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This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 2. |
A bar magnet is held perpendicular to a uniform magnetic field if the couple acting on magnet |
| Answer» EAR your QUESTION DEAR | |
| 3. |
A man whose mass is 70kg climbs from a hill station a to another hill station b the height of hill station a is 1200 m above the sea level and that of b is 1800 m above the sea level calculater the work done in going from a to b ( g =10m/s2) |
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Answer» ostheta=mg (1800-1200)×cos180=70×9.8×600×-1 |
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| 4. |
The speed of a wave travelling along a 0.650 m guitar string is 320 m/s. At n=5 (fifth harmonic), the frequency is 1230 Hz. What is the frequency if a string with a wave speed of 240 m/s is used? |
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Answer» fjkhemjkekdkfffkdifkkfekekekekkejjfjfkc |
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| 5. |
Advantages of coriander oil as biodiesel for ic engine |
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Answer» s from Vegetable Oils as Alternative Fuels: Advantages and DISADVANTAGES ..... 13.14 Biodiesel and Diesel Engine EMISSIONS . ..... ARCA sativa L., Cerbera odollam (sea mango), coriander.hope it HELPS you |
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| 6. |
An electric wire is stretched to increase the strength by 25% by what percent will the resistance be increased and what will be increase in its resistivity |
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Answer» A ρ is resistivity of the material L is length in meters A is cross-sectional area in m² we know the resistance will go up, and I think it will go up by about 50%, but NEED the math. first find out how much the cross-sectional area changes. volume of a cylinder = cross-sectional area x h V = Ah initial volume V1 = A1h1 FINAL volume V2 = A2h2 volume does not change A1h1 = A2h2 A1/A2 = h2/h1 = 1.25 so cross-sectional area will go down by 1.25 now resistance calculation initial resistance R1 = ρL1/A1 final resistance R2 = ρL2/A2 R2/R1 = ρL2/A2 / ρL1/A1 R2/R1 = (ρL2/A2) * (A1/ρL1) R2/R1 = (L2/L1) * (A1/A2) so the ratio is the product of the TWO R2/R1 = 1.25 * 1.25 R2/R1 = 1.56 resistance goes up by 56% |
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| 7. |
A man covered a certain distance at an average speed of 50km/hr and comes back at the speed of 40 km/hr. What is the average speed of the man during the whole journey? |
| Answer» SPEED =s/ T =s/t1+t2=s/(s/v+s/v)=1/(1/50+1/40) | |
| 8. |
a simple pendulum of length 0.8 takes 36s to complete 20 vibration.Calculate the value of got that place |
| Answer» ANSWER is 2√2 | |
| 9. |
A beam ab of 8 m span is simply supported at the ends. It carries a point load of 10 kn at a distance of 1 m from the end a and a uniformly distributed load of 5 kn/m for a length of 2 m from the end b. If , determine: a. Deflection at the mid-span b. Maximum deflection c. Slope at the end a |
| Answer» ROM which CHAPTER? | |
| 10. |
a resistance of 9 ohm is connected to the terminals of a cell a voltmeter connected across them is 1.8 volt when a resistance of 10 ohm is connected in series with 9ohm the voltmeter reading changes to 1.9 volt calculate the EMF of cell and its internal resistance please urgently send the answer |
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Answer» them is 1.8 VOLT when a resistance of 10 ohm is connected in - 776236… ... the EMF of cell and its INTERNAL resistance please urgently send the ANSWER. |
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| 11. |
What is magnification of mirror |
| Answer» TION, with SPHERICAL mirrors, it is possible to invert the IMAGE so that it is upside down. Magnificaton. Images NEED not look exactly as large as the objects from which they originate. The ratio of image size to object size is the MAGNIFICATION factor of a sphericalmirror. | |
| 12. |
In young's double slit experiment what happens if width of slits are doubled |
| Answer» TION:It's coherent enough to produce the interferencepattern. If the sunlight is passed through a single slitbefore the DOUBLE slits, you get light that's significantly more coherent. ... But you can only see visible light in theinterference pattern, and that is RELATIVELY small RANGE of wavelengths. | |
| 13. |
