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A point source is placed at a depth h below the surface of water (refractive index = μ). (a) Show that light escapes through a circular area on the water surface with its centre directly above the point source. (b) Find the angle subtended by a radius of the area on the source. |
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Answer» let x be the radius of circular AREA x/h= tan C x/h= sin c/√(1- sin ²c) = 1/μ/√(1-1/μ²) since sin c= 1/μx/h= 1/√μ²-1 x= h/√μ²-1 so light escapes through are on the water DIRECTLY above the point sorce b) ANGLE subtended by a radius of the area on the source c= sin⁻¹(1/μ) |
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