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The maximum speed of particle performingS.H.M. is 6.28 cm/s , if the length of its path is 8cm,then its period is... |
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Answer» Hope this will help you PLEASE mark me as brainleast Explanation: v= 6.28 l of path = 8 cm that means Amplitude A = 4 cm v=OMEGA*A omega= v/A =6.28/4 time period= 2π/(omega) = 6.28/(omega) =4 s |
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