Calculate the energy stored in a bubble of radius 4cm....... |
| Answer» R of SOAP bubble = 4 cm = 4 × 10-2mRadius of soap bubble = 2 × 10-2m INCREASE in SURFACE Area = 2 × 4πR2 (∵ 2, a bubble has 2 surfaces) Increase in Surface Area = 2 × 4 π × (2 X 10-2)2 | |
| 14. |
A conducting loop in the form of a circle is placed in a uniform magnetic field with its plane perpendicular |
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Answer» ϕ= B.A =BAcosθwhere ϕ=magnetic FLUX, B=magnetic FIELD and A =area vectorThe e.m.f. is INDUCED only when the flux linked with the coil changes.Since, field is constant , flux can be changed either by changing A or θ.Hence, answer are OPTION-(C) and (D). |
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| 15. |
Compare the masses of 2 bodies weing 10 kgf and 10N |
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Answer» ght of any body is the FORCE .which earth attracts the body TOWARDS its centre. It is PRODUCT of mass of body and accelration due to gravity (g) . And value of g VARIES along the earth from pole to equator .But in genral we take the value of g to be 9.81 m/s^2Hence , in your case weight of that body will be10kg *9.81m/s^2=98.1 N |
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| 16. |
Whta is magnification of lens |
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Answer» CATION OF A LENS The magnification of a lens may be defined as the ratio of the size (height) of the image to the size (height) of the object. The magnification of a lens is represented by the letter ‘m’. Thus, m = size of the image / size of the objector m = h2/h1 Where, h2 = size of image h1 = size of object The magnification (m) of lens can also be calculated in terms of image distance (v) and object distance (u), if we do not know the size (height) of object and image. Thus, m = image distance / object distance m = v/u Where, v = image distance u = object distance PLEASE note that the magnification formula is APPLICABLE both in CONVEX lenses and CONCAVE lenses. And the magnification m is positive when the image formed is virtual and erect. On the other hand, the magnification m is negative when the image formed is real and inverted. hope it HELP you |
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| 17. |
Accord to faraday second law the mass deposited on the electrode is directly proportional to |
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Answer» 's SECOND Law. This law states that “the mass of a substancedeposited or LIBERATED at any electrodeon passing a certain amount of charge is directly PROPORTIONAL to its chemical equivalent weight”. |
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| 18. |
How is kinetic energy of the body effected if its mass is double and velocity reduces to half |
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Answer» tor by which the kinetic energyof a MOVING body changes when its SPEED is reduced to half. A body ofmass 50 kg has a momentum of 3000 kg ms-1. ... The ratio of its initialkinetic energy and final kinetic energy,if the mass of the body is doubled andits velocity is HALVED will be. |
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| 19. |
a boy's 60 m in front of a wall and claps the boy continuous to clap every time and echo is heard another boy. The time taken between the first and fifty First Club is 20 s calculate the speed of sound |
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Answer» ed of SOUND will be 300 m/sExplanation : Distance between the boy's HAND and wall = 60 mTime between 1st and 51ST CLAP's echo = 20 secTotal echo between 1st and 51st clap = 51 - 1 = 50Hence distance covered by sound = 50 x 60 x 2= 6000Hence speed = distance by time=> s = 6000/20 = 300 m/sHence speed of sound will be 300 m/s |
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| 20. |
A car accelerates uniformly from rest to a speed of 20 metre per second in a spectre the mass of a car is 1200 kg calculate the acceleration of cars calculate the minimum force needed to produce an acceleration explain why the infant must produce a larger force is its acceleration is to be achieved |
| Answer» E GOOD MORNING DEAR I hope helped you | |
| 21. |
A stone is dropped from height of 45m onto a horiztonal level ground |
