Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

Among [Ag(NH_(3))_(2)]Cl, [Ni(CN)_(4))^(2-) and [CuCl_(4)]^(2-) which has square planar geometry ?

Answer»

SOLUTION :`[NI(CN)_(4)]^(2-)` has square PLANAR geometry.
2.

Among acetic acid , phenol and n-hexanol, which of the compounds will react with NaHCO_3 solution to give sodium salt and CO_2

Answer»

ACETIC ACID
phenol
n-hexanol
acetic acid and phenol

Answer :A
3.

Among 3d-, 4d- and 5d- series elements, which elements hasthe least and which has the highest I_(l)?

Answer»

Solution :Among first three SERIES of d-block, first ionisation energy is LEAST for LANTHANUM and is highest for MERCURY.
4.

Among 1M solution of glucose , NaCl, FeCl_3, CaCl_2, which one has the (a) highest boiling point (b) lowest boiling point ?

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SOLUTION :(a) `FeCL_3sol^@` (B) GLUCOSE solution .
5.

Among 1% solutions of urea. Glucose and sucrose

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the vapour PRESSURE and freezing point are the LOWEST for UREA
the vapour pressure and BOILING point are the lowest for urea
the depression in freezing point is the highest for urea
the elevation in boiling point is the highest for urea

Answer :A::C::D
6.

Amolal solution is one that contains 1 mole of a solute in

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1000 G of the SOLVENT
ONE LITRE of the solvent
one litre of the solution
22.4 litres of the solution

Answer :A
7.

Among 1% solution of urea, glucose and sucrose

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the vapour PRESSURE and freezing point are the lowest for urea
the vapour pressure and BOILING point are the lowest for urea
the DEPRESSION in freezing point is the highest for urea
the elevation in boiling point is the highest for urea.

Answer :A::C::D
8.

Ammonolysis of hydroxyl compounds is called ………………… reaction.

Answer»


ANSWER :SABATIER -mailhe
9.

Ammonolysis of methyl chloride can be used to obtain pure methylamine.

Answer»


ANSWER :F
10.

Ammonta has higher boiling point than expected because :

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1. It FORMS `NH_(4)OH` with WATER
2. its density decreases on freezing
3. it has strong intermolecular covalent BONDS
4. it has strong intermolecular hydrogen bonds.

SOLUTION :The higher boiling point of ammonia is because of strong intermolecular hydrogen bonds.
11.

Ammonolysis of alkyl halides to give amines is an example of_____reactions.

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SOLUTION :NUCLEOPHILIC SUBSTITUTION
12.

Ammonolysis of an ester gives,

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AMINE
AMIDE
Uride
None

Answer :B
13.

Ammonium sulphide and ammonium selenide onheating dissociates as (NH_4)_2S_((s)) hArr 2NH_(3(g)) + H_2S_((g)) , K_(p_1) = 9xx10^(-3) "atm"^3 (NH_4)_2Se_((s)) hArr 2NH_(3(g)) + H_2Se_((g)), K_(p_2) = 4.5xx10^(-3) "atm"^3 The total pressure over the solid mixture at equilibrium is

Answer»

<P>0.15 atm
0.3 atm
0.45 atm
0.6 atm

Solution :`(NH_4)_2Se_((s)) hArr UNDERSET(2p)(2NH_(3(G)))+underset"p"(H_2S_((g)))`
`(NH_4)_2Se_((s)) hArr underset"2q"(2NH_(3(g))) + underset"q" (H_2Se_((g)))`
`K_(p_1)=(p_(NH_3))^2 .p_(H_2S)=(2p+2q)^2. p=9.0xx10^(-3)`
`K_(p_2)= (p_(NH_3))^2. p_(H_2Se) = (2p+2q)^2. q= 4.5xx10^(-3)`
`therefore p/q=2 RARR p=2q`
`therefore K_(p_1)=(2p+p)^2 . p = 9.0xx10^(-3)`
`therefore` p=0.1 atm and `q=0.1/2`=0.05
Total pressure = 2p+2q+p+q=3p+3q
= 3 x 0.1 + 3 x 0.05 = 0.45 atm
14.

