67486 + Interview Questions in Secondary School in Physics

1.	A body covers first one third of the distance with a velocity of 20m/s, the second one third with a speed of 30m/s and last one third with a velocity of 40 m/s.Then the average velocity will be
Answer» EXPLANATION: The ANSWER is = 27.6m/s

1.

A body covers first one third of the distance with a velocity of 20m/s, the second one third with a speed of 30m/s and last one third with a velocity of 40 m/s.Then the average velocity will be

Answer»

The ANSWER is = 27.6m/s

2.	45 points questionTwo constant forces F1 and F2 acts on a body.These forces displaces the body from point P(1,-2,3) to Q(2,3,7) in 2s starting from rest. Force F1 is of magnitude 9N and is acting along vector (2i-2j+k).Work done by the force F1 is ???
Answer» SORRY I don’t KNOW but you can SEARCH on GOOGLE

Discussion

3.	Alls SamsEXERCISE 6.4Motion of Rigid body, Rotational variables, Relation between linear and angularvariables, Rigid body constraintSpe. 21. Consider the 'L' shaped bar shown in figure. At the instant shown, the bar is rotating at 4 rad/s and is slowingrod down at the rate of 2 rad/s2.y-axisВ2 mMotorX-axis2m-a. Find the acceleration of point A.b. Find the relative acceleration as of point B with respect to point A.
Answer» Answer: The acceleration of A is 32.25 m/s² The relative acceleration of B w.r.t. point A is 13.4 m/s² Explanation: The question is: Consider the L shaped bar as shown in the figure. At the instant shown, the bar is rotating at 4 rad/s² and is slowing down at the RATE of 2 rad/s². (a) FIND the acceleration of point A (b) Find the relative acceleration of point B with respect to point A. Solution: The diagram is attached At point A the acceleration will have two components, the TANGENTIAL acceleration $a_t$ and teh radial acceleration $a_r$ If the angular acceleration is $\alpha$ then $\alpha=-2$ rad/s² Therefore, the tangential acceleration $a_t=\alpha\times r$ $\implies a_t=-2\times 2$ $\implies a_t=-4$ m/s^2 The radial acceleration will be the centripetal acceleration, therefore $a_r=\omega^2r$ Given the angular velocity $\omega=4$ rad/s THUS $a_r=4^2\times 2$ $\implies a_r=32$ m/s² Thus total acceleration at A $a_A=\sqrt{a_t^2+a_r^2}$ $\implies a_A=\sqrt{(-4)^2+(32)^2}$ $\implies a_A=\sqrt{4^2+4^2\times 8^2}$ $\implies a_A=4\sqrt{1+64}$ $\implies a_A=4\sqrt{65}$ $\implies a_A=32.25$ m/s² Similarly for point B The radial DISTANCE will be $\sqrt{2^2+2^2}$ or $2\sqrt{2}$ Thus the tangetial acceleration at B $a_t=2\sqrt{2}\times(-2)$ $a_t=-4\sqrt{2}$ The radial acceleration will be $a_r=4^2\times 2\sqrt{2}$ $\implies a_r=32\sqrt{2}$ Total acceleration at B $a_B=\sqrt{a_t^2+a_r^2}$ $\implies a_B=\sqrt{(-4\sqrt{2})^2+(32\sqrt{2})^2}$ $\implies a_B=\sqrt{4^2\times 2+4^2\times 8^2\times 2}$ $\implies a_B=4\sqrt{2+128}$ $\implies a_B=4\sqrt{130}$ $\implies a_B=45.65$ m/s² The relative acceleration of B with respect to A $a_{B/A}=45.65-32.25$ $\implies a_{B/A}=13.4$ m/s²

3.

Alls SamsEXERCISE 6.4Motion of Rigid body, Rotational variables, Relation between linear and angularvariables, Rigid body constraintSpe. 21. Consider the 'L' shaped bar shown in figure. At the instant shown, the bar is rotating at 4 rad/s and is slowingrod down at the rate of 2 rad/s2.y-axisВ2 mMotorX-axis2m-a. Find the acceleration of point A.b. Find the relative acceleration as of point B with respect to point A.

Answer»

Answer:

The acceleration of A is 32.25 m/s²

The relative acceleration of B w.r.t. point A is 13.4 m/s²

Explanation:

The question is:

Consider the L shaped bar as shown in the figure. At the instant shown, the bar is rotating at 4 rad/s² and is slowing down at the RATE of 2 rad/s².

(a) FIND the acceleration of point A

(b) Find the relative acceleration of point B with respect to point A.

Solution:

The diagram is attached

At point A the acceleration will have two components, the TANGENTIAL acceleration $a_t$ and teh radial acceleration $a_r$

