Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

Ammonia water is a good cleaning agent because it:

Answer»

is WEAKLY basic
emulsifies grease
leaves no RESIDUE when WIPED out
all are true

Answer :D
Discussion
2.

Ammonia was first prepared by:

Answer»

Lavoisier
Priestley
Scheele
Cavendish

Answer :B
Discussion
3.

Ammonia reacts with oxygen according to the equation : 4NH_(3)(g)+5O_(2)(g)rarr4NO(g)+6H_(2)O(l) In an experiment in which the rate of change of nitric oxide is found to be 1.10"M=-min"^(-1), what is the rate of change of oxygen gas?

Answer»

`-1.38 "M.min"^(-1)`
`-0.880 "M.min"^(-1)`
`-0.275 "M.min"^(-1)`
`-0.220 "M.min"^(-1)`

ANSWER :A
Discussion
4.

Ammonia reacts with Nessler's reagent to a brown ppt known as Millon's base. This base is believed to have the structure

Answer»





SOLUTION :STRUCTURE of Millon.s BASE.
Discussion
5.

Ammonia reacts with excess of chlorine to give

Answer»

`NH_(4)Cl`
`Cl_(2)`
`NCl_(3)`
`NCl_(5)`

ANSWER :C
Discussion
6.

Ammonia reacts with excess of chlorine to form:

Answer»

`N_2` and `NH_4Cl`
`NCl_3` and HCL
`NH_4Cl` and `NCl_3`
`N_2` and HCl

Answer :B
Discussion
7.

Ammonia reacs with ____ to form urotropine.

Answer»

SOLUTION :FORMALDEHYDE.
Discussion
8.

Ammonia reacts with excess of chlorine to form

Answer»

`N_(2) and HCL`
`NH_(4)CL and NCl_(3)`
`NCl_(3) and HCl`
`N_(2) and NH_(4)Cl`

Solution :`NH_(3)+3Cl_(2)toNCl_(3)+3HCL`
Discussion
9.

Ammonia prepared by treating ammonium sulphate with calcium hydroxide is completely used NiCl_2.6H_2O to form a stable coordination compound. Assume that both the reactions are 100% complete. If 1584 g of ammonium sulphate and 952 g of NiCl_2.6H_2O are used in the preparation, the combined weight (in grams) of gypsum and the nickel - ammonia coordination compound thus produced is _____. (Atomic weights in g mol^(-1) : H=1,N=14,O=16 , S=32, Cl=35.5 , Ca=40 , Ni=59)

Answer»


ANSWER :2992
Discussion
10.

Ammonia on reaction with hypochlorite anion can form

Answer»

`NO`
`NH_4Cl`
`N_2H_4`
`HNO_2`

Solution :
CHLORAMINE is FORMED in the REACTION which DECOMPOSES HYDRAZINE to `NH_4CI`
Discussion
11.

Ammonia , on reaction with excess of chlorine, gives

Answer»

`NCl_(3)` and HCl
`N_(4)` and `NH_4Cl`
`H_(3)P_(4)`
`P_(2)O_(5)`

Solution :`NH_(3)+3Cl_(2) to NCl_(3)` is an explosive material.
Discussion
12.

Ammonia on heating with carbon dioxide under pressure gives:

Answer»

`NH_4HCO_3`
`(NH_4)_2CO_3`
`NH_2COONH_4`
`(NH_2)_2CO`

ANSWER :C
Discussion
13.

Ammonia on heating with hypochlorite anion can form

Answer»

NO
`NH_(2)CL`
`N_(2)H_(4)`
`HNO_(2)`

SOLUTION :`NaCl + K_(2) Cr_(2) O_(7) rarr CrO_(2) Cl_(2) + NaHCrO_(4) + K_(2) SO_(4) + H_(2)O`
Discussion
14.

Ammonia (NH_(3)) when treated with 'Nessler's reagent in the presence of an alkali gives a brown precipitate of

Answer»

 `NH_4Hgl_4`
`NH_2HgOHgl`
KI
 `(NH_4)_2Hgl_4`

ANSWER :B
Discussion
15.