Ammonium salts decompose quite readily on heating : (i) Ammonium salt of weak oxidizing anion (e.g. Cl^(-), CO_(3)^(2-), SO_(4)^(2-)) overset("heat")rarr Gas X (ii) Ammonium salt of strong oxidizing anion (e.g. NO_(2)^(-), NO_(3)^(-), CiO_(4)^(-), Cr_(2)o_(7)^(2-) overset("heat")rarr Gas Y/Z Identify X, Y, Z

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`N_(2), NH_(3), N_(2)O`
`NH_(3), N_(2), N_(2)O`
`N_(2)O, NH_(3), N_(2)`
`NO, NH_(3), N_(2)O`

Answer :B
15.

Ammonium salt of bezoic acid is heated strongly with P_2O_5 and the product so formed is reduced and then treated with NaNO_2"/"HCl at low temperature. The final compound formed is

Answer»

BENZENE DIAZONIUM chloride
Benzyl alcohal
Phenol
Nitrosobenzene

Answer :B
16.

Ammonium salt of benzoic acid isheated strongly and the product so formed is reduced and then treated with NaNO_(2)//HCl at low temperature. The final compound formed is …………

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Benzene diazonium chloride
Benzyl alcohol
Phenol
Nitrosobenzene

Solution :`C_(6)H_(5)COONH_(4)underset("Heat")OVERSET(P_(2)O_(5))(to)C_(6)H_(5)-C-=Noverset(LiAlH_(4))(to)C_(6)H_(5)CH_(2)NH_(2)overset(HNO_(2))(to) C_(6)H_(5)CH_(2)OH`
17.

Ammonium salt are oxidised in the soil to nirites by:

Answer»


ANSWER :B
18.

Ammonium persulphate solution on heating under reduced pressure gives :

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`H_2O_2`
`O_2`
`H_2`
`(NH_4)_2SO_4`

ANSWER :A
19.

Ammonium nitrate on heating gives

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NO
`N_(2)`
`N_(2)O`
`N_(2)O_(4)`

ANSWER :3
20.

Ammonium molybdate test is used for the estimation of :

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`PO_(4)^(3-)`
`NO_(3)^(-)`
`SO_(3)^(2-)`
`SO_(4)^(2-)`

ANSWER :A
21.

Ammonium molybdate is used to test the radical

Answer»

`PO_(4)^(3-)`
`AsO_(4)^(3-)`
`Cu^(2+)`
`AG^(o+)`

Solution :Both `PO_(4)^(3-) and AsO_(4)^(3-)` GIVE yellow ppt with ammonium molybdate
22.

Ammonium ion is

Answer»

neither an acid nor BASE
both an acid and a base
a conjugate acid
a conjugate base

Solution :Acid`hArr`conjugate base`+H^(o+)`
`NH_(4)^(+)hArrNH_(4)+H^(+)`
Ammonium ion is a conjugate acid.
23.

Ammonium hydroxide is a weaker base because it is :

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UNSTABLE
COVALENT COMPOUND
only SLIGHTLY ionises
none of these.

Answer :C
24.

Ammonium hydroxide is a weak base because

Answer»

It has low VAPOUR pressure
It is only slightly IONIZED
It is not a HYDROXIDE of any metal
It has low density

Solution :It is WEAK electrolyte since slightly ionized.
25.

Ammonium hydrogen sulfide dissociates as follows NH_4HS(s) hArr H_2S(g) +NH_3(g) if solid NH_4 HS is placed in an evacuated flask at a certain temperature, it will dissociate until the total gas pressure is 500 torr. Calculate the following. (a) Equilibrium constant for the dissociation reaction (b) if the additional NH_3 is introduced into the equilibrium mixture without change in temperature until the partial pressure of ammonia is 700 torr. (i) Whatis the partial pressure of H_2O under these conditions (ii) What is the total pressure in the flask ?

