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4. Determine the horizontal force P required to start moving the 500 N block as shown in figure 4 up the inclined surface. Assume us= 0.3.​

Answer»

P = MG sin 30 + u mgcos 30= 500 × 1/2 + 0.3 × 500 × √3/2=509.8 NHope this will be helpful for you. PLEASE MARK my answer the Brainliest ONE!



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