Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

Among LiCl , BeCl_2, Bcl_3 and C Cl_4 the covalent bond character follows the order :

Answer»

`LiClgtBeCl_2gtBCl_3gtC Cl_4`
`LiClltBeCl_2ltBCl_3ltC Cl_4`
`LiClltBeCl_2ltBCl_4gtBCl_3`
`LiClltBeCl_2ltBCl_3gtC Cl_4`

ANSWER :B
Discussion
2.

Among LiCl, BeCl_2, BCl_3 and C Cl_4, the covalent bond charater follows the order-

Answer»

`LICL LT BeCl_2 GT BCl_3 gt "CCl"_4`
`LiCl gt BeCl_2 lt BCl_3 lt "CCl"_4`
`LiCl lt BeCl_2 lt BCl_3 lt "CCl"_4`
`LiCl gt BeCl_2 gt BCl_3 gt "CCl"_4`

ANSWER :C
Discussion
3.

Among KO_(2),AlO_(2)^(-),BaO_(2)andNO_(2)^(+), unpaired electron is present in :

Answer»

`NO_(2)^(+)andBaO_(2)`
`KO_(2)andAlO_(2)^(-)`
`KO_(2)` only
`BaO_(2)` only

Answer :C
Discussion
4.

Among KO_(2), AlO_(2)^(-),BaO_(2) and NO_(2)^(+) unpaired electron is present in

Answer»

`NO_(2)^(+)` and `BaO_(2)`
`KO_(2)` and `AlO_(2)^(-)`
`KO_(2)`
`BaO_(2)` only

Solution :`NO_(2)^(+), BaO_(2)` and `AlO_(2)^(-)` have even number of electrons whereas `KO_(2)` has ODD number of electrons
Discussion
5.

Among isomeric o,m-and p-anisidines,_____is the weakest base.

Answer»

SOLUTION :m-anisidine.
Discussion
6.

Among isomeric amines possible for molecular formula C_(3)H_(9)N, correct order of basic strength is given by I) propanamine-1 II) N-methyl ethanamine III) N,N-dimethyl methanamine

Answer»

III GT I gt II 
IV gt III gt I gt II 
II gt I gt III 
II gt III gt I gt IV 

ANSWER :C
Discussion
7.

Among isomeric alkanes of molecular formula C_5H_12, identity the one that on photochemical chlorination yields 3 isomeric monochlorides

Answer»

SOLUTION :
Discussion
8.

Among HX. The maximum dipole moment is of :

Answer»

HF
HCL
HBr
HI

Answer :A
Discussion
9.

Among hypohalous acid the acid with highest Ka value is

Answer»

HIO
HFO
HClO
BrOH

Solution :GREATER ELECTRONEGATIVITY HFO do not EXIST
Discussion
10.

Among how many give positive Fe Cl_3 test.

Answer»

Solution :(I,II,III,IV,V,VI)
Discussion
11.

Among hexahalides of VIA group, the stable halides are

Answer»

HEXA IODIDES
hexa BROMIDES
hexa chlorides
hexa FLUORIDES

Answer :D
Discussion
12.

Among HCI, HNO_(3) and H_(2)SO_(4) which is the suitable medium for KMnO_(4) in oxidising reaction?

Answer»

SOLUTION :HCI and `HNO_(3)` cannot be used. HCl react with `KMnO_(4). HNO_(3)` is itself a good OXIDISING agent. HOWEVER, `H_(2)SO_(4)` is found to be most SUITABLE since it does not react with potassium permanganate.
Discussion
13.

Among halogens, the one which can oxidise water to oxygen is ……

Answer»

CHLORINE
BROMINE
FLUORINE
iodine

Answer :C
Discussion
14.

Among halogens maximum oxides are formed by

Answer»

Fluorine
Chlorine
Bromine
Iodine

Answer :B
Discussion
15.

Among halogens, fluorine is least reactive.

Answer»

Solution : Among HALOGENS. IODINE is LEAST REACTIVE.
Discussion
16.

Among halogens, F_(2) is the strongest oxidising agent. Or F_(2) is a strong oxidising agent in the 17th group.

Answer»

Solution :The standard electode potentials of halogens are :
`F_(2) + 2 E^(-) rarr 2 F^(-), E^(@) = + 2.87 V and Cl_(2) + 2E^(-) rarr 2 Cl^(-), E^(@) = + 1.36 V`
`Br_(2) 2e^(-) rarr 2 Br^(-), E^(@) = + 1.09 V and I_(2) + 2e^(-) rarr 2 I^(-), E^(@) = + 0.54 V`
Since `E^(@)` for `F_(2)//F^(-)` ELECTRODE is the maximum, `F_(2)` is REDUCED most readily. In other words, `F_(2)` is the stongest oxidising AGENT.
Discussion
17.