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Answer» at a point 45m from the base of the WALL.calculate the height of the wall ... On some planet other than Earth a ball is thrown upward at a velocity of 22.3 m/ s. .... The CANNON is at height H = 100 m above ground LEVEL, and the ball is fired .... A UNIFORM horiztonal beam is attached to a veritcal wall by a frictionless hinge . |
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| 22. |
To find the focal length of convvex mirror using a cnvex lens |
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Answer» To FIND the Focal Length of a Convex Mirror, Using a Convex LensFollow steps 1 to 4 of Experiment 1 (Section B). ...Clamp the holder with LENS in a fixed upright and KEEP the upright at 50 CM mark.Adjust the lens such that its surface is vertical and perpendicular to the length of the optical BENCH. |
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| 23. |
A bullet of mass 20 gm is horizontally fired with a velocity of 4 4 metre per second and another one "b" belonging to opposite team with mass 60 gram is moving with a velocity 3 metre per second in angle device racing the racing and feeling down find the velocity with which they fall down |
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| 24. |
A bullet of mass 20 gram is a false only fired with a velocity of 4 metre per second |
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| 25. |
A bulbe is rated 5.0 v , 100ma.Calcuate its rated paower and resistence |
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Answer» alues: V=5v , I=100mA or 0.1A To Find:POWER, Resistancesolution:V=IR 5=(0.1)R R, RESISTANCE=50 ohm Power ,P=VI =5(0.1) P=0.5WHence, Power=0.5Watt , Resistance,R=50 ohm |
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| 26. |
A body of mass m moving with a constant velocity collides head on with another stationary body of same mass |
| Answer» IES GET EXCHANGED. | |
| 27. |
I ask one question please answer me |
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Answer» this is the ANSWER |
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| 28. |
How triple covalent bond is formed in a molecule? explain with an example? |
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Answer» e bond is formed when TWO atoms share THREE pairs of electrons. The SHARING of two electrons is known as a covalent bond. ... A triple bond is made of two pi bonds and one sigmabond. Examples of compounds withtriple bonds INCLUDE nitrogen gas, the CYANIDE ion, acetylene and carbon monoxide. |
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| 29. |
Covex lens is called as converging lens. why |
| Answer» LENS are made up of SMALL prism .When light enter prism the light bends TOWARDS it's base.prism of convex lens have their bases at the center so when light TRAVEL through lens it bends towards center hence convex lens are called converging lens. | |
| 30. |
If 10 electrons are removed to another body how much time it would take to get total charge of 1 coulomb |
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Answer» rice: Rs. .... Electric CHARGE ... we know that 1 Coulomb = 6.242×1018 ELETRONS ... ELECTRONS will take 6.24×10^18/10^9Which is EQUAL to 6.24×10^9 |
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| 31. |
The instantaneous current from an ac source is y=0.5sin314t what is the rms and frequency of the current |
| Answer» U FIND it USEFUL | |
| 32. |
An engine approaches the hill with a constant speed. When it is at a distance of 0.9 km, it blows a whistle whose echo is heard after 5 seconds. What is the speed of engine. Speed of sound is 340 m/s. |
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Answer» istance/Time=900/5m/s=180m/s.ans......HOPE this will HELP you.Please MARK it as BRAINLIEST. |
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| 33. |
A car moves with a speed of 30km/h for half an hour and 25km/h for one hour and 40km/h for 2 hour . Calculate the average speed |
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Answer» oves with 30 km/h for 30 min means the car trvelled only 15km (i)In 2nd case the travels 25KM/h for one hour means the car travel 25km (ii)In 3rd case the car travels 40km/h for 2 hours means the car travles 40×2 = 80km avg. speed - total DISTANCE travelled/ total time TAKEN 1200m/ 210 = 5.7 km/h |
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| 34. |
Define the term overloading |
| Answer» DING MEANS to STORE or keep SOMETHING more than its capacity | |
| 35. |
Define the term short circuit |
