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A particle moves 3m in positive direction of x axis ,5m making 53 degree with positive direction of x axis and 4 m in positive direction of y axis . what is its displacement ? |
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Answer» Answer: Displacement = 10 m Explanation: A particle MOVES 3m in positive direction of x axis => Distance in x direction = 3 m & Distance in y direction = 0 m Then 5m making 53 degree with positive direction of x axis => Distance in x direction = 5Cos53 = 5 * 0.6 = 3 m & Distance in Y Direction = 5Sin53 = 5 * 0.8 = 4 m 4 m in positive direction of y axis => Distance in x direction = 0 & Distance in y direction = 4 m Total Distance in x direction = 3 + 3 + 0 = 6m Total Distance in y direction = 0 + 4 + 4 = 8 m Total Displacement = √6² + 8² = √36 + 64 = √100 = 10 m Displacement = 10 m |
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