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This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
What is the approximate length of aseconds (simple) pendulum on thesurface of moon? Given: 'g' at the moon= 1.6 m/s^2. |
Answer» 0.103mExplanation: Here is your answer if u get the concept than MARK this as a BRAINLIEST. |
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| 2. |
Variable focal length of eye lens is responsible for:(a) accommodation of eye(b) persistence of vision(c) colour blindnessd) least distance of district vision |
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Answer» Answer: a) ACCOMMODATION of eye Explanation: power of accommodation of HUMAN eye is the ability of the eye to OBSERVE distinctly the object situated ar WIDELY different DISTANCES from the eye. |
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| 3. |
What is nuclear energy.Explain it in 2 or 3 sentences with anexample of peaceful and destructive uses. |
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Answer» Nuclear power is the use of nuclear reactions that release nuclear ENERGY to GENERATE heat, which most frequently is then used in steam turbines to produce ELECTRICITY in a nuclear power plant. Nuclear power can be obtained from nuclear fission, nuclear decay and nuclear fusion reactionsthe energy released during nuclear fission or fusion, ESPECIALLY when used to generate electricity |
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| 4. |
The sequence of stepwise decays of radioactive nucleus X( Z= 71,A= 176) would finally result a nucleus X2 in the process.X (z=71,A=176) ------alpha----------- X1------beta------ X2; X2 is |
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Answer» heieosjeosjslslppdpd Explanation: hejekekkekekskskjsjususjjj |
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| 5. |
A constant force is applied for 2s on a body of mass 5kg.as a result, if the velocity of the body is changed from 3m/s to 7 m/s.find the value of the force applied |
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Answer» Answer: 10kg-m/s^(2) v=u+at 7=3+a*2 a=2m/s^(2) F=ma =5*2 F=10 |
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| 6. |
Give the reason :Q1. Velocity is a physical quantity. Q2. Emotions are not physical quantity. |
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Answer» Answer: 1.Explanation: A physical quantity is a property of a MATERIAL or system that can be quantified by measurement. velocity tells us about both MAGNITUDE of speed and a particular direction. hence, it is ALSO CONSIDERED a vector quantity. 2.Some example of non-physical quantities are: Feelings, Angriness, Rudeness, etc. No one can measure the feeling of a person, or love, etc. |
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| 7. |
Which of these metals cannot displace hydrogen from acids or water?a. Ironb. Zincc. Sodiumd. Silver |
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| 8. |
A soller coaster starts from rest A yola downthe track to B desember a circular loop of40-ī diameter and moves up and down pastpoint E take h saft and assume thatenergyloss due to frictionthere is noragothTforceDetermine theexertedhisby Jseat in a 215 4 sider at B and D.Force exertedbyseat on the rider at3force exerted1 ls .byseaton the sider at |
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Answer» Answer: roller coaster starts from rest at A, rolls down the TRACK to B, describes a CIRCULAR loop of 40-ft diameter, and moves up and down PAST point E. knowing that h=60 ft and assuming no energy loss due to friction, DETERMINE (a) the force exerted by his seat on a 160-lb rider at B and D, (b) the minimum value of the radius of curvature at E if the roller coaster is not to leave the track at that point. |
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| 9. |
Derive an expression for the minimum speed of the vehicle which derive in horizontal circle (well of death ) |
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Answer» Answer: When the motorcyclist is at the highest point of the death - well, the normal reaction R on the motorcyclist by the ceiling of the chamber ACTS downwards. His weight mg ALSO ACT downward Here V is the speed of the motorcyclist and m is the mass of does not fall down. The minimum speed required to perform a vertical loop is GIVEN by equation (1) when R=0. Therefore, |
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| 10. |
5. The speed of transverse waves in a wire of density 8.00 gm /cmis 340 m/s. Calculatethe tension-stress in the wire. |
