This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
Show an activity to determine the boiling point of water |
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Answer» e the mouth of the boiling tube with a rubber CORK that has two bores and clamp it with the stand. ... Introduce a THERMOMETER (temperature range -10 to 110°C) in one bore of the cork of the boiling tube. Keep the bulb of the thermometer about 3-5 cm above the SURFACE of the water. |
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| 2. |
Two thin lenses of power + 2.5 D and - 0.5 D are placed in contact. Find the power and focal length of the lens combination. Also calculate the focal length of the combination. |
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Answer» Explanation:Solution,Here, we have,Power ONE of LENS = P₁ = + 2.5 D Power two of lens = P₂ = - 0.5 DTo FIND,Power and FOCAL length We KNOW that,Power combination = P₁ + P₂= + 2.5 + (- 0.5)= 2.5 - 0.5= 2 DHence, the power is 2 D.Now, Focal length,We know that,Power = 1/focal length⇒ 2 = 1/f⇒ 2/1 = f ⇒ f = 2 mHence, the focal length is 2 m. |
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| 3. |
Difference between uniform and non uniform speed in byju's app |
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Answer» Explanation:UNIFORM SPEED:when a object covers EQUAL distance in equal interval of time is CALLED uniform speed. Non - Uniform speed:when object does not covers equal distance in equal interval of time is called non- uniform speed. THANK you ⚡⚡⚡⚡ |
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| 4. |
6. How is land breeze formed? Explain. |
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Answer» A high-PRESSURE zone forms as the cooler LAND cools the air immediately above the surface. WINDS aloft flow from the ocean to the land. Winds at the surface flow from high to low pressure, CREATING a land breeze. |
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| 5. |
There are four forces acting on a particle P, which then continuesto remain at rest. Evaluate theforces F, and F2.Answer it only if uh know the correct explanation. |
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Answer» F₁ = (1/√2) N and F₂ = (3/√2) NExplanation:APPLYING equilibrium conditions. : Horizantal Forces : F₁ + 1 SIN 45° - 2 sin 45° = 0⇒ F₁ = 2 sin 45° - 1 sin 45°⇒ F₁ = sin 45°⇒ F₁ = (1/√2) ------ (1)Now,VERTICAL Forces : 2 cos 45° + 1 cos 45° - F₂ = 0⇒ 3 cos 45° - F₂ = 0⇒ 3 cos 45° = F₂⇒ 3(1/√2) = F₂⇒ 3/√2 = F₂Therefore,F₁ = (1/√2) N and F₂ = (3/√2) NHope it HELPS! |
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| 6. |
The bob of a simple pendulum of length 1 m is drawn a side until the string becomes horizontal. Find the velocityof the bob, after it is released in the equilibrium position. |
| Answer» EXPLANATION:APPLY LAW of CONSERVATION of ENERGY. | |
| 7. |
A body travelling with velocity of 60m/s^-1 gains an acceleration of 100m/s^-2. Calculate the distance travelled by the body in 15 seconds. Please show the steps as well. |
| Answer» EXPLANATION:Solution,Here, we haveInitial velocity of BODY, U = 60 m/sAcceleration of body, a = 100 m/s²Time taken by particle, t = 15 secondsTo Find,Distance traveled, s = ??According to the 2nd equation of motion,we know that,s = ut + 1/2 × at²On PUTTING all the values, we get⇒ s = ut + 1/2 × at²⇒ s = 60 × 15 + 1/2 × 100 × 15²⇒ s = 900 + 1/2 × 100 × 225⇒ s = 900 + 50 × 225⇒ s = 900 + 11250⇒ s = 12150 m Hence, the distance traveled by the body in 15 seconds is 12150 m. | |
| 9. |
State a condition when force acting on an object doesn’t change the speed of the moving object but changes the direction of the object. Please answer it’s urgent. |
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Answer» tion:FORCE can change the direction of a moving or STILL object as SHOWN:You apply a force on a almirah to make it face in a different direction. A football player kicks a football to make it MOVE in a different direction, over to another player of his team. |
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| 10. |
Rina is holding a bucket by applying a force of 2kgf. She first moves on a horizontal road of distance 5m and then a vertical height of 8m. If Rina herself weighs 48kgf, find the total work done by her. |
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Answer» tion:horizontal WORK is zero as the force is in VERTICAL DIRECTION and the motion is in horizontal direction. |
