solution :`S_(2)O_(3)^(2-) + 4CI_(2) + 5H_(2)O RARR S + SO_(4)^(2-) + CI^(THETA)`
Discussion
19.

Are the following names correct according to IUPAC system of nomenclature? If not, the correct names: (a) Pent-3-yne (b) tert-Butanol (c) Hexa-1,6-diene (d)4,43-Trimethylhex-1-yne (e) 2-Keto-n-propanol (f) 1-Methoxyethan-2-ol (g) 3-Methylhexa-1,5-diyne (h) 4,4,5-Trimethylhex-1-yne

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ANSWER :No , it should be pent-2-yne (b) No , teri-word is not used in IUPAC SYSTEM . It is 2-methylpropan-2-ol (c) No , it should be hexa-1,5-diene (d) No , it should be 3,4,4-trimethylhex-1-yne (e) No , KETO is not used . It is the PRINCIPAL functional group . it is 1-hydroxy propan-2-one (f) No , it should be 2-methoxy ethan-1-ol (g) Yes(h) Yes
Discussion
20.

Aqueous solution of how many of the following species turn blue limtus red ? (i) SF_(4) (ii) PCl_(3) (iii) H_(2)O (iv) NO_(2)Cl (v) SF_(6) (vi) SeF_(6) (vii) AsCl_(3) (viii) POCl_(3) (ix) SO_(2) (x) SO_(2)Cl_(2) (xi) SOCl_(2) (xii) COCl_(2) (viii) C Cl_(4)

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ANSWER :10 (EXCEPT iii, v and XIII)
Discussion
21.

are related as:

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FUNCTIONAL Isomers
Position isomers
Chain isomers
Metamers

Solution :N//A
Discussion
22.

Aqueous solution of hydrogen peroxide .

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Turns BLUE litmus pink
Gives bright blue COLOUR in ETHER with acidified `K_2Cr_2O_7` SOLUTION
Gives yellow or orange coloured solution with an acidified solution of titanium salt
Bleaches blue litmus

Solution :NA
Discussion
23.

Are polyesters and polyacrylates same ? Justify your answer.

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SOLUTION :Polyesters and polyacrylates are different types of polymers and differ in the following characteristics :
(i) Polyacrylates are homopolymers while the polyesters are co-polymers in nature
(ii) The MODE of synthesis of polyacrylates is addition polymerisation while that of polyesters is condensation polymerisation.
(III) Polymerisation occurs ACROSS `C = C` bond in polyacrylates where as in polyesters it is through ester LINKAGE
Discussion
24.

Aqueous solution of HCl has the pH = 4. Its molarity would be

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4 M
0.4 M
0.0001 M
10 M

Solution :pH = 4 MEANS, `[H^(+)] = 10^(-4)` mol/l.
Discussion
25.

………………..arecarbohydrates that cannot be hydrolysed further and are also called simplesugars.

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SOLUTION :Monosacchrides
Discussion
26.

Aqueous solution of HCl conducts electricity because it

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ionises
DISSOCIATES
dimerises
forms HYDROGEN bond

SOLUTION :`HCl to H^(+) + Cl^(-)`
Discussion
27.

Are all the five bonds in PCl_(5)molecule equivalent ? Justify your answer.

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Solution :`PCl_(5)`has a trigonal bipyramidal STRUCTURE and the THREE EQUATORIAL P-Cl bonds are EQUIVALENT, while the two axial bonds are DIFFERENT and longer than equatorial bonds.
Discussion
28.

Aqueous solution of FeCl_3 is :

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ACIDIC
BASIC
AMPHOTERIC
netural

Answer :A
Discussion
29.

Are all the five bonds of PCl_(5) equivalent ? Justify your answer.

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Solution :No`PCl_(5)` has a trigonal bipyramidal structure. Three EQUITORIAL P-CI BONDS are equivalent, while the two axial bond are different and longer than equitorial bonds.
Discussion
30.

Aqueous solution of glucose on cystalline at 303k produces

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anomers
epimers
enantiomers
polymers

Answer :A
Discussion
31.

Aqueous solution of ferric chloride is

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Acidic
Basic
Neutral
Amphoteric

Solution :`FeCl_(3)` is a salt of STRONG acid and weak base. It GIVES `Fe(OH)_(3)` and HCl on hydrolysis. `Fe(OH)_(3)` is a weak base and HClis strong acid.
So the aqueous solution of `FeCl_(3)` will be acidic in NATURE
Discussion
32.

Are all the five bonds in PCI_(5) equivalent ? Justify.

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SOLUTION :`PCI_(5)` has trigonal bipyramid structure.It has THREE equatiorial bonds inclined at angle of `120^(@)` and two axial bonds inclined at an angle of `90^(@)`. Since two axial P-CI bonds are repelled by three bond pairs each while three equatorial P-CI bonds are repelled by two bond pairs each, therfore, axial bonds are longer (240 pm) and hence weaker as compared to more STABLE equatorial bonds (202 pm). Thus, all the five P-CI bonds in `PCI_(5)` are not equivalent.
Discussion
33.

Aqueous solution of CuSO_(4).5H_(2)O changes blue litmus paper to red due to

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Presence of `Cu^(++)` IONS
Presence of `SO_(4)^(--)` ions
Hydrolysis taking place
Reduction taking place

Solution :Hydrolysis of `Cu^(2+)` PRODUCES `H^(+)` ions in solution.
Discussion
34.

are :

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ENANTIOMERS
OPTICAL INACTIVE diastereomers
Optical ACTIVE diastereomers
Identical

Answer :B
Discussion
35.

are a pair of

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Enantiomers
Identical COMPOUNDS
Dia STEREO ISOMERS
Positional isomers

Answer :C
Discussion
36.

Aqueous solution of CuSO_(4).5H_(2)O changes blue litmus paper red due to

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HYDROLYSIS of `CU^(2+)` ion
Reduction TAKING place
Presence of `Cu^(2+)` ions
Presence of `SO_(4)^(2-)` ions

Answer :A
Discussion
37.

ArArr2B,K_(p),CrArrD+E,K_(p). Ifdegrees of dissociation of A and C are same and K_(p)=2K_(p), then the ratio of total presure p//p=?

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`(1)/(2)`
`(1)/(3)`
`(1)/(4)`
2

Answer :1
Discussion
38.

Aqueous solution of CuSO_4 is electrolysed using inert electrodes till the blue coloured solutionbecomes colourless. The colourless solution formed is

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`CU(OH)_(2)`
`H_(2)SO_(4)`
`CuSO_(4)`
`H_(2)O`
Discussion
39.

Aralkyl alcohols are also named as

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ALLYLIC ALCOHOL
VINYLIC alcohol
benzylic alcohol
aryl alcohol

ANSWER :C
Discussion
40.

Aqueous solution of carbon dioxide forms …………………. .

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ANSWER :CARBONIC ACID
Discussion
41.

Aqueous solution of copper sulphate changes blue litmus to red because:

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`Cu^-2` is PRESENT
`SO_4^-2`
HYDROLYSIS take place
REDUCTION takes place

Answer :C
Discussion
42.

Aradioactive isotope decays at such a rate that after 96 minutes only 1/8th of the original substance is left. The half life period of the nucleide is :

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12
24
32
48

Answer :C
Discussion
43.

Aqueous ZnSO_(4) treated with Na_(2)CO_(3)//H_(2)O produces A which when heated forms B which further treated with cobalt nitrate and warmed C is formed. A,B and C are respectively.

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`ZnCO_(3), Zn` and `CoO`
`ZnO,Zn` and `CoZnO_(2)`
`ZnCO_(3).3ZN(OH)_(2),ZnO` and `CoZnO_(2) ` respectively
`ZnCO_(3), ZnO,CoO`

ANSWER :C
Discussion
44.

Aqueous solution of carbohydrate with 2 drops of alcoholic solution of alpha-napthol and H_2SO_4 gives a ring at the junction . The colour of the ring is

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Yellow
Green
Violet
Red

Answer :C
Discussion
45.

Aquous solution of phenol is more acidic than which of the following ?

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ACETIC acid
ALCOHOL
(A) & (B) both
NONE of these

Solution :Alcohol
Discussion
46.

Aqueoussolutionof borax reactswithtwomol of acids.Thisis because of

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FORMATION of `2` MOL of `B(OH)_(3)` only
formation of `2` mol of `[B(OH)_(4)]^(Theta)` only
formation of `1` mol each of `B(OH)_(3)`and` [B(OH)_(4)]^(Theta)`only
formation of `2` mol each of `[B(OH)_(4)]^(Theta)`and `B(OH)_(3)` ofwhich`[B(OH)_(4)]^(Theta)` reactswithacid

Answer :d
Discussion
47.

Aqueous sulphuric acid reacts with 2-methy 1-1-butene to give predominantly :

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isobutyle HYDROGEN sulphite
2-methy1-1butane
2-methy1-2butanol
secondary butyle hydrogen sulphate

Answer :B
Discussion
48.

Aqueous Solution of BaBr_(2) gives yellow precipitate with:

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`K_(2)CrO_(4)`
`AgNO_(3)`
`(CH_(3)COO)_(2)Pb`
(A) and (B) both.

Solution :`BA^(2+)+CrO_(4)^(2-) to BaCrO_(4) darr("YELLOW"),Ag^(+) +Br to AgBr darr`(pale arrow)
Discussion
49.

Aqueous solutions of two compounds M_(1)-O-H and M_(2)-O-H are prepared in two different beakers. If, the electronegativity of M_(1)=3.4,M_(2)=1.2, O=3.5 and H=2.1, then the nature of two solutions will be respectively:

Answer»

ACIDIC, basic
acidic, acidic
basic, acidic
basic, basic

Solution :The electronegativity difference between `M_(1) and O ` is 0.1, which indicates `M_(1)-O` bond will be covalent, since O-H bond having more IONIC character thus bond will break and `H^(+)` ions will release andn acidic solution is formed. WHEREAS diference between electronegativity of `M_(2)-O` bond is 2,3, thus, `M_(2)-OH` bond will break. hence, solution will be basic in nature.
Discussion
50.

Aqueoussolution of BaBr_(2) , givesyellow ppt with

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`K_(2)CrO_(4)`
`AgNO_(3)`
both
none

Answer :C
Discussion