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Answer» Answer: Thodi Jagah de de mujhe tere PAAS MERA Jahan Khamoshiyan Teri SUNO aur Dur Tak Ja Apne Kuchh Main Tujhe Tere DARD SE jud Jau Mai |
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| 11. |
[6Question 3.Solve:(1) Find the mass of 444 cm of lead in kg when the density of lead is 11.5 g/m3 |
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| 12. |
An object of mass 1.5kg travelling in a straight line with a velocity of 5m/s collides with a wooden block of mass 5kg resting on the floor. This object sticks with the wooden block after collision and both move together in a straight line. Calculate:(a)the total momentum before collision.(b) total momentum after collision(c) the velocity of the combination of these objects after collisionPLEASE FAST VERY URGENT |
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Answer» This is your REQUIRED answer. |
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| 13. |
9)Give scientific reason: Plastic is an insulator because ______ (2mks) *it has low resistanceit has high resistanceit has high resistance and current cannot flow through itit has low resistance and current cannot flow through it |
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Answer» It has HIGH RESISTANCE and CURRENT can not FLOW through it |
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| 14. |
In an Ammeter, there are 5 divisions between 0 mark and 0.5 V mark. The least count of thevoltmeter isa) 0.5 Ab) 0.1 Ac) 0.2 Ad) 0.3 A |
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Answer» b) 0.1 A Explanation: 1 division is equal to 0.5÷5 =0.1 |
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| 15. |
Q.8Car A travelling from Madgao to Ponda with a velocity 50 km h and car B is travellingfrom Ponda to Madgao with a velocity 40 kmh Calculate the relative relocity of car Arespect to car B when they cross each other at Borim Bridge |
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Answer» Answer: 1
+S
=50km+60km=110km Total time t=t 1
+t 2
t= v 1
s 1
+ v 2
s 2
= 25 50
+ 20 60
=5 h Average VELOCITY = Total time of JOURNEY t Total distance travelled S
= 5h 110km
=22 kmh −1 |
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| 16. |
What are the evidence in favour of earth’s magnetic field?Discussthe causes and elements of earth’s magnetic field |
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Answer» Answer: As the inside of Earth cooled, magnesium oxide could precipitate out, driving convection and the geodynamo. The researchers believe INNER Earth eventually exhausted the magnesium oxide source to the point that the magnetic field ALMOST completely collapsed 565 million years ago. There are three components that are responsible for the MAGNITUDE as well as the direction of the earth's magnetic field: Magnetic declination. Magnetic INCLINATION or the angle of dip. Horizontal component of the earth's magnetic field.Sep 29, 2020 I hope this answer is help you |
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| 17. |
1. a) Nyasa is four feet tall and her friend Sonia is 150 cm tall. Who is taller and bymuch?b) The mass of an adult elephant is 4.2 tones. What is the mass of the elephant andin quintals? |
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| 18. |
& B=2i-j+2!Find a unit vector perpendicular to each of the vectors A=i+2j+3k?Physics |
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| 20. |
Two identical circular loops, P and Q , each of radius r and carrying currents I and 2Irespectively are lying in parallel planes such that they have common axis. The direction of current in both the loops is anticlockwise. Find the magnitude of the net magnetic field at point O |
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Answer»
HOPE it HELPS U AKASH........... hope it helps u akash........... |
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| 21. |
A body mass of 5kg is moving with an acceleration of 5m/s^2.what is the rate of change of momentum?plss help me guys |
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Answer» Given :
To find :
Note :- We also called rate of change of momentum is Force. It MEANS that we have to find Force So, → Force = Mass × Acceleration Or, → F = ma → F = 5 ×5 → F = 25 N So,the rate of change of momentum is 25. _____________________________ Newton's second law of motion :- The rate of change of momentum is directly proportional to the applied force, and takes place in the direction in which the force acts.