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| 11. |
Determine the p.d which must be applied to a 2k ohmresistor in order that a current of 10mA may flow |
| Answer» V= IR Where I= 10mA= 10/1000=1/100= 0.01 ,R= 2 OHM V=IR V= 0.01 × 2 V= 0.02voltsPlease | |
| 12. |
A body covers a distance of 10m/s with a velocity of 5m/s and further covers a distance of 20m with a velocity of 4m/s. Find the average velocity for the motion |
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Answer» Explanation:Correct Question,A BODY covers a distance of 10 m with a VELOCITY of 5 m/s and further covers a distance of 20 m with a velocity of 4 m/s. Find the AVERAGE velocity for the motion.Answer,Here, we haveDistance, D₁ = 10 mSpeed, S₁ = 5 m/sDistance, D₂ = 20 mSpeed, S₂ = 4 m/sTo Find,Average Speed.We KNOW that,Time taken = Distance/Speed⇒ Time taken in 1st case = 10/5 = 2 seconds⇒ Time taken in 2nd case = 20/4 = 5 seconds⇒ Total time taken = 2 + 5 = 7 secondsThen,⇒ Total distance covered = D₁ + D₂ = 10 + 20 = 30 mwe know that,Average velocity = total distance/total time taken⇒ Average velocity = 30/7⇒ Average velocity = 4.28 m/sHence, the average velocity of body is 4.28 m/s. |
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| 13. |
E. there is no relative motion between the two surfaces in contactin case of friction. |
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Answer» The force of frictionThe frictional force is the other COMPONENT; it is in a DIRECTION parallel to the plane of the interface between objects. ... When a frictional force exists but there is no relative motion of the SURFACES in contact (e.g., the book isn't sliding across the table), we call it a static frictional force. |
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| 14. |
How much mechanical work is done in raising a 20.7 kg mass a distance of 2.69 metres? Note 1: This question is not direction specific. Therefore, if using acceleration due to gravity, please use positive 9.81 m/s/s. |
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Answer» 546.25 JExplanation:Given: MASS(m) = 20.7 KG distance(s) = 2.69 m ACCELERATION due to GRAVITY (g) = 9.81m/s²To find: Work done = ? formula:therefore, work = mg × sSubstituting the values, work = 20.7(9.81) × 2.69 = 203.067 × 2.69 work = 546.25 N-m work = 546.25 Joules |
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| 15. |
Deceleration is Acquired unit |
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Answer» so what????????? ??? ??? |
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| 16. |
why it is easier to pull abucker from the well untill it is insidr thr water but difficult when it is out of water |
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Answer» ecause of the gravitational force working on the BUCKET when you THROW the bucket in the WELL it is empty so the force of gravitation is also less as it is directly PROPORTIONAL to weight but when you pull it out the water in the bucket increases its weight which causes more gravitational force to work on the bucket HOPE IT HELPS YOU PLEASE MARK AS BRAINIESTFOLLOW ME ❤️ |
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| 17. |
The positions of a body at different times are recorded in the table given below: Time(s) 0 1 2 3 4 5 6 7 8 Displacemet (m) 0 6 12 18 24 30 36 42 48 (a) Draw displacement time graph from the following data. (b) What does the slope of the graph give? (c) Calculate the speed of the motion. |
| Answer» TION:jhgivvogi KOH IGV VI JVI jiv i | |
| 18. |
Is it easier to remove to remove electron from sodium than from copper? Which metal has higher value of threshold frequency? No spam please It’s urgent!!!!!!!!!! |
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Answer» yes it is easier to remove fresh stains as when something is just spilt it is STILL wet and the cloth hasn't absorbed it YET, but when it is caused a few ...is easier to remove an ORBITAL electron from an atom, but quite difficult to remove a nucleon from a nucleus. |
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| 19. |
We know that fire requires oxygen for its combustion but how do sun is still full of fire without existence of oxygen in space??? |
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Answer» glows because it is a very big ball of gas, and a process called nuclear FUSION is TAKING place in its core. ... Hydrogen really doesn't burn, it fuses, into HELIUM. So no oxygen is required!...HOPE this HELPED.... |