Answer»


ANSWER :0.329 ATM
(a) `0.108 atm^2`
(b) 0.117 atm
(ii) 789 TORR
26.

Ammonium hydrogen sulphide dissociates as follows : NH_(4) HS(s) hArr H_(2) S(g) = NH_(3)(g) If solid NH_(4) HS is placed in an evacuated flask at a certain temperature, it will dissociate until the total gas pressure is 500 torr. Calculate the following : ( a) Equilibrium constant for the dissociation reaction ( b) If the additional NH_(3) is introduced into the equilibrium mixture without change intemperature until the partial pressure of ammonia is 700 torr. (i) What is the partial pressure of H_(2)S under the conditions. (ii) What is the total pressure in the flask ?

Answer»

<P>

Solution :SINCE, `P_(H_(2)S)= P_(NH_(3)) = ( 250)/( 760) = 0.329 `atm
( a) `K_(p ) =P_(H_(2)S) P_(NH_(3)) = 0 .108"atm"^(2)`
( b) `K_(p ) = P_(H_(2)S ) P_(NH_(3))`
`P_(H_(2)S) = ( 0.108)/( 700 // 760 ) = 0.117` atm
(ii)Total pressure `= P_(H_(2) S) + P_(NH_(3)) = 789 ` torr
27.

Ammonium formate on heating yields:

Answer»

Ammonia
Formamide
Formic ACID
AMMONIUM CARBONATE

ANSWER :B
28.

Ammonium dichromate is used in some fireworks. The green coloured powder blown is:

Answer»

`CrO_3`
`Cr_2O_3`
CR
`CRO(O_2)`

ANSWER :B
29.

Ammonium dichromate is used in fireworks. The green coloured blown in air is :

Answer»

`CrO_(3)`
`Cr_(2)O_(3)`
CR
`CrO(O)_(2)`

Solution :`(NH_(4))_(2)Cr_(2)O_(7) to Cr_(2)O_(3) + Cr_(2)O_(3) + N_(2) + 4H_(2)O`
30.

Ammonium cyanide is a salt of NH_(4)OH(K_(b)=1.8xx10^(-5)) and HCN (K_(a)=4.0xx10^(-10)). The hydrolysis constant of 0.1 M NH_(4)CN at 25^(@)C is :

Answer»

`1.4`
`7.2xx10^(-15)`
`7.2xx10^(-1)`
`1.4xx10^(-6)`

SOLUTION :`K_(H)=(K_(w))/(K_(a)xx K_(b))`
`=(1xx10^(-14))/(4.0xx10^(-10)xx1.8xx10^(-5))=1.4`
31.

Ammonium compound which upon heating does not give ammonia is :

Answer»

`(NH_(4))_(2)SO_(4)`
`(NH_(4))_(2)CO_(3)`
`NH_(4)NO_(2)`
`NH_(4)Cl`

SOLUTION :`NH_(4)NO_(2)overset("HEAT")to N_(2)+2H_(2)O`
32.

Ammonium chloride,when dissolved in water , leads to a cooling sensation . The dissolution of ammonium chloridae at constant temperature is accompanied by q

Answer»

increases in entropy
decreases in entropy
no CHANGE in entropy
no change in enthalpy

Solution :in dissolution , SOLID CHANGES to ions in solution , which have more RANDOMNESS
33.

Ammonium compound not used as a fertilizer is

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`(NH_4)_2SO_4`
`(NH_4)_2CO_3`
`NH_4NO_3`
`CAN ( CALCIUM AMMONIUM NITRATE )`

ANSWER :B
34.

Ammonium chloride is removed from its mixture by:

Answer»

Filtration
Distillation
Sublimation
A magnet

Answer :C
35.