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| 22. |
Q2. Calculate the gravitational force of attraction between thetwo bodies of masses 60kg 70 kg seperated by adistance of 18 m. Take G=6.7 X 10^_110m^2/kg 12- |
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Answer» We know that F = Gm1m2/r2 F = 6.67*10^-11 * 60*70/18*18 F = 6.67*10^-11* 12.96 F = 86.44*10^-11 Newton |
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| 23. |
The value of atmospheric pressure on the Earth's surface isa. 10 kPab. 100 kPac. 1000 kPad. 500 kPa |
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Answer» Answer: The standard, or near-average, atmospheric pressure at sea level on the Earth is 1013.25 millibars, or about 14.7 pounds per square inch. The gauge pressure in my automobile tires is a LITTLE more than twice that value. If you live at a higher ALTITUDE, the pressure will be lower since there is less air above weighing down UPON you. The pressure also varies by relatively small amounts as HIGH and low pressure systems move past. Explanation: pls make my answer brainliest......and GIVE ❤️ |
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| 24. |
50. In the following velocity-time graph, the distancetravelled by the body in metres is:AY20tu)15105102030T(s)(a) 200(b) 250(c) 300(d) 400 |
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Answer» okkkkkkkkkkkkkj Explanation: |
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| 25. |
Note the relationship between first two & suggest suitable word in the fourth place.Nearsightedness : Concave lens : : Farsightedness : _____________________ |
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Answer» Explanation: ......................... |
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| 26. |
Q.7 The specific resistance o of a thin wire of radius 7 cm, resistance R 12 and length L cm isgiven byπρRIf r = 0.20 -0.01 cm, R = 40:12, L = 20 = 0.5 cm=Lthen calculate the percentage error in O. |
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| 27. |
A pebble is dropped freely in a well from its top. It takes 20sec for the pebble to reach the watersurface in the well. Taking g = 10 m/s2 and speed of sound = 330 m/s ,Find i) the depth of water surface ii) the time when echo is heard after the pebble is dropped |
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Answer» Answer: |
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| 28. |
Derivethequestion of path of aprojectilethatbody andthe path of is perabolic |
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Answer» DRIVER the QUESTION of path of a PROJECT that any BODY and the path of is PERPENDICULAR |
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| 29. |
1. A ball is thrown horizontally from the top of a 20-m high hill. It strikes the ground at an angle of 45. With whatspeed was it thrown?A. 14m/sB. 20m/sC. 28m/sD. 32m/sE. 40m/s |
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Answer» Explanation: 28 m/s |
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| 30. |
The angle of incidence for a ray of light having zero angle of refraction will be (as light moves from one medium to another)(a) 0(b) 30°(c) 45°(d) 90° |
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Answer» Answer: 0° please MARK me as BRAINLIEST |
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| 31. |
A ball is thrown vertically upwards from the top of a tower with an initial velocity of 39.2 m/s. Theball reaches the ground after 5 s. Calculate (i) the height of the tower (ii) the velocity of ball on reaching the ground. (take g=9.8 m/s2) |
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Answer» S=ut+ |
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| 32. |
The angle between an incident ray and the plane mirror is 30°. The total anglebetween the incident ray and reflected ray will be(a)30°(b)60°(c)90°d) 120° |
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Answer» Answer: 60 SINCE ANGLE of incidence and angle of REFLECTION is equal so 30+30=60 |
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| 33. |
Don't spam ...Try to give my answers ---- What is crystal ? Derive the formula of lense ? |
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Answer» Answer: avhydp the DAY of your HELP with this ONE is the type that GIVES |
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| 34. |
A bullet is fired horizontally from a gun situated at a hight of 40m above a horizontal plane with a velocity of 200m/sec to hit a target on the horizontal plane. the target is situated at . |
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| 35. |
In which of the following cases of motion the distance moved and the masgnitude1)revolution of earth2) a cyclist moving in a circular path3) a car moving on staight road4) motion of swing |
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Answer» Answer: 3) a CAR moving on straight road.. Explanation: PLEASE MARK me as brainlest PLZ plz and follow me plz plz plz plz plz plz plz plz plz plz plz |
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| 36. |
A stone of (50 kg) Started rolling down a hill with a velocityof 20 m/s. How much frictional force will be required to stopthe stone when it covers 20 meters. |
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Answer» A stone of 1kg is THROWN with a velocity of 20m s −1 across the frozen surface of a lake and comes to rest after travelling a DISTANCE of 50m. What is the force of FRICTION between the stone and the ice? |
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| 37. |
A car goes from points A and B and then come back from B to A . What is the displacement and average velocity |
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Answer» Answer: displacement is the distance between initial and FINAL POSITION of the object. as the initial and final position of car is same so displacement of the car =0 Velocity is displacement PER unit time so velocity of the car=0 Hope it HELPS you |
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| 38. |
If two vectors and the value of their attainment are equal, what is the angle between the two vectors?correct answer will be 120°. |
Answer» Answer :Two vectors and their resultant have same magnitude. We have to find angle between both vectors ★ By triangle law or parallelogram law of vector addition, the magnitude of resultant R at two vectors A and B inclined to each other at angle θ, is GIVEN by
Let magnitude of both vectors be X. ATQ, resultant also have same magnitude.
