1.

A body travels from point A to point D along a square path of side 10 m as shown in the above figure. The magnitude of displacement of the body isImmersive Reader (1 Point) 10 m 30 m 40 m 0

Answer»

Explanation:Distance travelled from A to B = 10 mDisplacement from A to B = 10 mTherefore distance and displacement are equal if the object travels in the same straight PATH(b) Distance travelled from A to C = AB + BC= 10 + 10= 20 mDisplacement from A to C = AC = \displaystyle 10\sqrt{2} m.Therefore distance travelled is always more than the displacement if there is a change in DIRECTION of motion(c) Distance travelled from A, back to A = AB + BC + CD + DA= 10 + 10 + 10 + 10 = 40 mDisplacement from A, back to A = 0 mThis is because the shortest distance between initial position (A) and FINAL position (A) is zero.Therefore the displacement of a moving object may be zero but distance travelled CANN



Discussion

No Comment Found

Related InterviewSolutions