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1. 4.167 m/s(II) 1000 kg/m^3HOPE I HAVE ANSWERED YOUR QUESTION PLS MARK ME AS BRAINLIEST

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plz mark it bestExplanation:According to Archimedes principle, the WEIGHT of water displaced is equal to the weight of immersed PART.For a SOLID FLOATING in a liquid, its weight acting vertically down at its centre of gravity is equal to the weight of the liquid displaced by the immersed part of the solid acting vertically up at its centre of buoyancy. In the floating CONDITION, the apparent weight and the apparent density of the solid are zero and the body is said to be weightless.

This law states that, for any node (junction) in an electrical circuit, the sum of CURRENTS FLOWING into that node is equal to the sum of currents flowing out of that node; or equivalently: The algebraic sum of currents in a NETWORK of CONDUCTORS meeting at a point is ZERO.

m = 1.600×1000 = 1600m150 CM = 150÷100 = 1.5m

-0.4139774364 it is your ANSWER of your QUESTION.

tion:Yes, we TAKE G as constant in problems because we are dealing with very small distances. in U =-Gm1m2/r² , For large change in r² U CHANGES slightly because G value is very small (6.67 X 10^-11 N m2/kg2)And as we are dealing problems with distances in METRES only ,g changes very slightly that we can neglect the change. During rocket propulsion g change should. be considered because the distances difference is large.HOPE IT HELPS YOU !

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the RESISTANCE of the WIRE is is becomes ONE by FOURTH of original resistanceRnew=R/4

Given a = 55° write equations for the sum of forces acting on the pin at C. B 1P3] Write equations lor the sum of forces acting on the connection. Use P 500 lb and 0 650 lb. Concept 4 - Force along a spring [P7] The unstretched length of the spring is R = 300 MM. CALCULATE the magnitude of the spring force acting on pin P when it is located at position 0 = 30°. Take k = 10 N/mm. CA 21 P +0 [P3] Write equations for the sum of forces acting on the connection. Use P= 500 lb and Q = 650 lb.

sical density of a MATERIAL refers to the mass/volume ratio. ... The more optically dense that a material is, the slower that a wave will move through the material. ONE INDICATOR of the optical density of a material is the index of REFRACTION VALUE of the material.

P = MG sin 30 + u mgcos 30= 500 × 1/2 + 0.3 × 500 × √3/2=509.8 NHope this will be helpful for you. PLEASE MARK my answer the Brainliest ONE!

What is question I don't UNDERSTAND ....PLZ WRITE in only one ENGLISH

tion:I THINK (c) is correct ANSWER I am not SURE but PLS MARK as brainlist

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about 14.68%EXPLANATION:EXPERIMENTAL value- ACTUAL value= error(11.25-9.81) m/s square=error error=1.44 m/s squarethe PERCENTAGE error=(1.44×100)÷9.81 =14.68% (about)

∵ Difference between the C.I of two successive years=Rs.880−968=Rs.88 ∴Rate of interest=  P×T 100×I ​   =  880×1 100×88 ​   =10% Let the SUM of money=Rs.100 ∴interest for ONE year=10% of 100=  100 10 ​   ×100=Rs.10 AMOUNT after one year=100+10=Rs.110 ∴Interest foe second year=10% of 110=  100 10 ​   ×110=Rs.11 When the interest for second  year is rs .11 then sum=Rs.100 When the interest for second year is Rs.880 then sum=  11 100 ​   ×880=Rs.8000Explanation:hope it is help youplease MARK as me brainlist

If a body travels a DISTANCE equal to 2πr in circular path, it will reach the same position where it started. So, its DISPLACEMENT is zero.Explanation:PLEASE MARK me as brainliest

size of object = 5 CM DISTANCE between CANCAVE mirror and object = 12 cm radius of mirror =20 cm

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tion:When an ebonite ROD is rubbed with fur then, it acquires a positive CHARGE and the wool gains a negative charge. There is the changing in charge not in MASS. But, if we CALCULATE the mass of electron then, it is losing its mass.

