A particle has initial velocity 2i + 3 j and acceleration 0.3 i + 0.2

1.	A particle has initial velocity 2i + 3 j and acceleration 0.3 i + 0.2 j the magnitude of velocity after 10 seconds will be
Answer» Answer: The magnitude of velocity after 10 seconds is $5\sqrt{2}\ units$ . EXPLANATION: It is given that, INITIAL velocity of the particle, $u = 2 i +3 j$ Acceleration of the particle, $a=0.3i +0.2 j$ Time taken, t = 10 s We need to FIND the velocity after 10 seconds. Let it is EQUAL to V. Using first equation of motion as : $v=u+at$ $v=2 i +3 j+(0.3i +0.2 j)10$ $v=2 i +3 j+(3i +2 j)$ $v=5i+5j$ Magnitude of v, $\|v\|=\sqrt{5^2+5^2} =5\sqrt{2}\ units$ $5\sqrt{2}\ units$ So, the magnitude of velocity after 10 seconds is . Hence, this is the required solution.