A weight of 70 N is suspended to a rigid support with the help of stri

1.	A weight of 70 N is suspended to a rigid support with the help of strings as shown..find tension in string
Answer» GIVEN: WEIGHT of the block = 70N To find: The tension in the strings. Solution: Let the tension in the strings be T1 and T2 and the angle they make with the horizontal surface of the support be α and β respectively. The EQUATION of forces for the horizontal components will be: T1 cosα = T2 cosβ T1 = T2 cos β/ cosα Now, the equation of forces for the vertical components will be: T1 sinα + T2 sinβ = mg T2 sinα cosβ/ cosα + T2 sinβ = mg T2((sinα cosβ/ cosα) + sinβ) = 700 T2 = 700/((sinα cosβ/ cosα) + sinβ) T1 = T2 cosβ/ cosα Therefore the tension can be FOUND out by PUTTING the value of angles in the equations.

A weight of 70 N is suspended to a rigid support with the help of strings as shown..find tension in string

Answer»

WEIGHT of the block = 70N

To find:

The tension in the strings.

Solution:

Let the tension in the strings be T1 and T2 and the angle they make with the horizontal surface of the support be α and β respectively.

The EQUATION of forces for the horizontal components will be:

T1 cosα = T2 cosβ

T1 = T2 cos β/ cosα

Now, the equation of forces for the vertical components will be:

T1 sinα + T2 sinβ = mg

T2 sinα cosβ/ cosα + T2 sinβ = mg

T2((sinα cosβ/ cosα) + sinβ) = 700

T2 = 700/((sinα cosβ/ cosα) + sinβ)

T1 = T2 cosβ/ cosα

Therefore the tension can be FOUND out by PUTTING the value of angles in the equations.

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