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| 20. |
When the distance between two charged particle half, what is the force between them becomes? |
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Answer» ce between the two charges is directly proportional to the product of the charges and INVERSELY proportional to the square of the distance between them. HENCE, if distance between charges is HALVED (charges remaining kept constant), the force between the two charges is quadrupled.Høpe it will Help uh!!...XD♥️#Be BRAINLY#______________Thanks ✊ |
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| 22. |
If distance is in a circular path then the displacement will be |
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Answer» In a circular motion when the BODY COMES back to the original POSITION then the displacement of the body is shortest distance between the FINAL and the initial position of object. So the displacement is zero. |
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| 23. |
Person goes to market,makes purchases and comes back at a constant velocity of 45 km/h.draw velocity-time graph of the person |
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Answer» Figure (a) shows DISPLACEMENT TIME GRAPH. Parthas greater slope and part. Therefore, velocity while going to MARKET is higher compared to velocity while coming back. |
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| 24. |
Write the formula of specific heat of the substance? |
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Answer» The heat capacity and the specific heat are related by C=cm or c=C/m. The MASS m, specific heat c, change in temperature ΔT, and heat added (or subtracted) Q are related by the EQUATION: Q=mcΔT. Values of specific heat are dependent on the PROPERTIES and phase of a GIVEN substance. |
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| 25. |
A A = i cap +4 j cap + k cap Find the angle of A with x y z |
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Answer» if i CAP , jcap and kcap represents UNIT vectors along the X , y ,and Z axis then find the angle between i cap + jcap +k cap and i cap +j cap |
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| 26. |
Show how is commercial unit of electrical energy & SI unit of energy related. |
| Answer» GIVE its relationship with S.I. UNIT of ENERGY. COMMERCIAL unit of energy is the kilowatt-hour (KWH). The SI unit of energy is the Joule (J) | |
| 27. |
Raman is walking along a circular path of radius 80 m In 10 min he completes 2.5 revolution of the circular path his displacement is |
| Answer» ANSWER:Given, after HALF the circle, the particle will reach the DIAMETRICALLY OPPOSITE point i.e., from point A to point 6. And we KNOW displacement is shortest path between initial and final point. Hence, the displacement after half circle is 2r.Answer:Given, after half the circle, the particle will reach the diametrically opposite point i.e., from point A to point 6. And we know displacement is shortest path between initial and final point. Hence, the displacement after half circle is 2r. | |
| 28. |
A particle moves along a circle of radius 10m. Determine the distance and magnitude displacement after 0.5 revolution.. |
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Answer» The BODY COMPLETES 1 revolution in 4 secondsw = 2π4 rad/s W = π2 rad/sRadius of the circular path is 0.1 mCentripetal ACCELERATION is = r × W2 ar |
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| 29. |
Define the term :- Average relaxation time ? |
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Answer» Relaxation TIME can be defined as the time taken by electron to attain an average velocity which is 1/e times its value. The average time INTERVAL between TWO successive collisions is called relaxation time of electronsExplanation:AND MARK ME AS BRAINLIEST ANSWER PLZZZZZ |
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| 30. |
can anyone pls send the sol pic of this question please it is very urgent and pls don't respond if u don't know. |
| Answer» WAIT.................................................. | |
| 31. |
A particle first moves 4m due East and then 3m due south . Determine the displacement and distance travelled by particle . |
