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This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
Water from a pipe is coming at a rate of 100 litres per minute. If the radius of the pipe is 5 cm, the Reynolds number for the flow is of the order of : (density of water = 1000 kg/m³, coefficient of viscosity of water = 1 mPa s)(A) 10³(B) 10⁶(C) 10²(D) 10⁴ |
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Answer» Answer: OPTION (D) 10⁴ Explanation: Reynolds number = p v d / n Volume of FLOW RATE = v * π r^2 On putting the numbers we GET, approx. 2 * 10⁴ HOPE THAT IT WAS HELPFUL!!!! MARK IT THE BRAINLIEST IF IT REALLY WAS!!!! |
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| 2. |
An upright object is placed at a distance of 40 cm in front of a convergent lens of focal length 20 cm. A convergent mirror of focal length 10 cm is placed at a distance of 60 cm on the other side of the lens. The position and size of the final image will be:(A) 40 cm from the convergent mirror, same size as the object (B) 20 cm from the convergent mirror, same size as the object (C) 40 cm from the convergent lens, twice the size of the object (D) 20 cm from the convergent mirror, twice the size of the object |
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Answer» Answer: a in DEPTH survey has revealed the first of THREE NEW FEATURES that have won the first two or three times a week of a series that will be released in may |
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| 3. |
Two particles move at right angle to each other. Their de Broglie wavelengths are λ₁ and λ₂respectively. The particles suffere perfectly inelastic collision. The de Broglie wavelength λ , of the final particle, is given by: (A) λ = √(λ₁λ₂)(B) λ = (λ₁ + λ₂)/2(C) 2/λ = 1/λ₁ + 1/λ₂(D) 1/λ² = 1/λ₁² + 1/λ₂² |
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Answer» C OPTIONS is Right Answer is Right please MAKE me Brainlist have a Nice day...... |
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| 4. |
Voltage rating of a parallel plate capacitor is 500V. Its dielectric can withstand a maximum electric field of 10⁶ V/m . The plate area is 10⁻⁴ m². What is the dielectric constant if the capacitance is 15 pF? (given ∈ₒ = 8.86 × 10⁻¹² C²/ Nm² )(A) 3.8 (B) 6.2(C) 4.5 (D) 8.5 |
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Answer» Answer: Please make me Brainlist Have a NICE day |
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| 5. |
A boy’s catapult is made of rubber cord which is 42 cm long, with 6 mm diameter of cross – section and of negligible mass. The boy keeps a stone weighing 0.02 kg on it and stretches the cord by 20 cm by applying a constant force. When released, the stone flies off with a velocity of 20 ms⁻¹. Neglect the change in the area of cross section of the cord while stretched. The Young’s modulus of rubber is closest to: (A) 10³ Nm⁻²(B) 10⁶ Nm⁻²(C) 10⁸ Nm⁻²(D) 10⁴ Nm⁻² |
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Answer» please MAKE me Brainlist Have a NICE day.. |
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| 6. |
A 20 Henry inductor coil is connected to a 10 ohm resistance in series as shown in figure. The time at which rate of dissipation of energy (Joule’s heat) across resistance is equal to the rate at which magnetic energy is stored in the inductor, is(A) 2/(ln2)(B) ln2(C) (1/2)ln2(D) 2(ln2) |
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Answer» Answer: Explanation: HOPE the answer will help you |
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| 7. |
An alternating voltage v (t) 220 sin100πI volt is applied to a purely resistive load of 50Ω . The time taken for the current to rise from half of the peak value of the peak value is:(A) 2.2 ms (B) 3.3 ms(C) 5 ms (D) 7.2 ms |
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Answer» A Options is RIGHT Answer please MAKE me Brainlist have a Nice DAY.. |
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| 8. |
A wire of length 2L is made by joining two wires A and b of same lengths but different radii r and 2r and made of the same material. It is vibrating at a frequency such that the joint of the two wires forms a node. If the number of antinodes in wire A is p and that in B is q then the ratio p : q is:(A) 1 : 4 (B) 1 : 2(C) 3 : 5 (D) 4 : 9 |
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Answer» Let MASS per UNIT LENGTH of wires are μ1 and μ2 respectively. ∵ Materials are same, so density ρ is same. ∴μ1=Lρπr2L=μ and μ2=Lρ4πr2L=4μ Tension in both are same =T, let speed of wave in wires are V1 and V2 V1=μT=V.V2=4μT=2V So fundamental frequencies in both wires are f01=2LV1=2LV and f02=2LV2 |