Among group 14 elements, name the most metallic element

Answer»

SOLUTION :Lead (METALLIC CHARACTER increases on GOING down the group).
Discussion
18.

Among formic acid and acetic acid, which is more acidic ? Givereason.

Answer»

Solution :Formic ACID
In ACETIC acid METHYL groupcauses + I EFFECT and DECREASES the acidity
OR
Other suitable explanation.
Discussion
19.

Among formaldehyde, acetaldehyde, benzaldehyde and formic acid, which compounds undergo Cannzzaro reaction? Give reason.

Answer»


ANSWER :FORMALDEHYDE and benzaldehyde UNDERGO CANNIZZARO reaction, Aldehydes which do not have `alpha` HYDROGEN undergo Cannizzaro reaction. Formaldehyde and benazaldehyde do not have `alpha` hydrogen.
Discussion
20.

Among following statements on the nitration of aromatic compounds, the false one is

Answer»

the rate of NITRATION of benzene is almost the same as that of hexadeuterobenzene
therate of nitration of toluene is greater than that of benzene
the rate of nitration of benzene is greater than that of hexadeuterobenzene
nitration is an electrophilic SUBSTITUTION reaction.

Solution :Rate determining step in the electrophilic substitution of benzene is the ATTACK of electrophile on benzene ring and not the breaking of `C - H` bond in benzene.
Discussion
21.

Among following statement, the incorrect one is

Answer»

calamine and SIDERITE are carbonates
argentite and CUPRITE are oxides
zinc blende and PYRITES are sulphides
malachite and AZURITE are ores of copper

Answer :B
Discussion
22.

Among following cations which are more stabilized than

Answer»


`CH_(3)-UNDERSET(H)underset(|)overset(* *)N-overset(o+)CH_(2)`
`CH_(3)-underset(CH_(3))underset(|)overset(CH_(3))overset(|)(C^(o+))`
`CH_(2)=CH-overset(o+)CH_(2)`

Solution :(a) is aromatic
(b) is stabilise because of coplete octet.
`3^(@)` cation is more stabilise than `1(@)` aromatic
Discussion
23.

Among following molecules, N-Si bond length is minimum in :

Answer»

`NH(SiH_3)_2`
`NH_2(SiH_3)`
`N(SiH_3)_3`
All have equal N-Si BOND LENGTH

Solution :
Because only ONE side where BACK bond possible .
Discussion
24.

Among following anions which are more stable than

Answer»

`CH_(2)=CH-OVERSET(Ɵ)CH_(2)`

`CH_(3)-overset(O)overset(||)C-overset(Ɵ)CH_(2)`

SOLUTION :
Discussion
25.

Among fluroine-fluorine bond andchlorie-chlorine bond, which is more stronger and why?

Answer»

Solution :In C-Cl bond, a filled p-orbital of chlorine can overlap with a SUITABLE vacant d-orbital of adjacent chlorine THEREBY introducing some double bond CHARACTER. Thus the bond strength INCREASES. This is not POSSIBLE in fluorine as it has got no vacant d-orbital.
Discussion
26.

Among F_((g))^(-),Cl_((g))^(-0),Br_((g))^(-) and I_((g))^(-),which one requires the highest amount of energy to remove an electron. Why?

Answer»

SOLUTION :`Cl_((G))^(-)`
Discussion
27.

Among ferrous and ferric ions, which one is more stable? Why?

Answer»

Solution :Electroini configuration of Fe(26) `: [Ar] 4s^2 3d^6` Ferrous ION `Fe^(2+) : [Ar] 4s^0 3d^6` Ferric ion `Fe^(2+) : [Ar]4s^0 3d^6` Ferric ion ISMORE STABLE than ferrous ion. This is because ferric ion has HALF filled d-subshell stable electronic configuration .
Discussion
28.

Among Fe, Cu, Al and Pb, which metal(s) cannot be obtained by smelting ?

Answer»


ANSWER :AL.
Discussion
29.

Among ethanol (I) , Acetic acid (II), Phenol (III) and Benzoic acid (IV) , the corret order of increasing acid strength is

Answer»

I LT II lt III lt IV
I lt III lt II lt IV
I lt III lt IV lt II
III lt IV lt I ltII

Answer :B
Discussion
30.

Among dimethylamine (I), aniline (II) and methylaniline (III), the increasing order of basic strength is

Answer»

`II lt III lt I`
`I lt III lt II`
`III lt I lt II`
`II lt I lt III`

Solution :DIMETHYLAMINE `(K_(b)=5.4 xx 10^(-4))`
Methyl amine `(K_(b)=4.5 xx 10^(-4))`
ANILINE `(K_(b)=4.2 xx 10^(-10))`
`:.` Correct ORDER of basic strength is Aniline `lt` Methylamine `lt` Dimethylamine
or `II lt III lt I`
Discussion
31.