If the angular acceleration is $\alpha$ then

$\alpha=-2$ rad/s²

Therefore, the tangential acceleration

$a_t=\alpha\times r$

$\implies a_t=-2\times 2$

$\implies a_t=-4$ m/s^2

The radial acceleration will be the centripetal acceleration, therefore

$a_r=\omega^2r$

Given the angular velocity $\omega=4$ rad/s

THUS

$a_r=4^2\times 2$

$\implies a_r=32$ m/s²

Thus total acceleration at A

$a_A=\sqrt{a_t^2+a_r^2}$

$\implies a_A=\sqrt{(-4)^2+(32)^2}$

$\implies a_A=\sqrt{4^2+4^2\times 8^2}$

$\implies a_A=4\sqrt{1+64}$

$\implies a_A=4\sqrt{65}$

$\implies a_A=32.25$ m/s²

Similarly for point B

The radial DISTANCE will be $\sqrt{2^2+2^2}$ or $2\sqrt{2}$

Thus the tangetial acceleration at B

$a_t=2\sqrt{2}\times(-2)$

$a_t=-4\sqrt{2}$

The radial acceleration will be

$a_r=4^2\times 2\sqrt{2}$

$\implies a_r=32\sqrt{2}$

Total acceleration at B

$a_B=\sqrt{a_t^2+a_r^2}$

$\implies a_B=\sqrt{(-4\sqrt{2})^2+(32\sqrt{2})^2}$

$\implies a_B=\sqrt{4^2\times 2+4^2\times 8^2\times 2}$

$\implies a_B=4\sqrt{2+128}$

$\implies a_B=4\sqrt{130}$

$\implies a_B=45.65$ m/s²

The relative acceleration of B with respect to A

$a_{B/A}=45.65-32.25$

$\implies a_{B/A}=13.4$ m/s²

Discussion

4.	द्रव्यमान,कार्य,त्वरण तथा दाब मे कौन सी राशि सदिश है ?
Answer» ANSWER:- ACCELERATION is a VECTOR QUANTITY.

4.

द्रव्यमान,कार्य,त्वरण तथा दाब मे कौन सी राशि सदिश है ?

Answer»

ANSWER:-

ACCELERATION is a VECTOR QUANTITY.

Discussion

5.	40 points question...........Two constant forces F1 and F2 acts on a body.These forces displaces the body from point P(1,-2,3) to Q(2,3,7) in 2s starting from rest. Force F1 is of magnitude 9N and is acting along vector (2i-2j+k).Work done by the force F1 is ???
Answer» REFER to the ATTACHMENT! (^^)

Discussion

6.	a non conducting solid sphere of radius R is uniformly charged .The magnitude of electric field due to sphere at a distance r from its centre
Answer» EXPLANATION: Answer refer in Attachment Thank you

6.

a non conducting solid sphere of radius R is uniformly charged .The magnitude of electric field due to sphere at a distance r from its centre

Answer»

EXPLANATION:

Answer refer in Attachment

Thank you

Discussion

7.	Two vessels seprately contains two ideal gases A and B at same tempraturethe pressure of A being twice that of B jnder suchconditions the density of A is found go be 1.5 tjmes densitu of B the ratio of molecular wejght of A and B is
Answer» ANSWER: ❤️❤️3/4 is answer❤️❤️ Explanation: ❤️❤️hello dear here is your answer MARK it brainlist OK and FOLLOW me.. :) ☺️☺️❤️❤️

7.

Two vessels seprately contains two ideal gases A and B at same tempraturethe pressure of A being twice that of B jnder suchconditions the density of A is found go be 1.5 tjmes densitu of B the ratio of molecular wejght of A and B is

Answer»

ANSWER:

❤️❤️3/4 is answer❤️❤️

Explanation:

❤️❤️hello dear here is your answer MARK it brainlist OK and FOLLOW me.. :) ☺️☺️❤️❤️

Discussion

8.	To min = 60 secaz 36 Chart
Answer» What's the EXACT QUESTION can U ELABORATE

8.

To min = 60 secaz 36 Chart

Answer»

What's the EXACT QUESTION can U ELABORATE

Discussion

9.	A particle moves 3m in positive direction of x axis ,5m making 53 degree with positive direction of x axis and 4 m in positive direction of y axis . what is its displacement ?
Answer» Answer: Displacement = 10 m Explanation: A particle MOVES 3m in positive direction of x axis => Distance in x direction = 3 m & Distance in y direction = 0 m Then 5m making 53 degree with positive direction of x axis => Distance in x direction = 5Cos53 = 5 * 0.6 = 3 m & Distance in Y Direction = 5Sin53 = 5 * 0.8 = 4 m 4 m in positive direction of y axis => Distance in x direction = 0 & Distance in y direction = 4 m Total Distance in x direction = 3 + 3 + 0 = 6m Total Distance in y direction = 0 + 4 + 4 = 8 m Total Displacement = √6² + 8² = √36 + 64 = √100 = 10 m Displacement = 10 m

9.

A particle moves 3m in positive direction of x axis ,5m making 53 degree with positive direction of x axis and 4 m in positive direction of y axis . what is its displacement ?

Answer»

Answer:

Displacement = 10 m

Explanation:

A particle MOVES 3m in positive direction of x axis

=> Distance in x direction = 3 m

& Distance in y direction = 0 m

Then 5m making 53 degree with positive direction of x axis

=> Distance in x direction = 5Cos53 = 5 * 0.6 = 3 m

& Distance in Y Direction = 5Sin53 = 5 * 0.8 = 4 m

4 m in positive direction of y axis

=> Distance in x direction = 0

& Distance in y direction = 4 m

Total Distance in x direction = 3 + 3 + 0 = 6m

Total Distance in y direction = 0 + 4 + 4 = 8 m

Total Displacement = √6² + 8² = √36 + 64 = √100

= 10 m

Displacement = 10 m

Discussion

10.	A weight of 70 N is suspended to a rigid support with the help of strings as shown..find tension in string
Answer» GIVEN: WEIGHT of the block = 70N To find: The tension in the strings. Solution: Let the tension in the strings be T1 and T2 and the angle they make with the horizontal surface of the support be α and β respectively. The EQUATION of forces for the horizontal components will be: T1 cosα = T2 cosβ T1 = T2 cos β/ cosα Now, the equation of forces for the vertical components will be: T1 sinα + T2 sinβ = mg T2 sinα cosβ/ cosα + T2 sinβ = mg T2((sinα cosβ/ cosα) + sinβ) = 700 T2 = 700/((sinα cosβ/ cosα) + sinβ) T1 = T2 cosβ/ cosα Therefore the tension can be FOUND out by PUTTING the value of angles in the equations.

