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Light is incident from glass (μ= 1.50) to water (μ= 1.33). Find the range of the angle of deviation for which there are two angles of incidence. |
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Answer» μg=1.5=3/1μw=1.33= 4/3For two ANGLE of INCIDENCES = case 1: when light passes straight through normal :angle of i =0⁰angle of r= 0⁰angle of deviation =0⁰case 2:when light is INCIDENT at critical angle sin c/ sin r= μa/μgsin c=8/9c= sin⁻¹(8/9)= 62.73⁰angle of deviation = 90⁰-c= 90- sin⁻¹(8/9)=cos⁻¹(8/9)=37.27⁰we conclude that if angle of incidence is increased beyond Critical angle , total internal reflection OCCURS and deviation decreases .so range of deviation is o⁰ to cos⁻¹(8/9) |
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