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I don't have ... which CLASS you are

cartecian PLANE and also draw concave mirror on the centre Place the object in front of mirror on the centre of CURVATURE Draw a image the image is form on under the centre of curvatureThe object distance should be t hiaken negative because if we GO left hand of cartecian plane on the x-axis the no. goes in negative but height of object should be taken positive because if we go upward on y-axis the no. Is positive In case of image both height and distance is negativeIf you MEASURE distance you PREFER x-axis and if you are measuring height you wii prefer y-axis

When studying springs and ELASTICITY, the 17ᵗʰ century physicist Robert Hooke noticed that the stress vs strain curve for MANY materials has a linear region. Within certain limits, the force required to stretch an elastic object such as a metal spring is directly proportional to the extension of the spring. This is known as Hooke's law and commonly written: \boxed{F=-kx}  F=−kx ​   start box, F, equals, minus, k, x, end box Where FFF is the force, xxx is the length of extension/compression and kkk is a constant of proportionality known as the spring constant which is usually given in \mathrm{N/m}N/mN, slash, m. Though we have not explicitly established the DIRECTION of the force here, the negative sign is customarily added. This is to signify that the restoring force due to the spring is in the opposite direction to the force which caused the displacement. Pulling down on a spring will cause an extension of the spring downward, which will in turn result in an upward force due to the spring. It is always important to make sure that the direction of the restoring force is specified consistently when approaching mechanics problems involving elasticity. For simple problems we can often interpret the extension xxx as a 1-dimensional vector; in this case the resulting force will also be a 1-dimensional vector and the negative sign in Hooke’s law will give the CORRECT direction of the force. When calculating xxx, it is important to remember that the spring itself will also have some nominal length L_0L  0 ​   L, start subscript, 0, end subscript. The total length LLL of a spring under extension is equal to the nominal length plus the extension, L=L_0 + xL=L  0 ​   +xL, equals, L, start subscript, 0, end subscript, plus, x. For a spring under compression, it would be L=L_0-xL=L  0 ​   −xL, equals, L, start subscript, 0, end subscript, minus, x. Exercise 1: A 75 kg person stands on a compression spring with spring constant 5000~\mathrm{N/m}5000 N/m5000, SPACE, N, slash, m and nominal length 0.25~\mathrm{m}0.25 m0, point, 25, space, m. What is the total length of the loaded spring? [Solution] Exercise 2a: You are designing a mount for moving a 1 kg camera smoothly over a vertical distance of 50 mm. The design calls for the camera to slide on a pair of rails, with a spring supporting the camera and pulling it up against the tip of an adjustment screw as shown in Figure 1. The nominal length of the spring is L_0=50~\mathrm{mm}L  0 ​   =50 mmL, start subscript, 0, end subscript, equals, 50, space, m, m.Explanation:hope it is help youplease mark as me brainlist

In liquids, the heat transfer takes PLACE by convection. ... HOT water is less dense than cold water and thus rises up in the fluid also transferring the heat with it. This form of heat transfer, CALLED convection, happens in all FLUIDS (liquid and gases) and is due to the actual motion of fluid particles.

tion:  Alpha (α) is coefficient of linear expansion.♦  Increase in length during expansion is CALLED linear expansion.It means object one side increases.Hence α = 1 BETA (β) is coefficient of superficial expansion.♦ Increase in AREA during expansion is called superficial expansion.We know area = Length × BreadthNo. of sides = 2Hence, β = 2Gamma (\gammaγ ) is coefficient of cubical expansion.♦ Increase in volume during expansion is called cubical expansion.We know, volume = Length × BREADTH × HeightNo. of sides = 3Hence,\gammaγ  = 3HOPE I HAVE ANSWERED YOUR QUESTION PLS MARK ME AS BRAINLIEST

