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A body travelling with velocity of 60m/s^-1 gains an acceleration of 100m/s^-2. Calculate the distance travelled by the body in 15 seconds. Please show the steps as well. |
| Answer» EXPLANATION:Solution,Here, we haveInitial velocity of BODY, U = 60 m/sAcceleration of body, a = 100 m/s²Time taken by particle, t = 15 secondsTo Find,Distance traveled, s = ??According to the 2nd equation of motion,we know that,s = ut + 1/2 × at²On PUTTING all the values, we get⇒ s = ut + 1/2 × at²⇒ s = 60 × 15 + 1/2 × 100 × 15²⇒ s = 900 + 1/2 × 100 × 225⇒ s = 900 + 50 × 225⇒ s = 900 + 11250⇒ s = 12150 m Hence, the distance traveled by the body in 15 seconds is 12150 m. | |