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Answer:

in CGS MASS is Gram

in SI mass is KILOGRAM

In a triangle, if the square of one side is EQUAL to the sum of square of other TWO sides then prove that the triangle is right angled triangle.

________________________

Given : AC² = AB² + BC²

To prove : ABC is a right angled triangle.

CONSTRUCTION : Draw a right angled triangle PQR such that, angle Q = 90°, AB = PQ, BC = QR.

Proof : In triangle PQR,

Angle Q = 90° ( by construction )

Also,

PR² = PQ² + QR² ( By using Pythagoras theorem )...(1)

But,

AC² = AB² + BC² ( Given )

Also, AB = PQ and BC = QR ( by construction )

Therefore,

AC² = PQ²+ QR²....(2)

From eq (1) and (2),

PR² = AC²

So, PR = AC

Now,

In ∆ABC and ∆PQR,

AB = PQ ( By construction )

BC = QR ( By construction )

AC = PR ( Proved above )

Hence,

∆ABC is congruent to ∆PQR by SSS criteria.

Therefore, Angle B = Angle Q ( By CPCT )

But,

Angle Q = 90° ( By construction )

Therefore,

Angle B = 90°

Thus, ABC is a right angled triangle with Angle B = 90°

____________________

Hence proved!

EXPLANATION:

ELECTRIC fields are caused by electric charges, described by Gauss's law, or varying magnetic fields, described by FARADAY's law of induction. TOGETHER, these laws are enough to define the behavior of the electric field as a function of CHARGE repartition and magnetic field.

ANSWER:

PLEASEMARK me as BRAINLIST

ANSWER:

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Answer:

0.2sec

Explanation:

u=0

h=2m

h=ut+1/2gt^2

2=1/2×10t^2

t^2=0.4

t=0.2sec

If the object have zero momentum the it doesn,t have any kinetic energy because there is no MOVEMENT of the object becuase the VELOCITY is O ,So the object is not ABLE to ATTAIN kinetic energy due to no movement of the object.

EXPLANATION:

nsbsnsbdbjdbddhsjnsjsjsj

ANSWER:

with formula

EXPLANATION:

AVERAGE VELOCITY= V1*v2+v3/2

/v1+v2+v3/2

ANSWER:

No......

Explanation:

RATE of change of VELOCITY is acceleration and if no change in velocity occur then acceleration REMAINS 0

Answer:

It is BCZ society BECOME change bcz of education... Education MAKES right CHOICE of people... Education is very important because of change people's thinking to... Understand what's a wrong and what's a right...

Hope it HELPS..

EXPLANATION:

ADD all vectors

I+j+k+2i-j+k-3i+k

= 3k

so it will be on z-axis

In a triangle, if the square of one side is equal to the sum of square of other two sides then PROVE that the triangle is right angled triangle.

________________________

Given : AC² = AB² + BC²

To prove : ABC is a right angled triangle.

Construction : Draw a right angled triangle PQR such that, ANGLE Q = 90°, AB = PQ, BC = QR.

Proof : In triangle PQR,

Angle Q = 90° ( by construction )

Also,

PR² = PQ² + QR² ( By using Pythagoras theorem )...(1)

But,

AC² = AB² + BC² ( Given )

Also, AB = PQ and BC = QR ( by construction )

Therefore,

AC² = PQ²+ QR²....(2)

From eq (1) and (2),

PR² = AC²

So, PR = AC

Now,

In ∆ABC and ∆PQR,

AB = PQ ( By construction )

BC = QR ( By construction )

AC = PR ( Proved above )

Hence,

∆ABC is congruent to ∆PQR by SSS criteria.

Therefore, Angle B = Angle Q ( By CPCT )

But,

Angle Q = 90° ( By construction )

Therefore,

Angle B = 90°

Thus, ABC is a right angled triangle with Angle B = 90°

____________________

Hence proved!