10.

A weight of 70 N is suspended to a rigid support with the help of strings as shown..find tension in string

Answer»

GIVEN:

WEIGHT of the block = 70N

To find:

The tension in the strings.

Solution:

Let the tension in the strings be T1 and T2 and the angle they make with the horizontal surface of the support be α and β respectively.

The EQUATION of forces for the horizontal components will be:

T1 cosα = T2 cosβ

T1 = T2 cos β/ cosα

Now, the equation of forces for the vertical components will be:

T1 sinα + T2 sinβ = mg

T2 sinα cosβ/ cosα + T2 sinβ = mg

T2((sinα cosβ/ cosα) + sinβ) = 700

T2 = 700/((sinα cosβ/ cosα) + sinβ)

T1 = T2 cosβ/ cosα

Therefore the tension can be FOUND out by PUTTING the value of angles in the equations.

Discussion

11.	A converging lens produces a real, magnified and well defined image of a small iluminatedsquare on a screen. The area of the image is A1. When the lens is moved towards the screenwithout disturbing the object and the screen, the area of the well defined image obtained onthe screen is A2. What is the side of the square object?(a) (√A1 + √A2)/2(b) [(A1+ A2)/2]^1/2(c) (A1A2)^1/2(d) (A1A2)^1/4
Answer» Answer: Option (d) $(A_1A_2)^{1/4}$ Explanation: Let the side of the SQUARE is a The positions are conjugate positions. If in the FIRST case, the length of the image is a₁ then $\frac{<klux>V</klux>}{u}=\frac{a_1}{a}$ When the LENS is moved towards the screen, v and u will be interchanged. If the image size is a₂ then $\frac{u}{v}=\frac{a_2}{a}$ From the above two equations $\frac{a_1}{a}\times\frac{a_2}{a} =1$ $\implies a_1a_2=a^2$ $\implies a=\sqrt{a_1a_2}$ But $a_1=\sqrt{A_1}$ And $a_2=\sqrt{A_2}$ Therefore, $a=\sqrt{\sqrt{A_1}\sqrt{A_2}$ $\implies a=\sqrt{(A_1A_2)^{1/2}}$ $\implies a=((A_1A_2)^{1/2})^{1/2}$ $\implies a=(A_1A_2)^{1/4}$ Thus, CORRECT option is option (d)

11.

A converging lens produces a real, magnified and well defined image of a small iluminatedsquare on a screen. The area of the image is A1. When the lens is moved towards the screenwithout disturbing the object and the screen, the area of the well defined image obtained onthe screen is A2. What is the side of the square object?(a) (√A1 + √A2)/2(b) [(A1+ A2)/2]^1/2(c) (A1A2)^1/2(d) (A1A2)^1/4

Answer»

Answer:

Option (d) $(A_1A_2)^{1/4}$

Explanation:

Let the side of the SQUARE is a

The positions are conjugate positions. If in the FIRST case, the length of the image is a₁ then

$\frac{<klux>V</klux>}{u}=\frac{a_1}{a}$

When the LENS is moved towards the screen, v and u will be interchanged. If the image size is a₂ then

$\frac{u}{v}=\frac{a_2}{a}$

From the above two equations

$\frac{a_1}{a}\times\frac{a_2}{a} =1$

$\implies a_1a_2=a^2$

$\implies a=\sqrt{a_1a_2}$

But

$a_1=\sqrt{A_1}$

And $a_2=\sqrt{A_2}$

Therefore,

$a=\sqrt{\sqrt{A_1}\sqrt{A_2}$

$\implies a=\sqrt{(A_1A_2)^{1/2}}$

$\implies a=((A_1A_2)^{1/2})^{1/2}$

$\implies a=(A_1A_2)^{1/4}$

Thus, CORRECT option is option (d)

Discussion

12.	7. A girl has a small plastic tree. She wants to make a large tree cutout of the sameshape. Suggest a way to make it.& Give reasons for the following:
Answer» Answer: MAKE 2 part of the tree and chipka do USKE upar

12.

7. A girl has a small plastic tree. She wants to make a large tree cutout of the sameshape. Suggest a way to make it.& Give reasons for the following:

Answer»

Answer:

MAKE 2 part of the tree and chipka do USKE upar

Discussion

13.	A point travelling along a straight line, traversedone third the distance with a velocity vo. Theremaining part of the distance was covered withvelocity v, for half the time and with velocity v, forthe other half of the time. Find the mean velocity ofthe point averaged over the whole time of motion.
Answer» Answer: 6v0v1v2/(2V0 + V1 + v2) Explanation: Avg. velocity = total DISTANCE /total time = d/(d/3v0 + d/6v1 +d/6v2) = 1/(1/3v0 + 1/6v1 +1/6v2) = 3/(V0 + 0.5v1 + 0.5v2) = 6v0v1v2/(2v0 + v1 + v2)

13.

A point travelling along a straight line, traversedone third the distance with a velocity vo. Theremaining part of the distance was covered withvelocity v, for half the time and with velocity v, forthe other half of the time. Find the mean velocity ofthe point averaged over the whole time of motion.