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| 9. |
Four particles A, B, C and D with masses ᵐA = m, ᵐB = 2m, ᵐC = 3m and ᵐD = 4m are at thecorners of a square. They have accelerations of equal magnitude with directions as shown. The acceleration of the centre of mass of the particles is :(A) a/5(î – j^) (B) Zero (C) a/5(î + j^) (D) a(î – j^) |
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Answer» C options is RIGHT Answer please MAKE me Brainlist have a Nice DAY ............................... |
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| 10. |
Two identical beakers A and B contain equal volumes of two different liquids at 60° Ceach and left to cool down. Liquid in A has density of 8 × 10² kg/m³ and specific heat of 2000 Jkg⁻¹ K⁻¹ while liquid in B has density of 10³ kgm⁻³and specific heat of 4000Jkg⁻¹ K⁻¹ . Which of the following best describes their temperature versus time graph schematically? (assume the emissivity of both the beakers to be the same) |
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Answer» Answer: NYT and is the most important part in a NEW world class act and a LOT more than that will happen to you good LUCK if it doesn't work |
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| 11. |
If 10²² gas molecules each of mass 10⁻²⁶kg collide with a surface (perpendicular to it) elastically per second over an area 1 m² with a speed 10⁴ m/s, the pressure exerted by the gas molecules will be of the order of: (A) 10⁸ N/m²(B) 10³ N/m²(C) 10⁴ N/m²(D) 10¹⁶ N/m² |
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Answer» Answer: 77 inches of a barrel from a lot more to a lot more to me about in my FRIEND I was not able and the WAY we save the world is to get a good DEAL and a good morning foreign and a lot more to me and the more you are GOING through a bit |
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| 12. |
A particle moves in one dimension from rest under the influence of a force that varies with the distance traveled by that varies with the distance traveled by the particle as shown in the figure. The kinetic energy of the particle after it has traveled 3 m is:(A) 2.5 J (B) 4 J(C) 5 J(D) 6.5 J |
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Answer»
According to work ENERGY theorem Work done by force on the PARTICLE = CHANGE in KE Work done = AREA of F−x graph =∫F.dx =2×2+2(2+3)×1 W=KEfinal−KEinitial=6.5 KEinitial=0 KEfinal=6.5 J. |
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| 13. |
State and prove parallel axis thereom and its two application? |
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Answer» The theorem of parallel axis states that the moment of inertia of a body about an axis parallel to axis passing through CENTRE of MASS is equal to the sum of the moment of inertia of body about an axis passing through centre of mass and product of mass and SQUARE of distance between the TWO axes. Hope it helps Mark it as BRAINLIEST if you are satisfied with the answer |
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| 14. |
Find potential difference between E and G |
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Answer» Potential difference between two points in a current-carrying conductor is said to be 1 VOLT if 1 joule of WORK is DONE to CARRY a charge of 1 coulomb from one point to the other,i.e., 1volt=1joule1coulomb or 1V=1J1C=1JC-1. |
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| 15. |
24. Derive an expression for nuclear bindingenergy.(3 marks) |
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Answer» Answer: nuclear binding ENERGY can be calculated by converting that MASS to energy by USING E=mc^2 .mass must be in UNITS of KG. |
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| 16. |
Kis kisne corona per song banaya hai.. |
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Answer» HEY GUYS PLEASE FOCUS on the LATEST NEWS THAT IS DELIVERED RECENTLY BY OUR PM . ON THE TOPIC "CORONA" AND GIVE YOUR BESST TO PROTECT OURSELVES FORM THIS GREAT DEPRESSION BY FOLLOWING HIS ORDERS ,,❣❣✌ BE SAFE ... YOU ALL ARE REQUESTED TO LISTEN HIS SPEECH ☺ THANKS. |
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| 17. |
If theveryone unit of force is 1 kilo newton, the length is 1 km and time is 100 sec what will be the unit of mass |
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Answer» Answer: the answer is 1 KILOGRAM; UNIT is kg. pls THANK my answer and MARK as brainliest Explanation: |
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| 18. |