By substituting the values, we get ➝ x² = x² + x² + 2(x)(x) cosθ ➝ x² = 2x² + 2x² cosθ ➝ -x² = 2x² cosθ ➝ cosθ = -x²/2x² ➝ cosθ = -1/2 ➝ θ = cos‾¹ (-1/2) ➝ θ = 120° |
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| 39. |
M/c/MTIyMjM1MjQ5NDYz/a/MJEONDQyNjEOMDU5/detailsSUBJECT -: SCIENCE (PHYSICS)QUESTION 1. A bus is driving along a straight stretch of road. The bus driver, named Ray, has acup of water resting on the dashboard: Suddenly Ray has to slam on the brakes. What is mostlikely to happen to the water in the cup?A. The water will stay horizontal.WaterIB. The water will spill over side 1.12driving directionC. The water will spill over side 2.D. The water will spill but you cannot tell if it will spill at side 1 or side 2(1) |
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Answer» Answer: OPTION. b is correct Explanation: |
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| 40. |
Q.17 The average K.E of a gas molecule at T Kelvin isA)IKTC)32BY -KTDY3kТNIWNIC |
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Answer» Answer: xifxk sdyxdfrc mein BHI ek sath ek sath do SE hoto HAI HAM ki |
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| 41. |
A force of 45 N produces an acceleration of 1.5 m/s2in a box. Calculate the mass of the box. |
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Answer» F= ma 45 = m * 1.5 45/1.5 = m 30 kg = m m = 30 kg Explanation: |
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| 42. |
A chain of mass M and length L is hold vertically onSmooth horizontal table as shown. If chain is released fromrest then find the normal reaction as a function ofx. x is the distance which the chain has fallen& assume norebounding of chain after striking the surface |
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Answer» Answer: Lets take a SMALL element at a distance x of length dx. Lets take a small element at a distance x of length dx.The velocity with which element will strike the floor, Lets take a small element at a distance x of length dx.The velocity with which element will strike the floor,v=2gx Lets take a small element at a distance x of length dx.The velocity with which element will strike the floor,v=2gxMomentum transferred to floor is, Lets take a small element at a distance x of length dx.The velocity with which element will strike the floor,v=2gxMomentum transferred to floor is,dP=dmv=[LMxdx2gx] Lets take a small element at a distance x of length dx.The velocity with which element will strike the floor,v=2gxMomentum transferred to floor is,dP=dmv=[LMxdx2gx]F1=dtdp Lets take a small element at a distance x of length dx.The velocity with which element will strike the floor,v=2gxMomentum transferred to floor is,dP=dmv=[LMxdx2gx]F1=dtdpand, v=dtdx=2gx Lets take a small element at a distance x of length dx.The velocity with which element will strike the floor,v=2gxMomentum transferred to floor is,dP=dmv=[LMxdx2gx]F1=dtdpand, v=dtdx=2gxF1=LM2gx×2gx Lets take a small element at a distance x of length dx.The velocity with which element will strike the floor,v=2gxMomentum transferred to floor is,dP=dmv=[LMxdx2gx]F1=dtdpand, v=dtdx=2gxF1=LM2gx×2gxF1=L2mgx Lets take a small element at a distance x of length dx.The velocity with which element will strike the floor,v=2gxMomentum transferred to floor is,dP=dmv=[LMxdx2gx]F1=dtdpand, v=dtdx=2gxF1=LM2gx×2gxF1=L2mgxNow, the FORCE entered by length x due to its own WEIGHT is, Lets take a small element at a distance x of length dx.The velocity with which element will strike the floor,v=2gxMomentum transferred to floor is,dP=dmv=[LMxdx2gx]F1=dtdpand, v=dtdx=2gxF1=LM2gx×2gxF1=L2mgxNow, the force entered by length x due to its own weight is,w=Lmgx Lets take a small element at a distance x of length dx.The velocity with which element will strike the floor,v=2gxMomentum transferred to floor is,dP=dmv=[LMxdx2gx]F1=dtdpand, v=dtdx=2gxF1=LM2gx×2gxF1=L2mgxNow, the force entered by length x due to its own weight is,w=LmgxTherefore, Lets take a small element at a distance x of length dx.The velocity with which element will strike the floor,v=2gxMomentum transferred to floor is,dP=dmv=[LMxdx2gx]F1=dtdpand, v=dtdx=2gxF1=LM2gx×2gxF1=L2mgxNow, the force entered by length x due to its own weight is,w=LmgxTherefore,Total force=Lmgx+L2mgx Lets take a small element at a distance x of length dx.The velocity with which element will strike the floor,v=2gxMomentum transferred to floor is,dP=dmv=[LMxdx2gx]F1=dtdpand, v=dtdx=2gxF1=LM2gx×2gxF1=L2mgxNow, the force entered by length x due to its own weight is,w=LmgxTherefore,Total force=Lmgx+L2mgxF=L3mgx Lets take a small element at a distance x of length dx.The velocity with which element will strike the floor,v=2gxMomentum transferred to floor is,dP=dmv=[LMxdx2gx]F1=dtdpand, v=dtdx=2gxF1=LM2gx×2gxF1=L2mgxNow, the force entered by length x due to its own weight is,w=LmgxTherefore,Total force=Lmgx+L2mgxF=L3mgxExplanation: HOPE its help you |
