Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

Aqueous solutions of two compounds M - O - H and M' - O - H have been prepared in two different beakers. If the electronegativity of M = 3.5, M' = 1.72, O = 3.0 and H = 2.1, then the solution respectively are

Answer»

acidic , acidic
acidic , basic
basic , basic
basic , acidic

SOLUTION :In the compound M - O - H, if IE or E.N. of M is low, the compound will act as a base and if the IE or E. N. of M is high, the compound will behave as an ACID. Therefore, M - O - H will act as an acid E.N. of M is high (3.5) and M. - O - H will act as a base as E.N. of M. is low (1.72).
2.

Aqueous solution of an acetate salt, when heated with FeCl_3 solution gives a blood red solution due to the formation of :

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`FE(CNS)_3`
`(CH_3COO)_3Fe`
`Fe(OH)_3`
`FeCl_3.CH_3COOH`.

Solution :`3CH_3COOM + FeCl_3to UNDERSET("RED colour")((CH_3COO)_3 Fe) + 3MCl`
3.

Aqueous solutions of Na_(2)S_(2)O_(3) on reaction with Cl_(2) gives

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`Na_(2)S_(4)O_(6)`
`NaHSO_(4)`
NaCl
NaOH

Solution :`Na_(2)S_(2)O_(3)+4Cl_(2)+5H_(2)Oto2NaHSO_(4)+8HCl`
HENCE,(B) is the correct ANSWER.
4.

Aqueous solution of aluminium sulphate would show

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`H^(+)` IONS
`H_(2)^(+)` ions
`H_(3)O^(+)` ions
`H_(4)O^(+)` ions

Solution :`UNDERSET(aq.)(H_(2)O) + underset("acid")(HA) hArr H_(3)O^(+) + A^(-)`.
5.

Aqueous solution of alpha-amino acid is slightly acidic, which is due to

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ACIDIC CHARACTER of `NH_3^(+)`
BASIC character of `COO^-`
Acidic character of `COO^-`
basic character of `NH_3^(+)`

ANSWER :A
6.

Aqueous solutions of hydrogen suphide and sulphur dioxide when mixed together , yeild _________.

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SULPHUR and water
sulphur TRIOXIDE and sulphur
hydrogen PEROXIDE and sulphur
hydrogen and SULPHUROUS acid

Answer :A
7.

Aqueous solutions of HNO_(3), KOH, CH_(3)COOH and CH_(3)COONa of identical concentrations are provided. The pair (s) of solutions which form a buffer upon mixing is (are)

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`HNO_(3)` and `CH_(3)COOH`
KOH and `CH_(3)COONa`
`HNO_(3)` and `CH_(3)COONa`
`CH_(3)COOH` and `CH_(3)COONa`

SOLUTION :`HNO_(3) + CH_(3)COONa` mixture can ACT as buffer solutions if volume of `HNO_(3)` solution taken is LESSER than volume of `CH_(3)COONa` solution because of following reaction
`CH_(3)COONa+HNO_(3)RARR CH_(3)COOH + NaNO_(3)`
(d) `CH_(3)COOH + CH_(3)COONa`-mixture will act as buffer.
8.

Aqueous solution of AgNO_3 is electrolysed using inert electrodes. At the end of electrolysis

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pH of the SOLUTION INCREASES
pH of the solution decreases
pH of the solution remains unchanged
pH of the solution becomes14

Solution :at cathode `: AG^(+) + e^(-) to Ag ` , at anode `: 2H_2O to O_2 + 4H^(+) + 4e^(-)`
`[H^(+)]uarr [pH]^DARR pH = log""(1)/([H^(+)])`
9.

Aqueous solutions of hydrogen sulphide and sulphur dioxide when mixed together, yield

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SULPHUR and water
Sulphur TRIOXIDE and water
Hydrogen PEROXIDE and sulphur
Hydrogen and sulphurous acid

Solution :`SO_(2) +2H_(2)S to 3S +2H_(2)O`
10.