One SCR conducts during the positive half cycle and the other during the negative half cycle and thus UNIDIRECTIONAL CURRENT FLOWS in the load circuit. The main advantage of this circuit over ordinary full-wave rectifier circuit is that the output voltage can be controlled by adjusting the gate current.Explanation:hope it is help youplease mark as me brainlist

firstly BRO COMPLETE THREE of SERIES and then all parallel

Open main menuWikipediaSearchWiki Loves MONUMENTS: Photograph a monument, help Wikipedia and win!Learn morePolishingLanguageDownload PDFWatchEditFor other uses, see Polish (disambiguation).Learn moreThis article needs additional citations for verification.Polishing is the process of creating a smooth and shiny surface by rubbing it or using a chemical action, leaving a surface with a significant specular reflection (still limited by the index of refraction of the material according to the Fresnel equations.)[1] In some materials (such as metals, glasses, black or transparent stones), polishing is also able to reduce diffuse reflection to minimal values. When an unpolished surface is magnified thousands of times, it usually looks like mountains and valleys. By repeated abrasion, those "mountains" are WORN down until they are flat or just small "hills." The process of polishing with abrasives starts with coarse ones and graduates to fine ones.Mechanical properties EditThe strength of polished products can be higher than their rougher counterparts owing to the removal of stress concentrations present in the rough surface. They take the form of corners and other defects which magnify the local stress beyond the inherent strength of the material.[2]Types EditMetalworking EditMain article: Polishing (metalworking)Other polishing processes include:BurnishingMass finishingTumble finishingVibratory finishingSodablastingWoodworking EditFrench polishingWood finishingOther EditChemical-mechanical polishing, which is used in semiconductor fabricationFabrication and testing of optical componentsFlame polishing, a type of polishing used on glass and thermoplasticsUltra-fine, abrasive paste polishing, polishing for soft or fragile work surfacesVapor polishing, a method of polishing PLASTICS to optical clarityReferences Edit Floor Scrubber, archived from the original on 2016-08-31, retrieved 2008-01-04. Zucuni, Camila Pauleski; Dapieve, Kiara Serafini; Rippe, Marília Pivetta; Pereira, Gabriel Kalil Rocha; Bottino, Marco Cícero; Valandro, Luiz Felipe (2019). "Influence of finishing/polishing on the fatigue strength, surface topography, and roughness of an yttrium-stabilized tetragonal zirconia polycrystals subjected to grinding". Journal of the Mechanical Behavior of BIOMEDICAL Materials. 93: 222–229. doi:10.1016/j.jmbbm.2019.02.013. PMID 30831358.External links Edit4 Steps of Marble PolishingFlex GuideWikimedia Commons has media related to Polishing.Look up polishing in Wiktionary, the free dictionary.Last edited 4 months ago by InternetArchiveBotRELATED ARTICLESAbrasiverough material used to shape objects by frictionSurface finishingrange of processes that alter the surface of an item to achieve a certain propertyFabrication and testing of optical componentsWikipediaContent is available under CC BY-SA 3.0 unless otherwise noted.Privacy policyTerms of UseDesktop

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tion:The third drop is LEAVING the tap at the instant the first touches the ground. How far above ... The WATER drops fall at regular intervals from a tap 5 m above the ground. ... Height of tap = 5m and (g) = 10m/sec 2.

check in the attachment DOT PRODUCT and CROSS product solutions for the GIVEN VECTORS

tion:Magnetic Field STRENGTH for ElectromagnetsThe NUMBER of turns of WIRE WITHIN the coil. The AMOUNT of current flowing in the coil. The type of core material.

(4-4 ) m is the ANSWEREXPLANATION:DISPLACEMENT is the SHORTEST DISTANCE

Power = Work done / time = Force x velocityThe track is frictionless, so no frictional force acts on the mass.If the track was horizontal, the power required to give the mass m a forward ACCELERATION a when it is moving with velocity v is given byPower = Force x velocity = (ma) x v = mavBut in this case, the track is inclined at an angle O to the horizontal. The COMPONENT of the WEIGHT of the mass (against motion) along the track is mg SIN O. Therefore, a force is required to keep the mass stationary (from moving down along the inclined track). This force should be equal in magnitude to the component of the weight so that the RESULTANT acceleration (when considering only the component of the weight and this force) is zero.This force would result in a power of mg sin O x v = mgv sin O.So total power = mav + mgv sinO

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Turbine efficiency is the RATIO of actual work output of the turbine to the net INPUT energy SUPPLIED in the FORM of FUEL.

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