Answer»

Answer:

6v0v1v2/(2V0 + V1 + v2)

Explanation:

Avg. velocity = total DISTANCE /total time

= d/(d/3v0 + d/6v1 +d/6v2)

= 1/(1/3v0 + 1/6v1 +1/6v2)

= 3/(V0 + 0.5v1 + 0.5v2)

= 6v0v1v2/(2v0 + v1 + v2)

Discussion

14.	Explain the sound wave are longitutuanal wave
Answer» HELLO MATE... Sound waves are longitudinal in nature as the particals of medium move in same direction LIKE that of the wave .. So in a nutshell the particle of medium Maybe air or water vibrate PARALLEL as that of the sound wave... (θ‿θ)

14.

Explain the sound wave are longitutuanal wave

Answer»

HELLO MATE...

Sound waves are longitudinal in nature as the particals of medium move in same direction LIKE that of the wave ..

So in a nutshell the particle of medium Maybe air or water vibrate PARALLEL as that of the sound wave...

(θ‿θ)

Discussion

15.	D. The force constant of a wire is k and that of another wire is 2k. When both the wires arestretched through same distance, then the work done[MH CET 2000](a) W2 = 2W?(b) W, = 2W,(c) = W(d) W, -0.5W,
Answer» ANSWER: W∝K K2=2K1 W2=2W1 MARK as BRAINLIEST

15.

D. The force constant of a wire is k and that of another wire is 2k. When both the wires arestretched through same distance, then the work done[MH CET 2000](a) W2 = 2W?(b) W, = 2W,(c) = W(d) W, -0.5W,

Answer»

ANSWER:

W∝K

K2=2K1

W2=2W1

MARK as BRAINLIEST

Discussion

16.	Tension in string AB
Answer» ANSWER: which STRING??????? P.S. tension. tension always ACTS in the opposite direction to the force applied. on a body freely SUSPENDED using a string it acts upwards

16.

Tension in string AB

Answer»

ANSWER:

which STRING??????? P.S. tension. tension always ACTS in the opposite direction to the force applied. on a body freely SUSPENDED using a string it acts upwards

Discussion

17.	Derivation of third equation of motion
Answer» ANSWER: u: velocity at time t1 v: velocity at time t2 a: uniform acceleration of the body ALONG the straight line Displacement covered during the time interval t2 - t1 = Area ABt1t2 S = Area of TRIANGLE ABA’ + Area of rectangle AA’t2t1 = Area of trapezium S = ½ x Sum of parallel sides x Perpendicular distance begin mathsize 12px style straight s equals 1 half open PARENTHESES straight v plus straight u close parentheses straight t end style ....... (Equation 1) From the first equation of motion, v = u + at; begin mathsize 12px style straight t equals fraction numerator straight v minus straight u over denominator straight a end fraction end style Substituting in equation 1, we get begin mathsize 12px style straight s equals 1 half open parentheses straight v plus straight u close parentheses fraction numerator open parentheses straight v minus straight u close parentheses over denominator straight a end fraction end style or, v2 – u2 = 2as which is the REQUIRED equation of motion. Explanation: mark as brainliest

17.

Derivation of third equation of motion

Answer»

ANSWER:

u: velocity at time t1

v: velocity at time t2

a: uniform acceleration of the body ALONG the straight line

Displacement covered during the time interval t2 - t1 = Area ABt1t2

S = Area of TRIANGLE ABA’ + Area of rectangle AA’t2t1 = Area of trapezium

S = ½ x Sum of parallel sides x Perpendicular distance

begin mathsize 12px style straight s equals 1 half open PARENTHESES straight v plus straight u close parentheses straight t end style ....... (Equation 1)

From the first equation of motion, v = u + at;

begin mathsize 12px style straight t equals fraction numerator straight v minus straight u over denominator straight a end fraction end style

Substituting in equation 1, we get

begin mathsize 12px style straight s equals 1 half open parentheses straight v plus straight u close parentheses fraction numerator open parentheses straight v minus straight u close parentheses over denominator straight a end fraction end style

or, v2 – u2 = 2as

which is the REQUIRED equation of motion.

Explanation:

mark as brainliest

Discussion

18.	85. Fig. shows the displacement of a particle movingalong x-axis as a function of time. The accelerationof the particle is zero in the region :of the1th anddisplacementtime(a) AB(c) CD(b) BCspeed v(d) DEnd
Answer» ANSWER: where is ur DIAGRAM of this questions... add a diagram for this QUESTION

18.

85. Fig. shows the displacement of a particle movingalong x-axis as a function of time. The accelerationof the particle is zero in the region :of the1th anddisplacementtime(a) AB(c) CD(b) BCspeed v(d) DEnd

Answer»

ANSWER:

where is ur DIAGRAM of this questions... add a diagram for this QUESTION

Discussion

19.	uniform circular motion is called continuously accelerated motion because a direction of motion changes continuously bi speech changes Si velocity remains the same the direction of motion does not change
Answer» PLZZ POST your QUESTION in SUITABLE MANNER..............

Discussion

20.	Find the difference between weight and mass of 5 objects
Answer» Mass is a property of matter. The mass of an OBJECT is the same everywhere.Weight depends on the effect of gravity. Weight INCREASES or decreases with higher or lower gravity.Mass can NEVER be zero.Weight can be zero if no gravity ACTS UPON an object, as in space.Mass does not change according to location.Weight varies according to location.Mass is a scalar quantity. It has magnitude.Weight is a vector quantity. It has magnitude and is directed toward the center of the Earth or other gravity well.Mass may be measured using an ordinary balance.Weight is measured using a spring balance

Discussion

21.	A bike moves 100m along north. 400m along south and finally 400malong west. What is total displacement of bike from initial point?
Answer» EXPLANATION: v400^2+400^2 =v320000=565.6m

21.