Suppose a spacecraft is receding from earth at 2/10 speed of light. a light in the spacecraft appears blue to passengers in it. what colour does it appear to the people on earth? |
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Answer» Red. This is due to the REDSHIFT effect. The light faces an increase in wavelength, so to the observers, it will appear red because red has he highest wavelength. Please MARK as brainliest because it REALLY HELPS me a lot ✌️ |
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| 19. |
An air column in a pipe which is closed at one end,is in resonance with the vibrating body of frequency 83Hz .Then the length of air column is :(velocity of sound in air=332m÷s |
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Answer» L = 100cm Explanation: |
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| 20. |
What is the metal ???????????????and non metal???????? |
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Answer» Answer: Metal is a type of SOLID substance that is usually hard and shiny and that heat and electricity can TRAVEL through. Nonmetal is a chemical element that MOSTLY LACKS the characteristics of a metal. Physically, a nonmetal TENDS to have a relatively low melting point, boiling point, and density. A nonmetal is typically brittle when solid and usually has poor thermal conductivity and electrical conductivity. |
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| 21. |
Find the total resistance , find the total currentthe voltage drop in 84 resistorthe power in the 84 resistor |
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Answer» Explanation: |
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| 22. |
A body is moving with uniform accelerationdescribes 40 m in the first 5 sec and 65 m innext 5 sec. Its initial velocity will be |
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Answer» Answer: 5m/sec Explanation: distance=d d1=40m d2=65m time(t)=5sec velocity=d/t d1-d2/t 65-40/5 25/5 5 velocity=5 m/sec(ANS) |
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| 23. |
If I weighed 50N, then how much N will I weigh on Mars? And how much for Jupiter? |
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Answer» Gravity in earth is = 10 N/kg so mass is = 50 ÷ 10 = 5 kg So FIRST gravity at MARS is = 3.7 N/kg therefore weight at Mars is = 3.7 × 5 = 18.5 N Gravity at Jupiter is = 25 N/kg therefore weight at Jupiter = 25 × 5 = 125 N |
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| 24. |
The resultant R of and is perpendicularto P. Also P = R . The angle between Pcand Q is [tan 45º = 1] |
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| 25. |
An excited He⁺ ion emits two photons in succession, with wavelengths 108.5 nm and 30.4 nm, in making a transition to ground state. The quantum number n, corresponding to its initial excited state is (for photon of wavelength λ, energy E = 1240 eV/λ(in nm) :)(A) n = 4 (B) n = 6(C) n = 5 (D) n = 7 |
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| 26. |
At 40°C, a brass wire of 1 mm is hung from the ceiling. A small mass, M is hung from the free end of the wire. When the wire is cooled down from 40ºC to 20ºC it regains its original length of 0.2 m. The value of M is close to :(Coefficient of linear expansion and Young's modulus of brass are 10⁻⁵/ºC and 10¹¹ N/m², respectively; g = 10 ms⁻²)(A) 0.5 kg (B) 9 kg(C) 0.9 kg (C) 1.5 kg |
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Answer» 9kg |
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| 27. |
The stopping potential V₀ (in volt) as a function of frequency (v) for a sodium emitter, is shown in the figure. The work function of sodium, from the data plotted in the figure, will be :(Given : Planck's constant (h) = 6.63 × 10⁻³⁴ Js, electron charge e = 1.6 × 10⁻¹⁹ C)(A) 1.82 eV (B) 1.66 eV(C) 2.12 eV (D) 1.95 eV |
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Answer» hv=ϕ+ev0 v0=ehv−eϕ 0=ehv−eϕ⇒ϕ=hv =1.6×10−196.63×10−34×4×1014=1.66eV. |
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| 28. |
An electric dipole is formed by two equal and opposite charges q with separation d. The charges the same mass m. It is kept in a uniform electric field E. If it slightly rotated from its equilibrium orientation, then its angular frequency ω is:(A) √(qE/2md)(B) √(2qE/md)(C) √(qE/md)(D) 2√(qE/md) |
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Answer» OPTION (B) √(2 q E / m d) Explanation: MOMENT of INERTIA (I) = m ( d / 2)^2 * 2 Now by τ= Iα (q E)(d sinθ)= m d^2α / 2 ⇒α=( 2 q E/m d ) ⇒ Angular frequency ω = √(2 q E / m d) HOPE THAT IT WAS HELPFUL!!!! MARK IT THE BRAINLIEST IF IT REALLY WAS!!!!
