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This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
A particle is moving in circular path of radius 2m with a constant speed of 30m/s find the magnitude and direction of change in velocity as the particle moves from2)A to B 3)Cto D |
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| 2. |
When an object moves with constant speed in circular path ,then which of the following is false.A)The tangent to the circular pathB)The outward radiusC)The inward radiusD)The axis of rotationPLS EXPLAIN WHY |
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Answer» Answer: please follow me please make me brainlest Explanation: Review the key CONCEPTS, EQUATIONS, and skills for uniform circular MOTION, INCLUDING centripetal acceleration and the difference between LINEAR and angular velocity |
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| 3. |
Proof motional emf. AndIf the velocity 1 m per second length 132m and magmatic field is 320 Tesla registance is 10 ohm . Find current...( Ignore negative Sign) |
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Answer» plz MARK it as briliniast answer And when I was wondering if you are not AUDIBLE to us and we |
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| 4. |
17. Age of fossils can be determined by:(1) radio-carbon dating(2) astronomical studies(3) morphological analysis(4) platinum-dating |
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Answer» (1)radio carbon dating Explanation: |
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| 5. |
The numerical ratio of displacement to distance for a moving object is : *2 points(a) always less than 1(B) always equal to 1(C) always more than 1(D) equal or less than 1 |
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Answer» Answer: the RATIO of displacement to DISTANCE for a moving object is equal to less than 1. Explanation: FOLLOW me |
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| 6. |
The upper half of an inclined plane is smooth and the lower half rough. A blockallowed to slide down from the top is brought to rest by friction just as it reaches thebottom. Find the ratio of the force of friction to the weight of the particle, assumingfriction to be independent of velocity. |
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Answer» the answer is GIVEN above |
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| 7. |
3 oblainpossible speed at vehicle Alongan expression for maximumhorizontal corcular trackСІ |
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Answer» Answer: |
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| 8. |
Some substance given below identify and classify them as solids liquids and gaseous based on their physical states and write them in the table |
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| 9. |
Calculate the power of a concave lens whose principal focus is at a distance of500cm from its optical center |
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Answer» here is your answer -0.20 DIOPTRE |
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| 10. |
From a disc of radius R a mass M, a circular hole of diameter R, whose rim passes through the center is cut. What is the moment of inertia of the remaining part of the disc about a perpendicular axis to the plane of the disk and passing through other end of diameter itP.S I hope you die if you give a shlt answer |
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Answer» From a DISC of radius RandmassM, a circular hole of diameter R, whose rim passes through the CENTRE is cut. What is the moment of inertia of remaining part of the disc about a perependicular axis, PASSING through the centre ? =MR22-332MR2=1332MR2. |
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| 11. |
Why don't the magnetic field lines in a magnetic field intersect??Answer this question to get a brainliest |
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Answer» if they do so there will be TWO DIRECTIONS ,which is not possible. plz MARK as BRAINLIEST |
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| 12. |
Describle an activity to show that image distance and nature of image depends on objects distance for a concave mirror |
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Answer» The size of the image depends UPON the distance of the OBJECT from the mirror and it's position with respect to the mirror's SURFACE. ... Light rays parallel to the optical or principal axis are reflected from the surface in a manner that diverges from a FOCAL point that is behind the mirror. Explanation: Mark as brainlist |
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| 13. |
Which of the is true for displacement? (1)A) It cannot be zeroB) Its magnitude is greater than the distance travelled by the object. C) It's the shortest distance between initial & final position.D) It is a vector quantity. |
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Answer» ANSWER:kjcaachsdjdj jsfhjfhahdf fjsafhjfa Explanation: ajkdasnsjndsjdsjdhdjsdhsdhsd jsdsjdhsjdhskjdsjds |
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| 14. |
OThe Law of reflection hold true for:Planal mirror onlyConvex mirror onlyConcave mirror Onlyall deflecting sto face |
