Ammonia contains 82.35% of nitrogen and 17.65% of hydrogen. Water contains 88.90% of oxygen and 11.10% of hydrogen. Nitrogen trioxide contains 63.15% of oxygen and 36.85% of nitrogen. Show that these data illustrate the law of receprocal proportions.

Ammonia contains 82.35% of nitrogen and 17.65% of hydrogen. Water cont

1.	Ammonia contains 82.35% of nitrogen and 17.65% of hydrogen. Water contains 88.90% of oxygen and 11.10% of hydrogen. Nitrogen trioxide contains 63.15% of oxygen and 36.85% of nitrogen. Show that these data illustrate the law of receprocal proportions.
Answer» Solution :In `NH_(3), 17.65` g of H combine with N = 82.35 g `therefore"1 g of H combine with N"=(82.35)/(17.65)g=4.67g` In `H_(2)O,11.10g` of H combine with O = 88.90 g `therefore" 1 g of H combine with O"=(88.90)/(11.10)g=8.01g` `therefore"Ratio of the masses of N and O which combine with FIXED mass(= 1 g) of H "=4.67:8.01=1:1.72` In `N_(2)O_(3)`, ratio of masses of N and O which combine with each other = `36.85:63.13=1:1.71` THUS, the two ratios are the same. HENCE, it illustrates the law of reciprocal proportions.