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Ammonia forms the complex [Cu(NH_(3))_(4)]^(2+) will copper ions in alkaline solution but not in acidic solution. The reason for this is |
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Answer» In alkline solution `Cu(OH)_(2)` is precipitated which is soluble in exces of alkali `Cu^(2+)(aq)+4NH_(3) overset(OH^(+))hArr Cu^(2+)+4NH_(4)^(+)` (No complex formation) As `NH_(3)` combines with `H^(+)` of ACID and changes to `NH_(4)^(+)` which have no DONOR site. |
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