Aqueous solution of a salt (V) is alkaline to litmus. On strong heating, it swells-up to give a glassy material. When conc. H_(2)SO_(4) is added to a hot concentrated solution of (V), white crystals of a weak acid separates out. Hence, the compound (Y) is

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`Na_(2)SO_(4)10H_(2)O`
`Ca_(2)B_(2)O_(11).10H_(2)O`
`Na_(2)B_(2)O_(11)`
`Na_(2)Ba_(4)O_(7).10H_(2)O`

Solution :`(Y) is borax `Na_(2)B_(4)O_(7).10H_(2)O`
`Na_(2)B_(4)O_(7)+7H_(2)Otounderset(ubrace("Strong base WEAK acid")_("Alkaline"))(2NaOH+4H_(2)BO_(3))`
`Na_(2)B_(4)O_(7)overset(Delta)toubrace(2NaBO_(2)+B_(2)O_(3))_("Glassy-bead")`
`Na_(2)B_(4)O_(7)+H_(2)SO_(4)+5H_(2)OtoNa_(2)SO_(4)+4H_(2)BO_(3)`
Hence,(D) is the correct answer.
11.

Aqueous solution of which salt has the lowest pH :

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NAOH
`NH_4CL`
`Na_2CO_3`
Nacl

Answer :B
12.

Aqueous solution of a salt 'A', when mixed with NaoH solution and warmed, a black precipitate is formed. Black ppt. is filtered and dissolved in dil. H_(2)SO_(4) solution. The resulting solution gives a chocolate coloured precipitate with potassium ferrocyanide solution. the filtrate obtained after filtering off the black precipitate, upon warming with Zn and NaOH evolves a pungent smelling gas. the resulting solution also responds to the ring test. the filtrate does not evolve any gas when it is boiled with urea in the presence of H_(2)SO_(4). Q. The chocolate coloured precipitate is:

Answer»

`Fe_(2)[Fe(CN)_(6)]`
`Cu_(2)[Fe(CN)_(6)]`
`HgSO_(4)`
`[Fe(H_(2)O)_(5)(NO)]SO_(4)`

SOLUTION :`CuO+H_(2)SO_(4) to CuSO_(4)+H_(2)S`
`2CuSO_(4)+K_(4)[Fe(CN)_(6)] to underset("chocolate ppt.")(Cu_(2)[Fe(CN)_(6)]darr)+2K_(2)SO_(4)`
13.

Aqueous solution of which salt will not be hydrolysed?

Answer»

POTASSIUM nitrate
Potassium cyanide
Potassium formate
Potassium acetate

Answer :A
14.

Aqueous solution of a salt 'A', when mixed with NaoH solution and warmed, a black precipitate is formed. Black ppt. is filtered and dissolved in dil. H_(2)SO_(4) solution. The resulting solution gives a chocolate coloured precipitate with potassium ferrocyanide solution. the filtrate obtained after filtering off the black precipitate, upon warming with Zn and NaOH evolves a pungent smelling gas. the resulting solution also responds to the ring test. the filtrate does not evolve any gas when it is boiled with urea in the presence of H_(2)SO_(4). Q. The filtrate obtained after filtering off the black precipitate consists of:

Answer»

`NO_(2)^(-)`
`NO_(3)^(-)`
`CO_(3)^(2-)`
`Cl^(-)`

SOLUTION :`4Zn+NaNO_(3)+7NaOH to 4Na_(2)ZnO_(2)+2H_(2)O+underset("PUNGENT smell")(NH_(3)uarr)`
15.

Aqueous solution of a salt 'A', when mixed with NaoH solution and warmed, a black precipitate is formed. Black ppt. is filtered and dissolved in dil. H_(2)SO_(4) solution. The resulting solution gives a chocolate coloured precipitate with potassium ferrocyanide solution. the filtrate obtained after filtering off the black precipitate, upon warming with Zn and NaOH evolves a pungent smelling gas. the resulting solution also responds to the ring test. the filtrate does not evolve any gas when it is boiled with urea in the presence of H_(2)SO_(4). Q. Salt 'A' consists of:

Answer»

`Cu^(2+)`
`HG^(2+)` SALT
`Cu^(+)`
`Pb^(2+)`

SOLUTION :
16.

Aqueous solution of which of the following compounds is the best conductor ofelectric current ?

Answer»

Ammonia, `NH_(3)`
Fructose, `C_(6)H_(12)O_(6)`
Acetic acid , `C_(2)H_(4)O_(2)`
HYDROCHLORIC acid , HCl

Answer :D
17.