Ammonia (NH_(3)) obttained from different sources always has same proportion of Nitrogen and Hydrogen. It proves the vakidity of low of :

Answer»

RECIPROCAL proportion
Constant proportion
Multiple proportions
None of the above

Solution :Ammonia`(NH_(3))` obtainedfromdifferentsources alwayshas sameproportion of NITROGENAND Hydrogenand itprovesthe validityof lawof constantproportion.
Discussion
16.

Ammonia molecule is:

Answer»

A nucleophile
An electrophile
A homolytic
An acid

Answer :A
Discussion
17.

Aniline is less basic than ammonia

Answer»


ANSWER :T
Discussion
18.

Ammonia is generally manufactured for fertilizers by the reaction:

Answer»

`2NH_4Cl + Ca(OH)_2 RARR CaCl_2 + 2H_2O + 2NH_3`
By passing an electric discharge in a mixture of `N_2` and `H_2`
By REDUCING the byproduct NITRIC acid
By passing a mixture of `N_2` and `H_2` under high pressure and moderate temperature over a catalyst

Answer :D
Discussion
19.

Ammonia is always added in this reaction. Which of the following must be incorrect

Answer»

`NH_(3)` combines with `Ag^(+)` to form a complex
`Ag(NH_(3))_(2)^(+)` is a stronger oxidising reagent than `Ag^(+)`
In absence of `NH_(3)` silver SALT of gluconic acid is formed
`NH_(3)` has affected the standard REDUCTION potential of glucose/gluconic acid electrode

Solution :Ammonia has no effect on the standard reduction potential.
Discussion
20.

Ammonia is always added in this reaction. Which of the following must be incorrect?

Answer»

`NH_(3)` combines with `Ag^(+) ` to from a complex
`Ag((NH_(3))_(2)^(+)` is a weaker oxidizing reagent than `Ag^(+)`
In the ABSENCE of `NH_(3)` silver SALT of gluconic acid is formed electrode

SOLUTION :`NH_3` has no effect on the standard REDUCTION potential.
. The potential difference developed between metal electrode and the solution of its ions of unity molarity ( 1 M) at `25^(@)` C is called standard electrode potential.
. The standard reduction potential of an electrode means that reduction reaction is taking PLACE at the electrode.
Discussion
21.

Ammonia is a weak base that reacts with water according to the equation: NH_3(aq) +H_2O(I)

Answer»

ADDITION of HCI
Addition of H_2O
Addition of NaOH
Addition of NH_4CI

Answer :C
Discussion
22.

Ammonia is:

Answer»

POLAR solvent
Non-polar
Paramagnetic
None

Answer :A
Discussion
23.

Ammonia gas when passed through Nessler's reagent , forms a brown precipitate which corresponds to :

Answer»

`K_2[HgI_4]`
`NH_2HgOHgI`
`HgI_2`
`NH_2HgO`.

SOLUTION :`2K_2HgI_4 + NH_3 + 3KOH to H_2N HGO. HGI +7KI + 2H_2O`
Discussion
24.

Ammoniagasdoesnot evolvefromthe complexFeCl_(2).4NH_(3)Butitgiveswhite precipitate withaqueoussolutionof AgNO_(3). Coordinationnumberofcentralnameof thecomplexwillbe .

Answer»

Ammonium trichloro triamineiron(III )
Tetraamineiron(III )CHLORIDE
Dichlorido tetraamineiron(II )chloride
Dichlorido tetraamineiron(III )chloride

Solution :Dichloridotetraamineiron(III )chloride.
`[Fe(NH_(3))_(4)Cl_(2)]Cl`
Discussion
25.

Ammonia gas is dried over

Answer»

Quick lime
Conc `H_(2)SO_(4)`
`P_(2)O_(5)`
HCl

ANSWER :1
Discussion
26.

Ammonia gas dissolves in water to give NH_(4)OH. In this reaction water acts as

Answer»

An acid
A base
A salt
A conjugate base

Solution :`H_(2)O` acts as acid as it PROVIDES `H^(+)` to `NH_(3)`.
Discussion
27.

