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Two particles move at right angle to each other. Their de Broglie wavelengths are λ₁ and λ₂respectively. The particles suffere perfectly inelastic collision. The de Broglie wavelength λ , of the final particle, is given by: (A) λ = √(λ₁λ₂)(B) λ = (λ₁ + λ₂)/2(C) 2/λ = 1/λ₁ + 1/λ₂(D) 1/λ² = 1/λ₁² + 1/λ₂² |
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Answer» C OPTIONS is Right Answer is Right please MAKE me Brainlist have a Nice day...... |
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