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Explanation:The Carnot cycle is trying to be the most efficient at generating work GIVEN two HEAT reservoirs at different temperatures. To be the most efficient, it needs to minimize entropy generation. The PROTOTYPICAL example of entropy generation is heat flowing across a non-zero temperature gradient. That’s because as it leaves the hot object it removes entropy δQ/TH, and as the exact same heat enters the COLD body, it adds entropy δQ/TC. Since TH>TC, this is more entropy arriving than leaving, that is, a net increase. Therefore if you want efficiency, your candidate cycle elements are adiabatic (no heat flows at all) and isothermal at a temperature infinitesimally CLOSE to that of one of the reservoirs (heat flows infinitesimally slowly but with infinitesimally small entropy generation).

st lens:Object distance from the lens i.e. u is -40 cm.Let us assume that the image formation of the first lens takes place at the SCREEN which is 'X' cm AWAY.Using lens formula,1/F = 1/v - 1/uSubstitute the values,1/f = 1/x - 1/(-40)1/f = 1/x + 1/401/f = (40 + x)/40xf = 40x/(40 + x)40f + fx = 40x40f = 40x - fx40f = x(40 - f)40f/(40 - f) = x ...............(1st equation)For second lens:Object distance i.e. u from the screen is -80 cm and again the image formation i.e. v is 'x - 40' cm.Since the first lens image formation was x cm always from the lens and for the second ONE object is 80 cm away. So, object will be place at image distance from lens - object distance from the first lens. i.e. (x - 40)Using lens formula,1/f = 1/v - 1/uSubstitute the values,1/f = 1/(x-40) - 1/(-80)1/f = 1/(x-40) + 1/80 ...............(2nd equation)Substitute value of (1st equation) in (2nd equation)→ 1/f = 1/[40f/(40-f) - 40] + 1/80→ 1/f = 1/[(40f - 1600 + 40f)/(40 - f)] + 1/80→ 1/f = 1/[(80f -1600)/(40 - f)] + 1/80→ 1/f = (40 - f)/(80f -1600) + 1/80→ 1/f = 1/80 × (40 - f)/(f - 20) + 1/1→ 1/f = 1/80 × (40 - f + f - 20)/(f - 20)→ 1/f = 1/80 × (20)/(f - 20)→ 1/f = 20/80 × 1/(f - 20)→ 1/f = 1/4 × 1/(f - 20)→ 4/f = 1/(f - 20)Cross-multiply them,→ 4f - 80 = f→ 4f - f = 80→ 3f = 80→ f = 80/3Therefore, the focal length of the lens is 80/3 cm.Option (4) 80/3 cm

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Explanation:V=−(x+y+z)J/kg Relation between gravitational intensity   G  and gravitational potential: G =−  ∇ V =−(  ∂x ∂ ​     i ^ +  ∂y ∂ ​     j ^ ​   +  ∂z ∂ ​     k ^ )(−[x+y+z]) =  i ^   ∂x ∂ ​   (x+y+z)+  j ^ ​     ∂y ∂ ​   (x+y+z)+  k ^   ∂z ∂ ​   (x+y+z) =  i ^ +  j ^ ​   +  k ^  Therefore the field is CONSTANT everywhere

nfo : the distance between a real OBJECT and its real IMAGE is 56 cm formed by converging lens. To find : focal length of lens. Solution : let focal length of converging lens is F . A/c to question, u + V = 56 cm [ because real image formed by converging lens just opposite of its object ] now using formula, 1/v - 1/u = 1/f ⇒1/(56 - u) - 1/u = 1/f ⇒1/(56 - u) - 1/-u = 1/f ⇒(u + 56 - u)/(56u - u²) = 1/f ⇒56f = 56u - u² ⇒u² - 56u + 56 f = 0Discriminant = (56)² - 4 × 56f ≥ 0⇒56 × 56 ≥ 4 × 56 f ⇒14 ≥ f Therefore the focal length would be f ≤ 14

-Initial VELOCITY (u) = 0Final velocity (v) = 36 km/h × 5/18 = 10m/sTime taken (t) = 20sTᴏ ғɪɴᴅ :-ACCELERATION (a) sᴏʟᴜᴛɪᴏɴ :-We know that, Put the above GIVEN values in it, we GET, Hence, Acceleration = 0.5 m/s²Hence, OPTION (a) 0.5 m/s² is correct

0.02526 is ANSWER ekjtudiriuf

Explanation:Bernoulli's principle can be APPLIED to many EVERYDAY situations. For example, this principle explains why airplane wings are curved along the top and why ships have to STEER away from each other as they pass. The pressure above the wing is lower than below it, PROVIDING LIFT from underneath the wing.