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Answer» Here's Ur Answer..:-: A bad electrical CONNECTION that CAUSES a MACHINE to stop working.HOPE IT HELPS U..^-^ |
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| 36. |
Please give solution me |
| Answer» VALUE of d SUB SHELL is 2...from M shell d sub shell will START... | |
| 37. |
Find the angle of minimum deviation for an equilateral prism made of a material of refractive index 1.732. What is the angle of incidence for this deviation ? |
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| 38. |
A container contains water upto a height of 20 cm and there is a point source at the centre of the bottom of the container. A rubber ring of radius r floats centrally on the water. The ceiling of the room is 2.0 m above the water surface. (a) Find the radius of the shadow of the ring formed on the ceiling if r = 15 cm. (b) Find the maximum value 'of r for which the shadow of the ring is formed on the ceiling. Refractive index of water= 4/3. |
| Answer» WRITTEN the ANSWER in the PIC!Do REFER to it. | |
| 39. |
What do you mean by the term pitch ? |
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Answer» lity of a sound governed by the rate of vibrations producing it; the DEGREE of highness or LOWNESS of a tone. PITCH is directly proportional to FREQUENCY |
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| 40. |
A point source is placed at a depth h below the surface of water (refractive index = μ). (a) Show that light escapes through a circular area on the water surface with its centre directly above the point source. (b) Find the angle subtended by a radius of the area on the source. |
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Answer» let x be the radius of circular AREA x/h= tan C x/h= sin c/√(1- sin ²c) = 1/μ/√(1-1/μ²) since sin c= 1/μx/h= 1/√μ²-1 x= h/√μ²-1 so light escapes through are on the water DIRECTLY above the point sorce b) ANGLE subtended by a radius of the area on the source c= sin⁻¹(1/μ) |
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| 42. |
Is the ghost really explain in scientific knowledge plzzzzzzz I will mark it as brainlist:-);-):)):)):)):->:") |
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Answer» just an ILLUSION and effects created by our mind . Ghosts do not exist in REALITY. But, some negative sort of power has been SAID to exist. Hope it helps❤️❤️ |
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| 43. |
A solid sphere has a radius of 1.5cm and a mass of 0.038kg.the relative density of the sphere is a. 13.6 b.2.69 c.1.00 d.7.8 |
| Answer» E ANSWER 2.69 | |
| 44. |
A solid sphere has a radius of 1.5cm and a mass of 0.038kg.the relative density of the sphere is |
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Answer» is HELPS U MARK me as BRAINLIEST |
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| 46. |
Which of the following temperatures is the highest. a)100K b)-13 F c)-20 C d)-23C |
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| 47. |
Light is incident from glass (μ= 1.50) to water (μ= 1.33). Find the range of the angle of deviation for which there are two angles of incidence. |
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Answer» μg=1.5=3/1μw=1.33= 4/3For two ANGLE of INCIDENCES = case 1: when light passes straight through normal :angle of i =0⁰angle of r= 0⁰angle of deviation =0⁰case 2:when light is INCIDENT at critical angle sin c/ sin r= μa/μgsin c=8/9c= sin⁻¹(8/9)= 62.73⁰angle of deviation = 90⁰-c= 90- sin⁻¹(8/9)=cos⁻¹(8/9)=37.27⁰we conclude that if angle of incidence is increased beyond Critical angle , total internal reflection OCCURS and deviation decreases .so range of deviation is o⁰ to cos⁻¹(8/9) |
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| 48. |
Siple microscope image at infity |
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Answer» s that of the OBJECT |
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| 49. |
ight is incident from glass (μ= 1.5) to air. Sketch the variation of the angle of deviation 5 with the angle of incident i for 0 < i < 90°. |
| Answer» EAR friend ✌️✌️see the ATTACHMENT PIC for the answer..HOPE it will be HELPFUL to you..thanks.. | |
| 50. |
What is Resistance in parallel and in series |
| Answer» E resistors are arranged parallel to each other RESISTANCE =1/Rp=1/R1+1/R2+......when the resistors are arranged ONE after ANOTHER resistance =Rs=R1+R2....... | |