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| 29. |
50 W/m² energy density of sunlight is normally incident on the surface of a solar panel. Some part of incident energy (25%) is reflected from the surface and the rest is absorbed. The force exerted on 1 m² surface area will be close to (c = 3 × 10⁸ m/s)(A) 15 × 10⁻⁸ N(B) 35 × 10⁻⁸ N(C) 10 × 10⁻⁸ N(D) 20 × 10⁻⁸ N |
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| 30. |
A rectangles solid box of length 0.3 m is held horizontally, with one of its sides on the edge of a platform of height 5.. When released, it slips off the table in a very short time = 0.01 s, remaining essentially horizontal. The angle by which it would rotate when it hits the ground will be (in radians) close to:(A) 0.5 (B) 0.6(C) 0.02 (D) 0.28 |
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Answer» D. will be correct answers MARK the answer BRAINLIESTS please |
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| 31. |
Space between two concentric conducting spheres of radii a and b (b >a) is filled with a medium of resistivity rho. The resistance between the two spheres will be(A) rho/2π(1/a + 1/b)(B) rho/2π(1/a - 1/b)(C) rho/4π(1/a + 1/b)(D) rho/4π(1/a - 1/b) |
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Answer» dR=ρ.4πx2dx ∫dR=ρ.∫ab4πx2dx R=4πρ[−x1]ab R=4πρ(a1−b1) |
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| 32. |
A body of mass m₁ moving with an unknown velocity of v₁î undergoes a collinear collision with a body of mass m₂ moving with a velocityv₂î . After collision m₁ and m₂ move with velocities of v₃î and v₄î respectively.If m₂ = 0.5 m₁ and v₃ = 0.5 v₁ then v₁ is:(A) v₄ - v₂/2(B) v₄ - v₂/4(C) v₄ -v₂ (D) v₄ +v₂ |
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Answer» B options please MAKE me Brainlist how are you |
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| 33. |
Light is incident normally on a completely absorbing surface with an energy flux of 25 W cm⁻². If the surface has an area of 25 cm², the maximum transferred to the surface in 40 min time duration will be(A) 6.3 × 10⁻⁴ Ns (B) 3.5 × 10⁻⁶ Ns(C) 5.0 × 10⁻³ Ns (D) 1.4 × 10⁻⁶ Ns |
Answer» ANSWER:Correct OPTION is : ( C ). 5.0 × 10⁻³ NS Explanation :Refer the ATTACHED picture. |
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| 34. |
The physical sizes of the transmitter and receiver antenna in a communication system are:(A) Proportional of carrier frequency (B) Inversely proportional to modulation frequency (C) Inversely proportional to carrier frequency (D) Independent of both carrier and modulation frequency |
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Answer» RT to get a CHANCE of WINNING a condition in a row and a place to go |
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| 35. |
The following bodies are made to roll up (without slipping) the same inclined plane from a horizontal place: (i) a ring of radius R, (ii) a solid cylinder of radius R/2and (iii) a solid sphere of radius R/4. If, in each case, the speed of the center of mass at bottom of the incline is same, the ratio of the maximum heights they climb is :(A) 10 : 15 : 7 (B) 14: 15: 20(C) 4 : 3 : 2 (D) 2 : 3 : 4 |
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Answer» Given: The following bodies are made to roll up (without slipping) the same inclined plane from a horizontal place: (i) a ring of radius R, (II) a solid cylinder of radius R/2 and (iii) a solid sphere of radius R/4 To FIND: The ratio of the maximum heights they climb? Solution:
1/2 mv² x (1 + k²/r²) = mgh
h1 : h2 : h3 = (1 + 1) : (1 + 1/2) : (1 + 2/5) h1 : h2 : h3 = 2 : 3/2 : 7:5 h1 : h2 : h3 = 20 : 15 : 14 Answer: So the ratio is 20 : 15 : 14 |
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| 36. |
The logic gate equivalent to the given logic circuit is:(A) OR (B) AND(C) NOR (D) NAND |
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Answer» nand Explanation: The NAND gate is significant because any boolean function can be implemented by using a COMBINATION of NAND gates. This property is called functional completeness. It SHARES this property with the NOR gate. Digital systems employing certain LOGIC circuits take ADVANTAGE of NAND's functional completeness. |
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| 37. |
Water from a tap emerges vertically downwards with an initial speed of 1.0 ms⁻¹. The cross-sectional area of the tap is 10⁻⁴m². Assume that the pressure is constant throughout the stream of water and that flow is streamlined. The cross-sectional area of the stream, 0.15 m below the tap would be: (take g = 110 ms⁻²)(A) 5 × 10⁻⁴ m²(B) 5 × 10⁻⁵ m²(C) 1 × 10⁻⁵ m²(D) 2 × 10⁻⁵ m² |
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Answer» humus and a variety that can also help to get the DESIRED EFFECT of a natural LIGHT in a plant that can cause the disease in a few days and a day can cause SEVERE damage in |
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| 38. |