39 km/hrExplanation:Given,SPEED 1 = 40 km/hrSpeed 2 = 35 km/hrSpeed 3 = 42 km/hrAverage Speed = (ADDITION of all Speed)/(No. of Speed)= (35+40+42)/3 km/hr= 117/3 km/hr= 39 km/hrHope this helps.

yeah, It is said that we can time TRAVEL by WORM holes in SPACE because it's one mouth is connected to other mouth which can TAKE us to past or future but we can't do that because the force inside the worn hole can destroy EVERYTHING.

the same TEMPERATURE, it GIVES out 75,000 J of HEAT energy. (a) What is the SPECIFIC latent heat of the metal? (b) If the specific heat

e here is ur answerPotential difference is the difference in the amount of energy that charge carriers have between TWO points in a circuit. **Measured in VOLTS: **Potential difference (p.d.) is measured in volts (V) and is also called voltage. ... We use a voltmeter to measure potential difference (or voltage).hope it helps YOUMARK it as brainlist and follow methanks!

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tion:The work function (W)=1.9Ev=1.9×1.6×10^(-19)Joule ( converting EV into joule)incident wavelength=4000×10^(-10)meterwe know Ke=hc/wavelength-w(h is PLANKS constant and c is VELOCITY of light)ke=1.91×10^(-19)j=1.19evweknow,work function=h×threshold frequency1.9×e/h=ff=4.5×10^14 hzfor stopping potentialke=ev1.19e=e×vso v=1.19

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he branch of science concerned with the nature and properties of matter and ENERGY. The subject matter of physics includes mechanics, heat, LIGHT and other radiation, SOUND, electricity, MAGNETISM, and the structure of atoms.

hєчα mαtєSo due to the WIRES having electrical resistance, which means that they resist the motion of electrons, THEELECTRONS BUMP into atoms on theoutside of the wire, and some of their kinetic ENERGY is GIVEN to the atoms as thermal energy. This thermal energy causes the wire to heat up.plz mαrk αѕ вrαnlíѕt

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32 km/hr is the correct ANSWER SEE the ATTACHMENT Explanation:HOPE the answer will help you

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of wire of resistance R is cut into five equal parts. These parts are then connected in parallel . if the equivalent resistance of this combination is R' , then what is the RATIO  R / R' ?The equivalent resistance of 5 RESISTANCES ( R₁ , R₂ , R₃ , R₄ , R₅ ) connected in parallel will be given by LET , initial length of wire = 5 L initial area of cross section = A then,initial Resistance = R   will beNow,∵ Wire is DIVIDED in 5 equal parts Therefore,new length of each wire PIECE = L area of cross section of each wire piece = A( area of cross section will remain unchanged)so,new resistance of each part  will be5 pieces were connected in parallel connection so, Equivalent resistance of parallel combination = R' will be ▶ Now finding the ratio R / R'Hence ,the ratio R : R' = 25 : 1

et us SUPPOSE particle start at a moving with constant angular velocity ω starting at time t=0Displacement =ρABy applying cosine rule(PA) 2 =(OA) 2 +(OP) 2 −2(OA)(OP)cos(θ)∴OA=OP=a= RADIUS at circle.PA= Displacement=sθ= ANGLE between OA∝OP=ωts 2 =2a 2 [1−cosθ] =2a 2 ×2sin 22θ​ s=2asin 2θ​ =2asin 2ωt​ Hope it helps youPlz mark it as BRAINLIEST answer

I THINK it's TOTAL RESISTANCE is 5 and current flowing in circuit is 10V-2+3 = 5Vhope it's helpful

