1.

Aqueous solutions of two compounds M_(1)-O-H and M_(2)-O-H are prepared in two different beakers. If, the electronegativity of M_(1)=3.4,M_(2)=1.2, O=3.5 and H=2.1, then the nature of two solutions will be respectively:

Answer»

ACIDIC, basic
acidic, acidic
basic, acidic
basic, basic

Solution :The electronegativity difference between `M_(1) and O ` is 0.1, which indicates `M_(1)-O` bond will be covalent, since O-H bond having more IONIC character thus bond will break and `H^(+)` ions will release andn acidic solution is formed. WHEREAS diference between electronegativity of `M_(2)-O` bond is 2,3, thus, `M_(2)-OH` bond will break. hence, solution will be basic in nature.


Discussion

No Comment Found

Related InterviewSolutions