A magnetic compass needle oscillates 30 times per minute at a place where the dip is 45°, and 40 times per minute where the dip is 30º. If B₁ and B₂ are respectively the total magnetic field due to the earth at the two places, then the ratio B₁/B₂ is best given by :(A) 3.6 (B) 1.8 (C) 2.2 (D) 0.7 |
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Answer» D. will be correct answers MARK the answer BRAINLIESTS please |
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| 39. |
A concave mirror for face viewing has focal length of 0.4 m. The distance at which you hold the mirror from your face in order to see your image upright with a magnification of 5 is:(A) 0.16 m (B) 1.60 m(C) 0.24 m (D) 0.32 m |
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Answer» ANSWER m=f−uf 5=−40−u−40 u=−32cm |
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| 40. |
If the force is 15N and the mass is 15 kg what will the acceleration be ? |
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Answer» Answer: FORCE = MASS * ACCELERATION ∴ acceleration = force / mass acceleration = 15 / 15 acceleration = 1 m/s^2 pls THANK my answer and mark as brainliest Explanation: |
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| 41. |
Two moles of helium gas is mixed with three moles of hydrogen molecules (taken to be rigid). What is the molar specific heat of mixture at constant volume? (R = 8.3 J/mol K)(A) 17.4 J/mol K (B) 15.7 J/mol K(C) 19.7 J/mol K (D) 21.6 J/mol K |
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Answer» fmix=n1+n2n1f1+n2f2=52×3+3×5=521 Cv=2fR=521×2R=17.4 J/mol K. |
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| 42. |
The ratio of mass densities of nuclei of ⁴⁰Cₐ and ¹⁶O is close to:(A) 0.1 (B) 5(C) 2 (D) 1 |
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Answer» Option (D) 1 HOPE THAT IT WAS HELPFUL!!!! MARK IT THE BRAINLIEST IF IT REALLY WAS!!!! |
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| 43. |
The area of a square is 5.29 cm² The area of 7 such squares taking into account the significant figures is:(A) 37 cm²(B) 37.0 cm²(C) 37.03 cm²(D) 37.030 cm² |
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Answer» Answer: area of one square = 5.29 cm^2 area of seven such squares = 5.29 * 7 = 37.03 cm^2 therefore OPTION C) is the CORRECT answer pls thank my answer and mark as brainliest Explanation: |
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| 44. |
Why sun appears red in colour |
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Answer» Answer: because blue is scattering is greater than RED colour so the SUN APPEAR red colour |
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| 45. |
A metal coin of mass 5 g and radius 1 cm is fixed to a thin stick AB of negligible mass as shown in the figure. The system is initially at rest. The constant torque, that will make the system rotate about AB at 25 rotations per second is 5 s is close to (A) 2.0 × 10⁻⁵ Nm (B) 4.0 × 10⁻⁶ Nm(C) 1.6 × 10⁻⁵ Nm (D) 7.9 × 10⁻⁶ Nm |
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Answer» REFER to the ATTACHMENT for the SOLUTION |
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| 46. |
The time dependence of the position of a particle of mass m = 2 is given by ⃗r(t) = 2tî - 3t²jˆ Its angular momentum with respect to the origin at time t = 2 is . (A) -48 kˆ (B) 48(î +jˆ)(C) 36 kˆ (D) -34(kˆ -î ) |
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Answer» Answer: B OPTIONS is Right Answer please make me Brainlist |
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| 47. |
A signal A cos ωt is transmitted using V₀ sin ω₀t as carrier wave. The correct amplitude modulated (AM) signal is:(A) v₀ sin [ω₀(1 + 0.01A sin ωt)t](B) (v₀ sin ω₀t) + [(A/2)sin(ω₀- ω)t] + [(A/2)sin(ω₀+ ω)t](C) v₀sin ω₀t + A cos ωt(D) (v₀ + A) cos ωt sin ω₀t |
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Answer» D options is RIGHT answer please make me Brainlist have a Nice day |
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| 48. |
Acceleration of two trains are a1 and a2.Two trains enter a bridge with the velocity of u1 and u2 respectively and cross the bridge by same time. Prove that the length of the bridge is *......{2(u1-u2)(u1a2-u2a1)}÷(a1-a2)²......* |
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| 49. |
How is kinetic energy related to the velocity of a moving object |
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Answer» ------------- ● K.E.= 1/2(mv^2) I.e. kinetic ENERGY of a body is DIRECTLY PROPORTIONAL to the square of its VELOCITY.
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| 50. |
Name two derived physical quantity each of whichinvolves a single but different fundamental physical quantity.Also write down in bracket, beside the derived quantity, the involved fundamental quantity. |
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Answer» Answer: UNITS of derived QUANTITIES are CALLED derived units eg.newton,erg,joule.etc, |
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