Solid Ammonium carbamate dissociates as: NH_(2)COONH_(4)(s)hArr2NH_(3)(g)+CO_(2)(g). In a closed vessel, solid ammonium carbonate is in equilibrium with its dissociation products. At equilibrium, ammonia is added such that the partial pressure of NH_(3) at new equilibrium now equals the original total pressure. Calculate the ratio of total pressure at new equilibrium to that of original total pressure. Also find the partial pressure of ammonia gas added.

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`(27)/(31)`
`(31)/(27)`
`(4)/(9)`
`(41)/(9)`

ANSWER :B
36.

Ammonium cations can be detected using the complex

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`[Cu(NH_3)_4]^(2+)`
`[HgI_4]^(2-)`
`[AG(CN)_2]^-`
`[HgI_2]`

Answer :B
37.

Ammonium carbamate when heated to 200^(@)C gives a mixture of NH_(3) and CO_(2) vapours with a density of 16.0. What is the degree of dissociation of ammonium carbamate? (Given vapour density of ammonium carbamate is 48)

Answer»

`3//2`
`1//2`
2
1

Solution :`{:(,NH_(2)COONH_(4),rarr,2NH_(3),+,CO_(2)),("Initial","1 MOLE",,,,),("After disso.",1-alpha,,2alpha,,alpha):}`
Total = `1+2alpha`
THEORETICAL, density `(d)prop(1)/((1+2alpha)V)`
`THEREFORE (D)/(d)=1+2alpha`
or, `alpha=(1)/(2)((D-d)/(d))=(1)/(2)((48-16.0)/(16.0))=1.0`
38.

Ammonium carbamate is :

Answer»

`(HN_4)_2CO_3`
`NH_4COONH_2`
`NH_2CONH_2`
`HCOONH_4`

ANSWER :B
39.

Ammonium carbamate dissociates on heating as: NH_(2)COONH_(4)(g)hArr2NH_(3)(g)+CO_(2)(g) The equilibrium constant K_(p) for the reaction, at some temperature is 3.2xx10^(-5)atm^(3). Calculate the partial pressure of NH_(3) in the equilibrium system at the same temperature.

Answer»

<P>`2.0xx10^(-2)atm`
`4,0xx10^(-2)atm`
`3.2xx10^(-2)atm`
`6.4xx10^(-2)` atm

SOLUTION :`NH_(2)COONH_(4)(s)hArrunderset(2p)(2NH_(3)(G))+UNDERSET(p)(CO_(2)(g))`
`K_(p)=P_(NH_(3))^(2)xxp_(CO_(2))=(2p)^(2)xx=3.2xx10^(-5)atm^(3)`
`impliesp=2xx10^(-2)atm,""p_(NH_(3))=2xx2xx10^(-2)atm`
40.

Ammonium bydrogen sulfied, NH_(4)HS is unstable at room temperature and decomposes as : NH_(4)HS (s) hArr NH_(3) (g) + H_(2)S (g) Then which of the following will produce less H_(2)S (g) :

Answer»

Removing some of `NH_(3)` form flask.
Removing some of `NH_(4)HS (s)`.
On increasing pressure by DECREASING volume
Increasing TEMPERATURE.

Solution :(1) Removing product will shift EQUILIBRIUM forward.
(2) Adding or removing a SOLID doesn't effect equilibrium
(4) Decomposition reactions are endothermic in nature, increasing temperature will shift equilibrium forward.
41.

