18. In Fig. 1.35, a uniform bar of length 1 m is supportedat its ends

1.	18. In Fig. 1.35, a uniform bar of length 1 m is supportedat its ends and loaded by a weight W kgf at its middle.In equilibrium, find the reactions R, and R, at the ends.RAR2W kgf
Answer» Answer: R1+R2=w (Balancing FORCES in Y−ax) __(I) Writing EQUATION for torque about the CENTRE of bar : R1(0.5)+w(0)−R2(0.5)=0 R1=R2 __(II) From EQ. (I) & (II) R1=R2=2wKgf.

18. In Fig. 1.35, a uniform bar of length 1 m is supportedat its ends and loaded by a weight W kgf at its middle.In equilibrium, find the reactions R, and R, at the ends.RAR2W kgf

Answer»

Answer:

R1+R2=w (Balancing FORCES in Y−ax) __(I)

Writing EQUATION for torque about the CENTRE of bar :

R1(0.5)+w(0)−R2(0.5)=0

R1=R2 __(II)

From EQ. (I) & (II)

R1=R2=2wKgf.

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18. In Fig. 1.35, a uniform bar of length 1 m is supportedat its ends and loaded by a weight W kgf at its middle.In equilibrium, find the reactions R, and R, at the ends.RAR2W kgf​

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18. In Fig. 1.35, a uniform bar of length 1 m is supportedat its ends and loaded by a weight W kgf at its middle.In equilibrium, find the reactions R, and R, at the ends.RAR2W kgf