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Answer» ━━━━━━━━━━━━━✦ REQUIRED Answer:♦️ GiveN:The body moves 4 m East and then 3 m west.♦️ To FinD:Find DISTANCE....?Find displacement.....?━━━━━━━━━━━━━━━━━━━━✦ How to Solve?Before solving this question, we need to know the actual definitions of distance and displacement, especially their difference. The is the actual path covered by the body. The total length of the path travelled, whereas is the shortest path between the initial and final point. It doesn't depend the path covered by body, only we should consider the straight line joining the initial and final point to be the displacement. ━━━━━━━━━━━━━━━━━━━━✦ Solution: Refer to the attachment...Let the body started its journey from A, and travels 4 m east to reach B. Then it travels 3 m SOUTH to reach point C. So, the body travels from A to B, and then B to C. So, total distance travelled AB + BC.Now, we have initial point A and final point C, so we know that displacement is the shortest path between initial and final point. So, displacement will be AC.By using pythagoras theoram, ━━━━━━━━━━━━━━━━━━━━ |
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| 32. |
Is there a god ? Huh? |
| Answer» YES I BELIEVE in GOD......as it is SAID thatNATURE IS THE ART OF GOD | |
| 33. |
Light enters from air to glass having refractive index 1.50. What is the speed of light in the glass? The speed of light in vacuum is 3 x 108 ms-1. |
| Answer» N :- =>Refractive index of a medium (nm) = SPEED of light in vacuum/Speed of light in the medium=>Speed of light in vacuum (c) = 3 × 108 m/s=>Refractive index of GLASS (ng) = 1.50=>Speed of light in the glass (v) = Speed of light in vacuum/ Refractive index of glass= c/ng=3 × 108/1.50 = 2X 108 ms-1.Therefore, the speed of light in the glass is 2×108ms-1. | |
| 34. |
Describe an activity to find the focal length of a concave mirror. |
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Answer» ️✳️✳️✳️✳️✳️✳️✳️✳️✳️✳️✳️✳️✳️☆....☆....☆....☆....☆....☆....☆....☆.☆....☆....☆....☆....☆....☆....☆....☆✳️✳️✳️✳️✳️✳️✳️✳️✳️✳️✳️✳️✳️✳️✳️✳️✳️1.Fix CONCAVE mirror to mirror holder and place it on a plane surface (say a long table). Turn the face of mirror towards a distant object (may be candle).2.Now adjust the screen ,candle and the mounted concave mirror so that they are all on the principal axis.3.Move the screen back and forth and DETERMINE the position for the brightest clearest image4.Measure the distance between the concave mirror and the screen with a metre scale. Record your observations in observation table. 5.Repeat the experiment TWO or three times and find the MEAN value of the FOCAL length.✳️✳️✳️✳️✳️✳️✳️✳️✳️✳️✳️✳️✳️✳️✳️✳️✳️☆....☆....☆....☆....☆....☆....☆....☆☆....☆....☆....☆....☆....☆....☆....☆✳️✳️✳️✳️✳️✳️✳️✳️✳️✳️✳️✳️✳️✳️✳️✳️✳️ |
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| 35. |
23. There are four forces acting on a particle P, which then continuesto remain at rest. Evaluate theforces F, and F |
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Answer» the forces are balanced as there is no movementExplanation:Balanced forces are forces with a not force of 0Ex: when you PUSH a box against a WALL, the box doesent move as the wall provides an equal and OPPOSITE force and thus the net force is 0 |
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| 36. |
Please help me the following questions. |
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Answer» full FORM of SONAR is STANDS for sound NAVIGATION and rangingExplanation:HOPE it will help you |
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| 37. |
To make something blank both ends need to have the same weight |
| Answer» YES THATS what i THINK about the QUESTION | |
| 38. |
A car travels 40 km in 20 min next 30 km in 30 min. Calculate the average speed for the whole journey |
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Answer» AVERAGE SPEED:(40 km + 30 km)/(20 min + 30 min)70 km / 50 min1.4 km per MINUTE HOPE IT HELPS YOU ✌ |
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| 39. |
An observer standing between two cliffs hears two succesive echoes at 2s and 3s respectively. Calculate the distance between two cliffs? |
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Answer» 850mExplanation:VELOCITY of sound=340m/stime at FIRST interval=2stime at SECOND interval=3sdistance d=340*5/2=850m |
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| 41. |
Write any two questions to understand the magneticfield lines are closed lines |