Explanation:Distance travelled from A to B = 10 mDisplacement from A to B = 10 mTherefore distance and displacement are equal if the object travels in the same straight PATH(b) Distance travelled from A to C = AB + BC= 10 + 10= 20 mDisplacement from A to C = AC = \displaystyle 10\sqrt{2} m.Therefore distance travelled is always more than the displacement if there is a change in DIRECTION of motion(c) Distance travelled from A, back to A = AB + BC + CD + DA= 10 + 10 + 10 + 10 = 40 mDisplacement from A, back to A = 0 mThis is because the shortest distance between initial position (A) and FINAL position (A) is zero.Therefore the displacement of a moving object may be zero but distance travelled CANN

When n(1) is GREATER than n(2), the angle of refraction is ALWAYS larger than the angle of incidence. ... When the two refractive INDICES are EQUAL (n(1) = n(2)), then the light is passed through without refraction.Explanation:

Explanation:Let L be the latent specific heat of the METAL. When the metal is allowed to be solidified its MP i.e. 800  ∘ C, it will give out latent heat only. mL=75000 0.150×L=75000 L=500000Jkg  −1  ​    Now, Heat given out by the metal in cooling down to −50  ∘ C. Fall in temperature will be 800  ∘ C−(−50  ∘ C)=850  ∘ C Heat given out= m×s×t=(0.150×200×850)=25500J

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If a body travels EQUAL distance in equal time intervals, we can say it is in a constant velocity. There are very few examples of constant velocity MOTION around us. After reaching at terminal velocity, the motion of RAINDROPS are called constant velocity motion. As the magnitude of the air drag force is proportional to the velocity of the raindrops which pass through the air, the raindrops come down to a situation where they feel same magnitude of GRAVITATIONAL force and air drag force but these forces are opposite in direction. So, situation comes down to a conclusion where raindrops FALL at a constant velocity.

E=-i-j-2kExplanation:SEE the IMAGE. Hope it helps. Please MARK as brainliest pleaseeeee

heya ❤️Explanation:the kinetic energy of a PARTICLE moving in a straight line varies with respect to time. the FORCE acting on the particle is inversely PROPORTIONAL to the velcityhope it helps ✅

hey mateExplanation:equivalent resistance = 3+6+2+8 = 19 OHMI THINK this MIGHT be the correct answerhope it helped you PLEASE mark me as brainliest and follow me

ABC NV offer urged SAGA oven gf gd th hv hv hv uc ch if f if ch if ch h hod jejebfcjxjdbb hxjdrb dn dbhdrvpegeb R rdh tf ff Explanation:mg frrndi jaych hhfhshvrcdhvnuyfyfjfhfv HU e hv ch kb r the DISE vrvdjvdjt

Adiabatic compression is the process in which no heat is transferred to or from the system but the TEMPERATURE of the system changes. When we COMPRESS a gas in an adiabatic process the volume of the gas will DECREASE and the temperature of the gas rises as it is COMPRESSED which we seen the warming of a BICYCLE pump.

It's DISPLACEMENT will be EQUAL to the LENGTH of the SIDE BC.

of 1 E − =mg=9×10 −31 ×10=9×10 −30 We KNOW FORCE F=Eq⇒Eq=9×10 −30⇒E= 1⋅6×10 −19 9×10 −30 ⇒E=5⋅62×10 −11 N/C.mark me as BRAINLIEST

When the object is located at a LOCATION beyond the center of curvature, the image will always be located somewhere in between the center of curvature and the focal point. Regardless of exactly where the object is located, the image will be located in the specified region. In this case, the image will be an inverted image. That is to say, if the object is right side up, then the image is upside down. In this case, the image is reduced in size; in other WORDS, the image dimensions are smaller than the object dimensions. If the object is a six-foot tall person, then the image is less than six feet tall. Earlier in Lesson 2, the term magnification was introduced; the magnification is the ratio of the HEIGHT of the image to the height of the object. In this case, the absolute value of the magnification is less than 1. Finally, the image is a real image. Light rays actually converge at the image location. If a sheet of paper were placed at the image location, the ACTUAL replica of the object would appear projected upon the sheet of paper. Explanation: