A particle is released from rest from a tower of height 3h the ratio o

1.	A particle is released from rest from a tower of height 3h the ratio of the intervals of time to cover three equal heights age is
Answer» Answer: Explanation: we know that s = ut + (1/2)at2 here u = 0 a = g now for the first case, the TOTAL distance travelled in the 1second s1 = (1/2)gt12 similarly the distance travelled after 2 ad 3 seconds respectively s2 = (1/2).g.(t1 + t2)2 s3 = (1/2).g.(t1 + t2 + t3)2 so, the ratio of the height will be s1 : s2 : s3 = 1 : 2 : 3 = t12 : (t1 + t2)2 : (t1 + t2 + t3)2 or t1 : (t1 + t2) : (t1 + t2 + t3) = 1 : √2 : √3 thus, we GET (t1 : t2 : t3) = 1 : (√2 1) : (√3 √2

A particle is released from rest from a tower of height 3h the ratio of the intervals of time to cover three equal heights age is

Answer»

Answer:

Explanation:

we know that

s = ut + (1/2)at2

here

u = 0

a = g

now for the first case, the TOTAL distance travelled in the 1second

s1 = (1/2)gt12

similarly the distance travelled after 2 ad 3 seconds respectively

s2 = (1/2).g.(t1 + t2)2

s3 = (1/2).g.(t1 + t2 + t3)2

so, the ratio of the height will be

s1 : s2 : s3 = 1 : 2 : 3 = t12 : (t1 + t2)2 : (t1 + t2 + t3)2

t1 : (t1 + t2) : (t1 + t2 + t3) = 1 : √2 : √3

thus, we GET

(t1 : t2 : t3) = 1 : (√2 1) : (√3 √2

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A particle is released from rest from a tower of height 3h the ratio of the intervals of time to cover three equal heights age is

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