A bike moves 100m along north. 400m along south and finally 400malong west. What is total displacement of bike from initial point?

Answer»

EXPLANATION:

v400^2+400^2 =v320000=565.6m

Discussion

22.	what do you mean by, "gravitational force is significant between heavenly bodies but is insignificant in between ordinary bodies"?
Answer» Answer: The mass of an ordinary body is too LESS for gravitational FORCE to show a LARGE affect on them . But heavenly BODIES have a very large mass and hence gravitational force acting between them can be felt . Hope it helps. If the answer is helpful please MARK it as the brainliest

22.

what do you mean by, "gravitational force is significant between heavenly bodies but is insignificant in between ordinary bodies"?

Answer»

Answer:

The mass of an ordinary body is too LESS for gravitational FORCE to show a LARGE affect on them . But heavenly BODIES have a very large mass and hence gravitational force acting between them can be felt .

Hope it helps.

If the answer is helpful please MARK it as the brainliest

Discussion

23.	I am not getting the ans?
Answer» ANSWER: F=tension=Mgsin∅ a=F/m1+m2 both MASSES are of EQUAL masses so, m1+m2=2M a=Mgsin∅/2M a=gsin∅/2 mark as brainliest Explanation:

23.

I am not getting the ans?

Answer»

ANSWER:

F=tension=Mgsin∅

a=F/m1+m2

both MASSES are of EQUAL masses so,

m1+m2=2M

a=Mgsin∅/2M

a=gsin∅/2

mark as brainliest

Explanation:

Discussion

24.	Why do clouds appear white on green colour why not of any other particular colour
Answer» When clouds are white (and many are not), “it's because LIGHT from the sun is white, a combination of all the colors of the rainbow,” said Michael Kaufman, professor of physics and astronomy at San Jose State University in CALIFORNIA. As light moves through the clouds, it is DISPERSED by water droplets. please do mark me as brainliest

24.

Why do clouds appear white on green colour why not of any other particular colour

Answer»

When clouds are white (and many are not), “it's because LIGHT from the sun is white, a combination of all the colors of the rainbow,” said Michael Kaufman, professor of physics and astronomy at San Jose State University in CALIFORNIA. As light moves through the clouds, it is DISPERSED by water droplets.

please do mark me as brainliest

Discussion

25.	I need ans with explanation? Chapter- Newton's laws of motion
Answer» ANSWER: this answer is a)=0 . MASS have NEGLIGIBLE that why answer is ${0}^{ 0}$

25.

I need ans with explanation? Chapter- Newton's laws of motion

Answer»

ANSWER:

this answer is a)=0 .

MASS have NEGLIGIBLE

that why answer is

${0}^{ 0}$

Discussion

26.	Hii guys.... how are you all ?? your question is what is linear momentum ?? følløw Mē gūyß❤❤❤
Answer» Answer . In newtonian mechanics , linear momentum translational momentum , or simply momentum isthe product of yhe MASS and velocity of an object . It is a vector quantity, possesing a MAGNITUDE and a DIRECTIONAL in three dimnsional space SI UNIT :kg.m/s OTER UNITS :SLUG .ft /s COMMON SYMBOL: p .

26.

Hii guys.... how are you all ?? your question is what is linear momentum ?? følløw Mē gūyß❤❤❤

Answer»

Answer .

In newtonian mechanics , linear momentum translational momentum ,

or simply momentum isthe product of yhe MASS and velocity of an object .

It is a vector quantity, possesing a MAGNITUDE and a DIRECTIONAL in three dimnsional space

SI UNIT :kg.m/s

OTER UNITS :SLUG .ft /s

COMMON SYMBOL: p .

Discussion

27.	what is the cause of lateral inversion why is it that the images flipped only horizontally but not vertically
Answer» Explanation: To MAINTAIN the PROPERTY of IMAGE FORMATION by a plane mirror that is image distance is EQUAL to object distance.The image of an object is located at the same distance behind the mirror as the object is located infront of it.

27.

what is the cause of lateral inversion why is it that the images flipped only horizontally but not vertically

Answer»

Explanation:

To MAINTAIN the PROPERTY of IMAGE FORMATION by a plane mirror that is image distance is EQUAL to object distance.The image of an object is located at the same distance behind the mirror as the object is located infront of it.

Discussion

28.	The velocity-time graph (v-t) of a car moving along alevel road is shown below. The average speed of thecar in the time interval 0 to 8 s is about???
Answer» Answer: 4.48 m/s Explanation: VELOCITY at t = 0 is 10 m/s Velocity at t = 5 sec is -5 m/s Acceleration = (-5 -10)/(5 - 0) = - 3 m/s² Distance COVERED till SPEED becomes 0 using V² - U² = 2AS => S = (0² - 10²)/(2(-3)) => S = 50/3 m Distance covered from 0 velocity to - 5 = 5²/2(-3) = 25/6 m (in opposite direction) From 5 to 8 Sec Distance covered = -5 * 3 = 15 m ( in opposite direction) Total Distance Covered = 50/3 + 25/6 + 15 = 215/6 m Time = 8 sec Average Speed = (215/6)/8 = 4.48 m/s Average Velocity = (50/3 - 25/6 - 15)/8 = - 15/48 = -0.3125 m/s

28.

The velocity-time graph (v-t) of a car moving along alevel road is shown below. The average speed of thecar in the time interval 0 to 8 s is about???

