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The stopping potential V₀ (in volt) as a function of frequency (v) for a sodium emitter, is shown in the figure. The work function of sodium, from the data plotted in the figure, will be :(Given : Planck's constant (h) = 6.63 × 10⁻³⁴ Js, electron charge e = 1.6 × 10⁻¹⁹ C)(A) 1.82 eV (B) 1.66 eV(C) 2.12 eV (D) 1.95 eV |
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Answer» hv=ϕ+ev0 v0=ehv−eϕ 0=ehv−eϕ⇒ϕ=hv =1.6×10−196.63×10−34×4×1014=1.66eV. |
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