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| 43. |
Hello guys can you please answer this....Q. Ram pushes the box by applying a force of 500N in horizontal direction so that the box slides along the floor as shown in figure. Find the point where the frictional force acting on the box is maximum. |
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Answer» at P Explanation: because the surface is too ROUGH so fiction force can act maximum on the box hope it will HELP you please mark me as brainlist |
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| 44. |
15)The value of acceleration due to gravity *1 point15)The value of acceleration due to gravity * |
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Answer» Answer: The VALUE of ACCELERATION DUE to gravity: · is same on equator and poles · is least on poles · is least on equator · increases from POLE to equator. |
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| 45. |
3. Two bodies of masses mi and m2 are moving in a direction withvelocities uj and uz respectively. They collide with each other. Aftercollision their velocities become vi and V2. Then derive the equation-mjui + m2u2 = m Vi + m2V2 |
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Answer» Answer: 3. Two bodies of masses MI and m2 are MOVING in a direction with VELOCITIES uj and uz respectively. They collide with each other. After collision their velocities BECOME vi and V2. Then derive the equation- mjui + m2u2 = m Vi + m2V2 |
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| 46. |
2.2A particle moves in a straight Ime with omform acceleration from time t = 0 to t= 5 s andthen moves with an accelerabon brona tumef=sslot10 .The velocity - time graph representing this situation isFigure 1>Figure 2100)vrare 1Figure 3Figure 4V10.1(5) |
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| 47. |
5. The near point of a hypermetropic eye is 1.8 m. What is the power of the lens requiredto correct this defect? Assume that the near point of the normal eye is 25 cm.Chemin |
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Answer» Answer: The near point of a hypermetropic EYE is 1 m. What is the nature and power of the LENS required to correct this DEFECT ? (Assume that the near point of the normal eye is 25 CM). So, the power of convex lens required is + 3.0 DIOPTRES. |
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| 48. |
А trolley while going down an inclined plane has as acceleration of 2 cm/5² What will be itsvelocity 3s after the start. |
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Answer» Answer: helo guys its your answer Explanation: A TROLLEY while going down an inclined PLANE has an ACCELERATION of 2 cms-2. What will be its velocity 3 seconds after the start? ... The car stops in 5 s. Another driver going at 34 |
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| 49. |
Iv) The second law of thermodynamicsdeals with transfer of:(A) work done (B) energy(C) momentum (D) heatat |
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Answer» energy Explanation: mark as BRAINLIST |
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| 50. |
The farpoint of a myopic person is 100 cm in front of the eye. What is the nature andpower of the lens required to correct the problem? |
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Answer» Explanation: The person is suffering from myopia and hence need a concave lens to CORRECT the defect. The lens should be such that an OBJECT at infinity must form its image at the far point. Hence, f = - 100cm = - 1m The POWER of the lens can be obtained as : P = 1/f P = 1/(- 1) = - 1D Hope this helps. MARK AS BRAINLIEST. |
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