Answer»

Answer:

4.48 m/s

Explanation:

VELOCITY at t = 0 is 10 m/s

Velocity at t = 5 sec is -5 m/s

Acceleration = (-5 -10)/(5 - 0)

= - 3 m/s²

Distance COVERED till SPEED becomes 0

using V² - U² = 2AS

=> S = (0² - 10²)/(2(-3))

=> S = 50/3 m

Distance covered from 0 velocity to - 5

= 5²/2(-3)

= 25/6 m (in opposite direction)

From 5 to 8 Sec

Distance covered = -5 * 3

= 15 m ( in opposite direction)

Total Distance Covered

= 50/3 + 25/6 + 15

= 215/6 m

Time = 8 sec

Average Speed = (215/6)/8 = 4.48 m/s

Average Velocity = (50/3 - 25/6 - 15)/8 = - 15/48 = -0.3125 m/s

Discussion

29.	What is the Newton third law of motion????
Answer» ANSWER: EVERY action has EQUAL and opposite reaction. please MARK brainliest

29.

What is the Newton third law of motion????

Answer»

ANSWER:

EVERY action has EQUAL and opposite reaction.

please MARK brainliest

Discussion

30.	Cotton candy machine is a physics or chemistry model
Answer» ANSWER: cotton CANDY machine is a chemical model.

30.

Cotton candy machine is a physics or chemistry model

Answer»

ANSWER:

cotton CANDY machine is a chemical model.

Discussion

31.	An object is 100 mm in front of a concave mirror which produces an upright image.What is the radius of curvature of the mirror and how.
Answer» The RADIUS of curvature of the MIRROR is greater than 200 mm. As per the question, the image formed is erect. In this case, the object is placed between pole and focus. Since the object distance is 100 mm, the focal length must be greater than 100 mm. Radius of curvature is twice the focal length. HENCE, radius of curvature must be greater than 200 mm. PO = 100 mm PF = f > 100 mm [∵ O LIES between P and F] PC = R = 2f > 200 mm

31.

An object is 100 mm in front of a concave mirror which produces an upright image.What is the radius of curvature of the mirror and how.

Answer»

The RADIUS of curvature of the MIRROR is greater than 200 mm.

As per the question, the image formed is erect.
In this case, the object is placed between pole and focus.
Since the object distance is 100 mm, the focal length must be greater than 100 mm.
Radius of curvature is twice the focal length. HENCE, radius of curvature must be greater than 200 mm.

PO = 100 mm

PF = f > 100 mm [∵ O LIES between P and F]

PC = R = 2f > 200 mm

Discussion

32.	Calculate theforce in5ooopain 300 cm2 area
Answer» ANSWER: EXPLANATION:hhhhhhh

32.

Calculate theforce in5ooopain 300 cm2 area

Answer»

ANSWER:

EXPLANATION:hhhhhhh

Discussion

33.	What is sin theta square?
Answer» ANSWER: Sin 2 THETA is the sine of the angle which is double the value of theta. A formula to calculate sin 2 theta is: Sin 2 theta = 2 x (sin theta) x (COS theta) (x denotes multiplication) This can be used when you KNOW the value of sine and cosine of theta and not 2 theta. Mark me as BRAINLIEST

33.

What is sin theta square?

Answer»

ANSWER:

Sin 2 THETA is the sine of the angle which is double the value of theta. A formula to calculate sin 2 theta is: Sin 2 theta = 2 x (sin theta) x (COS theta) (x denotes multiplication) This can be used when you KNOW the value of sine and cosine of theta and not 2 theta.

Mark me as BRAINLIEST

Discussion

34.	What are the dimension of the quality l ll÷ g l being length and g the acceleration due.to gravity
Answer» ANSWER: GRIFFITH hjjllghgjkoiuhgbkbllgl

34.

What are the dimension of the quality l ll÷ g l being length and g the acceleration due.to gravity

Answer»

ANSWER:

GRIFFITH hjjllghgjkoiuhgbkbllgl

Discussion

35.	a circular track has a circumference of 3140 with ab as one of the diameters . a scooter is moving from A to B along a circular path find his distance and displacement .what will be the displacement if it covers three quarters of the circle
Answer» Answer: Explanation: If the CIRCUMFERENCE is 3140 METRES and AB is the diameter. Then the Distance from A to B would be half the circumference i.e. 31402 1570 metres. Now,The units are Distance 1570 m Speed 10 m/s So Time- Distance Speed 1570 ÷10= 157 seconds And the Displacement is the Diameter. So,π=Circumference ÷Diameter πx Diameter= Circumference Diameter =Circumference÷π (To make THINGS Simpler are taking the first Three 3 digits of pi i.e. 3.14 as 22/7- 3.1415.....) =3140÷ 3.14 =>3140÷3.14= 1000 So the Displacement or Diameter= 1000 Metres And the Time 157 seconds.

35.

a circular track has a circumference of 3140 with ab as one of the diameters . a scooter is moving from A to B along a circular path find his distance and displacement .what will be the displacement if it covers three quarters of the circle

Answer»

Answer:

Explanation:

If the CIRCUMFERENCE is 3140 METRES and AB is the diameter.

Then the Distance from A to B would be half the circumference i.e. 31402 1570 metres.

Now,The units are Distance 1570 m

Speed 10 m/s

So Time- Distance Speed 1570 ÷10= 157 seconds

And the Displacement is the Diameter.

So,π=Circumference ÷Diameter πx Diameter= Circumference

Diameter =Circumference÷π

(To make THINGS Simpler are taking the first Three 3 digits of pi i.e. 3.14 as 22/7- 3.1415.....)