Among different aliphatic amines correct order of basic strengths in vapour state is

Answer»

` 3^(@) GT 2^(@) gt 1^(@)`
` 1 ^(@) gt 2^(@) gt 3^(@)`
` 2^(@) gt 1^(@) gt 3^(@) `
` 3^(@) gt 1^(@) gt 2^(@) `

ANSWER :A
Discussion
32.

Among cuprous and cupric, which has more stable configuration? Why?

Answer»

Solution :Electronic configuration of `Cu^(+)` (cuprous) is `[Ar]3d^(10)` and of `Cu^(2+)` (cupric) is `[Ar]3d^(9)`
Cuprous has more stable configuration.
This isbecause `d^(10)` is COMPLETELY filled d-subshell. Due to SPHERICAL symmetry, it is more stable configuration:
Discussion
33.

Among complexes [Fe(H_(2)O)_(6))]^(3+)", [Fe(CN)_(6)]^(3-). [Fe(C_(2)O_(4))]^(3-), more stability is shown by

Answer»

`[Fe(H_(2)O)_(6)]^(3+)`
 `[Fe(CN)_(6)]^(2-)` 
`[Fe(P_(2)O_(4))_(3)]^(3-)`.
`[Fe(CI)_(6)]^(3-)`

Solution :Complex having more rings in structure will be more stable. Hence, (C) is the CORRECT answer.
Discussion
34.

Among Cu, Ag, Zn and Cd which one is the biggest atom? why?

Answer»

Solution :At the end of any SERIES atomic radius increases. THUS in between Cu and Zn, Zn is W BIGGER atom in between AG and Cd, Cd is the bigger atom.
In a GROUP from 3d- element to 4d- element atomic radius increase. Thus in between Zn and Cd, Cd is the bigger atom. So, among Cu, Ag, Zn and Cd, Cd is the biggest atom.
Discussion
35.

Among ClO^(-), ClO_(2)^(-), ClO_(3)^(-), ClO_(4)^(-) which one cannot disproportionate and why ?

Answer»

Solution :`ClO_(4)^(-)` cannot DISPROPORTIONATE because in this oxonation chlorine is present in its highest OXIDATION state. Remainingthree oxoanions undergo disproportionation because in these chlorine is in intermediate oxidation state.
`3overset((+1))(Cl)O^(-) overset(DELTA)rarr 2overset((+1))(Cl^(-)) + overset((+5))(Cl)O_(3)^(-), 6overset((+3))(Cl)O_(2)^(-) overset(h v)rarr 4overset((+5))(Cl)O_(3)^(-) + 2overset((-1))(Cl^(-)), 4overset((+5))(Cl)O_(3)^(-) rarr overset((-1))(Cl^(-)) + 3 overset((+7))(Cl)O_(4)^(-)`
Discussion
36.

Among Cl^-, Br^-, I^-, the correct order for being oxidise to dihalogen is

Answer»

`I^(-) GT CL^(-) gt BR^(-)`
`Cl^(-) gt Br^(-) gt I^(-)`
`I^(-) gt Br^(-) gt Cl^(-)`
`Br^(-) gt I^(-) gt Cl^(-)`

ANSWER :C
Discussion
37.

Among CH_4, NH_(3), and H_2O , acidity of H_2O is maximum becaues,

Answer»

Oxygen contain two LONE pair of electrons
Bond angle in water is less than `109^(0)28'`
Oxygen is more electronegative
Water is associated liquid

Answer :C
Discussion
38.

Among cellulose , poly(vinyl chloride) , nylon and natural rubber , the polymer in which the intermolecular force of attraction is weakest is

Answer»

Nylon
POLY(vinyl CHLORIDE)
CELLULOSE
Natural rubber

SOLUTION :Natural rubber has the weakest intermolecular forces of ATTRACTION.
Discussion
39.

Among cellulose, polyvinyl chloride, nylon and natural rubber, the polymer in which the intermolecular force of attraction is weakest is

Answer»

nylon
polyvinyl chloride
CELLULOSE
natural RUBBER

Solution :Nylon and cellulose, both have intermolecular hydrogen BONDING, polyvinyl chloride has dipole-dipole INTERACTIONS, while natural rubber has van der Waal forces which are WEAKEST.
Discussion
40.

Among cellulose, poly (vinyl chloride), nylon and natural rubber, the polymer in which the intermolecular force of attraction is weakest is

Answer»

Nylon 2-nylon 6 is a polyamide copolymer of alanine .
poly(VINYL CHLORIDE )
CELLULOSE
natural RUBBER .

Solution :Natual rubber has van der Waals forces, which are the weakest forces.
Discussion
41.