Ammonia gas dissolves in water to give NH_4OH In this reaction water act as :

Answer»

a base
an acid
a salt
a CONJUGATE base

Answer :B
Discussion
28.

The complex ion [Cu(NH_(3))_(4)]^(2+) has :

Answer»

In ACIDIC solutions hydration protects copper ions
In acidic solutions protons coordinate with ammonia MOLECULES forming `NH_4^(+)`ions and `NH_3` molecules are not available
In alkaline solutions INSOLUBLE `Cu(OH)_2` is precipitated which is SOLUBLE in excess of any alkali
Copper hydroxide is an AMPHOTERIC substance.

Answer :B
Discussion
29.

Ammonia forms the complex ion [Cu(NH_3)_4]^(2+)with copper ions in alkaline solutions but not in acidic solutions. The reason is

Answer»

In acidic SOLUTIONS hydration protects copper ions
In acidic solutions protons coordinate with ammonia molecules forming `NH_4^+`ions and `NH_3` molecules are not available
In ALKALINE solutions insoluble `Cu(OH)_2` is precipitated which is SOLUBLE in excess of any alkali
Copper hydroxide is an AMPHOTERIC substance.

Answer :B
Discussion
30.

Ammonia forms the complex ion, [Cu(NH_(3))_(4)]^(2+) with copper ions alkaline solutions but not in acidic solution. This is because

Answer»

in acidic solutions, protons COORDINATE with ammonia molecules forming `NH_(4)^(+)` IONS and `NH_(3)` molecules are THUS, not available
in alkaline solutions, insolube `Cu(OH)_(2)` is precipitated which is an soluble in EXCESS of any alkali
copper hydroxide is an amphoteric substance
in acidic solutions, hydration protects copper ion.

Solution :In acidic solution, `NH_(3)` forms a coordinate bond with `H^(+)` to form `NH_(4)^(+)` ion which does not have a lone pair of electrons on N to act as a ligand.
Discussion
31.

Ammonia forms the complex [Cu(NH_3)_4]^(2+) with copper ions in alkaline solution but not in acid solution. The reasons for it is:

Answer»

In alkaline solution `Cu(OH)_(2)` is precipitated which is soluble in excess of alkali
Copper hydroxide is AMPHOTERIC substance
In ACIDIC solution hydration protects `Cu^(2+)` ions
In acidic solution protons are COORDINATED with AMMONIA MOLECULES forming `NH_(4)^(+)` ions

Answer :D
Discussion
32.

Ammonia forms the complex [Cu(NH_(3))_(4)]^(2+) with copper ions in alkaline solution but not in acid solution. The reason for it is :

Answer»

in alkaline solution `Cu(OH)_(2)` is precipitated which is soluble in EXCESS of alkali.
copper HYDROXIDE is amphoteric.
in acidic solution hydration protects `Cu^(2+)` IONS.
in acidic solution protons coordinates with ammonia MOLECULES are not forming `NH_(4)^(+)` ions and `NH_(3)` molecules are not available.

Answer :D
Discussion
33.

Ammonia forms the complex [Cu(NH_(3))_(4)]^(2+) will copper ions in alkaline solution but not in acidic solution. The reason for this is

Answer»

In alkline solution `Cu(OH)_(2)` is precipitated which is soluble in exces of alkali
Copper hydroxide is amphoteric substance
in acidic solution hydration protects `Cu^(2+)` ions.
In acidic solution PROTONS are coordinated with ammonia molecules forming `NH_(4)+^(+)` ion.

Solution :`Cu^(2+)(aq)+4NH_(3)overset(OH^(-)) HARR [Cu(NH_(3))_(4)]^(2+)`
`Cu^(2+)(aq)+4NH_(3) overset(OH^(+))hArr Cu^(2+)+4NH_(4)^(+)` (No complex formation)
As `NH_(3)` combines with `H^(+)` of ACID and changes to `NH_(4)^(+)` which have no DONOR site.
Discussion
34.