=3140÷ 3.14

=>3140÷3.14= 1000

So the Displacement or Diameter= 1000 Metres

And the Time 157 seconds.

Discussion

36.	the angle subtended by moon at a point on earth is 0.31degrees if the distance of moon from earth is 3.84x10^8m find the diameter of moon
Answer» Answer: 20.736 multuply by 100000

36.

the angle subtended by moon at a point on earth is 0.31degrees if the distance of moon from earth is 3.84x10^8m find the diameter of moon

Answer»

Answer:

20.736 multuply by 100000

Discussion

37.	What is angle between i+2j+2k and i. options are 1. 0° 2. π/2. 3. π/3 4. none of the above
Answer» ANSWER: 4 NONE of the above answer is COS INVERSE 1/3

37.

What is angle between i+2j+2k and i. options are 1. 0° 2. π/2. 3. π/3 4. none of the above

Answer»

ANSWER:

4 NONE of the above answer is COS INVERSE 1/3

Discussion

38.	Plz solve.......... Find the derivative of que.4 in the picture ☺☺☺☺☺☺
Answer» please mark as brainliest I HOPE it MAY be help you

38.

Plz solve.......... Find the derivative of que.4 in the picture ☺☺☺☺☺☺

Answer»

please mark as brainliest

I HOPE it MAY be help you

Discussion

39.	8. A mass of 5 kg descending vertically, draws up amass of 3 kg by means of a light string passing overa pulley. At the end of 4 s, the string breaks. Howmuch higher the 3 kg mass would go ?
Answer» Given :- Mass of big block = M = 5 KG Mass of SMALL block = m = 3 Kg Force on big block = F = 5g Force on small block = f = 3g Time = t = 4 s ∆F = (M+m)a F - f = (5+3)a a = 2g/8 a = g/4 Using FIRST equation of Motion, v = at (Since Initial Velocity is Zero.) v = g/4 × 4 v = g As we know that, h = v²/2g h = g²/2g h = g/2 Taking 'g' = 9.8 ms-² h = 4.9 m Hence, Mass 3 kg will go = h = 4.9 m

39.

8. A mass of 5 kg descending vertically, draws up amass of 3 kg by means of a light string passing overa pulley. At the end of 4 s, the string breaks. Howmuch higher the 3 kg mass would go ?

Answer»

Given :-

Mass of big block = M = 5 KG

Mass of SMALL block = m = 3 Kg

Force on big block = F = 5g

Force on small block = f = 3g

Time = t = 4 s

∆F = (M+m)a

F - f = (5+3)a

a = 2g/8

a = g/4

Using FIRST equation of Motion,

v = at (Since Initial Velocity is Zero.)

v = g/4 × 4

v = g

As we know that,

h = v²/2g

h = g²/2g

h = g/2

Taking 'g' = 9.8 ms-²

h = 4.9 m

Hence,

Mass 3 kg will go = h = 4.9 m

Discussion

40.	Why is it hard to stop a boat
Answer» FLUIDS, such as liquid and gas, also EXERT a frictional force on the body moving through them. However, the frictional force due to water on the body moving through them is much less than the frictional force between any two solid surfaces. THUS, it is difficult to STOP boats.

Discussion

41.	Ques 1-a thick layer of ice on the the freezer of refrigerator isa. not not useful because it slows down the cooling rate b.not useful because its Harbour harmful bacteria c.not useful the power consumption is reduced d.useful because it cools the content of the refrigerator in less time
Answer» Answer: USEFUL as it COOL down the CONTENT of the REFRIGERATOR in less time

41.

Ques 1-a thick layer of ice on the the freezer of refrigerator isa. not not useful because it slows down the cooling rate b.not useful because its Harbour harmful bacteria c.not useful the power consumption is reduced d.useful because it cools the content of the refrigerator in less time

Answer»

Answer:

USEFUL as it COOL down the CONTENT of the REFRIGERATOR in less time

Discussion

42.	Advantages and disadvantages of half wave,full wave and bridge rectifier
Answer» Answer: ❤️❤️The HALF wave rectifier has more number of disadvantages as COMPARED to the advantages. Some of them are: 1. Since, power is delivered only during ONE half of the cycle of the INPUT alternating voltage, therefore, its power output and rectification frequency is low.❤️❤️ Explanation: ❤️❤️hello dear here is your answer mark it brainlist ok and FOLLOW me... :) ☺️☺️❤️❤️

42.

Advantages and disadvantages of half wave,full wave and bridge rectifier

Answer»

Answer:

❤️❤️The HALF wave rectifier has more number of disadvantages as COMPARED to the advantages. Some of them are: 1. Since, power is delivered only during ONE half of the cycle of the INPUT alternating voltage, therefore, its power output and rectification frequency is low.❤️❤️

Explanation:

❤️❤️hello dear here is your answer mark it brainlist ok and FOLLOW me... :) ☺️☺️❤️❤️

Discussion

43.	Which quantity is responsible for inertia
Answer» Answer: MASS is that QUANTITY that is solely DEPENDENT upon the INERTIA of an object.

43.

Which quantity is responsible for inertia

Answer»

Answer:

MASS is that QUANTITY that is solely DEPENDENT upon the INERTIA of an object.

Discussion

44.	Descride what is meant by significant figer and order of magnitude
Answer» Answer: Order of MAGNITUDE refers to rough approximation. Example: AROUND 100 COULD be anywhere from 50 to 200. Significant figures describes something fairly precise. Example: 1.26 (3 significant figures) MEANS something in the range 1.255 to 1.265.

