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There are four forces acting on a particle P, which then continuesto remain at rest. Evaluate theforces F, and F2.Answer it only if uh know the correct explanation. |
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Answer» F₁ = (1/√2) N and F₂ = (3/√2) NExplanation:APPLYING equilibrium conditions. : Horizantal Forces : F₁ + 1 SIN 45° - 2 sin 45° = 0⇒ F₁ = 2 sin 45° - 1 sin 45°⇒ F₁ = sin 45°⇒ F₁ = (1/√2) ------ (1)Now,VERTICAL Forces : 2 cos 45° + 1 cos 45° - F₂ = 0⇒ 3 cos 45° - F₂ = 0⇒ 3 cos 45° = F₂⇒ 3(1/√2) = F₂⇒ 3/√2 = F₂Therefore,F₁ = (1/√2) N and F₂ = (3/√2) NHope it HELPS! |
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