Ammonia form the complex ion[Cu(NH_(3))_(4)]^(2+) with copper ions inthe alkaline solution but not In acidic solution. What is the statement-2 for it?

Answer»

In acidic solution hydration PROTECT copper ions
In acidic solution protons co-ordinate with ammonia molecules forming `NH_(4)^(+)` ion and `NH_(3)` molecules are not available
In ALKALINE solution insolution `CU(OH)_(2)` is PRECIPITATED which is soluble in excess of any alkali
Copper hydroxide is an amphoteric substance.

Solution :The pair of electrons PRESENT with nitrogen will not be available to bedonates as `H^(+)` will consumed that one.
Discussion
35.

Ammonia contains 82.35% of nitrogen and 17.65% of hydrogen. Water contains 88.90% of oxygen and 11.10% of hydrogen. Nitrogen trioxide contains 63.15% of oxygen and 36.85% of nitrogen. Show that these data illustrate the law of receprocal proportions.

Answer»

Solution :In `NH_(3), 17.65` g of H combine with N = 82.35 g
`therefore"1 g of H combine with N"=(82.35)/(17.65)g=4.67g`
In `H_(2)O,11.10g` of H combine with O = 88.90 g
`therefore" 1 g of H combine with O"=(88.90)/(11.10)g=8.01g`
`therefore"Ratio of the masses of N and O which combine with FIXED mass(= 1 g) of H "=4.67:8.01=1:1.72`
In `N_(2)O_(3)`, ratio of masses of N and O which combine with each other = `36.85:63.13=1:1.71`
THUS, the two ratios are the same. HENCE, it illustrates the law of reciprocal proportions.
Discussion
36.

Ammonia contains 82.32% of nitrogen and 17.65 % of hydrogen . Water contains 88.90% of oxygen and 11.10% of hydrogen . Nitrogen trioxide contains 63.15% of oxygen and 36.85% of nitrogen. Show that these data illustrate the law of reciprocal proportions.

Answer»

Solution :In `NH_(3), 17.65 g` of H combine with N=82.35 g
`therefore` 1 g of H combine with H`=(82.35)/(17.65) g` =4.66 g
In `H_(2)O, 11.10 g` of H combine with O=88.90 g
`therefore` 1 g of H combine with `O=(88.90)/(11.10)` g =8.00 g`
`therefore Ratio of the weight of N and O which combine with fixed weight (=1g) of H=4.66:8.00=1:1.7 In `N_(2)O_(3)` , ratio of weigths of N and O which combine with each other =36.85:63.15:1:1.7 THUS the two ratios are the same. Hence it illustrate the LAW of reciprocal protortions.
Discussion
37.

Ammonia canot be dried by

Answer»

`H_(2)SO_(4)`
`P_(2)O_(5)`
`CaO`(ANHYD.)
`CuSo_(4)`

Answer :A::B::D
Discussion
38.

Ammonia chloride when heated with caustic soda gives ammonia gas. What weight of NH_4Cl should be used to get 2460 Ml. NH_3 at 1 atm pressure 827^@ C .

Answer»


ANSWER :5.35g
Discussion
39.

Ammonia cannot be dried over anhydrous calcium chloride. Why?

Answer»

Solution :When water is ABSORBED by calcium chloride, it undergoes HYDROLYSIS to GIVE HYDROCHLORIC acid.
`CaCl_(2)+2H_(2)O to Ca(OH)_(2)+2HCl`
Sinceammonia is basic, it is neutralisedby HCl to give salt.
`NH_(3)+HCl to NH_(4)Cl`.
Hence ammonia is dried over a basic oxide, quick lime.
Discussion
40.

Ammonia and red hot CuO react to produce :

Answer»

`Cu_(2)O,N_(2),H_(2)`
`CU,H_(2)O,N_(2)`
`Cu(OH)_(2),N_(2)`
`[Cu(NH_(3))_(4)](OH)_(2)`

SOLUTION :`2NH_(3)+3CuO to 3Cu+3H_(2)O+N_(2)`
Discussion
41.