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Answer» Questions to ask to FIND the magnetic LINES are closed loops are: 1.Where does the magnetic flow START and end in a magnet? 2. Are the magnetic lines BROKEN anywhere between the poles?EXPLANATION:AND MARK ME AS BRAINLIEST ANSWER PLZZZ |
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| 42. |
Q4. what is balance and unbalanced force define and explain with examples ? |
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Answer» Balanced FORCES do not CAUSE a change in motion. When balanced forces act on an object at REST, the object will not move. If you push against a WALL, the wall pushes back with an equal but opposite force. Neither you nor the wall will move. Forces that cause a change in the motion of an object are UNBALANCED forces |
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| 43. |
Friction is caused by _ the on thetwo substances incontact |
| Answer» FRICTION is CAUSED by interlocking of the 2 bodies in contact.Explanation:Your WELCOME;) | |
| 44. |
.. A cricket ball thrown across a field is at heights h, and hz from the point of projection at times t, and tą respectivelyafter the throw. The ball is caught by a fielder at the sameheight as that of projection. The time of flight of the ballin this journey isA. |
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Answer» a 30Explanation:+₹(&):/:'_73udifigogixgz"!_+_7₹6_(-9-9_+"+_+&8₹6264859&(_+₹73etogyfsSidophytotifriryrithofjoogoy |
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| 45. |
An object moving with constant acceleration along a horizontal path covers the distance between two points 60m apart in 6 seconds.its speed as it passes the second point is 15m/s.find (a)the speed at the first point (b)it's acceleration(c)the distance from point where the object was at rest at the first point. |
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Answer» u= 5 m/ s.Explanation:After 6s, it is given the final velocity is 15 m/ s.Therefore,15 = u + 6a2 × a × 60 = 15^2 - u^2120 = a^2+ 36A^2 + 12au - 2^2120 a = 36a^ + 12au120 a = 36a + 12au 10 = 3A + u15 = u + 3a + 3a15 = 10 + 3a a = 5/ 3m / 5^2Using this, we get u = 5m/ s.Hope it's help ! ...........Thank you...... |
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| 46. |
A truck running at 90 kmh-1 is bought to rest over a distance of 25 m . Calculate the retardation and the time for which brakes are applied. |
| Answer» SPEED =90km/h=25m/s DISTANCE = 25m 0-625=50a a=-12.5m/s^2 0=25-12.5t t=250/125=4sec Explanation:MARK ME AS BRAINLIEST ANSWER PLZZZ | |
| 47. |
Please tell me the correct answer |
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Answer» yrrr app PLZZ muje is book ka name book ka name bta SKTE ho kuki MERI mam BHI AESE hi ques deti h |
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| 48. |
I. The gravitational unit of the force- a.Gravitational force ii. Touchless force- b.Vector quantity iii. Velocity- c. Acquired unit iv. Deceleration- d. Kg-weight Pls solve this Matching list |
| Answer» KG wt is the gravitational UNIT of force.Explanation:MARK ME AS BRAINLIEST ANSWER PLZZ | |
| 49. |
Q1.A body starts to slide over a surface with initial velocity of 0.5m/s. Due to friction it’s velocity decreases,at the rate of 0.05m/sHow much time will it take for the body to stop?.Q2 A body travels along a circular path of radius 70m.After travelling half a revolution in 20s,Find a) average speed b) average velocityQ3.A cheetah spots it’s prey at a distance of 100m.What time does it take to get its prey,if average velocity is 90 km/h?Q4.Brakes applied to a car produce acceleration of 6 m/s in opposite direction to motion.If the car takes 2s to stop, calculate distance it travels during this time.Q5.A car starts from rest and moves along a straight line with constant acceleration. of 5m/s for 8 s.At the end of 8s,it continues to move with constant velocity.What distance will it cover in 12s?Q6 A car of mass 1500kg is moving with a speed of 36km/h.It is brought to rest by applying brakes in 2s. a)What is initial and final momentum of car? b) What is the force on car due to the brakes?Q7 A force of 10N gives a body of mass m, an acceleration of 10m/s and a body m' ,an acceleration of 20 m/s a)What is mass m? b)What is mass m'? c)What will be the acceleration if both masses were tied together?Q8.A body moves with uniform velocity under the action of applied force of 10N.How much is the frictional force acting on the body? |
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