Answer:

2:3

Explanation:

Let the distance through which the stone dropped = d

Now,

it is given that at 'd', potential energy = 9 × KINETIC energy

Potential energy when the stone dropped off to 'd' = mg(h-d)

where, m is the mass of the stone

g is the acceleration due to the gravity

also,

Now gain in kinetic energy while dropped through distance 'd' = loss in potential energy

or

Kinetic energy = mgd

now USING the relation given in the problem

mg(h-d) = 9 × mgd

or

h - d = 9d

or

d = h/10

therefore,

the kinetic energy for the first case = mgd = mg(h/10)

also

Kinetic energy = = mg(h/10)

where, v is the velocity

and potential energy = 9 × Kinetic energy = 9 × mg(h/10) = (9/10)MGH  .....(1)

now,

for the case 2

velocity of the stone = 2 times the velocity in case 1

or

v' = 2v

thus,

the kinetic energy = =

or

the kinetic energy =

or

the kinetic energy = 4×mg(h/10)

thus,

the potential energy at this point = Initial potential energy - Kinetic energy

or

the potential energy at this point = mgh - 4×mg(h/10) = (6/10)mgh  .......(2)

dividing 2 by 1, we have

PE₂/PE₁ =

or

Ratio of NEW potential energy to old = 2:3

Answer:

H of 2 means two ATOMS of HYDROGEN element WHEREAS 2H is two MOLES of Hydrogen

I think you did some spelling MISTAKES in WRITING QUESTION please POST the question agani please

Explanation:

the EQN will be y=ax-bx^2 where a and B R POSITIVE constants

ANSWER:

shgshhshshshshshshs

Answer:

EXPLANATION:

H=ut-(1/2)gt^2.

h=80m, g=10m/s^2. Then,

t^2-(2/g)ut+(2/g)h=0. Solving,

t={(2/g)u+_[(4/g^2)u^2–4(2/g)h]^(1/2)}/2

The difference between two roots is 6

[(1/25)u^2–64]^1/2=6. SQUARING

(1/25)u^2–64=36

u^2=2500 or

u=50m/s^2. Then, total HEIGHT,

H=u^2/2g=2500/20=125m

Answer:

Explanation:

we know that

s = ut + (1/2)at2

here

u = 0

a = g

now for the first case, the TOTAL distance travelled in the 1second

s1 = (1/2)gt12

similarly the distance travelled after 2 ad 3 seconds respectively

s2 = (1/2).g.(t1 + t2)2

s3 = (1/2).g.(t1 + t2 + t3)2

so, the ratio of the height will be

s1 : s2 : s3 = 1 : 2 : 3 =  t12 : (t1 + t2)2 : (t1 + t2 + t3)2

or

 t1 : (t1 + t2) : (t1 + t2 + t3)  = 1 : √2 : √3

thus, we GET

(t1 : t2 : t3)  =  1 : (√2 1) : (√3 √2

ANSWER:

the AVERAGE ACCELERATION is 5+5\10 that is 1

ANSWER:

PATA NAHI SOLVE your ANS yourself

Answer:

The magnitude of velocity after 10 seconds is .

EXPLANATION:

It is given that,

INITIAL velocity of the particle,

Acceleration of the particle,

Time taken, t = 10 s

We need to FIND the velocity after 10 seconds. Let it is EQUAL to V. Using first equation of motion as :

Magnitude of v,

So, the magnitude of velocity after 10 seconds is . Hence, this is the required solution.

ANSWER:

Explanation:

4/VAVG = 1/v1+1/2v1+1/2v1+1/3v1

4/ Vavg = (6+3+3+2)/6v1

4/Vavg = 14/6v1

Vavg = 24v1/14

ANSWER:

yes not

Explanation:

becouse in EARTH .. g os not CONSTANT...

when the objects is MOVE downward

ANSWER:

Unbalanced forces

Explanation:

The correct answer for the given question is "Unbalanced forces".

When the all the forces on any body are not BALANCED or the net FORCE (sum of all the forces ) is not equal to zero, the body tends to have acceleration and thus, the body CHANGES the speed or VELOCITY.

When the forces are balanced, there will be no change in the velocity.

ANSWER:

do this QUESTION by yourself

Answer:

Ratio,

Explanation:

Let the resistance of the identical resistor is R. In series combination, the equivalent resistance is given by :

Here, two resistors are identical

In parallel combination, the equivalent resistance is given by :

Heat PRODUCED is given by :

For series combination, ....(1)

For parallel combination, .........(2)

Dividing equation (1) and (2) as :

So, the ratio of heat produced in both CASES is 4 : 1. HENCE, this iss the REQUIRED solution.

In a triangle, if the SQUARE of ONE side is equal to the sum of square of other two sides then prove that the triangle is right angled triangle.

________________________

Given : AC² = AB² + BC²

To prove : ABC is a right angled triangle.

Construction : Draw a right angled triangle PQR such that, angle Q = 90°, AB = PQ, BC = QR.