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Answer» . . . \\\\\\\\\\ |
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| 15. |
The speed of a projectile u reduces by 50% on reaching maximum heightwhat is the range on the horizontal plane ? |
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Answer» your ANSWER is in this ATTACHMENT |
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| 16. |
सार्वत्रिक गुरुत्वीय नियतांक G की विमा क्या है?[M¹L²T⁰][M⁻¹L¹T⁻²][M²L¹T¹][M⁻¹L³T⁻²] |
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Answer» .............................................................................. ........................................,.................................... .............................................................................. |
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| 17. |
160लपराभर उ घटेर घय राननापिनगिऊगा कि उससीधेपू10२)3040हा- छलाप चपमघरपेपजाळ यहि पाल मापारि मारियोसाधीon०ਹਿੰਦੀل با کउिपरबाई हटीगा- कोणा पीणा कर रिण इत्त शनिंगघले |
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| 18. |
Single Line Question Option : No Option Orientation :erticalTwo point objects A and B each of mass 3 g and initially at rest are connected by masslessthreads as shown in the figure. A constant force 2 Nacts on the system at point P along OP.After the point 'O' has moved a distance 20 cm in the direction of force, the two objectscollide and stick together. The displacement and velocity of the centre of mass of thesystem immediately after collision are respectivelyఒక్కొక్కటి ద్రవ్యరాశి గల బిందు పరిమాణం గల A మరియు B అనే రెండు వస్తువులు పటంలోచూపిన విధంగా తేలికైన దారాలతో కలుపబడినవి. OP దిశలో P బిందువు వద్ద 20ల స్థిరబలం వ్యవస్థపై పనిచేయుచున్నది. '0' బిందువు బలప్రయోగ దిశలో 20 cm జరిగిన తర్వాత రెండు వస్తువులుఅభిఘాతం చెంది ఒకదానికి ఒకటి అతుక్కున్నవి. అభిఘాతం జరిగిన వెంటనే, వ్యవస్థ ద్రవ్యరాశి కేంద్రంయొక్క స్థానభ్రంశం మరియు వేగం వరుసగా10cm1|190600OP90060F=2NI10cmB |
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Answer» if a ORIENTATION is 0 and 20 cm and 3g of INTIALLY at rest so 10 cm 100 f=2n |
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| 19. |
The value of magnetic susceptibility of paramagnetic substance(a)negative and small(b)negative and large(c)positive and small(d)positive and large |
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Answer» MAGNETIC susceptibility is χ>0 which means it is always a small POSITIVE value for paramagnetic materials. These materials are TEMPERATURE dependent and are weekly attracted by magnets with relative permeability 1.00001 to 1.003. (C) Positive and Small |
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| 20. |
The maximum speed of particle performingS.H.M. is 6.28 cm/s , if the length of its path is 8cm,then its period is... |
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Answer» Hope this will help you PLEASE mark me as brainleast Explanation: v= 6.28 l of path = 8 cm that means Amplitude A = 4 cm v=OMEGA*A omega= v/A =6.28/4 time period= 2π/(omega) = 6.28/(omega) =4 s |
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| 21. |
The number of electric lines of force radiating from a closed surface in vacuum is 1.1The charge enclosed by the surface is |
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| 22. |
06.एक वस्तु L लंबाई की एक डोरी के सिरे पाऊर्ध्वाधर तल मे घूम सकती है। उच्चतम स्थितिमे वस्तु को दिया गया क्षैतिज वेग, यदि न्यूनतमस्थिति मे डोरी मे तनाव वस्तु के भार का दसगुना है, होगा:(A)/13gl(B)(6gL(C)5gL(D)✓ gl |
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Answer» √gl is the WRITE answer |
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| 23. |
The average translational kinetic energy of O2(molar mass 32) molecules at a particulartemperature is 0.048 eV. The translationalkinetic energy of N, (molar mass 28)molecules in eV at the same temperature is1) 0.0015 2) 0.003 3) 0.048 4) 0.768 |
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Answer» 33.4 is was the crect answer |
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| 24. |
4 pointsThe dimensional equation cannot be used --- 1) to check the correctness of a physical quantity 2) to derive the relation between different physical quantities 3) to find out constant of proportionality which many be pure number 4) to change from one system of units to another system. |
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Answer» Answer: 3............................. |
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| 25. |
29. Can a body possess energy even when it is notin motion ? Explain your answer with anexample. |
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Answer» Explanation: YES, a body possesses energy even when it is not in motion ; Consider a body raised to a certain height say H. It its velocity is zero. Kinetic energy will be zero but the body will have. P.E. = mgh Thus, a body may POSSESS energy even though it is not in motion. |
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| 26. |
Q10: I am a country where democratic function of the government is based on byparty ( two party) system. Name me.1 |
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Answer» America hope you GOT it.. |
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| 27. |