Among carbon and carbon monoxide which one is a better reducing agent for Fe_(2)O_(3),above 1000 K?

Answer»

SOLUTION :Above 1000 K carbon is BETTER reducing AGENT for `Fe_(2)O_(3)`.
Discussion
42.

Among CaH_(2),BeH_(2),BaH_(2), the order of ionic character is

Answer»

`BeH_2ltBaH_2 LT CaH_2`
`CaH_2ltBeH_2ltBaH_2`
`BeH_2ltCaH_2 ltBaH_2`
`BaH_2 lt BeH_2 lt CaH_2`

ANSWER :C
Discussion
43.

Which of the following is a colligative property

Answer»

SOLUTION :OSMOTIC PRESSURE is COLLIGATIVE property. The OTHERS are not colligative properties.
Discussion
44.

Among boron trifluoride, stannic chloride and stannous chloride, Lewis acid is represented by

Answer»

only stannic chloride
boron TRIFLUORIDE and stannic chloride
boron trifluoride and stannous chloride
only boron trifluoride

Solution :LEWIS acid is that COMPOUND which have electron deficiency. Eg. `BF_(3),SnCl_(2)`.
Discussion
45.

Among benzene and toluene, which one will undergo nitration reactions easily and why ?

Answer»

Solution :(i) If electron desnity of the benzene right increases, then reactivity of the ring towards electrophillic SUBSTITUTION also increases. In TOLUENE, `-CH_(3)` group increases the electron density of the ring and as a result, reactivity of the ring also increases due `+1` and hyperconjugation effect of `-CH_(3)` group. So, nitration occurs more easily for toluene than unsubstituted benzene
(ii) `{:(underset(A)(CH-=CNA) underset(1mol)overset(Na)larr CH-= CH underset(1% HgSO_(4), 80^(@)C)overset(dil H_(2)SO_(4))rarr underset(B)(CH_(3)CHO)),(underset("acetylide")("Monosodium") ""darrunderset(600^(@)C)("Red hot iron tune,") "Acetaldehyde"),(""underset(C)(""C_(6)H_(6)) overset(Fe//Cl_(2)(1 "mol"))rarr underset(D)(C_(6)H_(5)Cl)),("Benznechlorobenzene"):}`
A: Monosodium acetylide `(CH -= CNa)`
B: Acetaldehyde `(CH_(3)CHO)`
C: Benzene `(C_(6)H_(6))`, D: Chlorobenzene `(C_(6)H_(5)Cl)`
Discussion
46.

Among alpha-Nitroacetic acid (1) alpha-Fluoro Acetic Acid (2) , alpha-Fluoro Acetic Acid (2) , alpha- Bromoacetic acid (3) , alpha-Cyanoacetic acid (4) the correct order of increasing acid strength is

Answer»

`3 LT 2 lt 4 lt 1`
`1 lt 2 lt 3 lt 4`
`2 lt 1 lt 3 lt 4`
`4 lt 1 lt 2 lt 3`

ANSWER :A
Discussion
47.

Among alkali metal salts, the lithium salts are the poore conductors of electricity in aqueous solution because of

Answer»

easy diffusion of `LI^(+)` IONS
lower ABILITY of `Li^(+)` ions to polarize water molecules
lowest CHARGE to radius ratio
higher degree of hydration of `Li^(+)` ions

Answer :D
Discussion
48.

Among Al_(2)O_(3), SiO_(2),P_(2)O_(3) and SO_(2), the correct order of acid strength is :

Answer»

`Al_(2)O_(3)ltSiO_(2)ltSOI_(2)ltP_(2)O_(3)`
`SiO_(2)ltSO_(2)ltAl_(2)O_(3)ltP_(2)O_(3)`
`SO_(2)ltP_(2)O_(3)ltSiO_(2)Al_(2)O_(3)`
`Al_(2)O_(3)ltSiO_(2)ltP_(2)O_(3)ltSO_(2)`.

SOLUTION :HIGHER the oxidation state and higher the electronegativity, more ACIDIC is the oxide.
Discussion
49.

Among [Ag(NH_(3))_(2)]Cl, [Ni(CN)_(4))^(2-) and [CuCl_(4)]^(2-) which remains colourless in aqueous solutions and why ?

Answer»

SOLUTION :`[Ag(NH_(3))_(2)]Cl` remains colourless in aqueous solution because `Ag^(+)` has no UNPAIRED ELECTRON, therefore, it cannot undergo d-d transition.
`[Ni(CN)_(4)]^(2-)` ALSO remains colourless as it does not have unpaired electrons.
Discussion
50.

Among alcohols and phenols which one is more acidic ? And why ?

Answer»

Solution :PHENOLS are more acidic than alcohols. This is because the phenoride ION FORMED from the ionisation of PHENOL is STABILISED by resonance.
Discussion