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A constant force is applied for 2s on a body of mass 5kg.as a result, if the velocity of the body is changed from 3m/s to 7 m/s.find the value of the force applied |
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Answer» Answer: 10kg-m/s^(2) v=u+at 7=3+a*2 a=2m/s^(2) F=ma =5*2 F=10 |
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