A cheetah can start from rest and attain velocity 72 km/hr in 2 seconds. calculate the acceleration of cheetah.Plz... Answer me guys.. It's very urgent... |
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Answer» a = 10m/s^2 Explanation: v = U + at 20 = 0 + 2a a = 10m/s^2 fairly high |
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| 28. |
A concave mirror of focal length f, forms the virtual and erect image larger in size of the object. The object is placed at a distanceSelect one:a. Beyond Cb. Between C and fc. Between P and fd. At C |
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| 29. |
4. How two resistors are joined with a battery such that equivalent resistance is morethan either of the two resistances *(1 Point)Enter your answer |
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Answer» CORRECT EXPLANATION and correct answer |
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| 30. |
The areas of pistons in a hydraulic machine are 5 centimetre square and 250 centimetre square. What force on the smaller piston willport a load of 1250 N on the larger piston?10 N15 N20 N25 N |
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Answer» ruzotsiz7ra74q3y4q7xlxgzufzits59s6psori6s6osyspyoetisw7 |
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| 31. |
A heater rated at and , calculate:a) Currentb) Energy consumed in 2 hoursc) Cost if is priced at `4.60/- |
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| 32. |
A jeep traveling at a constant speed of 108 km/h rounds a cure of radius100m. Find its acceleration?A. 3m/sec?B. 6m/sec?C. 7m/sec?D. 8m/sec?E. 9m/secThe answer is E. All I want is the solution with explanation plz |
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Answer» E.9m/sec Explanation: |
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| 33. |
18. In Fig. 1.35, a uniform bar of length 1 m is supportedat its ends and loaded by a weight W kgf at its middle.In equilibrium, find the reactions R, and R, at the ends.RAR2W kgf |
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Answer» Answer: R1+R2=w (Balancing FORCES in Y−ax) __(I) Writing EQUATION for torque about the CENTRE of bar : R1(0.5)+w(0)−R2(0.5)=0 R1=R2 __(II) From EQ. (I) & (II) R1=R2=2wKgf. |
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| 34. |
17. A uniform metre rule of mass 100 g is balanced on afulcrum at mark 40 cm by suspending an unknownmass m at the mark 20 cm.(i) Find the value of m.(ii) To which side the rule will tilt if the mass m ismoved to the mark 10 cm ?(iii) What is the resultant moment now?(iv) How can it be balanced by another mass of50 g ?Ans. (i) m = 50 g, (ii) on the side of mass m,(iii) 500 gf x cm (anticlockwise),(iv) by suspending the mass 50 g at the mark 50 cm. |
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Answer» From the principle of moments, Clockwise moment = Anticlockwise moment 100 g × (50 – 40) cm = m × (40 – 20) cm 100 g × 10 cm = m × 20 cm m = 50 g If the mass m is MOVED to the mark 10 cm, the rule will tilt on the side of mass m (anticlockwise) Anticlockwise moment if mass m is moved to the mark 10 cm = 50 g × (40 – 10) cm = 50 g × 30 cm = 1500 g cm Clockwise moment = 100 g × (50 – 40) cm = 100 g × 10 cm = 1000 g cm Resultant moment = 1500 g cm – 1000 g cm = 500 g cm (anticlockwise) According to the principle of moments. Clockwise moment = Anticlockwise moment To balance it, 50 g WEIGHT should be kept on right-hand side so as to produce a clockwise moment. Let d cm be the DISTANCE from the fulcrum. Then, 100 g × (50 – 40) cm + 50 g × d = 50 g × (40 – 10) cm 100 g × 10 cm + 50 g × d = 50 g × 30 cm 1000 g cm + 50 g × d = 1500 g cm 50 g × d = 500 g cm Then, d = 10 cm It can be balanced by suspending the mass 50 g at the mark 50 cm. |
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| 35. |
5. The following observations were take fordetermining surface tension of water bycapillary tube method. Diameter of capillar,D=125x10-2m and rise of water incapillaryh=1.46 x 10-2m.Taking g=9.80ms-2 and using therelationT=(rgh/2) x 103Nm"?, what is the possibleerror in surface tension T?(a) 2.4%(b) 15%(c) 1.6%(d)0.15% |
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Answer» Answer: The force of surface tension on a ring SITUATED on the surface of WATER is 14π×10^-4N. Then the diameter of the ring is (surface tension of water = 70×10^-3 N/m) a) 5 mm b) 1 cm c) 2 cm d) 4 cm plz.*solve* & *explain it..* |
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| 36. |
What will happen to the gravitational force between two bodies if the massesof one body is doubled? |
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Answer» The GRAVITATIONAL FORCE will ALSO be DOUBLED |
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| 37. |
Which of following nature of light waves is supported10.by the phenomenon of interference :(1) longitudinal(2) transverse(3) both transverse and longitudinal(4) None of the above |
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| 38. |
16. The far point of a myopic eye is 80 cm in front of the eye. What is the power of thelens required to enable him to see far off objects? |
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Answer» Answer: The nature and the POWER of LENS required to enable him to SEE very distant objects clearly is CONCAVE lens with -1.25 D. Explanation: For person affected with myopic condition, the image instead of forming on retina, it forms in front of it. In order to CURE such type of defect, concave lens is used this is right answer |