Aqueous solution of 3% non-volatile solute exerts a pressure of 1 bar at the boiling point of the solvent. Calculate the molar mass of solute.

Answer»

Solution :DATA: (i) Vapour pressure of water at its [BOILING point temperature]`=P^(@)=1.013` bar
(ii) Vapour pressure of solution at normal boiling point P=1bar
3% solution=3g of solute in 100G of solution.
(iii) Mass of solute=3g(iv) Mass of solvent=100-3=97g
(v) RELATIVE lowering of vapoure pressure`=(P^(@)-P)/(P)=(1.013-1)/(1.013)=0.0128`
(vi) Molar mass of water=18g `mol^(-1)`
Formula, `M_(2)=(W_(2))/(W_(1))xx(M_(1))/([(P^(@)-P)/(P^(@))])`
Substitution: `M_(2)=(3)/(97)xx(18)/(0.0128)`
ANSWER `M_(2)=43.49g//mol`.
18.

Aqueous solution having highest pH is

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`0.1 M NH_4CL`
`0.1 M NACL`
`0.1 M (NH_4)_2 SO_4`
`0.1 M CH_3COONa`

ANSWER :1
19.

Aqueous solution contains Zn(CH_(2)COO)_(2),Cd(CH_(3)COO)_(2) and Cu(CH_(3)COO)_(2) on passing H_(2)S gas, therte is a precipitate of ……. As sulphide

Answer»

`ZN^(2+)`
`Cd^(2+)`
`Cu^(2+)`
NONE of these

Answer :a,B,c
20.

Aqueous sol. Of two compound M_(1)-O-H & M_(2)-O-H are prepared in two different beakers. If EN of M_(1) =3.4, M_(2)+1.2,O=3.5& M=2.1. Then nature of sol. Will be respectively

Answer»

ACIDIC, Basic
Acidic, Basic
Basic, Acidic
Basic, Basic.

Answer :A
21.

Aqueous sodium cyanide is used as a reagent in the metal extraction. This process is called

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PYROMETALLURGY
ELECTROMETALLURGY
Hydrometallurgy
None of these

Answer :C
22.

Aqueous silver nitrate is subjected to electrolysis, using platinum electrodes. What will be the nature of the solution after some time?

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Solution :At platinum cathode reduction takes place, `Ag_((aq))^(+)+E^(-) rarr Ag_((s))`At platinum anode oxidation takes place, `2H_(2)O_((l)) rarr 4e^(-) +O_(2)+4H_((aq))^(+)`.As a result of the conversion of WATER to proton, the solution becomes ACIDIC (nitric ACID ) The pH of the solution decreases.
23.

Aqueous NaOH reacts with white Phospho rous to form Phosphine and

Answer»

`NaH_(2)PO_(2)`
`P_(2)O_(5)`
`Na_(3)PO_(3)`
`P_(2)O_(3)`

Answer :1
24.

Aqueous NaCl solution is electrolyzed using platinum electrodes. What is the product formed at cathode?

Answer»

NA
`H_2`
`O_2`
`Cl_2`

ANSWER :B
25.

Aqueous HCL is an acidic solution whereas aqueous NH_3is a basic solution. Justify this statement.

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Solution :`HCl+H_2O leftrightarrow H_3O^(+)+ Cl^-`
In this CASE, in ADDITION to auto ionisation of water. HCl molecule also produces `H_3O^+` ion by donating a proton to water and hence `[H_3O^+] gt [OH^-]` . It means that the AQUEOUS HCl solution is acidic. Similarly in BASIC solution such as aqueous `NH_3,[OH^-] gt [H_3O^+]` and it is basic.
26.

Aqueous ethanolic solution of 2-3% Iodine is

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ANTISEPTIC
Tincture of iodine
Antihistamine
Antifertility drug

SOLUTION :low CONC phenol act as antiseptic and in high conc act as disinfectant
27.

Aqueous copper sulphate solution (blue in colour) gives : (i) a green precipitate with aqueous potassium fluoride and (ii) a bright green solution with aqueous potassium chloride. Explain these experimental results.