44.

Descride what is meant by significant figer and order of magnitude

Answer»

Answer:

Order of MAGNITUDE refers to rough approximation. Example: AROUND 100 COULD be anywhere from 50 to 200. Significant figures describes something fairly precise. Example: 1.26 (3 significant figures) MEANS something in the range 1.255 to 1.265.

Discussion

45.	A bus with a vertical wind shield moves horizontally at a speed of 40km/hr, while rain is falling vertically at a speed of 30km/hr. The angle at which rain drops strike the wind shield is?
Answer» ANSWER: θ = 53⁰ Explanation: Let angle θ at which RAIN drops strike the wind shield . GIVEN : Horizontal component of falling rain is 40 km / hr Vertical component is 30 km / hr . We know tan θ = Horizontal component / Vertical component tan θ = 40 km / hr / 30 km / hr . tan θ = 4 / 3 θ = tan⁻¹ ( 4 / 3 ) . θ = 53⁰

45.

A bus with a vertical wind shield moves horizontally at a speed of 40km/hr, while rain is falling vertically at a speed of 30km/hr. The angle at which rain drops strike the wind shield is?

Answer»

ANSWER:

θ = 53⁰

Explanation:

Let angle θ at which RAIN drops strike the wind shield .

GIVEN :

Horizontal component of falling rain is 40 km / hr

Vertical component is 30 km / hr .

We know

tan θ = Horizontal component / Vertical component

tan θ = 40 km / hr / 30 km / hr .

tan θ = 4 / 3

θ = tan⁻¹ ( 4 / 3 ) .

θ = 53⁰

Discussion

46.	Which surface has the least amount of friction
Answer» ANSWER: *SMOOTH* *SURFACE* *HAS* *THE* *LEAST* AMOUNT OF *FRICTION* DUE TO LESS IRREGULARITIES**.

46.

Which surface has the least amount of friction

Answer»

ANSWER:

SMOOTH SURFACE HAS THE LEAST AMOUNT OF FRICTION DUE TO LESS IRREGULARITIES.

Discussion

47.	a particle is moving under the influence of a force given by F=kx where k is constant and x is the distance moved.the energy(in kg) gained by the particle in moving for x=0 to x=5 is what
Answer» ANSWER: the CHROMOSOME number in the daughter cellos similar to the PARENT CELL

47.

a particle is moving under the influence of a force given by F=kx where k is constant and x is the distance moved.the energy(in kg) gained by the particle in moving for x=0 to x=5 is what

Answer»

ANSWER:

the CHROMOSOME number in the daughter cellos similar to the PARENT CELL

Discussion

48.	At any instant t = 0 a motorbike start from rest in a given direction, a car moving with constant speed overtakes themotorbike at that instant when it is moving with a speed 40 m/s. Motor bike accelerates uniformly till t = 18s andthen move with constant speed and overtakes the car at t = 27 s.The maximum speed of motorbike in m/s isA) 80(B) 60(C) 100(D) 120plz tell
Answer» Answer: 60 m/sec Explanation: At t=0,u=0for the MOTORBIKE And at t=18, v=18a(which will be the Vmax) So, S1=1/2a18^2=162a..........EQ (I) And S2=(27-18)18a=162a........eq (II) S1+S2= distance travelled by the CAR in 27 sec S1+S2=4027=1080.......(iii) Putting the value of S1and S2 from eq (I) and (ii) in eq (iii) 162a+162a=1080 a =1080/324=3.33m/sec^2 Vmax=18*3.33=59.94=60m/sec.

48.

At any instant t = 0 a motorbike start from rest in a given direction, a car moving with constant speed overtakes themotorbike at that instant when it is moving with a speed 40 m/s. Motor bike accelerates uniformly till t = 18s andthen move with constant speed and overtakes the car at t = 27 s.The maximum speed of motorbike in m/s isA) 80(B) 60(C) 100(D) 120plz tell

Answer»

Answer:

60 m/sec

Explanation:

At t=0,u=0for the MOTORBIKE

And at t=18, v=18a(which will be the Vmax)

So, S1=1/2a18^2=162a..........EQ (I)

And S2=(27-18)*18a=162a........eq (II)

S1+S2= distance travelled by the CAR in 27 sec

S1+S2=40*27=1080.......(iii)

Putting the value of S1and S2 from eq (I) and (ii) in eq (iii)

162a+162a=1080

a =1080/324=3.33m/sec^2

Vmax=18*3.33=59.94=60m/sec.

Discussion

49.	2Dimension and optainequantity.Dimensions offollowing Physical]force
Answer» DIMENSIONAL formula is presentation of a PHYSICAL QUANTITY in terms of FUNDAMENTAL quantities rised to a power the dimensional formula for force is [MLT-²]

49.

2Dimension and optainequantity.Dimensions offollowing Physical]force

Answer»

DIMENSIONAL formula is presentation of a PHYSICAL QUANTITY in terms of FUNDAMENTAL quantities rised to a power

the dimensional formula for force is [MLT-²]

Discussion

50.	Shaded area of the diagram will be
Answer» Answer: 8/3 Explanation: LIMITS of X =0 and x=2 let US integrate them we GET x^3/3 substitute the limits 2^3/3 8/3

50.

Shaded area of the diagram will be

Answer»

Answer:

8/3

Explanation:

LIMITS of X =0 and x=2

let US integrate them

we GET x^3/3

substitute the limits

2^3/3

8/3

Discussion

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