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| 39. |
Calculate the mass of the body whose volume is 5 cu.m and relative density is 2.5?1250 kg 2500 kf 12,500 kg 12.5 kg |
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Answer» ............. |
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| 40. |
A particle moves in straight line with velocity 6 m/s and3 m/s for time intervals which are in ratio 1:2. Findaverage velocity.(a) 2 m/s (6) 3 m/s (c) 4 m/s(d) 5 m/s |
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Answer» Answer: Key Idea average velocity and instantaneous VELOCITIES have same value in a uniform motion. Average velocity is that uniform velocity with which the object will cover the same displacement in same interval of time as it does with actual VARIABLE velocity during that time interval. =(3m/s×20s)+(4m/s×20s)+(5m/s×20s) =(60+80+100)−240m Total time taken =20+20+20 =60s ∴ Average velocity = 60 240 =4m/s Explanation: MARK as brainliest |
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| 41. |
Question related to physics the first correct answer for the same question will be marked as brainliestIrrelevant answer will be reported |
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Answer» 1 is the answer bro PLEASE MARK AS BRAINLIEST |
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| 42. |
A stone thrown vertically upwards with an initial velocity 30 metre per second comes to a stop in 5 s. Find the retardationoptions are: 6 metre per second square- 6 metre per second square5 metre per second square-5 metre per second square |
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Answer» ACCELERATION a= t v−u
= 5s 0−50ms −1
=−10ms −2
Retardation=−Acceleration −2 |
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| 43. |
20. Two vectors S and R are such that ISI = 4, IRI = 6 and S.R = 13.5. Find theangle between S and R.A. 11.770B. 22.999C. 55.770D. 77.81°E. 99.18 |
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| 44. |
(c) I, III and IV6. A particle moves in straight line with velocity 6 m/s and3 m/s for time intervals which are in ratio 1:2. Findaverage velocity.(a) 2 m/s (b) 3 m/s (c) 4 m/s (d) 5 m/s(11 m The magnitude |
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Answer» Answer: The SLOPE of a POSITION-TIME graph REPRESENTS velocity. The steeper the slope is, the faster the motion is changing. Average velocity can be calculated from a position-time graph as the change in position divided by the corresponding change in time. mark as brainliest Explanation: |
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| 45. |
18. A block of mass 120 g moves with a speed of 6.0 m/son a frictionless horizontal surface towards anotherblock of mass 180 g kept at rest. They collide and thefirst block stops. Find the speed of the other blockafter the collision. |
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Answer» Answer: 55ggtvtj the water 9 should I will SEND it out LOUD when we are done and all of your family members are in the same and I can object in a bit to see and HEAR the NEWS of their own thing and all the rider for the NEXT |
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| 46. |
It takes 0.3 s for a pendulum bob to move from mean position to one end.What is the time period of pendulum?181.5 s1.2 s2 s |
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Answer» jsgdjshbxbdhdndjjdn Answer: jdnxhdjjdjdkdju3hxhzfshhdjdjxhdyshjshrhehydhdjdhhdydhdhdh Explanation: ajsjsgshhshwjdjdndhdjdnejjdndbdusbbnshhsbdhxybsjdudhgeysyydy |
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| 47. |
If a body is moving on a circular path of radius 21m then distance travelled and displacement of the body after 1 complete round will be132 and 0132 and 1320 and 00 and 132 |
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Answer» Answer: HOPE MY ANSWERS HELPS U IF U HAD PLZZZ BRAINLIST ME AND FOLLOW ME Explanation: Displacement is the SHORTEST distance travelled from the initial POINT to the final point. After half revolution the displacement is the length of the diameter which is equal to 2R. HENCE the displacement is 2r. |
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| 48. |
Q8. If both the masses aredoubled and distance betweenthem is same then force ofattraction between the masseswill be |
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Answer» hope its helpful to you |
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| 49. |
A stone is dropped from a height 4.9 m from the ground. Find with which velocity it touches the ground.( Take g= 9.8 metre per secondsquare)options are:0 m/s14 m/s9.8 m/s5 m/s |
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Answer» a) v=0+9.8×2 v=19.6m/s^2 Explanation: PLEASE FOLLOW me and MARK me as BRAINLIEST plzzzzzzzzxx |
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| 50. |
An alpha particle is moving towards a "person" facing east the direction of magnetic field lines when will be |
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Answer» Answer: anticlockwise I think but not SURE |
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