Proof : In triangle PQR,

Angle Q = 90° ( by construction )

Also,

PR² = PQ² + QR² ( By using Pythagoras theorem )...(1)

But,

AC² = AB² + BC² ( Given )

Also, AB = PQ and BC = QR ( by construction )

Therefore,

AC² = PQ²+ QR²....(2)

From EQ (1) and (2),

PR² = AC²

So, PR = AC

Now,

In ∆ABC and ∆PQR,

AB = PQ ( By construction )

BC = QR ( By construction )

AC = PR ( Proved above )

Hence,

∆ABC is congruent to ∆PQR by SSS criteria.

Therefore, Angle B = Angle Q ( By CPCT )

But,

Angle Q = 90° ( By construction )

Therefore,

Angle B = 90°

Thus, ABC is a right angled triangle with Angle B = 90°

____________________

Hence proved!

PRESSURE cannot be MEASURED in KGWT

The tangential acceleration of the PARTICLE is given by:

v²/r

After one rotation, the POINT COMES BACK to its initial position. So, its radial acceleration at that point is zero

THEREFORE, the ratio of the radial acceleration to the tangential acceleration is also zero...

ANSWER:

EXPLANATION:

ACCELERATION =2/root5 m/s2

Final VELOCITY =2root5m/s

Distance COVERED= 5root5meter

Answer:

v₂ =   or v₂ =

EXPLANATION:

The minimum SPEED (v) of a particle at the lowest POINT is given by the formula

v =

where,

g is the acceleration due to the gravity

R is the radius

Now,

for the first CASE Radius = R

and for the cases 2 Radius = R/4

let the speed for the case 2 be v₂

thus,

v₂ =

or

v₂ =  

or we can say

v₂ =

hence, the value of the speed for radius R/4 becomes half the value of speed for radius = R

Answer:

Explanation:

At this POINT it is desirable to become somewhat explicit about the FUNCTION P(Κ) where now P(Κ)D3 K is the probability that the target nucleus has initial momentum in d3k about K. We choose to DIGRESS and examine the problem this poses for us in some details — both because of its wide-ranging importance to us and because it PROVIDES us with another opportunity to illustrate the application of basic principles to the analysis of real systems…

Answer:

c) flowing of water

Explanation:

potential ENERGY is the amt. of mechanical work OBTAINABLE from a BODY due to change of it's POSITION or shape.

Hope it helps you

Explanation:

STEADY, inviscid and irrotational: ... Irrotational flow is a flow in which each element of the moving FLUID undergoes no NET rotation with respect to a chosen coordinate AXES from one instant to other. A well-known example of irrotational motion is that of the carriages of the Ferris WHEEL (giant wheel).

Answer:  1/lemda = R( 1/n1^2 - 1/n2^2)

Explanation:

According to Bohr when an atom makes a transition from higher energy LEVEL to a lower ta a lower energy level it EMITS a PHOTON with energy equal to the energy difference between the initial and final LEVELS. If E1 is the initial energy of the atom before such a transition E1 is its final energy after the transition ,and the photon's energy is hf = hc/lemda , then conservation of energy gives

hf = hc/ lemda = E1 - E2                           (energy of emitted photon)

ANSWER:

TOTAL distance = 143 km

pls see the attachment

ANSWER: 60 km/h

.

.v=12 km/h

T= 30 min or 30/60h

Therefore

DISTANCE = 6 km

( as distance = speed x time )

.

Now d = 6km

Time = 5 min or 5/60h

Therefore speed = 72 km/h

.

Speed INCREASED = 72-12 = 60 m/s

Explanation:

So in FACT it just boils down to the fact that transverse-WAVES need a MEDIUM rigid enough to propagate, which LIQUIDS can't provide. Also remember that not all transverse waves require a rigid medium to travel. Transverse waves can also travel along the surface TENSION of the ocean, creating water waves.

ANSWER:

The WALLS are COOL can be the answer.

Answer:

5

Explanation:

v1 = 3I + 4J + K

v2 = i - j - k

v1 + v2 = 3i + 4j + k + i - j - k

= 4i + 3j

|v1 + v2| = √(4² + 3²)

= √25

= 5

Explanation:

This means to excite hydrogen atom, the energy required to be given to it is E2 – E1 = -3.4 + 13.6 = 10.2 EV. HENCE, 10.2 eV is the FIRST excitation energy of the hydrogen atom.

Answer:

FIRST EXCITATION potential value is

-3.4

But this is with RESPECT to hydrogen.

For any other METAL u can use

ANSWER:

PLS SEE the ATTACHMENT

CAMELS have MODIFIED padded feet which helps them to stand in the hot SAND while horse don,t.