Ammonia at a pressure of 10atm and CO_(2) at a pressure of 20 atm are introduced into an evacuated chamber. If K_(p) for the reaction NH_(2)COONH_(4)(s)hArr2NH_(3)(g)+CO_(2)(g) is 2020 "atm"^(3), the total pressure after a long time is

Answer»

LESS than 30 atm
more than 30atm
equal to 30atm
can't be predicted

Solution :Since there is no `NH_(2)COONH_(4)(s)` PRESENT in the chamber. Pressure will not change.
Discussion
42.

Ammonia and oxygen react at high temperature as: 4NH_(3) (g) + 5O_(2)(g) rarr 4NO(g) + 6H_(2)O (g) In an experiment, the rate of formation of NO is 3.6 xx 10^(-3) Ms^(-1). Calculate (a) the rate of disappearance of ammonia and (b) the rate of formation of water.

Answer»


Solution :GIVEN : `4NH_(5(g)) +5O_(2(g)) to 4NO_((g))+ 6H_(2)O_((g))`
`(d[NO])/(DT) = 3.6 XX 10^(-3)molL ^(-1) s^(-1)`
(a) `-(1)/(4) (d[NH_(3)])/(dt) =(1)/(4)(d[NO])/(dt)`
`:.` Rateof disappearance of `NH_(3)`
`=(-d[NH_(3)])/(dt) = (d[NO])/(dt)`
`=3.6 xx 10^(-3)mol L^(-1) s^(-1)`
`:.`Rateof formationof `H_(2)O`
`=(d[H_(2)O])/(dt)=(6)/(4) (d[NO])/(dt)`
`=(6)/(4) xx 3.6 xx10^(-3)`
`=5.4 xx 10^(-3) molL^(-1) s^(-1)`
Discussion
43.

Ammonia and Nitric acid are two industrially important compounds. Write any two uses of ammonia.

Answer»

Solution :AMMONIA is USED for the manufacture of fertilizers such as urea. It is used for the - manufacture of NITRIC acid.-
Discussion
44.

Ammonia and Nitric acid are two industrially important compounds. Phosphorus forms a number of oxoacids.. Write the name or formulae of any two oxoacids. of phosphorus.

Answer»

SOLUTION :Orthophosphorus ACID `(H_3PO_3)`is DIBASIC.
Discussion
45.

Ammonia and Nitric acid are two industrially important compounds. Complete the following equations. (Balancing is not required) NH_3+excess Cl_2to

Answer»

SOLUTION :`NH_3+3Cl_2toNCl_3+3HCl`
Discussion
46.

Ammonia and Nitric acid are two industrially important compounds. Complete the following equations. (Balancing is not required) Zn+dil.HNO_3to

Answer»

SOLUTION :`4Zn+10HNO_3to4Zn(NO_3)_2+N_2O+5H_2O`
Discussion
47.

Ammonia and Nitric acid are two industrially important compounds. Complete the following equations. (Balancing is not required) NH_3+o_2underset(500K,9"bar")overset(pt)to

Answer»

SOLUTION :`4NH_3+5O_2underset(500K,9"BAR")OVERSET(PT)to4NO+6H_2O`
Discussion
48.

Ammonia and Nitric acid are two industrially important compounds. Complete the following equations. (Balancing is not required) Cu+con.HNO_3to

Answer»

SOLUTION :`Cu+4HNO_3toCu(NO_3)_2+2NO_2+2H_2O`
Discussion
49.

Ammonia and Nitric acid are two industrially important compounds. Account for the following:PCl_5 fumes in moist air

Answer»

Solution :`PCl_5` readily UNDERGOES hydrolysis with MOISTURE to FORM FUMING HYDROGEN "chloride gas `PCl_5+4H_2OtoH_3PO_4+5HCl`
Discussion
50.

Ammonia and Nitric acid are two industrially important compounds. Account for the following: NO_2 undergoes dimerisation.

Answer»

Solution :`NO_2` is an odd electron molecule. Odd electrons PRESENT on TWO nitrogen ATOMS form covalent bond on dimerisation.. Thus it is CONVERTED to stable `N_2O_4` with even NUMBER of electrons.
Discussion