1.

Ammonia and oxygen react at high temperature as: 4NH_(3) (g) + 5O_(2)(g) rarr 4NO(g) + 6H_(2)O (g) In an experiment, the rate of formation of NO is 3.6 xx 10^(-3) Ms^(-1). Calculate (a) the rate of disappearance of ammonia and (b) the rate of formation of water.

Answer»


Solution :GIVEN : `4NH_(5(g)) +5O_(2(g)) to 4NO_((g))+ 6H_(2)O_((g))`
`(d[NO])/(DT) = 3.6 XX 10^(-3)molL ^(-1) s^(-1)`
(a) `-(1)/(4) (d[NH_(3)])/(dt) =(1)/(4)(d[NO])/(dt)`
`:.` Rateof disappearance of `NH_(3)`
`=(-d[NH_(3)])/(dt) = (d[NO])/(dt)`
`=3.6 xx 10^(-3)mol L^(-1) s^(-1)`
`:.`Rateof formationof `H_(2)O`
`=(d[H_(2)O])/(dt)=(6)/(4) (d[NO])/(dt)`
`=(6)/(4) xx 3.6 xx10^(-3)`
`=5.4 xx 10^(-3) molL^(-1) s^(-1)`


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