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Solution :Aqueous `CuSO_(4)` solution EXISTS as `[Cu(H_(2)O)_(4)]SO_(4)` which has blue colour.
(i) When KF is added, weak `H_(2)O` ligands are replaced by F ligands forming `[CuF_(4)]^(2-)` ions which is a green precipitate.
`[Cu(H_(2)O)_(4)]^(2+)+4F^(-)tounderset("Tetrafluorocuprate(II)(Green ppt.)")([CuF_(4)]^(2-))+4H_(2)O`
(ii) When KCl is added, weak `H_(2)O` ligands are replaced by `CL^(-)` ligands forming `[CuCl_(4)]^(2-)` ion which has bright green colour.
`[Cu(H_(2)O)_(4)]^(2+)+4Cl^(-)tounderset("Tetrachlorocuprate(II)(Bright Green solution)")([CuCl_(4)]^(2-))+4H_(2)O`
28.

Aqueous copper sulphate solution (blue in colour) gives (i) a green precipitate with aqueous potassium fluoride, and (ii) a bright green solution with aqueous potassium chloride. Explain these experimental results.

Answer»

Solution :Aqueous `CuSO_(4)` solution exists as `[Cu(H_(2)O)_(4)]SO_(4)` which has blue COLOUR due to `[Cu(H_(2)O)_(4)]^(2+)` ions. (i) When KF is added, the weak `H_(2)O` LIGANDS are replaced by `F^(-)` ligands FORMING `[CuF_(4)]^(2-)` ions which is a green precipitate.
`[Cu(H_(2)O)_(4)]^(2+)+4F^(-)rarrunderset(("Green ppt."))underset("Tetrafluorocuprate(II)")([CuF_(4)]^(2-))+4H_(2)O`
(ii) When KCl is added, `Cl^(-)` ligands replace the weak `H_(2)O` ligands forming `[CuCl_(4)]^(2-)` ION which has bright green colour.
`[Cu(H_(2)O)_(4)]^(2+)+4Cl^(-)rarrunderset(("Green solution"))underset("Tetrachlorocuprate(II)")([CuCl_(4)]^(2-))+4H_(2)O`
Alternatively, directly we can write the REACTION as :
`CuSO_(4)(aq)+4KF(aq)rarrK_(2)[CuF_(4)]+K_(2)SO_(4)`
`CuSO_(4)(aq)+4KCl(aq)rarrK_(2)[CuCl_(4)]+K_(2)SO_(4)`
29.

Aqueous copper sulphate solution and aqueous silver nitrate solution are electrolysed separated electrolytic cells. Will the mass of copper and silver deposited on the cathode be same different ? Explain your answer.

Answer»

Solution :* It will be different. ACCORDING to Faraday.s second law, the amounts of different substances liberated by the same quantity of electricity passing through the electrolytic solution are
Proportional `("Atomic mass of meta")/("No. of electrons")` to their chemical EQUIVALENT weights electrons required to reduce the cation.
Here, for the electrode reactions:
`Ag^(+)+e^(-) to Ag and Cu^(2+) +2e^(-) to Cu`
* Hence, one mole of `Cu^(2+) and Ag^(3+)` REQUIRE 2 mol of electron (2F) and 1 mol of electrons `(F_(1))` respectively.
30.

Aqueous copper sulphate solution and aqueous silver nitrate solution are electrolysed by 1 ampere current for 10 minutes in separate electrolytic cells. Will the mass of copper and silver deposited on the cathode be same or different ? Explain your answer.

Answer»

Solution :Different. ACCORDING to Faraday.s second law, amounts of different substances liberated by the same quantity of electricity PASSING through the electrolytic solutions are proportional to their chemical equivalent weights. SINCE the equivalent weights of copper and SILVER are different, we shall obtain different masses of copper and silver.
31.

Aqueous 10% NaHCO_3 solution is used as a reagent for identifying X'. Which one of the following compounds yields 'X' on hydrolysis?

Answer»

`CH_(3) CO_(2) C_(2) H_(5)`
`C_(2) H_(5) - O - C_(2) H_(5)`
`CH_(3) CHO`
`CH_(3) - CH_(2) - OH`

Answer :A
32.

Aquatic animals are more comfortable in cold water rather in warm water. Give reason.

Answer»

SOLUTION :Because solubility of oxygen in more in COLD WATER than in WARM water.
33.