Ammonium acetate which is 0.01 M , is hydrolysed to 0.001 M concentration . Calculate the change in pH in 0.001 M solution , if initially pH = pK_(a)

Answer»

5
10
100
1

Solution :`CH_(3)COO^(-)+NH_(4)^(+)+H_(2)O hArr CH_(3)COOH+NH_(4)OH`
`{:("Initial",0.01M,0.01M,(0.01-0.001)M,(0.01-0.001)M),("At eqm.",0.001M,0.001M,=0.009M,=0.009M):}`
`K_(h)=([CH_(3)COOH][NH_(4)OH])/([CH_(3)COO^(-)][NH_(4)^(+)])=((0.009)^(2))/((0.001)^(2))=10^(2)`
`K_(h)=(K_(W))/(K_(a) xx K_(b))`
`:. K_(b)=(K_(w))/(K_(a)xxK_(h))=(10^(-14))/(K_(a)xx 10^(2))=(10^(-16))/(K_(a))`
`[H^(+)]=sqrt((K_(a)xxK_(w))/(K_(b)))=sqrt((K_(a)xx10^(-14))/(10^(-16)//K_(a)))=10K_(a)`
`(pH)_("Initial")=pK_(a)`
`(pH)_("Final")=-log[H^(+)]=-log(10K_(a))=pK_(a)-1`
Change in pH `=(pH)_("Final")-(pH)_("Inital")`
`=pK_(a)-1-pK_(a)= -1`
42.

Ammonium acetate reacts with acetic acid at 110^(@)C to give

Answer»

Urea
Formamide
ACETIC ANHYDRIDE
ACETAMIDE

ANSWER :D
43.

Ammonical cuprous chloride will give red precipitate with which one of the following

Answer»

`CH_3-C-=C-CH_3`
`CH_3-CH=CH_2`
`CH_3-C-=CH`
`CH_3-CH=CH-CH_3`

ANSWER :C
44.

Ammonium acetate on heating gives :

Answer»

Acetamide
Acetic anhydride
Acetaldehyde AMMONIA
Acetic acid and ammonia .

Solution :`CH_(3)COONH_(4)overset("Heat")tounderset("Acetamide")(CH_(3)CONH_(2))`
45.

Ammonical AgNO_(3) gives white ppt after with any compound then this reflects the presence of

Answer»

One-`CHO` group
One triple bond
A terminal ALKYNE
Compound is unsaturated

Solution :Terminal alkyne give `AgNO_(3)` (Ammonical) test.
46.

Ammonical CuCl absorbs :

Answer»

`CO_2`
`SO_2`
`H_2SO_4`
`CO`

ANSWER :D
47.

Ammonium and phosphate resemble each other in:

Answer»

SOLUBILITY in water
forming SALT with acid
stability
reducing character

Answer :B
48.

Ammoniacal solution of MgSO_(4) in presence of NH_(4)Cl is heated with Na_(2)HPO_(4), a white precipitate is formed of

Answer»

`Mg(NH_(4))PO_(4)`
`Mg_(3)(PO_(3))_(2)`
`MgSO_(4)*MgCl_(2)`
`MgSO_(4)*MgPO_(4)`

ANSWER :A
49.

Ammoniacal solution of silver nitrate is known as _____.

Answer»

SOLUTION :Tollen.s REAGENT
50.

Ammonia undergoes self dissociation according to the reaction 2 NH_(3(l)) hArr NH_(2(am))^(+)+NH_(2(am))^(-)where am, stands for ammoniated. When 1 mol of NH_(4) CI is dissolved in 1 kg of liquid ammonia, the b.p. at 760 torr is observed as -32.7^(@)C (normal boiling b.p. of NH_(3(l)) is 33.4^(@)C). What conclusion is reached about the nature of thesolution

Answer»

`NH_(4)` CI is completely dissociated in `NH_(3)`
`NH_(4)` CI is partially dissociated in `NH_(3)`
`NH_(4)`CI is not dissociated in `NH_(3)`
BOILING POINT is not raised

Solution :`NH_(4)Cl` is a STRONG acid in liq. `NH_(3)`. SINCE, it ionizes to give `NH_(4)^(+)` (which is cation of the the SOLVENT).
`NH_(4)Cl hArr NH_(4)^(+)+Cl^(-)`