Aquaregia is

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1:3 conc. `HNO_(3)` and conc. HCI
1:2 conc. `HNO_(3)` and conc. HCI
3:1conc. `HNO_(3)` and conc. HCI
2:1 conc. `HNO_(3)` and conc. HCI

Solution :ONE PART of CONCENTRATED `HNO_3 and 3` parts concentrated HCL form AQUAREGIA.
34.

Aqua regia is used for dissolving which metals

Answer»

Alkali
Alkaline earth
Noble
Transition

Answer :C
35.

Aqua regia reacts with Pt to yield:

Answer»

`PT(NO_3)_4`
`H_2PtCI_6`
`PtCI_4`
`PtCI_2`

ANSWER :B
36.

Aqua regia is a mixture of ________ and _______ in the ratio of 3:1.

Answer»

SOLUTION :CONC. HCL. Conc. `HNO_3.`
37.

Aqua regia is a mixture of .......... and ............ in the ratio 3:1 .

Answer»

SOLUTION :CONC. HCL. Conc. `HNO_3.`
38.

Aqua-regia is a mixture of:

Answer»

`3HCL + HNO_3`
`3HNO_3 + HCL`
`H_3PO_4 + H_2SO_4`
`HCl + CH_3COOH`

ANSWER :A
39.

Aquaregia is a mixture of

Answer»

`HCl +CH_(3)COOH`
`3HNO_3+HCl`
`H_(3)PO_(4)+H_(2)SO_(4)`
`3HCl + HNO_3`

Solution :Aqua-regia : 3 moles of CON. HCI + 1 mol of con. HNO,
40.

Aqua regia is a mixture of .......... .

Answer»

SOLUTION :CONC. `HNO_(3)` (1 part) + conc. HCL(3 parts)
41.

Aqua regia is

Answer»

`conc. HC + conc. HNO_3 in 1: 3 ratio`
`DIL. HCI and di.HNO_3 in 3:1 ratio`
`dil. HCT and dil. HNO_3 in 3:1 ratio`
`conc. HCl and conc. HNO_3 in 3 : 1 ratio`

Answer :D
42.

Aqua regia has the composition :

Answer»

1 PART CONC. `HNO_3 + 2` PARTS conc. HCI
1 part conc. `HNO_3 + 3` parts conc. HCI
1 part conc. `HNO_3` + 1 part conc. HCl
2 parts conc. `HNO_3 + 3` parts conc. HCI

Solution : 1 part conc. `HNO_3 + 3` parts conc. HCI
43.

Aqua regia a mixture of?

Answer»

`3:` ratio of conc HCl and Conc. `HNO_(3)`
`3:1` ratio of conc `HNO_(3)` and Conc. HCl
`1:3` ratio of conc HCl and CON. `HNO_(3)`
`1:3` ratio of conce HCl and conc .`H_(2)SO_(4)`

SOLUTION :Conceptual
44.

Aqua fortis is :

Answer»

`HNO_3`
`HNO_2`
`H_2NO_2`
`H_2N_2O_2`

ANSWER :A
45.

Aqueous solution of HCI conducts electricity because :

Answer»

It UNDERGOES ionisation
It associates
Forms HYDROGEN bonds
None

Answer :A
46.

Aq. Solutionof CH_3CH_2COONa on electrolysis gives propane. Is it true or false?

Answer»

SOLUTION :n-butane
47.

Aq solution contains Zn(CH_(3)COO)_(2) Cd(CH_(3)COO)_(2) and Cu(CH_(2)COO)_(2) on passing H_(2)Sgas there is precipitateof …….. As sulphide.

Answer»

`ZN^(2+),CD^(2+)`
`CU^(2+),Cd^(2+)`
`Zn^(2+),Cu^(2+)`
`Zn^(2+),Cu^(2+),Cd^(2+)`

ANSWER :d
48.

Aprotic solvent is :

Answer»

`CCl_4`
`C_6H_6`
`SO_2`
All of these

Answer :D
49.

Approximately what percentage of air by volume gets used in a process of combustion:

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`20%`
`10%`
`35%`
`55%`

ANSWER :A
50.

Approximately linearrelationship between the square roots of the frequencies of the X-raysemitted by a number of different elements and the atomic numbers was discovered by:

Answer»

Newland
Moseley
Dobereiner
Memdeleev

Answer :C